How to use joda time to parse a date time value like this "2011-03-01T01:00:00-07:00"
Does anyone has any code sample to parse the above datetime pattern?
This is an ISO formatted date string. Jodatime supports it as follows:
DateTimeFormatter psr = ISODateTimeFormat.dateTimeParser()
DateTime date = psr.parseDateTime("2011-03-01T01:00:00-07:00")
Related
I have really simple date as string as ISO const mytDate = '2021-10-24T16:00:00.000Z' and I want to format it like format(new Date(myDate), 'yyyy-MM-dd HH:mm:ss') but new Date() cause that it convert it to my local timezone and I do not want it. I would like to take this string date and just format it as it is.
Is there a solution ?
Cheers!
In my Laravel 5.8 application, I to convert date in string format like
02 May, 2019 to date time using Carbon. I try like :
setlocale(LC_TIME, 'en');
$filter_check_in_datepicker_till = Carbon::createFromFormat( 'dd MMMM YYY', $filter_check_in_datepicker_till )->locale('en_EN');;
But got error:
"message": "Unexpected data found.\nA textual month could not be found\nData missing",
Which is right way?
Thanks!
The Carbon docs say:
createFromFormat() is mostly a wrapper for the base php function DateTime::createFromFormat.
It isn't entirely clear from the docs, but that means the $format parameter passed to createFromFormat() is a DateTime format, not a Carbon format. So instead of dd MMMM YYY, you should use d, M Y (check the DateTime format reference):
\Carbon\Carbon::createFromFormat('d, M Y', '02, May 2019');
// returns 2019-05-02 12:48:26
For reference, there are several problems in your Carbon format, so even if createFromFormat took a Carbon format string what you have would not work. Checking the Carbon format reference:
dd is actually "Minified day name (from Su to Sa), transatable". You really want DD for the zero-padded day of month;
The date format you are using includes a comma, but your format string is missing that;
YYY is not actually a valid Carbon format string. You really wanted YYYY for 4-digit year;
With Joda library, you can do
DateTimeFormat.forPattern("yyyy").parseLocalDate("2008")
that creates a LocalDate at Jan 1st, 2008
With Java8, you can try to do
LocalDate.parse("2008",DateTimeFormatter.ofPattern("yyyy"))
but that fails to parse:
Text '2008' could not be parsed: Unable to obtain LocalDate from TemporalAccessor: {Year=2008},ISO of type java.time.format.Parsed
Is there any alternative, instead of specifically writing sth like
LocalDate.ofYearDay(Integer.valueOf("2008"), 1)
?
LocalDate parsing requires that all of the year, month and day are specfied.
You can specify default values for the month and day by using a DateTimeFormatterBuilder and using the parseDefaulting methods:
DateTimeFormatter format = new DateTimeFormatterBuilder()
.appendPattern("yyyy")
.parseDefaulting(ChronoField.MONTH_OF_YEAR, 1)
.parseDefaulting(ChronoField.DAY_OF_MONTH, 1)
.toFormatter();
LocalDate.parse("2008", format);
String yearStr = "2008";
Year year = Year.parse(yearStr);
System.out.println(year);
Output:
2008
If what you need is a way to represent a year, then LocalDate is not the correct class for your purpose. java.time includes a Year class exactly for you. Note that we don’t even need an explicit formatter since obviously your year string is in the default format for a year. And if at a later point you want to convert, that’s easy too. To convert into the first day of the year, like Joda-Time would have given you:
LocalDate date = year.atDay(1);
System.out.println(date);
2008-01-01
In case you find the following more readable, use that instead:
LocalDate date = year.atMonth(Month.JANUARY).atDay(1);
The result is the same.
If you do need a LocalDate from the outset, greg449’s answer is correct and the one that you should use.
I didn't get you
but from the title I think you want to parse a String to a localdate so this is how you do it
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("d/MM/yyyy");
String date = "16/08/2016";
//convert String to LocalDate
LocalDate localDate = LocalDate.parse(date, formatter);
From a java.util.Date( a timestamp), how can I get the hour of day?
In joda.time I use getHourOfDay().
There are multiple solutions for this. If you wish to use the Java 8 classes from java.time the following you need to covert a Date to one of the DateTime classes. The following can be used to convert a Date to a ZonedDateTime where you then can get the hour:
Date date = new Date();
// Convert to java 8 ZonedDateTime
Date date = new Date();
final ZonedDateTime dateTime = date.toInstant()
.atZone(ZoneId.systemDefault());
// Get the hour
int hour = dateTime.getHour();
Quite verbose as you have noticed but the simple reason for this is that a Date is sort of an Instant
Despite its name, java.util.Date represents an instant on the time-line, not a "date". The actual data stored within the object is a long count of milliseconds since 1970-01-01T00:00Z (midnight at the start of 1970 GMT/UTC).
Another approach is simply to get the field from a Calendar instance.
final Calendar instance = Calendar.getInstance();
instance.setTime(date);
final int hourOfDay = instance.get(Calendar.HOUR_OF_DAY);
How can I concatenate the values of two datetimepicker?
DateTimePicker1 - this is for the the DATE mm/dd/yyyy
DateTimePicker2 - this is for the the TIME hh:mm:ss
I want a value of ... mm/dd/yyy hh:mm:ss in one variable, how can I do that?
One easy way would be
DateTime dt = new DateTime(dtp1.Year, dtp1.Month, dtp1.Day, dtp2.Hour, dtp2.Minute, dtp2.Second);
Please check the order of the parameters, I am writing from memory.
Here dtp1 is a DateTime object from the first datetime picker.