Im having trouble inserting a row in my table. Here is the insert statement and table creation. This is part of a uni assignment hence the simplicity, what am i doing wrong? Im using oracle SQL developer Version 3.0.04.'
The problem i am having is that it is only inserting the dd/mon/yy but not the time. How do i get it to insert the time as well?
INSERT INTO WORKON (STAFFNO,CAMPAIGNTITLE,DATETIME,HOURS)
VALUES ('102','Machanic Summer Savings',TO_DATE('22/April/2011 8:30:00AM','DD/MON/YY HH:MI:SSAM'),'3')
;
CREATE TABLE WorkOn
(
StaffNo NCHAR(4),
CampaignTitle VARCHAR(50),
DateTime DATE,
Hours VARCHAR(2)
)
;
Thanks for the help.
EDIT: This is making no sense, i enter just a time in the field to test if time is working and it outputs a date WTF? This is really weird i may not use a date field and just enter the time in, i realise this will result in issues manipulating the data but this is making no sense...
You can use
insert into table_name
(date_field)
values
(TO_DATE('2003/05/03 21:02:44', 'yyyy/mm/dd hh24:mi:ss'));
Hope it helps.
You are doing everything right by using a to_date function and specifying the time. The time is there in the database. The trouble is just that when you select a column of DATE datatype from the database, the default format mask doesn't show the time. If you issue a
alter session set nls_date_format = 'dd/MON/yyyy hh24:mi:ss'
or something similar including a time component, you will see that the time successfully made it into the database.
Try this:
...(to_date('2011/04/22 08:30:00', 'yyyy/mm/dd hh24:mi:ss'));
Just use TO_DATE() function to convert string to DATE.
For Example:
create table Customer(
CustId int primary key,
CustName varchar(20),
DOB date);
insert into Customer values(1,'Vishnu', TO_DATE('1994/12/16 12:00:00', 'yyyy/mm/dd hh:mi:ss'));
create table Customer(
CustId int primary key,
CustName varchar(20),
DOB date);
insert into Customer values(1,'kingle', TO_DATE('1994-12-16 12:00:00', 'yyyy-MM-dd hh:mi:ss'));
Related
I have a table named masterregistry and it contains all the info and business logic in it and the data type of the colum is clob
desc master_registy:
id number not null,
name varchar2(100),
value clob
select value from master_registry where name='REG_DATE';
o/p
11-10-17
This date is common across all the business logic, I need to query my tables which has ,
desc get_employee
====================
id number not null,
first_name varchar2(100),
last_name varchar2(100),
last_mod_dt timestamp
Now I need to get all the values from the get_employee whose last_mod_dt should be greater than the value of master_registry where name='REG_DATE'.The value in the latter table is clob data, how to fetch and compare the date of a clob data against the timestamp from another table. Please help.
Maybe you need something like this.
SELECT *
FROM get_employee e
WHERE last_mod_dt > (SELECT TO_TIMESTAMP (TO_CHAR (VALUE), 'DD-MM-YY')
FROM master_registy m
WHERE m.id = e.id);
DEMO
Note that i have used the column value directly in TO_CHAR. You may have to use TRIM,SUBSTR or whatever required to get ONLY the date component.
I did the following:
CREATE TABLE BOOK(
BOOK_ID VARCHAR(4) PRIMARY KEY,
ISBN_10 VARCHAR(10),
TITLE VARCHAR(50),
CATEGORY VARCHAR(25),
PRICE DECIMAL(6,2),
BINDING VARCHAR(2),
PUB_DATE DATE,
AUTHOR_ID SMALLINT,
PUBLISHER_ID SMALLINT
);
2.
ALTER SESSION SET nls_date_format = 'DD-MM-YYYY HH24:MI:SS';
3.
INSERT INTO BOOK
VALUES('4','123459','INTRODUCTION TO SmallTalk','IT',157.00,'S',**'26-01-1991'**,13,103);
It gave an error:
ORA-01843: not a valid month
However if do the following there is no problem:
Query:
INSERT INTO
BOOK
VALUES('4','123459','INTRODUCTION TO Small Talk','IT',157.00,'S','**26-JAN-1991**',13,103);
Can anyone explain why?
You want to read the Datetime Literals section of the manual. Alternatives are:
Use a date literal: DATE '1991-01-26'
Convert from string: TO_DATE('26-01-1991', 'DD-MM-YYYY')
If you set NLS_DATE_FORMAT you can omit TO_DATE()'s second argument but not skip the function entirely.
See also: Datetime Format Models
It worked for me. That implies that your alter statement did not work for some reason. However, it is not good practice to assume a specific date format on a system when using literals. Instead, cast the literal with a format mask on the insert, such as:
INSERT INTO BOOK
VALUES('4','123459','INTRODUCTION TO Small Talk','IT',157.00,'S',
to_date('26-JAN-1991','DD-MON-YYYY'), 13,103);
(or whatever format you require as a literal input value)
This because in your database, nls_date_time is set to 'DD-MON-RRRR' format, you can check this using
select * from V$NLS_PARAMETERS
In this query
INSERT INTO BOOK VALUES('4','123459','INTRODUCTION TO SmallTalk','IT',157.00,'S','26-01-1991',13,103);
date format is 'dd-mm-rrrr', change the statement as
INSERT INTO BOOK VALUES('4','123459','INTRODUCTION TO SmallTalk','IT',157.00,'S',to_date('26-01-1991', 'dd-mm-rrrr'),13,103);
and it will also run since you have now provided the date format.
When you set
ALTER SESSION SET nls_date_format = 'DD-MM-YYYY HH24:MI:SS';
then your insert must match this format, i.e.
INSERT INTO BOOK VALUES('4','123459','INTRODUCTION TO SmallTalk','IT',157.00,'S',
'26-01-1991 00:00:00'
,13,103);
However, the more secure way is to use date literals or TO_DATE function.
You just need to use
INSERT INTO TABLE_NAME VALUES('07-JAN-96');
Oracle always takes "DD-MMM-YY" format. You should write your month as the first 3 characters of month name.
Table creation query:
create table students(
student_no number,
student_name varchar2(20),
student_addres varchar2(25),
student_dob date
joining_time date
)
Insert query:
insert into students
values (1,'ram','chittoor',to_date('02/04/2012','dd/mm/yyyy'),to_date('01:21:45','hh:mi:ss))
result:1 row inserted
Query to check insert:
select * from students
Result:
student_no student_name student_address student_dob joining_date
.......... ............ ............... ........... ............
1 ram chittoor 2-apr-2012 1-jul-2012
Qhy are the time values not getting inserted properly?
Your date is inserted properly, the tool you're using just seems to show the date without the time potion, check your tool settings;
Oracle has no support for Time only format, only date and time. Here is an excerpt from Oracle type documentation:
In a time-only entry, the date portion defaults to the first day of
the current month
Which is the case, you you get 1-July.
Based on this info, you'll need to rethink your queries.
Here is working example
If you want to get the Time from joining_time column then your,
Select query should be
SELECT student_no,
student_name,
student_addres,
student_dob,
TO_CHAR (joining_time, 'hh:mi:ss') AS joining_time
FROM students
My table has two DATE format attributes, however, when i try to insert value it throws an error: date format picture ends before converting entire input string.
Here is my attempted code:
insert into visit
values(123456, '19-JUN-13', '13-AUG-13 12:56 A.M.');
I think the problem is with 12:56 but Oracle documentation says date implies both date and time.
Perhaps you should check NLS_DATE_FORMAT and use the date string conforming the format.
Or you can use to_date function within the INSERT statement, like the following:
insert into visit
values(123456,
to_date('19-JUN-13', 'dd-mon-yy'),
to_date('13-AUG-13 12:56 A.M.', 'dd-mon-yyyy hh:mi A.M.'));
Additionally, Oracle DATE stores date and time information together.
you need to alter session
you can try before insert
sql : alter session set nls_date_format = 'YYYY-MM-DD HH24:MI:SS'
What you're trying to insert is not a date, I think, but a string. You need to use to_date() function, like this:
insert into table t1 (id, date_field) values (1, to_date('20.06.2013', 'dd.mm.yyyy'));
I had this error today and discovered it was an incorrectly-formatted year...
select * from es_timeexpense where parsedate > to_date('12/3/2018', 'MM/dd/yyy')
Notice the year has only three 'y's. It should have 4.
Double-check your format.
I have a pair of columns that were unfortunately defined incorrectly as TIMESTAMP(6) instead of TIMESTAMP(6) WITH TIME ZONE. I would like to migrate those columns from the old, wrong datatype to the new, correct one. On top of that, the values appear to have been captured in E(S|D)T and I need the value in UTC.
So far, the best I've got is:
alter table OOPSIE_TABLE add (
NEW_COLUMN_A timestamp(6) with time zone,
NEW_COLUMN_B timestamp(6) with time zone
);
update OOPSIE_TABLE set
NEW_COLUMN_A = COLUMN_A,
NEW_COLUMN_B = COLUMN_B
;
alter table OOPSIE_TABLE drop column (
COLUMN_A,
COLUMN_B
);
alter table OOPSIE_TABLE rename column NEW_COLUMN_A to COLUMN_A;
alter table OOPSIE_TABLE rename column NEW_COLUMN_B to COLUMN_B;
Unfortunately, that leaves me with data that looks like 15-JUN-12 05.46.29.600102000 PM -04:00, when I want 15-JUN-12 09.46.29.600102000 PM UTC (or however Oracle would format it).
I've done select dbtimezone from dual; and it shows me +00:00, so I'm not sure how to proceed. Ideally, I would be able to do this in pure DML, and have it account for DST based on the old date values (which I'm sure are in the America/New_York timezone).
With a little help from #JustinCave, I arrived at the following solution, which accomplishes exactly what I wanted:
-- Rename the old columns so we can use them as a data source *AND* so
-- we can roll back to them if necessary.
alter table OOPSIE_TABLE rename column COLUMN_A to OLD_COLUMN_A;
alter table OOPSIE_TABLE rename column COLUMN_B to OLD_COLUMN_B;
-- Define COLUMN_A and COLUMN_B to have TIME ZONE support.
alter table OOPSIE_TABLE add (
COLUMN_A timestamp(6) with time zone,
COLUMN_B timestamp(6) with time zone
);
-- Populate the "new" columns with the adjusted version of the old data.
update OOPSIE_TABLE set
COLUMN_A = from_tz(OLD_COLUMN_A, 'America/New_York') at time zone 'UTC',
COLUMN_B = from_tz(OLD_COLUMN_B, 'America/New_York') at time zone 'UTC'
;
For me it looks good.
`SELECT SYS_EXTRACT_UTC(TIMESTAMP '2012-06-15 05:46:20 -04:00') FROM DUAL;`
gives:
2012-06-15 09:46:20
You simply live in country with 4 hour difference to UTC.
Also try something like:
SELECT to_char(new_column_a, 'YYYY-MM-DD HH24:MI:SS TZD'), sys_extract_utc(new_column_a) FROM oopsie_table;