Trimming a String - windows

I'm using windows 7 and Visual C++. I have a console program and I am trying to trim a string at the begining and the end. TrimLeft() and TrimRight() don't seem to work without MFC. Here is what I have so far.
pBrowser->get_LocationURL(&bstr);
wprintf(L" URL: %s\n\n", bstr);
SysFreeString(bstr);
std::wstring s;
s = bstr;
s.TrimStart("http://");
s.TrimEnd("/*");
wprintf(L" URL: %s\n\n", s);
I'm trying to go from this:
"http://www.stackoverflow.com/questions/ask"
to this:
"www.stackoverflow.com"

TrimStart/End usually return a value, so you would have to set 's' to equal the value of s.TrimStart() and s.TrimEnd() respectively.
try,
s = s.TrimStart("http://");
s = s.TrimEnd("/*");

You should use find/rfind(right find - find from right) and substr(sub string) in sequence to do what you need to do.
1) Find the index of the first pattern (such as http://) with find - you already know its length, add this to the start index as the origo of your trimmed string
2) Find the last index of the ending pattern with find
3) Create a substring from the origo to the end using substr
These methods are all in std::string

Related

FoxPro Deleting after specific

I am trying to replace text after "/" on foxpro. Shelly Jones/Foundation Director, How to delete everything after the "/"?
A common way of doing it is to combine the left() and atc() functions, like so:
lcStr = "Shelly Jones/Foundation Director"
lcNewStr = LEFT(lcStr, ATC('/', lcStr) - 1)
The -1 is needed to get the portion of the string ending before the / character.
Assuming this is VFP 7 or later, use the StrExtract function:
cResult = STREXTRACT(cOriginalString, '', '/')

string size limit input cin.get() and getline()

In this project the user can type in a text(maximum 140 characters).
so for this limitation I once used getline():
string text;
getline(cin, text);
text = text.substr(1, 140);
but in this case the result of cout << text << endl; is an empty string.
so I used cin.get() like:
cin.get(text, 140);
this time I get this error: no matching function for call to ‘std::basic_istream::get(std::__cxx11::string&, int)’
note that I have included <iostream>
so the question is how can I fix this why is this happening?
Your first approach is sound with one correction - you need to use
text = text.substr(0, 140);
instead of text = text.substr(1, 140);. Containers (which includes a string) in C/C++ start with index 0 and you are requesting the string to be trimmed from position 1. This is perfectly fine, but if the string happens to be only one character long, calling text.substr(1, 140); will not necessarily cause the program to crash, but will not end up in the desired output either.
According to this source, substr will throw an out of range exception if called with starting position larger than string length. In case of a one character string, position 1 would be equal to string length, but the return value is not meaningful (in fact, it may even be an undefined behavior but I cannot find a confirmation of this statement - in yours and my case, calling it returns an empty string). I recommend you test it yourself in the interactive coding section following the link above.
Your second approach tried to pass a string to a function that expected C-style character arrays. Again, more can be found here. Like the error said, the compiler couldn't find a matching function because the argument was a string and not the char array. Some functions will perform a conversion of string to char, but this is not the case here. You could convert the string to char array yourself, as for instance described in this post, but the first approach is much more in line with C++ practices.
Last note - currently you're only reading a single line of input, I assume you will want to change that.

How to replace the last two '/' characters from a string in Go

profilePicture := strings.Replace(tempProfile, "/", "%2F", -2)
I tried this code but its replace all / in the string
tempProfile = "https://firebasestorage.googleapis.com/v0/b/passporte-b9070.appspot.com/o/profilePicturesOfAbmin/original/1492674641download (3).jpg?alt=media"
the result which want is
tempProfile = "https://firebasestorage.googleapis.com/v0/b/passporte-b9070.appspot.com/o/profilePicturesOfAbmin%2Foriginal%2F1492674641download (3).jpg?alt=media"
First, from the documentation:
Replace returns a copy of the string s with the first n non-overlapping instances of old replaced by new. If old is empty, it matches at the beginning of the string and after each UTF-8 sequence, yielding up to k+1 replacements for a k-rune string. If n < 0, there is no limit on the number of replacements. (Emphasis added)
Which explains why your -2 isn't working.
The simplest approach to your stated problem is probably something like this:
parts := strings.Split(tempProfile, "/")
parts = append(parts[:len(parts)-3], strings.Join(parts[len(parts)-3:], "%2F"))
profilePicture := strings.Join(parts, "/")
But a better approach is probably to do proper URL encoding with the url package.

In TI-BASIC, how do I add a variable in the middle of a String?

I am wondering how to make something where if X=5 and Y=2, then have it output something like
Hello 2 World 5.
In Java I would do
String a = "Hello " + Y + " World " + X;
System.out.println(a);
So how would I do that in TI-BASIC?
You have two issues to work out, concatenating strings and converting integers to a string representation.
String concatenation is very straightforward and utilizes the + operator. In your example:
"Hello " + "World"
Will yield the string "Hello World'.
Converting numbers to strings is not as easy in TI-BASIC, but a method for doing so compatible with the TI-83+/84+ series is available here. The following code and explanation are quoted from the linked page:
:"?
:For(X,1,1+log(N
:sub("0123456789",ipart(10fpart(N10^(-X)))+1,1)+Ans
:End
:sub(Ans,1,length(Ans)-1?Str1
With our number stored in N, we loop through each digit of N and store
the numeric character to our string that is at the matching position
in our substring. You access the individual digit in the number by
using iPart(10fPart(A/10^(X, and then locate where it is in the string
"0123456789". The reason you need to add 1 is so that it works with
the 0 digit.
In order to construct a string with all of the digits of the number, we first create a dummy string. This is what the "? is used
for. Each time through the For( loop, we concatenate the string from
before (which is still stored in the Ans variable) to the next numeric
character that is found in N. Using Ans allows us to not have to use
another string variable, since Ans can act like a string and it gets
updated accordingly, and Ans is also faster than a string variable.
By the time we are done with the For( loop, all of our numeric characters are put together in Ans. However, because we stored a dummy
character to the string initially, we now need to remove it, which we
do by getting the substring from the first character to the second to
last character of the string. Finally, we store the string to a more
permanent variable (in this case, Str1) for future use.
Once converted to a string, you can simply use the + operator to concatenate your string literals with the converted number strings.
You should also take a look at a similar Stack Overflow question which addresses a similar issue.
For this issue you can use the toString( function which was introduced in version 5.2.0. This function translates a number to a string which you can use to display numbers and strings together easily. It would end up like this:
Disp "Hello "+toString(Y)+" World "+toString(X)
If you know the length of "Hello" and "World," then you can simply use Output() because Disp creates a new line after every statement.

Processing-NullPointerException when converting string to char

So I have a set of different strings made if a certain key is pressed using keyPressed(), but some of those strings i want to convert to characters and tried doing so like this:
char keyChar = keyChanged.charAt(0);
except now i get a nullpointerexpression. if it matters, keyChanged would be a 1 letter string like "r".
You can avoid a NullPointerException like this:
if (keyChanged != null){
char keyChar = keyChanged.charAt(0);
}
Solved it, It was pretty stupid on my part, I just set the original keyChanged variable as a character instead.

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