BASH shell script echo to output on same line - bash

Question

I have a simple BASH shell script which checks the HTTP response code of a curl command.
The logic is fine, but I am stuck on "simply" printing out the "output".
I am using GNU bash, version 3.2.25(1)-release (x86_64-redhat-linux-gnu)
I would like to output the URL with a tab - then the 404|200|501|502 response. For example:
http://www.google.co.uk<tab>200
I am also getting a strange error where the "http" part of a URL is being overwritten with the 200|404|501|502. Is there a basic BASH shell scripting (feature) which I am not using?
thanks
Miles.
#!/bin/bash
NAMES=`cat $1`
for i in $NAMES
do
URL=$i
statuscode=`curl -s -I -L $i |grep 'HTTP' | awk '{print $2}'`
case $statuscode in
200)
echo -ne $URL\t$statuscode;;
301)
echo -ne "\t $statuscode";;
302)
echo -ne "\t $statuscode";;
404)
echo -ne "\t $statuscode";;
esac
done

Answer 1

From this answer you can use the code
response=$(curl --write-out %{http_code} --silent --output /dev/null servername)
Substituted into your loop this would be
#!/bin/bash
NAMES=`cat $1`
for i in $NAMES
do
URL=$i
statuscode=$(curl --write-out %{http_code} --silent --output /dev/null $i)
case $statuscode in
200)
echo -e "$URL\t$statuscode" ;;
301)
echo -e "$URL\t$statuscode" ;;
302)
echo -e "$URL\t$statuscode" ;;
404)
echo -e "$URL\t$statuscode" ;;
* )
;;
esac
done
I've cleaned up the echo statements too so for each URL there is a new line.

Answer 2

try
200)
echo -ne "$URL\t$statuscode" ;;

Answer 3

I'm taking a stab here, but I think what's confusing you is the fact that curl is sometimes returning more than one header info (hence more than one status code) when the initial request gets redirected.
For example:
[me#hoe]$ curl -sIL www.google.com | awk '/HTTP/{print $2}'
302
200
When you're printing that in a loop, it would appear that the second status code has become part of the next URL.
If this is indeed your problem, then there are several ways to solve this depending on what you're trying to achieve.
If you don't want to follow redirections, simple leave out the -L option in curl
statuscode=$(curl -sI $i | awk '/HTTP/{print $2}')
To take only the last status code, simply pipe the whole command to tail -n1 to take only the last one.
statuscode=$(curl -sI $i | awk '/HTTP/{print $2}' | tail -n1)
To show all codes in the order, replace all linebreaks with spaces
statuscode=$(curl -sI $i | awk '/HTTP/{print $2}' | tr "\n" " ")
For example, using the 3rd scenario:
[me#home]$ cat script.sh
#!/bin/bash
for URL in www.stackoverflow.com stackoverflow.com stackoverflow.com/xxx
do
statuscode=$(curl -siL $i | awk '/^HTTP/{print $2}' | tr '\n' ' ')
echo -e "${URL}\t${statuscode}"
done
[me#home]$ ./script.sh
www.stackoverflow.com 301 200
stackoverflow.com 200
stackoverflow.com/xxx 404