Bash, loop unexpected stop - bash

Question

I'm having problems with this last part of my bash script. It receives input from 500 web addresses and is supposed to fetch the server information from each. It works for a bit but then just stops at like the 45 element. Any thoughts with my loop at the end?
#initializing variables
timeout=5
headerFile="lab06.output"
dataFile="fortune500.tsv"
dataURL="http://www.tech.mtu.edu/~toarney/sat3310/lab09/"
dataPath="/home/pjvaglic/Documents/labs/lab06/data/"
curlOptions="--fail --connect-timeout $timeout"
#creating the array
declare -a myWebsitearray
#obtaining the data file
wget $dataURL$dataFile -O $dataPath$dataFile
#getting rid of the crap from dos
sed -n "s/^m//" $dataPath$dataFile
readarray -t myWebsitesarray < <(cut -f3 -d$'\t' $dataPath$dataFile)
myWebsitesarray=("${myWebsitesarray[#]:1}")
websitesCount=${#myWebsitesarray[*]}
echo "There are $websitesCount websites in $dataPath$dataFile"
#echo -e ${myWebsitesarray[200]}
#printing each line in the array
for line in ${myWebsitesarray[*]}
do
echo "$line"
done
#run each website URL and gather header information
for line in "${myWebsitearray[#]}"
do
((count++))
echo -e "\\rPlease wait... $count of $websitesCount"
curl --head "$curlOptions" "$line" | awk '/Server: / {print $2 }' >> $dataPath$headerFile
done
#display results
echo "Results: "
sort $dataPath$headerFile | uniq -c | sort -n

Answer 1

It would certainly help if you actually passed the --connect-timeout option to curl. As written, you are currently passing the single argument --fail --connect-timeout $timeout rather than 3 distinct arguments --fail, --connect-timeout, and $timeout. This is one instance where you should not quote the variable. IOW, use:
curl --head $curlOptions "$line"