How can I return an id value from a div already populated through ajax - ajax

Question

I am having some difficulty passing a correct id function back to AJAX.
I'm creating a product bulletin generator that lets items to be added by their SKU code (which works fine). My problem is that when a bulletin is clicked on, a preview of that bulletin is loaded into a div and shows all products associated with that bulletin.
From inside those results, I am trying to add the ability to delete a product from the bulletin. The problem is that the value being passed back to AJAX belongs to the first product only. It won't send the value belonging to the particular item if it is any other item than the first one.
This is the code (belonging to main.php) that gets loaded via AJAX into a div and is looped with each product associated with a selected bulletin
echo "<form name='myDelForm'>
$news_gen_id<br>
<input type='hidden' id='delccode' value='".$news_gen_id."'>
<input type='hidden' id='deledit' value='".$edit."'>
<input type='button' onclick='ajaxDelCcode()' value='Delete' /><br></form>
</td>";
The AJAX code (on index.php, where the div that calls in main.php is also located) is this
function ajaxDelCcode(){
var ajaxRequest; // The variable that makes Ajax possible!
try{
// Opera 8.0+, Firefox, Safari
ajaxRequest = new XMLHttpRequest();
} catch (e){
// Internet Explorer Browsers
try{
ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
try{
ajaxRequest = new
ActiveXObject("Microsoft.XMLHTTP");
} catch (e){
// Something went wrong
alert("Your browser broke!");
return false;
}
}
}
// Create a function that will receive data sent from the server
ajaxRequest.onreadystatechange = function(){
if(ajaxRequest.readyState == 4){
var ajaxDisplay = document.getElementById("ajaxMain2");
ajaxDisplay.innerHTML = ajaxRequest.responseText;
}
}
var deledit = document.getElementById("deledit").value;
var delccode = document.getElementById("delccode").value;
var queryString = "?delccode=" + delccode + "&deledit=" + deledit;
ajaxRequest.open("GET", "main.php" + queryString, true);
ajaxRequest.send(null);
}
//-->
</script>
Currently, using those two pieces of code, I can successfully delete only the first product. The delccode variables do not seem to change when the products are looped (although when I echo the variables during the loop, it is definitely changing to the appropriate value...it's just not passing it correctly back to AJAX.)
I tried taking the AJAX code, putting it inside the main.php product loop, and change the function name during each loop (so ajaxDelCcode$news_gen_id() for example) and also to the button itself so that it is calling the AJAX specific to it. And it works if you are visiting main.php directly...but not from index.php after main.php has been called into the div.
I can't figure out how to pass the correct looped value from main.php within the div, back to the AJAX code on index.php
Can anyone help me with this?
Thanks,
Dustin

Answer 1

Instead of storing the id in the input, just pass it as an argument to the function:
function ajaxDelCcode(delccode) { ...
<input type='button' onclick='ajaxDelCcode(\"".$news_gen_id."\")' value='Delete' />
Also, I'd swap the quotes if I were you. Or better yet, instead of using echo, break the PHP code and just write HTML:
<? ... ?><input type="button" onclick="ajaxDelCcode('<?= $news_gen_id ?>')" value="Delete" /><? ... ?>

Answer 2

What does the code you use to delete look like? Is it in the same php file as the form you posted above? If so, is the form getting submitted to itself accidentally? Like perhaps when a user presses enter while on an input type=text control? I understand that you want to do this by ajax but I am suspecting that the form is your problem.
Seconding the jQuery comment.

Answer 3

Here try this
1) add jquery to your document.
<script type="text/javascript" src="//ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
2) give your inputs name attributes
<input type='hidden' name='delcode' id='delccode' value='".$news_gen_id."'>
<input type='hidden' name='deledit' id='deledit' value='".$edit."'>
3) Use a function something like this instead of all that code above
function ajaxDelCcode() {
$.ajax({
url: "main.php",
type: "GET",
dataType: "text",
data: $("#myDelForm").serialize(),
success: function(rText) {
$("#ajaxMain2").text(rText);
}
});
}