Can't get wordpress ajax form to submit - ajax

I am porting an application to WordPress. It uses a form to select what attributes the customer is looking for in an Adult Family Home via checkboxes and drop-downs. It re-searches the database on each onchange and keyup. Originally I had the application standalone in PHP, but when I migrated it to WordPress I started having issues.
Currently in WP I have the code conditionalized ($DavesWay == 1) to do ajax the normal no-WordPress-way and ($DavesWay == 0) to do it the WordPress-way.
In the non-WordPress-way, the ajax works fine EXCEPT that I get a WP header and menu between the search form and the results-div that Ajax puts the data in. I get no errors from WP or in the JS console. In the WP-way The search form displayed, but nothing happens when I check any of the checkboxes. The JS console displays
POST http://localhost/demo4/wp-admin/admin-ajax.php 400 (Bad Request)
But I don't see any way to tell exactly what it is complaining about. How should I troubleshoot this?
Troubleshooting = Examine the HTML output, lots of echos and exits in PHP code, look at JS console.
function submitPg1(theForm) {
// Used with onChange from "most" form elements, but not on those that change the page
// rather than the select criteria. Such as rowsPerPage, pageNumber etc.
setById("pageNo", "1"); // set inital page
mySubmit();
}
function mySubmit(theForm) { // The actual ajax submit
// DO NOT set page number
jQuery.ajax({ // create an AJAX call...
data: jQuery("#asi_search_form").serialize(), // get the form data
type: jQuery("#asi_search_form").attr("method"), // GET or POST
url: jQuery("#asi_search_form").attr("action"), // the file to call
success: function (response) { // on success..
jQuery("#result").html(response); // update the DIV
}
})
}
function setById(id, value) { // Used to set vales by Id
x = document.getElementById(id).value;
x.value = value;
}
// 1st submit with blank selection
jQuery(document).ready(function () { submitPg1(this.form) });
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
Code fragments: (from the displayed page source)
<div id="asi_container" class="asi_container" >
<noscript><h2>This site requires Javascript and cookies to function. See the Help page for how to enable them.</h2></noscript>
<div id="searchForm">
<form id="asi_search_form" name="asi_search_form" method="post" action="http://localhost/demo4/wp-admin/admin-ajax.php">
<input type="hidden" name="action" value="asi_LTCfetchAll_ajax" style="display: none; visibility: hidden; opacity: 0;">
<table id="greenTable" class="asi_table" title="The Green areas are for site administration, not typical users">
<tbody>
PHP code:
$DavesWay = 0;
if ($DavesWay == 1){ //echo "Daves Way Setup"; // Dave's way, which works but prints the menu twice
if( $operation == "submit"){
require("asi_LTCfetchAll.php"); // for each onchange or onkeyup
}else{
add_filter( 'the_content', 'asi_tc_admin', '12' ); // Initial page refresh # must be >12
}
}else{
// The WordPress way that I could't get to work -- asi_LTCfetch never gets called
function asi_LTCfetchAll_ajax(){
//echo "<br /> Goto to Submit function"; // DEBUG
require($asi_plugin_dir . "/includes" . '/asi_LTCfetchAll.php');
}
add_action( "wp_ajax_asi_LTCfetchAll_ajax", "asi_LTCfetchAll_ajax" ); // admin users
add_action( "wp_ajax_nopriv_asi_LTCfetchAll_ajax", "asi_LTCfetchAll_ajax" ); // non-logged in users
add_filter( "the_content", "asi_tc_admin", "12" ); // Initial page refresh # must be >12
}

Try changing the JavaScript to the way WordPress recommends it in their documentation:
var data = {
'action': 'my_action',
'whatever': 1234
};
jQuery.post(ajaxurl, data, function(response) {
alert('Got this from the server: ' + response);
});

I suggest trying following URL: https://codex.wordpress.org/AJAX_in_Plugins
Also you can use the plugin: https://wordpress.org/plugins/ajax-search-lite/

Related

Javascript file not working after ajax call

I am using a pagination script. I got it from a template. It has search option plus show items like 5,10,15,20 and and and prev button. Script is working nicely but when i use ajax and refresh that table part using
$(#tablerefresh).html(data)
then just a table is show with no search options, no next previous options nothing just all rows show.
<script type='text/javascript' src='../../js/plugins/Table/Table.js'></script>
thats the script file. I placed this inside the calling php page but nothings work. I will post the code if you want to see the script code.any suggestions?
In sucess function else part runs when updating occurs:
else
{
// Dropdown start option.
$('select').val(0);
// Clear fields data. (text).
$('form :input[type=text]').attr('value','');
// Password error hide.
$('#userpassword').css("border-color", "#918C8C");
$('#userconfirm').css("border-color", "#918C8C");
$('#usershowdiv').hide();
// Username - Space error show.
$('#userspace').css("border-color", "#918C8C");
$('#usershowdiv3').hide();
// Username - User already exists error show.
$('#userexists').css("border-color", "#918C8C");
$('#usershowdiv4').hide();
// Show ok image.
$('#okicon2').show();
// Hide ok image.
$('#okicon2').delay(8000).fadeOut();
// Show success message.
$('#usersuccess').show();
// Show success message hide after some time.
$('#usersuccess').delay(8000).fadeOut();
// Hide x image.
$('#crossicon2').hide();
// Again Display Table after refresh.
$('#refreshuserlist').html(data);
}
js:
<script type="text/javascript">
$(document).ready(function()
{
// dataTable
if($(".fTable").length > 0)
$(".fTable").dataTable({bSort: true,
"iDisplayLength": 5, "aLengthMenu": [5,10,25,50,100], // can be removed for basic 10 items per page
"aoColumnDefs": [{"bSortable": false,
"aTargets": [ -1 , 0]}]});
// eif dataTable
});
</script>
how i use that:
<table class="table fTable lcnp" cellpadding="0" cellspacing="0" width="100%">
</table>
If your pager and search are dynamically added to page, then in ajax success re-call these functions to apply to new elements, that was replaced in your page:
function createSearchField(){
$('body').append('<div class="search"></div>');
}
In ajax:
$.ajax({
url: 'example.com',
success: function(){ createSearchField(); //Call once more. }
})

Ajax send parameters through url

I'm new with ajax and thought i'd be a fun experiment to put into my project. I've created my own lightbox type feature to send a message on a website I'm creating. When the user clicks "Send Message", that's when the lightbox appears, and at the top I'm trying to get it to say "Send message to User", where User is the name of the user they're sending a message too. My lightbox html elements are actually on a seperate webpage, which is why I'm using ajax. this is what I have so far, and can't seem to figure out what the problem is:
user.php page
<div id = "pageMiddle"> // This div is where all the main content is.
<button onclick = "showMessageBox(UsersName)">Send Message</button>
</div>
Note: The username passes correctly into the javascript function, I have checked that much.
main.js page
function showMessageBox(user){
alert(user); // where i checked if username passes correctly
var ajaxObject = null;
if (window.XMLHttpRequest){
ajaxObject = new XMLHttpRequest();
}else if (window.ActiveXObject){
ajaxObject = new ActiveXObject("Microsoft.XMLHTTP");
}
if (ajaxObject != null){
ajaxObject.open("GET", "message_form.php", true);
ajaxObject.send("u="+user);
}else{
alert("You do not have a compatible browser");
}
ajaxObject.onreadystatechange = function(){
if (ajaxObject.readyState == 4 && ajaxObject.status == 200){
document.getElementById("ajaxResult").innerHTML = ajaxObject.responseText;
// use jquery to fade out the background and fade in the message box
$("#pageMiddle").fadeTo("slow", 0.2);
$("#messageFormFG").fadeIn("slow");
}
};
}
message_form.php page
<div id = "messageFormFG">
<div class = "messageFormTitle">Sending message to <?php echo $_GET['u']; ?></div>
</div>
Note: When accessing this page directly through the URL, giving it a parameter of u and a value, it displays correctly
Use jQuery.ajax();
http://api.jquery.com/jQuery.ajax/
$.ajax({
type: "GET",
url: "message_form.php",
data: { name: "John", location: "Boston" }
}).done(function( msg ) {
alert( "Data Saved: " + msg );
});
freakish way to do it (old school) :)
anyway i think the problem may be that you are loading an entire html page to a div! meaning tags and stuff, a good way to understand what's wrong would be to use a debugger and see what comes in ajaxObject.responseText.
Hope this helps.
Btw convert to jQuery ajax!! saves you loads of time =)
I believe that you need to add a request header prior to sending your data. So you'd have this:
ajaxObject.open("GET", "message_form.php", true);
ajaxObject.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
ajaxObject.send("u="+encodeURIComponent(user));
Instead of what you have.
However, it may be a good idea to allow a library to do this for you. It looks like you already have jQuery loaded, so why not let it handle your AJAX requests instead?
I figured it out after watching some ajax tutorials from bucky :) aka thenewboston. If I'm using the GET method, i just had to add the parameter to the end of the url in the .open function, instead of passing it through the send function (like you would a post method).
if you want to send number of field values using ajax.you can use serilalize function.
Example:
jQuery.ajax({
url: 'filenamehere.php',
type: 'post',
data: $("#formidhere").serialize(),
success: function(data){
..//
}
});

How can I return an id value from a div already populated through ajax

I am having some difficulty passing a correct id function back to AJAX.
I'm creating a product bulletin generator that lets items to be added by their SKU code (which works fine). My problem is that when a bulletin is clicked on, a preview of that bulletin is loaded into a div and shows all products associated with that bulletin.
From inside those results, I am trying to add the ability to delete a product from the bulletin. The problem is that the value being passed back to AJAX belongs to the first product only. It won't send the value belonging to the particular item if it is any other item than the first one.
This is the code (belonging to main.php) that gets loaded via AJAX into a div and is looped with each product associated with a selected bulletin
echo "<form name='myDelForm'>
$news_gen_id<br>
<input type='hidden' id='delccode' value='".$news_gen_id."'>
<input type='hidden' id='deledit' value='".$edit."'>
<input type='button' onclick='ajaxDelCcode()' value='Delete' /><br></form>
</td>";
The AJAX code (on index.php, where the div that calls in main.php is also located) is this
function ajaxDelCcode(){
var ajaxRequest; // The variable that makes Ajax possible!
try{
// Opera 8.0+, Firefox, Safari
ajaxRequest = new XMLHttpRequest();
} catch (e){
// Internet Explorer Browsers
try{
ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
try{
ajaxRequest = new
ActiveXObject("Microsoft.XMLHTTP");
} catch (e){
// Something went wrong
alert("Your browser broke!");
return false;
}
}
}
// Create a function that will receive data sent from the server
ajaxRequest.onreadystatechange = function(){
if(ajaxRequest.readyState == 4){
var ajaxDisplay = document.getElementById("ajaxMain2");
ajaxDisplay.innerHTML = ajaxRequest.responseText;
}
}
var deledit = document.getElementById("deledit").value;
var delccode = document.getElementById("delccode").value;
var queryString = "?delccode=" + delccode + "&deledit=" + deledit;
ajaxRequest.open("GET", "main.php" + queryString, true);
ajaxRequest.send(null);
}
//-->
</script>
Currently, using those two pieces of code, I can successfully delete only the first product. The delccode variables do not seem to change when the products are looped (although when I echo the variables during the loop, it is definitely changing to the appropriate value...it's just not passing it correctly back to AJAX.)
I tried taking the AJAX code, putting it inside the main.php product loop, and change the function name during each loop (so ajaxDelCcode$news_gen_id() for example) and also to the button itself so that it is calling the AJAX specific to it. And it works if you are visiting main.php directly...but not from index.php after main.php has been called into the div.
I can't figure out how to pass the correct looped value from main.php within the div, back to the AJAX code on index.php
Can anyone help me with this?
Thanks,
Dustin
Instead of storing the id in the input, just pass it as an argument to the function:
function ajaxDelCcode(delccode) { ...
<input type='button' onclick='ajaxDelCcode(\"".$news_gen_id."\")' value='Delete' />
Also, I'd swap the quotes if I were you. Or better yet, instead of using echo, break the PHP code and just write HTML:
<? ... ?><input type="button" onclick="ajaxDelCcode('<?= $news_gen_id ?>')" value="Delete" /><? ... ?>
What does the code you use to delete look like? Is it in the same php file as the form you posted above? If so, is the form getting submitted to itself accidentally? Like perhaps when a user presses enter while on an input type=text control? I understand that you want to do this by ajax but I am suspecting that the form is your problem.
Seconding the jQuery comment.
Here try this
1) add jquery to your document.
<script type="text/javascript" src="//ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
2) give your inputs name attributes
<input type='hidden' name='delcode' id='delccode' value='".$news_gen_id."'>
<input type='hidden' name='deledit' id='deledit' value='".$edit."'>
3) Use a function something like this instead of all that code above
function ajaxDelCcode() {
$.ajax({
url: "main.php",
type: "GET",
dataType: "text",
data: $("#myDelForm").serialize(),
success: function(rText) {
$("#ajaxMain2").text(rText);
}
});
}

ajaxComplete/ajaxStop/ajaxSuccess not firing

I appreciate any and all help. I am a beginner with little jQuery/AJAX experience and I have been going crazy trying to figure out why I can't figure this out.
I'm writing a Facebook page application that has the user grant permissions and upload a video to the page. All of this works fine and dandy. This is not so much a Facebook API related issue as it is an ajax issue (at least I think).
Basically, I am trying to gain control of the page IN SOME WAY after the user uploads a video. I am using the [malsup jQuery Form Plugin][1] to have the resulting page (which is a page on Facebook displaying returned JSON values) load in a hidden iframe.
I am able to get ajaxStart to fire, and I've tested this by having it change the background color or print an alert message when I click "Upload". However, when the upload completes (and it does complete successfully), NOTHING ELSE HAPPENS. The returned JSON values load in the hidden iframe and the page sits there. I have tried getting ajaxComplete, ajaxStop and ajaxSuccess to fire, but none of them do for whatever reason.
So overall, here is what I am trying to accomplish:
- I want to redirect the user or make some hidden content appear after the file upload completes. I don't even care if there's errors. I just need SOMETHING to happen.
- I am using the jQuery Form Plugin because I am not unfortunately not advanced enough to figure out how to use that value and do something with it, but if anyone can steer me in the right direction, that would be appreciated.
And finally, here is my code:
<html>
<head>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.6/jquery.js"></script>
<script type="text/javascript" src="http://malsup.github.com/jquery.form.js"></script>
<script type="text/javascript">
// prepare the form when the DOM is ready
$(document).ready(function() {
var options = {
target: '#output2', // target element(s) to be updated with server response
iframeTarget: '#output2',
beforeSubmit: showRequest, // pre-submit callback
success: showResponse // post-submit callback
};
// bind form using 'ajaxForm'
$('#theform').ajaxForm(options);
});
// pre-submit callback
function showRequest(formData, jqForm, options) {
return true;
}
// post-submit callback
function showResponse(responseText, statusText, xhr, $form) {
alert(responseText);
}
</script>
<script type="text/javascript">
jQuery().ready(function(){
$('body').ajaxStart(function() {
$(this).css("background-color","red");
});
$('body').ajaxSend(function() {
$(this).css("background-color","blue");
});
$('body').ajaxComplete(function() {
$(this).css("background-color","green");
});
$('body').ajaxStop(function() {
$(this).css("background-color","purple");
});
});
</script>
</head>
<body>
<?php
$app_id = "xxxxxxx";
$app_secret = "xxxxx";
$my_url = "xxxxxx";
$video_title = "xxxxxxxxx";
$video_desc = "xxxxxxxxx";
$page_id = "xxxxxxxx";
$code = $_REQUEST["code"];
if(empty($code)) {
// Get permission from the user to publish to their page.
$dialog_url = "http://www.facebook.com/dialog/oauth?client_id="
. $app_id . "&redirect_uri=" . urlencode($my_url)
. "&display=popup&scope=email,publish_stream,manage_pages";
$current_url = (!empty($_SERVER['HTTPS'])) ? "https://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI'] : "http://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI'];
if ($current_url != $dialog_url)
{
echo('<script>window.location ="' . $dialog_url . '";</script>');
}
} else {
// Get access token for the user, so we can GET /me/accounts
$token_url = "https://graph.facebook.com/oauth/access_token?client_id="
. $app_id . "&redirect_uri=" . urlencode($my_url)
. "&client_secret=" . $app_secret
. "&code=" . $code;
$access_token = file_get_contents($token_url);
$accounts_url = "https://graph.facebook.com/me/accounts?" . $access_token;
$response = file_get_contents($accounts_url);
// Parse the return value and get the array of accounts we have
// access to. This is returned in the data[] array.
$resp_obj = json_decode($response,true);
$accounts = $resp_obj['data'];
// Find the access token for the page to which we want to post the video.
foreach($accounts as $account) {
if($account['id'] == $page_id) {
$access_token = $account['access_token'];
break;
}
}
// Using the page access token from above, create the POST action
// that our form will use to upload the video.
$post_url = "https://graph-video.facebook.com/" . $page_id . "/videos?"
. "title=" . $video_title. "&description=" . $video_desc
. "&access_token=". $access_token;
// Create a simple form
echo '<form action=" '.$post_url.' " method="POST" enctype="multipart/form-data" id="theform">';
echo 'Please choose a file:';
echo '<input name="file" type="file">';
echo '<input type="submit" value="Upload" id="button-upload" />';
echo '</form>';
}
?>
<iframe id="output2" name="output2"></iframe>
</body></html>
Thank you for your help!!
It seams you are getting an Ajax Error. I don't see any error handler in your code. Could you try to add an error handler as follows
<script>
$(document).ready(function(){
$(document).ajaxError(function(e, jqxhr, settings, exception) {
alert(exception);
})
})
</script>
I have played around with file uploads, and there are a complicated beast because of all the security that browsers have for protecting users file systems and whatnot.
On to your problem, I think that there is a good chance that your AjaxForm jQuery plugin doesn't connect properly to the global Ajax state for Jquery. Even if it did, I would say that tapping into the global Ajax state is a bad design. If you add any other ajax requests to this page, then your ajaxComplete, ajaxStop, etc. functions are going to start getting called.
Your better approach is to use the callbacks provided by the AjaxForm plugin. Lets focus on this first part of your code.
Does this work?
success: showResponse // post-submit callback
...
// post-submit callback
function showResponse(responseText, statusText, xhr, $form) {
alert(responseText);
}
If so, could you replace this:
$('body').ajaxComplete(function() {
$(this).css("background-color","green");
});
With this:
function showResponse(responseText, statusText, xhr, $form) {
$(this).css("background-color","green");
}
I believe that using the success: callback is the intended use of the AjaxForm plugin.
The jquery ajaxSend or ajaxStart throws some kind of an error and the document does not execute ajaxComplete. I tried to fix the bug for quite a while and was only able to find a workaround:
function hideAjaxIndicator() {
$('#ajax-indicator').hide();
}
$(document).ready(function () {
setTimeout(hideAjaxIndicator, 1000);
});
You can add this to .js file.

I cant update the progressbar via $.ajax on form submit

After the form submits, the progressbar appears, and the getProgress function is called. getProgress check a php file (which uses the uploadprogress apache mod to get the current upload progress) and returns a number from 0 to 100 (which means complete).
OK, The idea is that getProgress is self-executed if the number returned is not 100. Otherwise, the form continues to upload.php where the file is manipulated.
THIS IS WHAT IM LOOKING FOR: http://screenr.com/ByG <- video.
Here is the HTML part.
<form method="post" action="upload.php" enctype="multipart/form-data" id="UploadForm">
<input type="hidden" id="uid" name="UPLOAD_IDENTIFIER" value="<?php echo $uid; ?>">
<input type="file" name="file">
<input type="submit" name="submit" value="Upload!">
</form>
<div id="UploadBarContainer">
<div id="LoadBar"></div>
<div id="ProgressBar"></div>
</div>
Here is the jQuery part. Which seems to be broken
$(function(){
// This flag determines if the upload has started
var started = false;
// Start progress tracking when the form is submitted
$('#UploadForm').submit(function() {
//Update the flag to true.
started = true;
//Hide the form.
$('#UploadForm').hide();
//Show the progress bar.
$('#UploadBarContainer, #LoadBar, #ProgressBar').show();
//Start updating progress after a 2 second delay.
//This is to prevent the getprogress.php assume that upload is complete.
setTimeout(function () {
// We pass the upload identifier to our function
getProgress($('#uid').val());
}, 2000);
});
//Function used to get the current upload progress.
//It should be executed over and over again untill the result is 100.
function getProgress(id) {
//Get the current time.
var time = new Date().getTime();
//Make an ajax request to the server.
$.ajax({
//Pass the data trought GET method.
type: 'GET',
//Get the progress from this php file.
url: 'getprogress.php',
//Pass our upload identifier as a parameter and current time to prevent caching.
data: { uid: id, t: time },
//Get the results.
success: function (data) {
//Get the output as an integer.
var progress = parseInt(data, 10);
//If upload progress is not 100, change bar percentage and update again.
if (progress < 100) {
//Update the progress bar percentage.
//But only if we have started.
$('#ProgressBar').css('width', progress + '%');
//If we aren't done, update again.
getProgress(id);
}
}
});
}
});
Just i case this helps, here is the getprogress.php file called on the $.ajax request.
if (isset($_GET['uid'])) {
// Fetch the upload progress data
$status = uploadprogress_get_info($_GET['uid']);
if ($status) {
// Calculate the current percentage
echo round($status['bytes_uploaded']/$status['bytes_total']*100);
}
else {
// If there is no data, assume it's done
echo 100;
}
}
Any help is appreciated, i have a live demo but i scared about what you could upload.
only new versions of some browsers support file upload progress. You should check your net with firebug if getprogress.php send numbers or just errors.
You may look these:
http:
Server-side, get progress on sending file
may use swf swfupload
another jquery plugin: uploadify
Well finally i came to the conclusion it is not possible to get this working on webkit browsers such as opera, chrome and safari, not so on firefox and internet explorer.
Webkit browsers tend to block any ajax while a file is being uploaded.
You may want to check this out: https://bugs.webkit.org/show_bug.cgi?id=23933

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