I have a persistence layer (JPA entity objects) created and managed by Roo. It is in its own project, builds to a jar, and I have used it with a separate Spring MVC 3 web application.
I'd like to use this same Roo persistence project in another web application powered by Apache Wicket. I have seen a couple of the Roo add-ons made for Wicket, but none of them even compile (I'm not the only one to have the issue).
The problem I am encountering is that whenever I try to call one of my Roo entities from within a Wicket Page or component, I get the following exception:
Caused by: java.lang.IllegalStateException: Entity manager has not been injected (is the Spring Aspects JAR configured as an AJC/AJDT aspects library?)
at com.x.domain.UserAccount_Roo_Entity.ajc$interMethod$com_x_domain_UserAccount_Roo_Entity$com_x_domain_UserAccount$entityManager(UserAccount_Roo_Entity.aj:91)
at com.x.domain.UserAccount.entityManager(UserAccount.java:1)
I have configured my application following the Spring+Wicket wiki here: https://cwiki.apache.org/WICKET/spring.html
Does anyone know the 1,2,3 steps to set up a Wicket application to utilize Spring Roo entities? Any help is appreciated. Thanks!
I found this in google code, sounds like its doing exactly what you want http://code.google.com/p/spring-roo-wicket-addon/
I found the solution to my problem. When I ran my wicket webapp using the Maven jetty:run goal, it worked. However, I was trying to start Jetty via Java code:
public class Start {
public static void main(String[] args) throws Exception {
Server server = new Server();
SocketConnector connector = new SocketConnector();
server.start();
}
}
I was not loading the Spring ApplicationContext in this "Start" class. Once I modified this class to load the Spring application context, it worked
Related
I am new with Spring Boot Development and currently can't move-on on the issue of how to load my spring application configuration outside the jar file.
My existing code looks like this
private ApplicationContext context;
public static void main(String[] args){
SpringApplication.run(SMPPEngine.c1ass);
new SMPPEngine();
}
public SMPPEngine(){
loadConfiguration();
process();
}
private void loadConfiguration(){
context = new ClassPatthlApplicationContext(”application-context.xm1”);
}
What I want to achieve is to have the jar file next to application-context.xml in one directory so that when there are configuration changes,I don't need to recompile my code just to reflect the changes on application-context.xml.
Based on what I've read on the internet, this is possible by using 'file://directory/application.xml' instead of classpath. But my problem on using the later is that when you place your jar and file to other location, I am required to do code change to reflect the new directory which does not solve the problem of getting away from code recompilation.
I hope I made my issue clear, and get an immediately response with you guys :)
Thanks in advance :)
There are many approaches to do this, standard, you can use spring file: prefix for accessing filesystem paths.
but with spring boot, you can specifiy it in application.properties with
spring.config.location propertiy, or you can add it in command line when run the spring boot jar file like
java -jar myproject.jar --spring.config.location=classpath:/default.properties,classpath:/override.properties
But for your codes, actually you do not need to re-create the spring context from the configuration files, but you want get the context instance, you just need to inject it
#Autowired
private ApplicationContext context;
Another approach, if you have the infrastructure. Would be to use Spring Cloud Config. After your Boot application is configured to read from it, they can be modified at anytime without recompilation or restarting.
I am trying to use Spring MVC 4's Rest templates to support google protocol buffers as message format. I have am following this post on Spring framework blog
spring-mvc-google-protocol-buffers
I checked out the sourceCode trying to implement it in my environment.
I have two issues- I cannot get it to compile when I turn Java.version to 1.6 and i cannot get it to work as a webapp (don't know what
will be the context-root of the converted war file)
-Details-
I have a requirement to make this code work as a web-app and deploy on java6 container (weblogic 10.3.6 -servlet 2.5 compliant)
So i changed the java 8 features from the codebase to make it Java 6 compatible.
The only problem is when I change the pom.xml's following section
<properties>
<project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
<start-class>demo.DemoApplication</start-class>
<java.version>1.8</java.version>
</properties>
to change the java.version to 1.6 value, then try to do mvn clean install , the DemoApplicationTests class fails to compile with this error.
-google-protocol-buffers-master\src\test\java\demo\DemoApplicationTests.java:28: cannot find symbol
[ERROR] symbol : constructor RestTemplate(java.util.List<org.springframework.http.converter.protobuf.ProtobufHttpMessageConverter>) is not defined
[ERROR] location: class org.springframework.web.client.RestTemplate
The following link shows that Spring codebase normally doesn't have any Java 8 specific source code so not sure why this code only compiles in Java 8
https://spring.io/blog/2015/04/03/how-spring-achieves-compatibility-with-java-6-7-and-8
--------------------------------------------------------------------------------
The following link shows how to convert a spring boot application to a WAR app.
I did change the pom.xml packaging option to war.
The code gets build by mvn clean install without issues and the .war file gets generated.
But there's no web.xml - so i cannot tell what will be the context-root of the deployed web app.
I either way deployed the webapp on weblogic 10.3.6 ( which is java 6 compatible)
and it deployed fine.
But when I run the DemoApplicationTests (that I have changed to point straight to the URL
using this call (got the context-root from the weblogic console by clicking on the deployed web app)
ResponseEntity<CustomerProtos.Customer> customer = restTemplate.getForEntity(
"http://127.0.0.1:7001/demo-0.0.1-SNAPSHOT/customers/2", CustomerProtos.Customer.class);
I keep getting 404 not found error.
I have put up my changed code here.
https://github.com/robinbajaj123/spring-and-google-protocol-buffers
Your feedback will be appreciated.
You'd need to convert the Spring Boot app to also be a valid Servlet application. If you were using Servlet 3 or later and chose a .war-based deployment from start.spring.io you'd get a ServletIntializer which is a Java class that is the programmatic equivalent of web.xml. Since you're using 2.5, not 3.0, you need an explicit web.xml. You might check out this sample on how to get a Boot app hoisted up in a Servlet 2.5 environment, though using Servlet 2.5 is not recommended!. It's worth mentioning that Servlet 3.0 support was introduced in 2009..
Finally, this code uses Java 8 lambdas. You'll need to replace the lambdas with Java 6-equivalent code. One example I see is:
#Bean
CustomerRepository customerRepository() {
...
The last line in the #Bean definition returns a lambda: customers::get. Replace it with:
final Map<Integer, CustomerProtos.Customer> customers =
new ConcurrentHashMap<Integer, CustomerProtos.Customer>();
return new CustomerRepository() {
public CustomerProtos.Customer findById(int id) {
return customers.get( id) ;
}
};
Similarly, replace the forEach method in the List w/ an old-school for-in loop:
for (CustomerProtos.Customer c : Arrays.asList( ... )) {
customers.put(c.getId(), c);
}
I'm facing a JAXBException " is not known to this context" when calling a web service from within a job controlled by Quartz on Spring:
javax.xml.ws.WebServiceException: javax.xml.bind.JAXBException: com.xxxx.yyyy.zzzz.ImageMetaData is not known to this context
at org.apache.axis2.jaxws.ExceptionFactory.createWebServiceException(ExceptionFactory.java:175)
at org.apache.axis2.jaxws.ExceptionFactory.makeWebServiceException(ExceptionFactory.java:70)
at org.apache.axis2.jaxws.ExceptionFactory.makeWebServiceException(ExceptionFactory.java:128)
at org.apache.axis2.jaxws.marshaller.impl.alt.DocLitWrappedMinimalMethodMarshaller.demarshalResponse(DocLitWrappedMinimalMethodMarshaller.java:624)
at org.apache.axis2.jaxws.client.proxy.JAXWSProxyHandler.createResponse(JAXWSProxyHandler.java:593)
at org.apache.axis2.jaxws.client.proxy.JAXWSProxyHandler.invokeSEIMethod(JAXWSProxyHandler.java:432)
at org.apache.axis2.jaxws.client.proxy.JAXWSProxyHandler.invoke(JAXWSProxyHandler.java:213)
at com.sun.proxy.$Proxy299.findAllImageMetaData(Unknown Source)
I'm having a Spring 3.2.4 Java EE application with JSF running on IBM WebSphere v8.
When calling a specific web service from the JSF part of the application (i.e. from an action or a service), everything's ok.
The exception occurs only when the call is done from within a Quartz/Spring triggered job.
Executing exacty the same job code from the action does not result in an exception.
I tried a lot of different things like using a corresponding #XmlSeeAlso annotation in the JAXB generated classes but even using the annotation in the webservice interface itself does not solve the issue.
I also updated the Spring and Quartz libraries to more recent versions but this didn't help.
Anyone any idea?
I've finally solved the issue.
After much analysis I encountered the following issue in the Spring framework:
https://jira.spring.io/i#browse/SPR-11125
When a job is triggered via Spring/Quartz on WebSphere, the wrong ContextClassLoader is set.
This may cause many different problems - among them is the JAXBException as described.
The Spring bug is still open - so as a workaround I had to overwrite the context class loader of the current thread by the correct one:
ClassLoader cl = invoiceService.getClass().getClassLoader();
Thread.currentThread().setContextClassLoader(cl);
The correct class loader can be simply retrieved by a class that has been loaded by the container. Using this class loader as the context class loader for the current thread solved my issue.
I have a WAR application as follows:
JPA/Hibernate 4.1.9.Final
Hibernate Envers 4.1.9.Final
Spring 3.1.3.RELEASE
Spring MVC with JSON/REST
My frontend (web page) makes a request, this leads to a new entity to be saved (this seems to succeed in any case) and then Envers will save corresponding revision info.
Typical deployment is in Tomcat 7, where this works just fine.
For unit testing I spin up a Jetty (8.1.9.v20130131) programmatically, which fails. It baffles me why this behavior is different. I can only imagine that Jetty has a different (lesser standard, perhaps) transaction management on board than Tomcat, but I've failed to pin it down or otherwise work around this.
Below is how I create the web application programmatically:
#RunWith(SpringJUnit4ClassRunner.class)
#ContextConfiguration({"classpath:applicationContext.xml" })
public class AddCustomerTest {
And:
server = new Server(serverPort);
WebAppContext webAppContext = new WebAppContext();
webAppContext.setContextPath("/webapp");
webAppContext.setWar("src/main/webapp");
webAppContext.setServer(server);
server.setHandler(webAppContext);
Below is the essential exception that I'm getting:
Caused by: org.springframework.transaction.IllegalTransactionStateException: No existing transaction found for transaction marked with propagation 'mandatory'
at org.springframework.transaction.support.AbstractPlatformTransactionManager.getTransaction(AbstractPlatformTransactionManager.java:357)
at org.springframework.transaction.interceptor.TransactionAspectSupport.createTransactionIfNecessary(TransactionAspectSupport.java:334)
at org.springframework.transaction.interceptor.TransactionInterceptor.invoke(TransactionInterceptor.java:105)
at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:172)
at org.springframework.aop.framework.JdkDynamicAopProxy.invoke(JdkDynamicAopProxy.java:202)
at com.sun.proxy.$Proxy115.getByUuid(Unknown Source)
at com.totaalsoftware.incidentmanager.entity.audit.RevisionEntityListener.setUser(RevisionEntityListener.java:53)
at com.totaalsoftware.incidentmanager.entity.audit.RevisionEntityListener.instanceNewRevision(RevisionEntityListener.java:40)
at com.totaalsoftware.incidentmanager.entity.audit.RevisionEntityListener.newRevision(RevisionEntityListener.java:34)
at org.hibernate.envers.revisioninfo.DefaultRevisionInfoGenerator.generate(DefaultRevisionInfoGenerator.java:95)
at org.hibernate.envers.synchronization.AuditProcess.getCurrentRevisionData(AuditProcess.java:124)
at org.hibernate.envers.synchronization.AuditProcess.executeInSession(AuditProcess.java:106)
at org.hibernate.envers.synchronization.AuditProcess.doBeforeTransactionCompletion(AuditProcess.java:155)
at org.hibernate.engine.spi.ActionQueue$BeforeTransactionCompletionProcessQueue.beforeTransactionCompletion(ActionQueue.java:662)
... 80 more
My RevisionEntityListener looks up some user data (from the database, using Hibernate of course). Clearly there's no transaction available, but only when running in Jetty. I've tried marking the RevisionEntityListener transactional in various ways, to no avail.
Let me know if you need any other info. Your help much appreciated!
Stupid me...
The following two lines were copied over from some other test class:
#RunWith(SpringJUnit4ClassRunner.class)
#ContextConfiguration({"classpath:applicationContext.xml" })
These two lines served no purpose since the entire application was loaded through the instantiation and configuration of Jetty. But somehow the above clashed with the application in the Jetty server, probably due to being in the same JVM. Removing the above two lines from the test class fixed it!
I'm writing some JUnit-based integration tests for a RESTful web service using JerseyTest. The JAX-RS resource classes use Spring and I'm currently wiring everything together with a test case like the following code example:
public class HelloResourceTest extends JerseyTest
{
#Override
protected AppDescriptor configure()
{
return new WebAppDescriptor.Builder("com.helloworld")
.contextParam( "contextConfigLocation", "classpath:helloContext.xml")
.servletClass(SpringServlet.class)
.contextListenerClass(ContextLoaderListener.class)
.requestListenerClass(RequestContextListener.class)
.build();
}
#Test
public void test()
{
// test goes here
}
}
This works for wiring the servlet, however, I'd like to be able to share the same context in my test case so that my tests can have access to mock objects, DAOs, etc., which seems to call for SpringJUnit4ClassRunner. Unfortunately, SpringJUnit4ClassRunner creates a separate, parallel application context.
So, anyone know how can I create an application context that is shared between the SpringServlet and my test case?
Thanks!
Override JerseyTest.configure like so:
#Override
protected Application configure() {
ResourceConfig rc = new JerseyConfig();
rc.register(SpringLifecycleListener.class);
rc.register(RequestContextFilter.class);
rc.property("contextConfigLocation", "classpath:helloContext.xml");
return rc;
}
For me the SpringServlet was not required, but if you need that you may be able to call rc.register for that too.
I found a couple of ways to resolve this problem.
First up, over at the geek#riffpie blog there is an excellent description of this problem along with an elegant extension of JerseyTest to solve it:
Unit-testing RESTful Jersey services glued together with Spring
Unfortunately, I'm using a newer version of Spring and/or Jersey (forget which) and couldn't quite get it to work.
In my case, I ended up avoiding the problem by dropping the Jersey Test Framework and using embedded Jetty along with the Jersey Client. This actually made better sense in my situation anyway since I was already using embedded Jetty in my application. yves amsellem has a nice example of unit testing with the Jersey Client and embedded Jetty. For Spring integration, I used a variation of Trimbo's Jersey Tests with Embedded Jetty and Spring