How do I go about echoing only the filename of a file if I iterate a directory with a for loop?
for filename in /home/user/*
do
echo $filename
done;
will pull the full path with the file name. I just want the file name.
If you want a native bash solution
for file in /home/user/*; do
echo "${file##*/}"
done
The above uses Parameter Expansion which is native to the shell and does not require a call to an external binary such as basename
However, might I suggest just using find
find /home/user -type f -printf "%f\n"
Just use basename:
echo `basename "$filename"`
The quotes are needed in case $filename contains e.g. spaces.
Use basename:
echo $(basename /foo/bar/stuff)
Another approach is to use ls when reading the file list within a directory so as to give you what you want, i.e. "just the file name/s". As opposed to reading the full file path and then extracting the "file name" component in the body of the for loop.
Example below that follows your original:
for filename in $(ls /home/user/)
do
echo $filename
done;
If you are running the script in the same directory as the files, then it simply becomes:
for filename in $(ls)
do
echo $filename
done;
You can either use what SiegeX said above or if you aren't interested in learning/using parameter expansion, you can use:
for filename in $(ls /home/user/);
do
echo $filename
done;
if you want filename only :
for file in /home/user/*; do
f=$(echo "${file##*/}");
filename=$(echo $f| cut -d'.' -f 1); #file has extension, it return only filename
echo $filename
done
for more information about cut command see here.
Related
I would want to iterate over contents of a directory and list only ordinary files.
The path of the directory is given as an user input. The script works if the input is current directory but not with others.
I am aware that this can be done using ls.. but i need to use a for .. in control structure.
#!/bin/bash
echo "Enter the path:"
read path
contents=$(ls $path)
for content in $contents
do
if [ -f $content ];
then
echo $content
fi
done
ls is only returning the file names, not including the path. You need to either:
Change your working directory to the path in question, or
Combine the path with the names for your -f test
Option #2 would just change:
if [ -f $content ];
to:
if [ -f "$path/$content" ];
Note that there are other issues here; ls may make changes to the output that break this, depending on wrapping. If you insist on using ls, you can at least make it (somewhat) safer with:
contents="$(command ls -1F "$path")"
You have two ways of doing this properly:
Either loop through the * pattern and test file type:
#!/usr/bin/env bash
echo "Enter the path:"
read -r path
for file in "$path/"*; do
if [ -f "$file" ]; then
echo "$file"
fi
done
Or using find to iterate a null delimited list of file-names:
#!/usr/bin/env bash
echo "Enter the path:"
read -r path
while IFS= read -r -d '' file; do
echo "$file"
done < <(
find "$path" -maxdepth 1 -type f -print0
)
The second way is preferred since it will properly handle files with special characters and offload the file-type check to the find command.
Use file, set to search for files (-type f) from $path directory:
find "$path" -type f
Here is what you could write:
#!/usr/bin/env bash
path=
while [[ ! $path ]]; do
read -p "Enter path: " path
done
for file in "$path"/*; do
[[ -f $file ]] && printf '%s\n' "$file"
done
If you want to traverse all the subdirectories recursively looking for files, you can use globstar:
shopt -s globstar
for file in "$path"/**; do
printf '%s\n' "$file"
done
In case you are looking for specific files based on one or more patterns or some other condition, you could use the find command to pick those files. See this post:
How to loop through file names returned by find?
Related
When to wrap quotes around a shell variable?
Why you shouldn't parse the output of ls
Is double square brackets [[ ]] preferable over single square brackets [ ] in Bash?
I have a folder with few images, all have the same name format:
some-random-name-min.jpg
another-random-name-min.jpg
and-another-random-name-min.jpg
I want to strip the last -min so following this answer
I tried this bash script:
#!/bin/bash
for filename in /home/al/domus-images/portfolio/white snow/*.jpg; do
mv $filname $(echo $filename | sed -e 's/....\.jpg$//');
done
but after running the script nothing happened..any idea what am I missing here?
Thanks
You can use find command to list the files and then to remove -min from file name follow below script.
for filename in `find "/home/al/domus-images/portfolio/white snow/" -name "*.jpg"`;
do
mv $filname $(echo $filename | sed 's/-min.jpg$/.jpg/');
done
This remove last "-min" from file name.
this could be an idea:
#!/bin/bash
for filename in *\-min.jpg
do
newFile=$(echo $filename |sed "s/\-min//g")
printf "before\t:filename[$filename]\tnewFile[$newFile]\n"
mv $filename $newFile
printf "after\t:filename[$filename]\tnewFile[$newFile]\n"
done
output
[shell] ➤ ./myMove
before :filename[and-another-random-name-min.jpg] newFile[and-another-random-name.jpg]
after :filename[and-another-random-name-min.jpg] newFile[and-another-random-name.jpg]
before :filename[another-random-name-min.jpg] newFile[another-random-name.jpg]
after :filename[another-random-name-min.jpg] newFile[another-random-name.jpg]
before :filename[some-random-name-min.jpg] newFile[some-random-name.jpg]
after :filename[some-random-name-min.jpg] newFile[some-random-name.jpg]
this *\-min.jpg is just to be sure to get only the file you need
This might be what you're looking for
#!/bin/bash
for filename in /home/al/domus-images/portfolio/white snow/*-min.jpg
do
mv ${filename} ${filename//-min.jpg/.jpg}
done
Can't get it simpler than this.
rename 's/\-min.jpg$/.jpg/' *-min.jpg
I have a directory with list of files abc_1.txt abc_2.txt.
I am have to parse the file name and do some processing over the file
#shellscript /tmp/log*
file_list=`ls $1`
for file_name in $file_list
do
# need to do some processing over the file name
echo $file_name
done
the script is not giving the proper output i.e script is not giving matching wildcard file name for the ls cmd.
the usage of the above script is shellscript /tmp/log*
Bash expands shellscript /tmp/log/abc* to a list of files names as input to your script. ls is not needed. Just iterate over the input. Try it like this
for f in $*
do
echo "Processing $f"
# do something on $f
done
http://www.cyberciti.biz/faq/bash-loop-over-file/ even gives you some more examples.
When you want filenames without the dir you can use
if [ ! -d "$*" ]; then
echo "Usage: $0 dirname"
exit 1
fi
cd "$*"
find . -type f | cut -c3- | while read file_name; do
echo "Found ${file_name}"
done
Just remove the wildcard character "*" since it matches all the files in the given path. Removing it will just pass the directory path and your script will print each file
I want to write a code is shell scripting which will rename all the files of extension .txt in a current directory to extension .c .Suppose my current directory contains some 100 .txt file. This number is not fixed.
for f in *.txt; do echo mv "$f" "${f%.txt}.c"; done
Remove "echo" when you're satisfied it's working. See the bash manual for the meaning of "%" here.
See man rename. You can rename multiple files providing regexp substitution.
rename 's/\.txt$/.c/' *.txt
If you don't have rename in you system, you can use find:
find . -name '*.txt' | while read FILE; do echo mv "$FILE" "$(echo "$FILE" | sed 's/\.txt$/.c/g')"; done
Remove echo when you verify it does what you want.
awk can do this trick too:
kent$ ls *.txt|awk '{o=$0;gsub(/txt$/,"c"); print "mv "o" "$0;}'|sh
I am trying to loop through all the files in a directory.
I want to do some stuff on each file (convert it to xml, not included in example), then write the file to a new directory structure.
for file in `find /home/devel/stuff/static/ -iname "*.pdf"`;
do
echo $file;
sed -e 's/static/changethis/' $file > newfile +".xml";
echo $newfile;
done
I want the results to be:
$file => /home/devel/stuff/static/2002/hello.txt
$newfile => /home/devel/stuff/changethis/2002/hello.txt.xml
How do I have to change my sed line?
If you need to rename multiple files, I would suggest to use rename command:
# remove "-n" after you verify it is what you need
rename -n 's/hello/hi/g' $(find /home/devel/stuff/static/ -type f)
or, if you don't have rename try this:
find /home/devel/stuff/static/ -type f | while read FILE
do
# modify line below to do what you need, then remove leading "echo"
echo mv $FILE $(echo $FILE | sed 's/hello/hi/g')
done
Are you trying to change the filename? Then
for file in /home/devel/stuff/static/*/*.txt
do
echo "Moving $file"
mv "$file" "${file/static/changethis}.xml"
done
Please make sure /home/devel/stuff/static/*/*.txt is what you want before using the script.
First, you have to create the name of the new file based on the name of the initial file. The obvious solution is:
newfile=${file/static/changethis}.xml
Second you have to make sure that the new directory exists or create it if not:
mkdir -p $(dirname $newfile)
Then you can do something with your file:
doSomething < $file > $newfile
I wouldn't do the for loop because of the possibility of overloading your command line. Command lines have a limited length, and if you overload it, it'll simply drop off the excess without giving you any warning. It might work if your find returns 100 file. It might work if it returns 1000 files, but it might fail if your find returns 1000 files and you'll never know.
The best way to handle this is to pipe the find into a while read statement as glenn jackman.
The sed command only works on STDIN and on files, but not on file names, so if you want to munge your file name, you'll have to do something like this:
$newname="$(echo $oldname | sed 's/old/new/')"
to get the new name of the file. The $() construct executes the command and puts the results of the command on STDOUT.
So, your script will look something like this:
find /home/devel/stuff/static/ -name "*.pdf" | while read $file
do
echo $file;
newfile="$(echo $file | sed -e 's/static/changethis/')"
newfile="$newfile.xml"
echo $newfile;
done
Now, since you're renaming the file directory, you'll have to make sure the directory exists before you do your move or copy:
find /home/devel/stuff/static/ -name "*.pdf" | while read $file
do
echo $file;
newfile="$(echo $file | sed -e 's/static/changethis/')"
newfile="$newfile.xml"
echo $newfile;
#Check for directory and create it if it doesn't exist
$dirname=$(dirname "$newfile")
if [ ! -d "$dirname" ]
then
mkdir -p "$dirname"
fi
#Directory now exists, so you can do the move
mv "$file" "$newfile"
done
Note the quotation marks to handle the case there's a space in the file name.
By the way, instead of doing this:
if [ ! -d "$dirname" ]
then
mkdir -p "$dirname"
fi
You can do this:
[ -d "$dirname"] || mkdir -p "$dirname"
The || means to execute the following command only if the test isn't true. Thus, if [ -d "$dirname" ] is a false statement (the directory doesn't exist), you run mkdir.
It's a fairly common shortcut when you see shell scripts.
find ... | while read file; do
newfile=$(basename "$file").xml;
do something to "$file" > "$somedir/$newfile"
done
OUTPUT="$(pwd)";
for file in `find . -iname "*.pdf"`;
do
echo $file;
cp $file $file.xml
echo "file created in directory = {$OUTPUT}"
done
This will create a new file with name whatyourfilename.xml, for hello.pdf the new file created would be hello.pdf.xml, basically it creates a new file with .xml appended at the end.
Remember the above script finds files in the directory /home/devel/stuff/static/ whose file names match the matcher string of the find command (in this case *.pdf), and copies it to your present working directory.
The find command in this particular script only finds files with filenames ending with .pdf If you wanted to run this script for files with file names ending with .txt, then you need to change the find command to this find /home/devel/stuff/static/ -iname "*.txt",
Once I wanted to remove trailing -min from my files. i.e. wanted alg-min.jpg to turn into alg.jpg. so after some struggle, managed to figure something like this:
for f in *; do echo $f; mv $f $(echo $f | sed 's/-min//g');done;
Hope this helps someone willing to REMOVE or SUBTITUDE some part of their file names.