I want to write a code is shell scripting which will rename all the files of extension .txt in a current directory to extension .c .Suppose my current directory contains some 100 .txt file. This number is not fixed.
for f in *.txt; do echo mv "$f" "${f%.txt}.c"; done
Remove "echo" when you're satisfied it's working. See the bash manual for the meaning of "%" here.
See man rename. You can rename multiple files providing regexp substitution.
rename 's/\.txt$/.c/' *.txt
If you don't have rename in you system, you can use find:
find . -name '*.txt' | while read FILE; do echo mv "$FILE" "$(echo "$FILE" | sed 's/\.txt$/.c/g')"; done
Remove echo when you verify it does what you want.
awk can do this trick too:
kent$ ls *.txt|awk '{o=$0;gsub(/txt$/,"c"); print "mv "o" "$0;}'|sh
Related
I have a script that creates a file list of directories available in another path.
Now, I would like to do some tasks only if the Directory is of the format "YYYY_MM_DD_HH" in this file list.
My file list has following entries:
2014_04_21_01
asdf
2012_01_19_10
2010_01
Now I would like to move the directories with names as YYYY_MM_DD_HH to another path. I.e., only 2014_04_21_01 & 2012_01_19_10 MUST be MOVED.
Please advise.
Use bash regex pattern matching:
for dir in $list
do if [[ "$dir" =~ ^[0-9]{4}_[0-9]{2}_[0-9]{2}_[0-9]{2}$ ]]
then mv "$dir" newdir/
fi
done
Assuming you have a GNU version of sed on your computer, you could use it to easily parse your directory names and execute a command.
Say we have following input file:
2014_04_21_01
asdf
2012_01_19_10
2010_01
2012_01_19_10_09
62012_01_19_10
You can search for your regex with sed and replace it with a mv command as follows:
sed 's/^[0-9]\{4\}\(_[0-9]\{2\}\)\{3\}$/mv "&" "other_dir"/' file_list
will output:
mv "2014_04_21_01" "other_dir" # We want to run this
asdf
mv "2012_01_19_10" "other_dir" # and this
2010_01
2012_01_19_10_09
62012_01_19_10
Now if you add the (GNU sed) e option at the end of sed substitution (and -n option before sed script to ensure only successul substitutions are executed), the generated command will be piped into your shell:
sed -n 's/^[0-9]\{4\}\(_[0-9]\{2\}\)\{3\}$/mv "&" "other_dir"/e' file_list
# ^^ ^
I would recommand to run it first without the e option so as to check that mv commands will be properly formatted.
Why to make separate file for file list. Just go in that directory execute following command. I have taken the destination directory as /home/newdir/
ls | grep [0-9][0-9][0-9][0-9]_[01][0-9]_[0123][0-9]_[012][0-9] | awk '{print $0" /home/newdir/"}' | xargs mv
Be Careful while working with dates. As you have mentioned that file name is in format YYYY_MM_DD_HH then we have restrictions on MM,DD and HH. If we talk about restrictions then we know how a calendar is constructed. So 9999_99_99_99 is invalid file name. It is not satisfying YYYY_MM_DD_HH.
We have to build script for restrictions or I can say whole calendar. Still working on it.
Example:
perl -nle 'system("mv $_ dir/year$1") if /^(\d{4})_\d\d_\d\d_\d\d/$' flist
would extract the year and rename dir 2014_04_21_01 to dir/year2014
This single find command with -regex option should take care of this:
cd /base/path/of/these/dirs
find . -type d -regextype posix-egrep -regex '.*/[0-9]{4}_[0-9]{2}_[0-9]{2}_[0-9]{2}$' \
-exec mv '{}' /dest/dir/ \;
I have a directory like: /data/work/files/
calldata_phonecalls_2131201401_01.zip
calldata_phonecalls_7373201401_02.zip
In this directory I want to create new files corresponding to the zipfiles like , but modifying a small part of the name in BASH:
calldata_calllog_2131201401_01.tsv
calldata_calllog_7373201401_02.tsv
pl note "phonecalls" changed to "calllog"
Pl help.
Using Shell Parameter Expansion and basename:
for f in /data/work/files/*.zip; do
mv "$f" "$(basename "${f/phonecalls/calllog}" .zip).tsv"
done
Using rename (part of perl distribution):
rename 's/phonecalls/calllog/;s/\.zip$/.tsv/' /data/work/files/*.zip
Using rename :
Using one version of rename:
rename 's/^fgh/jkl/' fgh*
Using another version of rename :
rename fgh jkl fgh*
You should check your platform's man page to see which of the above applies.
Using mv:
find ./ -name "*.xyz\[*\]" | while read line
do
mv "$line" ${line%.*}.xyz
done
Another way
ls -1 | nawk '/foo-bar-/{old=$0;gsub(/-\(.*\)/,"",$0);system("mv \""old"\" "$0)}'
Yet another:
for f in fgh*; do mv $f $(echo $f | sed 's/^fgh/jkl/g'); done
There are several other answers under stackoverflow and superuser pages:
Copied/summarized from the following links:
Rename multiple files in Unix
How to use mv command to rename multiple files in unix?
I have files with name of the form "NAME-xxxxxx.tedx" and I want to remove the "-xxxxxx" part. The x are all digits.
The regex "\-[0-9]{1,6}" matches the substring, but I have no idea how to remove it from the filename.
Any idea how I can do that in the shell?
If you have the perl version of the rename command installed, you could try:
rename 's/-[0-9]+//' *.tedx
Demo:
[me#home]$ ls
hello-123.tedx world-23456.tedx
[me#home]$ rename 's/-[0-9]+//' *.tedx
[me#home]$ ls
hello.tedx world.tedx
This command is smart enough to not rename files if it means overwriting an existing file:
[me#home]$ ls
hello-123.tedx world-123.tedx world-23456.tedx
[me#home]$ rename 's/-[0-9]+//' *.tedx
world-23456.tedx not renamed: world.tedx already exists
[me#home]$ ls
hello.tedx world-23456.tedx world.tedx
echo NAME-12345.tedx | sed "s/-[0-9]*//g"
will give NAME.tedx. So you can use a loop and move the files using mv command:
for file in *.tedx; do
newfile=$(echo "$file" | sed "s/-[0-9]*//g")
mv "$file" $newfile
done
If you want to use just the shell
shopt -s extglob
for f in *-+([0-9]]).tedx; do
newname=${f%-*}.tedx # strip off the dash and all following chars
[[ -f $newname ]] || mv "$f" "$newname"
done
I have a directory with a bunch of files with names like:
001234.jpg
001235.jpg
004729342.jpg
I want to remove the leading zeros from all file names, so I'd be left with:
1234.jpg
1235.jpg
4729342.jpg
I've been trying different configurations of sed, but I can't find the proper syntax. Is there an easy way to list all files in the directory, pipe it through sed, and either move or copy them to the new file name without the leading zeros?
for FILE in `ls`; do mv $FILE `echo $FILE | sed -e 's:^0*::'`; done
sed by itself is the wrong tool for this: you need to use some shell scripting as well.
Check Rename multiple files with Linux page for some ideas. One of the ideas suggested is to use the rename perl script:
rename 's/^0*//' *.jpg
In Bash, which is likely to be your default login shell, no external commands are necessary.
shopt -s extglob
for i in 0*[^0]; do mv "$i" "${i##*(0)}"; done
Maybe not the most elegant but it will work.
for i in 0*
do
mv "${i}" "`expr "${i}" : '0*\(.*\)'`"
done
Try using sed, e.g.:
sed -e 's:^0*::'
Complete loop:
for f in `ls`; do
mv $f $(echo $f | sed -e 's:^0*::')
done
I dont know sed at all but you can get a listing by using find:
find -type f -name *.jpg
so with the other answer it might look like
find . -type f -name *.jpg | sed -e 's:^0*::'
but i dont know if that sed command holds up or not.
Here's one that doesn't require sed:
for x in *.jpg ; do let num="10#${x%%.jpg}"; mv $x ${num}.jpg ; done
Note that this ONLY works when the filenames are all numbers. You could also remove the leading zeros using the shell:
for a in *.jpg ; do dest=${a/*(0)/} ; mv $a $dest ; done
In Bash shell you can do:
shopt -s nullglob
for file in 0*.jpg
do
echo mv "$file" "${file##*0}"
done
I'd like to rename some files that are all in the same directory. The file name pattern used is Prefix_ddmmyy.tex with a european date format. For the sake of readability and the ordering I'd like to rename the files in a pattern Prefix_yymmdd.tex with a canonical date format.
Anyone ideas how I can do this automatically for a complete directory? My sed and regexp knowledge is not very sharp...
for file in Prefix_*.tex ; do
file_new=echo "$file" | sed -e 's:\([0-9][0-9]\)\([0-9][0-9]\)\([0-9][0-9]\)\(\.tex\):\3\2\1\4:'
test "$file" != "$file_new" && mv -f "$file" "$file_new"
done
Or, if you have a lot of files and/or want to process files recursively, replace:
for file in Prefix_*.tex ; do
with:
find . -name Prefix_*.tex -print | while read file ; do
or (non-recursive, GNU):
find . -maxtdepth 1 -name Prefix_*.tex -print | while read file ; do
You can also do it with any bourne-type shell without external commands:
for f in *.tex; do
_s=.${f##*.} _f=${f%.*} _p=${f%_*}_
_dt=${_f#$_p} _d=${_dt%????} _m=${_dt%??}
_y=${_dt#$_m} _m=${_m#??}
mv -- "$f" "$_p$_y$_m$_d$_s"
done
With zsh it would be:
autoload -U zmv
zmv '(*_)(??)(??)(??)(.tex)' '$1$4$3$2$5'
You can try "mmv".