Files
events-number1.10a.pdf
Result
events-number1.10a.docx.pdf
Ideal
events-number1.10a.pdf
events-number1.10a.docx.pdf
A simple rename command will do the job.
rename 's/(?=\.pdf$)/.docx/' *.pdf
You can try this simple bash script
#!/bin/bash
for file in *.pdf
do
new_file=$(echo "$file" | sed -r 's/(.*)(\.pdf)/\1.docx\2/')
mv $file $new_file
done
Output:
events-number1.index10a.docx.pdf
events-number1.index10b.docx.pdf
events-number1.index10c.docx.pdf
events-number2.index10a.docx.pdf
events-number2.index10b.docx.pdf
events-number2.index10c.docx.pdf
If you want copy the file using cp command instead of mv command
cp $file $new_file
So your existing files won't change.
Explanation :
Passing all the log file to for loop ,then split the file name to your expected result for using sed command and stored in one variable . Then mv the old file to new file that mean your expected file .
is it possible to wipe the contents of all given files in a directory? e.g. if I have a bunch of .csv files I want wiped.
I generally use "# > .csv" on the command line for a single csv file, but a "# > *.csv" results in a error: bash: *.csv: ambiguous redirect
I have tried piping /dev/null to *.csv but get same result. When I have a directory full of files whose content I want wiped, it's a real pain.
If I use a script and for loop on all the files I get the same error when using the redirect on the $f (the file) in the loop.
Thanks
for f in *.csv; do
> "$f"
done
You can use truncate for the same :
truncate -s 0 *.csv
When you say "wipe" you mean:
"overwite" with random content,
or an simple "truncate"
or even simpler delete?
Delete:
rm *.csv #will delete all .csv file in the currect directory
Truncate
see #John Zwinkcs answer
Overwrite with random and delete
shopt -s nullglob
for file in *.csv
do
echo "wiping $file" >&2
eval "$(gstat -c 'count=%b;blocksize=%B' "$file")"
dd if=/dev/random of="$file" bs="$blocksize" count="$count" 2>/dev/null
rm "$file"
done
This is a way using sed
sed -i '1,$d' *.csv
also
sed -ni '' *.csv
Suppose I have some files in a dir called test_dir, like a.sh, b.sh, c.sh, d.bash, and so on. I need to change all the file *.sh to *.bash. How can I achieve it using shell?
Can be done in a single one-liner:
ls *.sh | while read i; do mv "$i" "${i%.sh}.bash"; done
I want to write a code is shell scripting which will rename all the files of extension .txt in a current directory to extension .c .Suppose my current directory contains some 100 .txt file. This number is not fixed.
for f in *.txt; do echo mv "$f" "${f%.txt}.c"; done
Remove "echo" when you're satisfied it's working. See the bash manual for the meaning of "%" here.
See man rename. You can rename multiple files providing regexp substitution.
rename 's/\.txt$/.c/' *.txt
If you don't have rename in you system, you can use find:
find . -name '*.txt' | while read FILE; do echo mv "$FILE" "$(echo "$FILE" | sed 's/\.txt$/.c/g')"; done
Remove echo when you verify it does what you want.
awk can do this trick too:
kent$ ls *.txt|awk '{o=$0;gsub(/txt$/,"c"); print "mv "o" "$0;}'|sh
I am trying to loop through all the files in a directory.
I want to do some stuff on each file (convert it to xml, not included in example), then write the file to a new directory structure.
for file in `find /home/devel/stuff/static/ -iname "*.pdf"`;
do
echo $file;
sed -e 's/static/changethis/' $file > newfile +".xml";
echo $newfile;
done
I want the results to be:
$file => /home/devel/stuff/static/2002/hello.txt
$newfile => /home/devel/stuff/changethis/2002/hello.txt.xml
How do I have to change my sed line?
If you need to rename multiple files, I would suggest to use rename command:
# remove "-n" after you verify it is what you need
rename -n 's/hello/hi/g' $(find /home/devel/stuff/static/ -type f)
or, if you don't have rename try this:
find /home/devel/stuff/static/ -type f | while read FILE
do
# modify line below to do what you need, then remove leading "echo"
echo mv $FILE $(echo $FILE | sed 's/hello/hi/g')
done
Are you trying to change the filename? Then
for file in /home/devel/stuff/static/*/*.txt
do
echo "Moving $file"
mv "$file" "${file/static/changethis}.xml"
done
Please make sure /home/devel/stuff/static/*/*.txt is what you want before using the script.
First, you have to create the name of the new file based on the name of the initial file. The obvious solution is:
newfile=${file/static/changethis}.xml
Second you have to make sure that the new directory exists or create it if not:
mkdir -p $(dirname $newfile)
Then you can do something with your file:
doSomething < $file > $newfile
I wouldn't do the for loop because of the possibility of overloading your command line. Command lines have a limited length, and if you overload it, it'll simply drop off the excess without giving you any warning. It might work if your find returns 100 file. It might work if it returns 1000 files, but it might fail if your find returns 1000 files and you'll never know.
The best way to handle this is to pipe the find into a while read statement as glenn jackman.
The sed command only works on STDIN and on files, but not on file names, so if you want to munge your file name, you'll have to do something like this:
$newname="$(echo $oldname | sed 's/old/new/')"
to get the new name of the file. The $() construct executes the command and puts the results of the command on STDOUT.
So, your script will look something like this:
find /home/devel/stuff/static/ -name "*.pdf" | while read $file
do
echo $file;
newfile="$(echo $file | sed -e 's/static/changethis/')"
newfile="$newfile.xml"
echo $newfile;
done
Now, since you're renaming the file directory, you'll have to make sure the directory exists before you do your move or copy:
find /home/devel/stuff/static/ -name "*.pdf" | while read $file
do
echo $file;
newfile="$(echo $file | sed -e 's/static/changethis/')"
newfile="$newfile.xml"
echo $newfile;
#Check for directory and create it if it doesn't exist
$dirname=$(dirname "$newfile")
if [ ! -d "$dirname" ]
then
mkdir -p "$dirname"
fi
#Directory now exists, so you can do the move
mv "$file" "$newfile"
done
Note the quotation marks to handle the case there's a space in the file name.
By the way, instead of doing this:
if [ ! -d "$dirname" ]
then
mkdir -p "$dirname"
fi
You can do this:
[ -d "$dirname"] || mkdir -p "$dirname"
The || means to execute the following command only if the test isn't true. Thus, if [ -d "$dirname" ] is a false statement (the directory doesn't exist), you run mkdir.
It's a fairly common shortcut when you see shell scripts.
find ... | while read file; do
newfile=$(basename "$file").xml;
do something to "$file" > "$somedir/$newfile"
done
OUTPUT="$(pwd)";
for file in `find . -iname "*.pdf"`;
do
echo $file;
cp $file $file.xml
echo "file created in directory = {$OUTPUT}"
done
This will create a new file with name whatyourfilename.xml, for hello.pdf the new file created would be hello.pdf.xml, basically it creates a new file with .xml appended at the end.
Remember the above script finds files in the directory /home/devel/stuff/static/ whose file names match the matcher string of the find command (in this case *.pdf), and copies it to your present working directory.
The find command in this particular script only finds files with filenames ending with .pdf If you wanted to run this script for files with file names ending with .txt, then you need to change the find command to this find /home/devel/stuff/static/ -iname "*.txt",
Once I wanted to remove trailing -min from my files. i.e. wanted alg-min.jpg to turn into alg.jpg. so after some struggle, managed to figure something like this:
for f in *; do echo $f; mv $f $(echo $f | sed 's/-min//g');done;
Hope this helps someone willing to REMOVE or SUBTITUDE some part of their file names.