I'm practicing some basic coding, I'm running a simple math program running in the terminal on Visual Studio Code.
How do I create an option to return to the beginning of the program, or exit the program after getting caught in an if statement?
Example:
#beginning of program
user_input=input('Please select "this" or "that": ')
findings=user_input
If findings == this:
print(this)
# How can I redirect back to first user input question, instead
# of just ending here?
if findings == that:
print (that)
# Again, How do I redirect back to first user input, instead of
# the program ending here?
# Can I setup a Play_again here with options to return to user_input,
# or exit program? And then have all other If statements
# redirect here after completion? How would I do that? with
# another If? or with a for loop?
#end program
You can try wrapping the whole program in a while loop like this:
while(True):
user_input=input('Please select "this" or "that": ')
this = 'foo'
if user_input == this:
print(this)
continue
if user_input == this:
print(this)
continue
Unfortunately, that 'another technique' I thought of using didn't work.
Here's the code (the first example modified):
import sys
def main():
# Lots of setup code here.
def start_over():
return #Do nothing and continue from the next line
condition = 1==1 #Just a sample condition, replace it with "check(condition)".
float_condition = condition
def play(*just_define:bool):
if not just_define:
play_again = input('play again? "y" or "n"')
if play_again == 'y':
start_over() #Jump to the beginning of the prohram.
if play_again == 'n':
sys.exit() #Exit the program
while True:
if float_condition == True:
# print(float_condition)
play() #skip to play_again from here?
if float_condition == False:
#print(float_condition)
play() #skip to play_again from here?
#I removed the extra "main()" which was here because it'd cause an infinite loop-like error.
main()
Output:
play again? "y" or "n"y
play again? "y" or "n"n
Process finished with exit code 0
The * in the play(*just_define:bool) function makes the just_define parameter optional. Use the parameter if you want to only tell Python to search for this function, so it doesn't throw a ReferenceError and not execute anything that's after the line if not just_define:. How to call like so: play(just_define=True).
I've used nested functions. I've defined play so that you can call it from other places in your code.
Thanks to #Hack3r - I was finally able to choose to return back to the beginning of the program or exit out. But it resulted in a new issue. Now my print(results) are printing 4 or 5 times...
Here is the actual code I built and am working with:
def main():
math_Options=['Addition +','Subtraction -','Multiplication *','Division /']
math_func=['+','-','*','/']
for options in math_Options:
print(options)
print('Lets do some Math! What math function would you like to use? ')
while True:
my_Math_Function = input('Please make your choice from list above using the function symbol: ')
my_Number1=input('Please select your first number: ')
x=float(my_Number1)
print('Your 1st # is: ', x)
my_Number2=input('Please select your Second Number: ')
y=float(my_Number2)
print('Your 2nd # is: ', y)
z=float()
print('')
for Math_function in math_func:
if my_Math_Function == math_func[0]:
z=x+y
if my_Math_Function == math_func[1]:
z=x-y
if my_Math_Function == math_func[2]:
z=x*y
if my_Math_Function == math_func[3]:
z=x/y
if (z % 2) == 0 and z>0:
print(z, ' Is an EVEN POSITIVE Number')
if (z % 2) == 1 and z>0:
print(z, ' IS a ODD POSTIVE Number')
if (z % 2) == 0 and z<0:
print(z, ' Is an EVEN NEGATIVE Number')
if (z % 2) ==1 and z<0:
print(z, ' IS a ODD NEGATIVE Number')
if z==0:
print(z, 'Is is Equal to Zero')
print('')
play_again=input('Would you like to play again? "y" or "n" ')
if play_again == 'y':
continue
if play_again == 'n':
break
main()
main()
I have a text file that I want to open first for reading or writing, but want the user to manually enter the text_file name (which opens the file for reading) first like so:
def read_in_albums
puts "Enter file name: "
begin
file_name = gets().chomp
if (file_name == "albums.txt")
puts "File is open"
a_file = File.new("#{file_name}", "r")
puts a_file.gets
finished = true
else
puts "Please re-enter file name: "
end
end until finished
end
From this unfinished code below, selecting 1 would go to the above procedure. I want the user to select 1 first, and if they choose 2 without having gone through read_in_albums they just get some sort of message like "no file selected and sent back to menu screen.
def main()
finished = false
begin
puts("Main Menu:")
puts("1- Read in Album")
puts("2- Display Album Info")
puts("3- Play Album")
puts("4- Update Album")
puts("5- Exit")
choice = read_integer_in_range("Please enter your choice:", 1, 5)
case choice
when 1
read_in_albums
when 2
display_album_info
when 5
finished = true
end
end until finished
end
main()
The only thing I can think of is something like
when 2
if(read_in_albums == true)
display_album_info
and have it return true from read_in_albums.
which I don't want to do as it just goes through read_in_albums again, when I only want it to do that if the user pressed 1.
All of your application's functionality depends on whether the album data has been read. You are no doubt storing this data as an object in memory referenced by some variable.
$album_data = File.read 'album.txt'
You can test whether this data is present in order to determine whether the file data has been read:
if $album_data.nil?
# ask user for album file
else
# show album user interface
end
There is no need for a separate flag. The mere presence of the data in memory serves as a flag already.
You could either set a flag when option 1 was selcted
has_been_read = false
...
when 1
read_in_albums
has_been_read = true
when 2
if has_been_read
display_album_info
else
puts "Select Option 1 first"
end
Or just test if your file name is a valid string.
I am struggling to find a text comparison tool or algorithm that can compare an expected text against the current state of the text being typed.
I will have an experimentee typewrite a text that he has in front of his eyes. My idea is to compare the current state of the text against the expected text whenever something is typed. That way I want to find out when and what the subject does wrong (I also want to find errors that are not in the resulting text but were in the intermediate text for some time).
Can someone point me in a direction?
Update #1
I have access to the typing data in a csv format:
This is example output data of me typing "foOBar". Every line has the form (timestamp, Key, Press/Release)
17293398.576653,F,P
17293398.6885,F,R
17293399.135282,LeftShift,P
17293399.626881,LeftShift,R
17293401.313254,O,P
17293401.391732,O,R
17293401.827314,LeftShift,P
17293402.073046,O,P
17293402.184859,O,R
17293403.178612,B,P
17293403.301748,B,R
17293403.458137,LeftShift,R
17293404.966193,A,P
17293405.077869,A,R
17293405.725405,R,P
17293405.815159,R,R
In Python
Given your input csv file (I called it keyboard_records.csv)
17293398.576653,F,P
17293398.6885,F,R
17293399.135282,LeftShift,P
17293399.626881,LeftShift,R
17293401.313254,O,P
17293401.391732,O,R
17293401.827314,LeftShift,P
17293402.073046,O,P
17293402.184859,O,R
17293403.178612,B,P
17293403.301748,B,R
17293403.458137,LeftShift,R
17293404.966193,A,P
17293405.077869,A,R
17293405.725405,R,P
17293405.815159,R,R
The following code does the following:
Read its content and store it in a list named steps
For each step in steps recognizes what happened and
If it was a shift press or release sets a flag (shift_on) accordingly
If it was an arrow pressed moves the cursor (index of current where we insert characters) – if it the cursor is at the start or at the end of the string it shouldn't move, that's why those min() and max()
If it was a letter/number/symbol it adds it in curret at cursor position and increments cursor
Here you have it
import csv
steps = [] # list of all actions performed by user
expected = "Hello"
with open("keyboard.csv") as csvfile:
for row in csv.reader(csvfile, delimiter=','):
steps.append((float(row[0]), row[1], row[2]))
# Now we parse the information
current = [] # text written by the user
shift_on = False # is shift pressed
cursor = 0 # where is the cursor in the current text
for step in steps:
time, key, action = step
if key == 'LeftShift':
if action == 'P':
shift_on = True
else:
shift_on = False
continue
if key == 'LeftArrow' and action == 'P':
cursor = max(0, cursor-1)
continue
if key == 'RightArrow' and action == 'P':
cursor = min(len(current), cursor+1)
continue
if action == 'P':
if shift_on is True:
current.insert(cursor, key.upper())
else:
current.insert(cursor, key.lower())
cursor += 1
# Now you can join current into a string
# and compare current with expected
print(''.join(current)) # printing current (just to see what's happening)
else:
# What to do when a key is released?
# Depends on your needs...
continue
To compare current and expected have a look here.
Note: by playing around with the code above and a few more flags you can make it recognize also symbols. This will depend on your keyboard. In mine Shift + 6 = &, AltGr + E = € and Ctrl + Shift + AltGr + è = {. I think this is a good point to start.
Update
Comparing 2 texts isn't a difficult task and you can find tons of pages on the web about it.
Anyway I wanted to present you an object oriented approach to the problem, so I added the compare part that I previously omitted in the first solution.
This is still a rough code, without primary controls over the input. But, as you asked, this is pointing you in a direction.
class UserText:
# Initialize UserText:
# - empty text
# - cursor at beginning
# - shift off
def __init__(self, expected):
self.expected = expected
self.letters = []
self.cursor = 0
self.shift = False
# compares a and b and returns a
# list containing the indices of
# mismatches between a and b
def compare(a, b):
err = []
for i in range(min(len(a), len(b))):
if a[i] != b[i]:
err.append(i)
return err
# Parse a command given in the
# form (time, key, action)
def parse(self, command):
time, key, action = command
output = ""
if action == 'P':
if key == 'LeftShift':
self.shift = True
elif key == 'LeftArrow':
self.cursor = max(0, self.cursor - 1)
elif key == 'RightArrow':
self.cursor = min(len(self.letters), self.cursor + 1)
else:
# Else, a letter/number was pressed. Let's
# add it to self.letters in cursor position
if self.shift is True:
self.letters.insert(self.cursor, key.upper())
else:
self.letters.insert(self.cursor, key.lower())
self.cursor += 1
########## COMPARE WITH EXPECTED ##########
output += "Expected: \t" + self.expected + "\n"
output += "Current: \t" + str(self) + "\n"
errors = UserText.compare(str(self), self.expected[:len(str(self))])
output += "\t\t"
i = 0
for e in errors:
while i != e:
output += " "
i += 1
output += "^"
i += 1
output += "\n[{} errors at time {}]".format(len(errors), time)
return output
else:
if key == 'LeftShift':
self.shift = False
return output
def __str__(self):
return "".join(self.letters)
import csv
steps = [] # list of all actions performed by user
expected = "foobar"
with open("keyboard.csv") as csvfile:
for row in csv.reader(csvfile, delimiter=','):
steps.append((float(row[0]), row[1], row[2]))
# Now we parse the information
ut = UserText(expected)
for step in steps:
print(ut.parse(step))
The output for the csv file above was:
Expected: foobar
Current: f
[0 errors at time 17293398.576653]
Expected: foobar
Current: fo
[0 errors at time 17293401.313254]
Expected: foobar
Current: foO
^
[1 errors at time 17293402.073046]
Expected: foobar
Current: foOB
^^
[2 errors at time 17293403.178612]
Expected: foobar
Current: foOBa
^^
[2 errors at time 17293404.966193]
Expected: foobar
Current: foOBar
^^
[2 errors at time 17293405.725405]
I found the solution to my own question around a year ago. Now i have time to share it with you:
In their 2003 paper 'Metrics for text entry research: An evaluation of MSD and KSPC, and a new unified error metric', R. William Soukoreff and I. Scott MacKenzie propose three major new metrics: 'total error rate', 'corrected error rate' and 'not corrected error rate'. These metrics have become well established since the publication of this paper. These are exaclty the metrics i was looking for.
If you are trying to do something similiar to what i did, e.g. compare the writing performance on different input devices this is the way to go.
I have made that loop my self and Iam trying to make it faster, better... but sometimes after it repeat searching for existing... it press random ( i think cuz its not similar to any img iam using in sikuli ) place on the screen. Maybe you will know why.
Part of this loop below
while surowiec_1:
if exists("1451060448708.png", 1) or exists("1451061746632.png", 1):
foo = [w_lewo, w_prawo, w_dol, w_gore]
randomListElement = foo[random.randint(0,len(foo)-1)]
click(randomListElement)
wait(3)
else:
if exists("1450930340868.png", 1 ):
click(hemp)
wait(1)
hemp = exists("1450930340868.png", 1)
elif exists("1451086210167.png", 1):
click(tree)
wait(1)
tree = exists("1451086210167.png", 1)
elif exists("1451022614047.png", 1 ):
hover("1451022614047.png")
click(flower)
flower = exists("1451022614047.png", 1)
elif exists("1451021823366.png", 1 ):
click(fish)
fish = exists("1451021823366.png")
elif exists("1451022083851.png", 1 ):
click(bigfish)
bigfish = exists("1451022083851.png", 1)
else:
foo = [w_lewo, w_prawo, w_dol, w_gore]
randomListElement = foo[random.randint(0,len(foo)-1)]
click(randomListElement)
wait(3)
I wonder if this is just program problem with img recognitions or I have made a mistake.
You call twice the exist method indending to get the same match (the first one in your if statement, the second time to assign it to the value. You ask sikuli to evaluate the image twice, and it can have different results.
From the method's documentation
the best match can be accessed using Region.getLastMatch() afterwards.
I have an if:
-12.times do |control|
-dia += 1
-if control == 1
%a#hoy{:href=>'/dias/algo'}<
-else
%a{:href=>'/dias/algo'}<
=dia
%span=dias[rand(7)]
The problem is I need =dia and span elements inside the anchor tag in both cases (true/false), and when I quit one identation it fails, because haml will end the if (which is also normal).
Is there any way to force end an if? I have tried it in many ways, but couldn't find the right way if it exist.
Thanks.
-12.times do |control|
-dia += 1
%a{:id => control == 1 ? "hoy" : "", :href=>'/dias/algo'}<
=dia
%span=dias[rand(7)]
Didn't test it but it should work ...