Spring MVC save uploaded MultipartFile to specific folder - spring

Question

I want to save uploaded images to a specific folder in a Spring 3 MVC application deployed on Tomcat
My problem is that I cannot save the uploaded images files to the host where the appliciation is running.
Here is what I tried:
private void saveFile(MultipartFile multipartFile, int id) throws Exception {
String destination = "/images/" + id + "/" + multipartFile.getOriginalFilename();
File file = new File(destination);
multipartFile.transferTo(file);
}
Result: FileNotFoundException - Yes sure, I do want create this file!?!
I tried it using the context.getRealPath or getResources("destination"), but without any success.
How can I create a new file in a specific folder of my app with the content of my multipart file?

Answer 1

This code will surely help you.
String filePath = request.getServletContext().getRealPath("/");
multipartFile.transferTo(new File(filePath));

Answer 2

Let's create the uploads directory in webapp and save files in webapp/uploads:
#RestController
public class GreetingController {
private final static Logger log = LoggerFactory.getLogger(GreetingController.class);
#Autowired
private HttpServletRequest request;
#RequestMapping(value = "/uploadfile", method = RequestMethod.POST)
public
#ResponseBody
ResponseEntity handleFileUpload(#RequestParam("file") MultipartFile file) {
if (!file.isEmpty()) {
try {
String uploadsDir = "/uploads/";
String realPathtoUploads = request.getServletContext().getRealPath(uploadsDir);
if(! new File(realPathtoUploads).exists())
{
new File(realPathtoUploads).mkdir();
}
log.info("realPathtoUploads = {}", realPathtoUploads);
String orgName = file.getOriginalFilename();
String filePath = realPathtoUploads + orgName;
File dest = new File(filePath);
file.transferTo(dest);
the code
String realPathtoUploads = request.getServletContext().getRealPath(uploadsDir);
returns me next path if I run the app from Idea IDE
C:\Users\Iuliia\IdeaProjects\ENumbersBackend\src\main\webapp\uploads\
and next path if I make .war and run it under Tomcat:
D:\Programs_Files\apache-tomcat-8.0.27\webapps\enumbservice-0.2.0\uploads\
My project structure:

Answer 3

You can get the inputStream from multipartfile and copy it to any directory you want.
public String write(MultipartFile file, String fileType) throws IOException {
String date = LocalDateTime.now().format(DateTimeFormatter.ofPattern("yyMMddHHmmss-"));
String fileName = date + file.getOriginalFilename();
// folderPath here is /sismed/temp/exames
String folderPath = SismedConstants.TEMP_DIR + fileType;
String filePath = folderPath + File.separator + fileName;
// Copies Spring's multipartfile inputStream to /sismed/temp/exames (absolute path)
Files.copy(file.getInputStream(), Paths.get(filePath), StandardCopyOption.REPLACE_EXISTING);
return filePath;
}
This works for both Linux and Windows.

Answer 4

I saw a spring 3 example using xml configuration (note this does not wok for spring 4.2.*): http://www.devmanuals.com/tutorials/java/spring/spring3/mvc/spring3-mvc-upload-file.html
`
<bean id="multipartResolver"
class="org.springframework.web.multipart.commons.CommonsMultipartResolver">
<property name="maxUploadSize" value="100000" />
<property name="uploadTempDir" ref="uploadDirResource" />
</bean>
<bean id="uploadDirResource" class="org.springframework.core.io.FileSystemResource">
<constructor-arg>
<value>C:/test111</value>
</constructor-arg>
</bean>

Answer 5

String ApplicationPath =
ContextLoader.getCurrentWebApplicationContext().getServletContext().getRealPath("");
This is how to get the real path of App in Spring (without using response, session ...)

Answer 6

The following worked for me on ubuntu:
String filePath = request.getServletContext().getRealPath("/");
File f1 = new File(filePath+"/"+multipartFile.getOriginalFilename());
multipartFile.transferTo(f1);