I have a problem of downloading my uploaded files from amazon s3 service. I have succesfully implemented the upload section, all I need is to download these file to my local hardrive the view them later. My application is a spring mvc application.
This is my controller to call the download service
#Controller
public class fileController{
#Autowired S3Service s3Service;
#Autowired AwsConfig awsConfig;
#Autowired Environment env;
#Autowired DocRepository docRepo;
#RequestMapping(value="downloadDocume")
public void downloadDocument(#RequestParam("docId") Long docId
,HttpServletRequest request ,HttpServletResponse response)){
Document doc = docRepo.findOne(docId);
String docName = doc.getAsset().getName();
String ASSET_PATH = awsConfig.getBaseUrl()+"/"+
awsConfig.getBucket()+"/";
if (Objects.equals(env.getProperty("spring.profiles.active"),"prod")){
ASSET_PATH= awsConfig.getBaseUrl()+"/"+
awsConfig.getBucket()+"/";
}
String filtered = StringUtils.delete(docName, ASSET_PATH);
String mimetype = request.getSession().getServletContext().getMimeType(filtered);
FileStream file = s3Service.getAssetByName("/Documents/", filtered);
response.setContentType(mimetype);
response.setContentLength((int) file.getSize());
response.setHeader("Content-Disposition","attachment; filename=\"" + docName +"\"");
FileCopyUtils.copy(file.getInputStream(), response.getOutputStream());
}
}
//This is my S3Sservice class with the download method
#Service
public class S3Service{
public FileStream getAssetByName(String path , String name)
throws FileNotFoundException{
AmazonS3Client s3 = new AmazonS3Client(
new BasicAWSCredentials(awsConfig.getAccessKey(), awsConfig.getSecretKey()));
s3.setEndpoint(awsConfig.getBaseUrl());
s3.setS3ClientOptions(new S3ClientOptions().withPathStyleAccess(true));
S3Object obj = s3.getObject(new GetObjectRequest(awsConfig.getBucket(), getS3Path(path) + name));
return new FileStream(obj.getObjectContent(), obj.getObjectMetadata().getContentLength());
}
}
Wow.. The solution was very simple.. I just used the the html download link and passed the parameters on my jsp like this. This is i my document.jsp
<a class="btn btn-primary" href="${document.asset.name}" download="${document.asset.name}">Download Document</a>
I change my downloadDocument() in my controller to look like this
public void downloadDocument(#RequestParam("docId") Long docId
,HttpServletRequest request ,HttpServletResponse response)){
Document doc = docRepo.findOne(docId);
model.addAtribute("document" , doc);
return "document";
}
}
Related
When I run the code the external configuration in the application.properties file does not get populated into the variable within the DataBucketUtil. I'm sure I'm doing something stupid,but I can not find out wheres the problem.
public class DataBucketUtil {
private static final Logger logger = LoggerFactory.getLogger(DataBucketUtil.class);
#Value("${gcp.config.file}")
private String gcpConfigFile;
#Value("${gcp.project.id}")
private String gcpProjectId;
#Value("${gcp.bucket.id}")
private String gcpBucketId;
#Value("${gcp.directory.name}")
private String gcpDirectoryName;
/**
* Upload file to GCS
*
* #param multipartFile-
* #param fileName-
* #param contentType-
* #return -
*/
public FileDto uploadFile(MultipartFile multipartFile, String fileName, String contentType) {
try {
logger.debug("Start file uploading process on GCS");
byte[] fileData = FileUtils.readFileToByteArray(convertFile(multipartFile));
InputStream inputStream = new ClassPathResource(gcpConfigFile).getInputStream();
StorageOptions options = StorageOptions.newBuilder().setProjectId(gcpProjectId)
.setCredentials(GoogleCredentials.fromStream(inputStream)).build();
Storage storage = options.getService();
Bucket bucket = storage.get(gcpBucketId, Storage.BucketGetOption.fields());
RandomString id = new RandomString(6, ThreadLocalRandom.current());
Blob blob = bucket.create(gcpDirectoryName + "/"
+ fileName + "-" + id.nextString() + checkFileExtension(fileName),
fileData, contentType);
if (blob != null) {
logger.debug("File successfully uploaded to GCS");
return new FileDto(blob.getName(), blob.getMediaLink());
}
} catch (IOException e) {
logger.error("An error occurred while uploading data. Exception: ", e);
throw new RuntimeException("An error occurred while uploading data to GCS");
}
throw new RuntimeException("An error occurred while uploading data to GCS");
}
My application properties is given below:
gcp.config.file=gcp-config/gcs-prod-ho-finance.json
gcp.project.id=brac-main gcp.bucket.id=prod-ho-finance
gcp.dir.name=gs://prod-ho-finance
It is not entirely clear from your code snippet but my guess would be that your DataBucketUtil is not instantiated as a Bean and therefore the #Value annotated fields are not populated. See here for more details about the #Value annotation.
You could transform your class to a service or component with the #Component or #Service annotation and then autowire it to where you need it. See here for more information about beans.
Please add Annotations. I hope it work.
#EnableConfigurationProperties
#Component
public class DataBucketUtil {
private static final Logger logger = LoggerFactory.getLogger(DataBucketUtil.class);
#Value("${gcp.config.file}")
private String gcpConfigFile;
#Value("${gcp.project.id}")
private String gcpProjectId;
#Value("${gcp.bucket.id}")
private String gcpBucketId;
#Value("${gcp.directory.name}")
private String gcpDirectoryName;
/** ............ **/
}
I want to upload a multipart file to AWS S3. So, i have to convert it.
But new File method needs a local location to get the file.
I am able to do in local. But running this code in every machine seems like a issue.
Please find both scenarios.
Working
private File convertMultiPartToFile(MultipartFile multipartFile) throws IOException {
File convFile = new File("C:\\Users\\" + multipartFile.getOriginalFilename());
multipartFile.transferTo(convFile);
return convFile;
}
Not working
private File convertMultiPartToFile(MultipartFile multipartFile) throws IOException {
File convFile = new File(multipartFile.getOriginalFilename());
multipartFile.transferTo(convFile);
return convFile;
}
Error received :
java.io.FileNotFoundException: newbusiness.jpg (Access is denied)
at java.io.FileOutputStream.open0(Native Method)
at java.io.FileOutputStream.open(FileOutputStream.java:270)
at java.io.FileOutputStream.<init>(FileOutputStream.java:213)
at java.io.FileOutputStream.<init>(FileOutputStream.java:162)
You could use Spring Content S3. This will hide the implementation details so you don't need to worry about them.
There are Spring Boot starter alternatives but as you are not using Spring Boot add the following dependency to your pom.xml
pom.xml
<dependency>
<groupId>com.github.paulcwarren</groupId>
<artifactId>spring-content-s3</artifactId>
<version>0.0.11</version>
</dependency>
Add the following configuration that creates a SimpleStorageResourceLoader bean:
#Configuration
#EnableS3Stores
public class S3Config {
#Autowired
private Environment env;
public Region region() {
return Region.getRegion(Regions.fromName(env.getProperty("AWS_REGION")));
}
#Bean
public BasicAWSCredentials basicAWSCredentials() {
return new BasicAWSCredentials(env.getProperty("AWS_ACCESS_KEY_ID"), env.getProperty("AWS_SECRET_KEY"));
}
#Bean
public AmazonS3 client(AWSCredentials awsCredentials) {
AmazonS3Client amazonS3Client = new AmazonS3Client(awsCredentials);
amazonS3Client.setRegion(region());
return amazonS3Client;
}
#Bean
public SimpleStorageResourceLoader simpleStorageResourceLoader(AmazonS3 client) {
return new SimpleStorageResourceLoader(client);
}
}
Create a "Store":
S3Store.java
public interface S3Store extends Store<String> {
}
Autowire this store into where you need to upload resources:
#Autowired
private S3Store store;
WritableResource r = (WritableResource)store.getResource(getId());
InputStream is = // plug your input stream in here
OutputStream os = r.getOutputStream();
IOUtils.copy(is, os);
is.close();
os.close();
When your application starts it will see the dependency on spring-content-s3 and your S3Store interface and inject an implementation for you, therefore, you don't need to worry about implementing this yourself.
IF you writing some sort of web application or microservice and you need a REST API then you can also add this dependency:
<dependency>
<groupId>com.github.paulcwarren</groupId>
<artifactId>spring-content-rest</artifactId>
<version>0.0.11</version>
</dependency>
Update your S3Config.java as follows:
#Configuration
#EnableS3Stores
#Import(RestConfiguration.class)
public class S3Config {
...
Update your store as follows:
S3Store.java
#StoreRestResource(path="s3docs")
public interface S3Store extends Store<String> {
}
Now when your application starts it will see your Store interface and also inject an #Controller implementation that will forward REST request onto your store. This replaces the autowiring code above obviously.
Then:
curl -X POST /s3docs/example-doc
with a multipart/form-data request will store the image in s3.
curl /s3docs/example-doc
will fetch it again and so on. This controller supports full CRUD and video streaming by the way.
If you want to associate this "content" with JPA Entity or something like that then you can have your S3Store extend AssociateStore or ContentStore and you have additional methods available that provide for associations.
There are a couple of getting started guides here. The s3 reference guide is here. And there is a tutorial video here. The coding bit starts about 1/2 way through.
HTH
Since it needs a temporary location to place files. Below code worked after deploying war on AWS.
private File convertMultiPartToFile(MultipartFile multipartFile) throws IOException {
File convFile = new File(System.getProperty("java.io.tmpdir") + System.getProperty("file.separator") +
multipartFile.getOriginalFilename());
multipartFile.transferTo(convFile);
return convFile;
}
You have problems with relative Paths
You can do this
public class UploadStackoverflow {
private String location = "upload-dir";
private Path rootLocation;
public File convertFile(MultipartFile file) throws IOException {
rootLocation = Paths.get(location);
Files.createDirectories(rootLocation);
String filename = StringUtils.cleanPath(file.getOriginalFilename());
InputStream inputStream = file.getInputStream();
Files.copy(inputStream, this.rootLocation.resolve(filename),
StandardCopyOption.REPLACE_EXISTING);
return new File(this.rootLocation.resolve(filename).toAbsolutePath().toString());
}
}
I am new in Spring-Boot...
I want to upload images or videos, and store them in a persistant folder "upload-storage" in the class-path of my project in the server. I don't want to store them in the database (20 Mo).
Spring-Boot store them in target/upload-storage.
That functions : I can show the videos on the view with the controller and Thymeleaf. I can close tomcat, close the browser, and open them again : that functions.
But the day after, upload-storage is disapeared !
I think that I don't use the good process.
But I found how to upload an image : ok. I found how to show images from a folder in class-path : ok. I found how to upload images to database. But nothing to store the uploaded images in a persistant folder.
Can you help me ? Can you tell me the good process ?
Some details :
I have an entity "video" to store name, extension, length,... of the video.
I have "VideoRepository" and "VideoService" to manage the requests with "Video".
I have a "StorageService" and "StorageServiceImpl" to manage the upload of video and images : It as to upload the video and save it in a folder called "upload-storage" : I will come back on it farther.
I have a videoForm.html first with a form to select a file and send it to "UploadController", then an other form to show the video, the datas extracted from the video, modify the name or add precisions, and send this form to a "VideoController" who save the entity.
A part of the code of "UploadController" :
`
#Controller
public class UploadController extends BaseController {
private final StorageService storageServiceImpl;
#Autowired
public UploadController(StorageService storageServiceImpl) {
this.storageServiceImpl = storageServiceImpl;
}
#PostMapping("/upload")
public String recupereUpload(#RequestParam("file") MultipartFile file,Model model){
String filename ="";
try {
final long limit = 200 * 1024 * 1024;
if (file.getSize() > limit) {
model.addAttribute("message", "Taille du fichier trop grand (>200MB)");
model.addAttribute("ok", false );
}
filename = storageServiceImpl.store(file);
model.addAttribute("filename", filename);
model.addAttribute("message", "Le téléchargement de " + filename+" est réussi !");
} catch (Exception e) {
model.addAttribute("message", "FAIL to upload " + filename + "!");
model.addAttribute("ok", false );
}
Video video = new Video();
model.addAttribute("ok", true );
model.addAttribute("video", video);
String baseName = storageServiceImpl.getBaseName(filename);
String ext = storageServiceImpl.getExtension(filename);
model.addAttribute("nom", baseName);
model.addAttribute("ext", ext);
model.addAttribute("nomorigin", filename);
model.addAttribute("size", Math.round(file.getSize()/1024));
String typExt = storageServiceImpl.getType(ext);
model.addAttribute("typExt", typExt);
return "elementVideo/videoForm";
}
`
"StorageServiceImpl" has different methods :
getExtension(String filename){...}
getType(String ext){...}
getType(String ext){...}
getBaseName(String filename){...}
The main method is store(MultipartFile file) {...} :
#Service
public class StorageServiceImpl implements StorageService {
private final Path storageLocation = Paths.get("upload-storage");
#Override
public String store(MultipartFile file) {
try {
// Vérification de l'existence :
if (file.isEmpty()) {
throw new Exception("Failed to store empty file " + file.getOriginalFilename() );
}
// Vérification de la nature et traitement du fichier uploadé :
String ext = getExtension(file.getOriginalFilename());
String[] extAutorise = {"mp4", "avi","ogg","ogv","jpg","jpeg","png","gif"};
String fileNameTarget ="";
if ( ArrayUtils.contains( extAutorise, ext)) {
//Définir le fichier destination :
fileNameTarget = file.getOriginalFilename();
fileNameTarget = fileNameTarget.replaceAll(" ", "_");
File dir = storageLocation.toFile();
String serverFile = dir.getAbsolutePath() + File.separator + fileNameTarget ;
try {
try (InputStream is = file.getInputStream();
BufferedOutputStream stream = new BufferedOutputStream(new FileOutputStream(serverFile))
) {
int i;
while ((i = is.read()) != -1) {
stream.write(i);
}
stream.flush();
}
} catch (IOException e) {
System.out.println("error : " + e.getMessage());
}
}
return fileNameTarget;
} catch (Exception e) {
throw new RuntimeException("FAIL!");
}
}
`
With this code, a folder "upload-storage" is created at the root of the project.
The video is uploaded in this folder...
But in "videoForm.html", the code
<video id="video" th:src="'/upload-storage/'+${filename}" height="60"
autoplay="autoplay"></video>
shows nothing.
I have an other solution.
In StorageServiceImpl, I use the code :
private final String storageLocation = this.getClass().getResource("/static/").getPath();
at place of :
private final Path storageLocation = Paths.get("upload-storage");
then :
File dir = new File(storageLocation + File.separator + "upload-storage");
at place of :
File dir = storageLocation.toFile();
then :
File serverFile = new File(dir.getAbsolutePath() + File.separator + fileNameTarget);
at place of :
String serverFile = dir.getAbsolutePath() + File.separator + fileNameTarget ;
With this solution, upload-storage is created in target folder.
I use an other controller BaseController :
public class BaseController {
public static final String PARAM_BASE_URL = "baseURL";
public String getBaseURL(HttpServletRequest request){
return request.getScheme() + "://" + request.getServerName() + ":" + request.getServerPort() + request.getContextPath();
}
}
`
UploadController extends this BaseController.
I add HttpServletRequest request in recupereUpload() :
#PostMapping("/upload")
public String recupereUpload(#RequestParam("file") MultipartFile file,
Model model, HttpServletRequest request ){
I add in the model sent by recupereUpload :
model.addAttribute(PARAM_BASE_URL, getBaseURL(request));
And at last, I can see my video in videoForm.html with the code :
<video id="video" th:src="${baseURL}+'/upload-storage/'+${filename}" height="60" autoplay="autoplay"></video>
I can close Tomcat, close Eclipse, close the machine, and open all again : all is preserved and I can see the video.
But some time later : all is disappeared.
There must be a better solution.
Can you help me ?
Why dont you use Spring Content for the video content portion of your solution? That way you won't need to implement any of the video content handling. Spring Content will provide this for you. To add Spring Content to your project:
Add Spring Content to your classpath.
pom.xml
<dependency>
<groupId>com.github.paulcwarren</groupId>
<artifactId>spring-content-rest-boot-starter</artifactId>
<version>0.0.10</version>
</dependency>
<dependency>
<groupId>com.github.paulcwarren</groupId>
<artifactId>content-fs-spring-boot-starter</artifactId>
<version>0.0.10</version>
</dependency>
Associate content with your Video entity.
Video.java
#Entity
public class Video {
...
#ContentId
private String contentId;
#ContentLength
private Long contetLen;
#MimeType
private String mimeType;
...
Set up a "persistent folder" as the root of your video store. This is where uploaded videos will be stored/streamed from. Also create a VideoStore interface to describe to SC how you want to associate your content.
SpringBootApplication.java
#SpringBootApplication
public class YourSpringBootApplication {
public static void main(String[] args) {
SpringApplication.run(YourSpringBootApplication.class, args);
}
#Configuration
#EnableFilesystemStores
public static class StoreConfig {
File filesystemRoot() {
return new File("/path/to/your/videos");
}
#Bean
public FileSystemResourceLoader fsResourceLoader() throws Exception {
return new FileSystemResourceLoader(filesystemRoot().getAbsolutePath());
}
}
#StoreRestResource(path="videos")
public interface VideoStore extends ContentStore<Video,String> {
//
}
}
This is all you need to create a REST-based video service at /videos. Essentially, when your application starts, Spring Content will look at your dependencies (seeing Spring Content FS/REST), look at your VideoStore interface and inject an implementation of that interface based on the filesystem. It will also inject a controller that forwards http requests to that implementation as well. This saves you having to implement any of this yourself.
So...
POST /videos/{video-entity-id}
with a multipart/form-data request will store the video in /path/to/your/videos and associate it with the video entity whose id is video-entity-id.
GET /videos/{video-entity-id}
will fetch it again. This supports partial content requests or byte ranges; i.e. video streaming too.
and so on...support full CRUD.
There are a couple of getting started guides here. The reference guide is here. And there is a tutorial video here. The coding bit starts about 1/2 way through.
HTH
Did you enable the upload by adding the following property in the application.properties file?
## MULTIPART (MultipartProperties)
# Enable multipart uploads
spring.servlet.multipart.enabled=true
I have written an article about how to upload a multipart file in spring boot using thymeleaf. Here is the service used for the upload.
package com.uploadMultipartfile.storage;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Service;
import org.springframework.util.StringUtils;
import org.springframework.web.multipart.MultipartFile;
import java.io.IOException;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;
import java.nio.file.StandardCopyOption;
#Service
public class FileSystemStorageService implements StorageService
{
private final Path rootLocation;
#Autowired
public FileSystemStorageService(StorageProperties properties) {
this.rootLocation = Paths.get(properties.getUploadDir()).toAbsolutePath().normalize();
try {
Files.createDirectories(this.rootLocation);
} catch (Exception ex) {
throw new StorageException("Could not create the directory where the uploaded files will be stored.", ex);
}
}
#Override
public String store(MultipartFile file)
{
// Normalize file name
String fileName = StringUtils.cleanPath(file.getOriginalFilename());
try
{
if (file.isEmpty())
{
throw new StorageException("Failed to store empty file " + file.getOriginalFilename());
}
// Copy file to the target location (Replacing existing file with the same name)
Path targetLocation = this.rootLocation.resolve(fileName);
Files.copy(file.getInputStream(), targetLocation, StandardCopyOption.REPLACE_EXISTING);
return fileName;
}
catch (IOException e)
{
throw new StorageException("Failed to store file " + file.getOriginalFilename(), e);
}
}
#Override
public void init()
{
try
{
Files.createDirectory(rootLocation);
}
catch (IOException e)
{
throw new StorageException("Could not initialize storage", e);
}
}
}
Here is a link to get the code of the application. http://mkaroune.e-monsite.com/pages/spring/spring-boot-multipart-file-upload.html
I'm implementing a web application using Spring MVC. I'm trying to implement the module that allows to upload images. I'm using Apache Commons FileUpload and this is the controller that handle the post request:
/**
* Upload single file using Spring Controller
*/
#RequestMapping(value = "/upload", method = RequestMethod.POST)
public String uploadFileHandler(#RequestParam("name") String name,
#RequestParam("file") MultipartFile file) {
if (!file.isEmpty()) {
String fileContentType = file.getContentType();
if (contentTypes.contains(fileContentType)) {
// You have the correct extension
// rest of your code here
try {
byte[] bytes = file.getBytes();
// Creating the directory to store file
String rootPath = System.getProperty("catalina.home");
File dir = new File(rootPath + File.separator + "bills");
if (!dir.exists())
dir.mkdirs();
// Create the file on server
File serverFile = new File(dir.getAbsolutePath()
+ File.separator + name);
BufferedOutputStream stream = new BufferedOutputStream(
new FileOutputStream(serverFile));
stream.write(bytes);
stream.close();
System.out.println("Server File Location="
+ serverFile.getAbsolutePath());
return "redirect:/";
} catch (Exception e) {
//TODO handle error
}
} else {
//TODO handle error
}
} else {
//TODO handle error
}
}
My first doubt is where should i save the images uploaded? Right now the directory is inside a GlassFish folder, is it ok? And I don't know why but the uploaded picture has no extension... is a simple file without any extension!
Now I want to let the user access these images but I don't know how to insert those inside the JSP page. I know that I should save the path inside the database relating it to a specified user but I don't know what to do next. Does anyone have any suggestions? Thank you very much!
About the way how to use uploaded images, I found this solution that seems working but I don't know if it's the best one or not. Inside the jsp file I have this:
<spring:url value="/file/download/" var="url"/>
<html>
<head>
<title>Title</title>
</head>
<body>
<img src="${url}${imageName}"/>
</body>
</html>
Where imageName is a value inside the model that contains, as the name clearly says, the name of the file, and url contains the path of the service that returns the stream of the image. This HTTP request is handled by the following controller:
public #ResponseBody byte[] getImageWithMediaType(#PathVariable("name") String name) throws IOException {
String rootPath = System.getProperty("catalina.home")
String partialPath = File.separator + "bills" + File.separator + name + ".png"
FileInputStream file = new FileInputStream(rootPath + partialPath);
InputStream is = new BufferedInputStream(file);
return IOUtils.toByteArray(is);
}
Do you think this is the best way to do so?
Why dont you use Spring Content? Then you don't need to implement any of that controller code at all. Assuming you are using Spring Boot (let me know if you are not) then it would look something like this:
pom.xml
<dependency>
<groupId>com.github.paulcwarren</groupId>
<artifactId>spring-content-rest-boot-starter</artifactId>
<version>0.0.10</version>
</dependency>
<dependency>
<groupId>com.github.paulcwarren</groupId>
<artifactId>content-fs-spring-boot-starter</artifactId>
<version>0.0.10</version>
</dependency>
SpringBootApplication.java
#SpringBootApplication
public class YourSpringBootApplication {
public static void main(String[] args) {
SpringApplication.run(YourSpringBootApplication.class, args);
}
#Configuration
#EnableFilesystemStores
public static class StoreConfig {
File filesystemRoot() {
String rootPath = System.getProperty("catalina.home");
File dir = new File(rootPath + File.separator + "bills");
if (!dir.exists())
dir.mkdirs();
}
// this bean is the spring resource loader that will be used by
// the product store
#Bean
public FileSystemResourceLoader fsResourceLoader() throws Exception
{
return new FileSystemResourceLoader(filesystemRoot().getAbsolutePath());
}
}
#StoreRestResource(path="upload")
public interface BillStore extends Store<String> {
//
}
}
Note that you are not writing any controller code here but this is enough to create a REST-based content service at /upload that actually supports full CRUD functionality (as well as video streaming in case that us useful to you). Create == POST, Read == GET (include byte-range support), Update == PUT, Delete == DELETE.
e.g.
POST /upload/my-image.jpg
will store the uploaded image to System.getProperty("catalina.home") + File.Separator + "bills" + "my-image/jpg".
I am assuming you want your users to eventually be able to view their images after upload, upload new versions and possibly delete as well. Given this /upload is probably not a great name. But it is what you used in the question so what I went with in my answer. IF you really do just want upload functionality then you can use Spring Security to make the other actions impossibly to perform.
I have Java Web Application using Spring Boot, I want to display in JSP page ,images which are in an extern folder (E:/images) in file system.
I looked too many pages in google,I found on stackoverflow a post that say I should write a servlet to get the image : am I missing something or should I do it with an other way , please give me more details I m kind of new to Spring. thanks for your help.
in my Controller :
#RequestMapping(value="/images",method = RequestMethod.GET)
public #ResponseBody void affichimage(#RequestParam("id") Integer Iddd,HttpServletResponse response,HttpServletRequest request) throws IOException
{
Annonce annonce=new Annonce();
annonce=annoncedao.findOne(Iddd); // get the right annonce from
//database
File imageFile = new File(annonce.getimage()); // in image I have
//the link to images ex : E:/images/image1.jpeg
response.setContentType("image/jpeg");
BufferedImage image = ImageIO.read(imageFile);
ImageIO.write(image, "image/jpeg", response.getOutputStream());
}
in JSP :
< img class="imagesaffichage" src="/images?id=${annonce.id}" alt="No image"/>
I also added this to my application :
public void addResourceHandlers(ResourceHandlerRegistry registry) {
registry.addResourceHandler("/resources/**")
.addResourceLocations("file:///E:/images/");
}
I found the solution , I had to change the above method :
#RequestMapping(value="/images",method = RequestMethod.GET)
public #ResponseBody void affichimage(#RequestParam("id") Integer
Iddd,HttpServletResponse response,HttpServletRequest request) throws
IOException,NullPointerException
{
Annonce annonce=new Annonce();
annonce=annoncedao.findOne(Iddd); // get the right annonce from
//database
File imageFile = new File(img);
response.setContentType("image/jpeg");
InputStream in=new FileInputStream(imageFile);
IOUtils.copy(in, response.getOutputStream());
}