Whenever we select rows the in jqGrid and perform search operation at the end search reloads the grid and all the user checked rows are unchecked .... I want the selected rows to be selected even after search perform or we go to next page.
Does anyone have solution on this?????? I need it URGENT
You should remember the selected rows before search and select them again after. For example, you define onSearch event:
var selected_rows = [];
onSearch: function(){
selected_rows = $('#your_grid').jqGrid('getGridParam', 'selarrrow');
}
Then you define gridComplete event, so that it would select the rows if any:
gridComplete: function(){
$.each(selected_rows, function(_, row_id){
$("#your_grid").jqGrid('setSelection', row_id, false);
});
selected_rows = [];
}
You can use onPaging event in similar way to deal with paging.
Related
I'm having a problem here:
When I select a radion button in a page 1 and another one in the same page it works fine, but when I select a radio button in the page number 2, and go back to the page number 1, that first radio button still selected and the one in the page number 2 is also selected, how can I solve this problem? I was looking for a solution here in the forum but couldn't find someone with the same problem.
*[code] $(document).ready(function () { var oTable = $('#example').dataTable({ "bJQueryUI": true, "sPaginationType": "full_numbers" }); }); [/code]*
There is no solution from DataTables itself. You'll have to do it on your own.
What you can do is save the selected value yourself on a click. Imagine you have a table called projectsTable. Then you can write:
var selection = -1;
$("#projectsTable input[type=radio]").on
(
"click",
function()
{
selection = $(this).val();
}
);
Then, you'll have to unselect all the wrong values every time the page changes. Add a callback in the construction of your table for page draw to do that:
//other settings go here, like the dom one
//you can choose your own, no need for this specific one
"dom": "lfBrtip",
"fnDrawCallback":
function(oSettings)
{
$("#projectsTable input[type=radio][value!="+selection+"]").prop('checked', false);
}
Every time the page is changed, this piece of code deselects everything you don't want to be selected any longer.
I am using Kendo UI grid without pagination. I have set the below code to load the data in the grid view while scrolling
scrollable: { virtual: true },
My problem is, I have selected 100th row in the grid by scrolling . I am refreshing the grid. After refresh, I need to select the 100th row again. Is it possible ?
Regards
Senthil
After refresh select the row you need as shown below
var grid = $("#grid").data("kendoGrid");
grid.select("tr:eq(100)");
For more info check out kendo DOC http://docs.telerik.com/kendo-ui/api/javascript/ui/grid#methods-select
Basically the question is annotate the row that you have selected when it changes to do so and then in dataBound event select that same row.
In order to save the selected row you can do:
change: function (e) {
// Save some information from the selected row
var item = this.dataItem(this.select());
// Here we save uid
var uid = item.uid;
this.selectedRow = uid;
},
dataBound: function (e) {
// If we have any row selected
if (this.selectedRow) {
// Use this.select for selecting it
this.select("tr[data-uid='" + this.selectedRow + "']");
}
}
You can see this here: http://jsfiddle.net/OnaBai/eLk7zkzs/
I have a two level jqGrid (grid/subgrid) implementation that works very fine.
Now I have a requirement that push me to implement a third level subgrid in only some of the second level rows.
Is there any way to exclude the opening of the third level if any condition on the row does not permit it?
Thanks very much
EDIT as per #Oleg answer
I have implemented the more complex logic example as in the referenced answer, that is
loadComplete: function() {
var grid = $("#list");
var subGridCells = $("td.sgcollapsed",grid[0]);
$.each(subGridCells,function(i,value){
[...]
var rowData = grid.getRowData( ??? );
});
}
Can I use any field to retrieve the rowData in the each loop?
If I understand your question correctly you can do the same like I described in the answer, but do this on the second level of subgrids. To hide "+" icon in some rows you need just execute .unbind("click").html(""); on "td.sgcollapsed" elements of the second level subgrids.
UPDATED: The demo demonstrate how you can get rowid and use getLocalRow (alternatively getRowData) to hide selective subgrid icons ("+" icons). I used the following loadComplete code in the demo:
loadComplete: function () {
var $grid = $(this);
$.each($grid.find(">tbody>tr.jqgrow>td.sgcollapsed"), function () {
var $tdSubgridButton = $(this),
rowid = $tdSubgridButton.closest("tr.jqgrow").attr("id"),
rowData = $grid.jqGrid("getLocalRow", rowid);
if (rowData.amount > 250 ) {
$tdSubgridButton.unbind("click").html("");
}
});
}
I am using a custom formatter to create hyperlinks in one of the columns of my grid.
In my code, there are cases when I need to disable the selected row. The row disabling works as I want it to, but the hyperlink for that row is not disabled. I can not select the row and all the other column values are displayed as grey colored to indicate that the row is disabled. The only column whose content does not change color is the one having links.
Any ideas on how to disable links?
This is my loadComplete function:
loadComplete: function (data) {
var ids =jQuery("#list").jqGrid('getDataIDs');
for(var i=0;i < ids.length;i++){
var rowId = ids[i];
var mod = jQuery("#list").jqGrid('getCell',ids[i],'mod');
if(mod=='y'){
jQuery("#jqg_list_"+rowId).attr("disabled", true);
$("#list").jqGrid('setRowData',ids[i],false, {weightfont:'bold',color:'silver'});
var iCol = getColumnIndexByName.call(this, 'adate');
$(this).jqGrid('doInEachRow', function (row, rowId, localRowData) {
$(row.cells[iCol]).children("a").click(function (e) {
e.preventDefault();
// any your code here
alert("No Good");
return false;
});
});
}
}
}
I want the links disabled in all the rows where the value of the column mod=y
You can try to use onClick callback of dynamicLink formatter described here, here and here. It gives you maximum flexibility. Inside of onClick callback you can test something like $(e.target).closest("tr.jqgrow").hasClass("not-editable-row") and just do nothing in the case.
Good morning, I'm working on a jqGrid that have the multiselection active.
I need to limit the selection of the row only using the multisel box, not by clicking everywhere on the row.
Thats's because I need to do some action by clicking links on some cells and I won't alter the active multiselection.
I tried to set the multiboxonly property, but it's not what I need.
I didn't find anything else to customize this function of the grid.
You can control on which click the row will be selected with respect of your custom beforeSelectRow event handler. If the handler return true, the row will be selected. If you return false the row will be not selected.
The second parameter of beforeSelectRow is event object, e.target is the DOM element which was clicked. You can get the cell (<td>) in which the click done with $(e.target).closest('td'). Then you can use $.jgrid.getCellIndex to get the index of the cell insido of the row. The index in the colModel should point to the 'cb' column which contain the checkboxes. So the code could be the following:
beforeSelectRow: function (rowid, e) {
var $myGrid = $(this),
i = $.jgrid.getCellIndex($(e.target).closest('td')[0]),
cm = $myGrid.jqGrid('getGridParam', 'colModel');
return (cm[i].name === 'cb');
}
The corresponding demo you can see here.
I would like to suggest easier solution:
beforeSelectRow: function(rowid, e) {
return $(e.target).is('input[type=checkbox]');
},
When multiselect is set to true, clicking anywhere on a row selects that row; when multiboxonly is also set to true, the multiselection is done only when the checkbox is clicked.
So the answer would be:
multiboxonly: true