How do I render a view after POSTing data via AJAX? - ajax

I've built an app that works, and uses forms to submit data. Once submitted, the view then redirects back to display the change. Cool. Django 101. Now, instead of using forms, I'm using Ajax to submit the data via a POST call. This successfully saves the data to the database.
Now, the difficult (or maybe not, just hard to find) part is whether or not it's possible to tell Django to add the new item that has been submitted (via Ajax) to the current page, without a page refresh. At the moment, my app saves the data, and the item shows up on the page after a refresh, but this obviously isn't the required result.
If possible, I'd like to use exactly the same view and templates I'm using at the moment - essentially I'd like to know if there's a way to replace a normal HTTP request (which causes page refresh) with an Ajax call, and get the same result (using jQuery). I've hacked away at this for most of today, so any help would be appreciated, before I pull all of my hair out.

I had a very similar issue and this is how I got it working...
in views.py
from django.utils import simplejson
...
ctx = {some data to be returned to the page}
if ajax == True:
return HttpResponse(simplejson.dumps(ctx), mimetype='json')
then in the javascript
jQuery.ajax({
target: '#id_to_be_updated',
type: "POST",
url: "/",
dataType: 'json',
contentType: "text/javascript; charset=\"utf-8\"",
data: {
'foo':foo,
'bar':bar,
},
success: function(data){
$("#id_to_be_updated").append(data.foo);
}
});

Here's how I did it:
The page that has the form includes the form like so
contact.html
{% include "contact_form.html" %}
This way it's reusable.
Next I setup my view code (this view code assumes the contact form needs to be save to the db, hence the CreateView):
class ContactView(CreateView):
http_method_names = ['post']
template_name = "contact_form.html"
form_class = ContactForm
success_url = "contact_form_succes.html"
There are a few things to note here,
This view only accepts pots methods, because the form will be received through the contact.html page. For this view I've setup another template which is what we included in contact.html, the bare form.
contact_form.html
<form method="POST" action="/contact">{% crsf_token %}
{{ form.as_p }}
</form>
Now add the javascript to the contact.html page:
$("body").on("submit", 'form', function(event) {
event.preventDefault();
$("#contact").load($(this).attr("action"),
$(this).serializeArray(),
function(responseText, responseStatus) {
// response callback
});
});
This POSTS the form to the ContactView and replaces whatever is in between #contact, which is our form. You could not use jquery's .load function to achieve some what more fancy replacement of the html.
This code is based on an existing working project, but slightly modified to make explaining what happens easier.

Related

Refresh form in Django without reloading page

Hi I'm new in Ajax and django and I want to refresh my form. I try some code but it didn't work. I'm sure what I want to do is very basic.
Here my html:
<div class="row" style="padding-top:20px;">
<div class="col-md-12" id="testAjax">
{% load crispy_forms_tags %}
{% crispy form %}
</div>
</div>
I want to refresh my form in the div testAjax.
Here my view:
def createPin(request):
error = False
if request.method == "POST":
form = CreatePinForm(request.POST)
if form.is_valid():
pin = form.save(commit=False)
pin.customer = request.user.customer
pin.save()
msg = "pin saved"
return redirect('/pin/CreatePin', {'form': form, 'msg': msg})
else:
error = True
else:
form = CreatePinForm()
return render(request, 'createPin.html', {'form': form, 'error': error,})
My Ajax:
function refresh()
{
$form=$('#createPin');
var datastring = $form.serialize();
$.ajax({
type: "POST",
url: '/pin/CreatePin/',
dataType: 'html',
data: datastring,
success: function(result)
{
/* The div contains now the updated form */
$('#testAjax').html(result);
}
});
}
Thanks alot for your help.
When I need to do some operations and I don't want to reload the page I use a JQuery call to Ajax, I make the pertinent operations in AJAX and then receive the AJAX response in the JQuery function without leaving or reloading the page. I'll make an easy example here for you to understand the basics of this:
JQuery function, placed in the template you need
function form_post(){
//You have to get in this code the values you need to work with, for example:
var datastring = $form.serialize();
$.ajax({ //Call ajax function sending the option loaded
url: "/ajax_url/", //This is the url of the ajax view where you make the search
type: 'POST',
data: datastring,
success: function(response) {
result = JSON.parse(response); // Get the results sended from ajax to here
if (result.error) { // If the function fails
// Error
alert(result.error_text);
} else { // Success
//Here do whatever you need with the result;
}
}
}
});
}
You have to realize that I cannot finish the code without knowing what kind of results you're getting or how do you want to display them, so you need to retouch this code on your needs.
AJAX function called by JQuery
Remember you need to add an url for this Ajax function in your urls.py something like:
url(r'^/ajax_url/?$', 'your_project.ajax.ajax_view', name='ajax_view'),
Then your AJAX function, it's like a normal Django View, but add this function into ajax.py from django.core.context_processors import csrf from django.views.decorators.csrf import csrf_exempt from django.utils import simplejson
#csrf_exempt
def ajax_view(request):
response = []
#Here you have to enter code here
#to receive the data (datastring) you send here by POST
#Do the operations you need with the form information
#Add the data you need to send back to a list/dictionary like response
#And return it to the JQuery function `enter code here`(simplejson.dumps is to convert to JSON)
return HttpResponse(simplejson.dumps(response))
So, without leaving the page you receive via javascript a list of items that you sended from ajax view.
So you can update the form, or any tag you need using JQuery
I know that this can be so confusing at the beginning but once you are used to AJAX this kind of operations without leaving or reloading the page are easy to do.
The basics for understanding is something like:
JQuery function called on click or any event you need
JQuery get some values on the template and send them to AJAX via
POST
Receive that information in AJAX via POST
Do whatever you need in AJAX like a normal DJango view
Convert your result to JSON and send back to the JQuery function
JQuery function receive the results from AJAX and you can do
whatever you need

Prestashop: How to submit data from adminpanel template to Admin Controller?

I'm trying to make a custom page in the adminpanel of Prestashop where the shopowner can fill in his upcoming events that will appear in a column in the header.tpl page. The templates and controller are working so far, with a structure based on an answer here at Stack Overflow:
How to create a new page in prestashop admin panel?
Now I have made in the content.tpl (with the added custom JavaScript and CSS files) the form with the input fields. The next step is to send it to the controller to save it in the database. But I'm stuck this part. I can't find how I can nicely submit the form to the controller. First I tried it with an Ajax function but I couldn't find the right way. Also without Ajax no success.
$.ajax({
type: 'POST',
headers: { "cache-control": "no-cache" },
url: baseUri + '?rand=' + new Date().getTime(),
async: true,
cache: false,
dataType : "json",
data:{
processEvents: true,
ajax: 'true',
controller: 'AdminEvents',
token: static_token
},
//success: function(jsonData){
//}
});
This is an example of an Ajax function that I tried. My questions:
How does other tpl or js files receive the baseUri, where is that
variable set?
What is the function of the ?rand date and time in that line? A kind
of security token?
What is the url of the controller? Also the url when I use
I guess the processEvents : true and Ajax : true is for security
reasons and to check if the form is submitted by Ajax or not?
Why is it necessary to send the controller name?
Where does the token come from?
Questions about the controller:
Which (Prestashop default functions) can or do need to use? For
example:
if (Tools::isSubmit('name')){
etc.
if (Tools::getValue('create_account')){
etc.
Can I use that functions anywhere or maybe only in an Init function?
A lot of questions, feel free to answer only a part of it, I just need a good push in the right direction, searching and reading in the online documentation and on the internet doesn't brought me the solution and brainwashed me a little.
EDIT:
I made a little progress by myself:
Where does the token come from?
What is the url of the controller? Also the url when I use
With the tools getAdminTokenLite and the controller name I generated the controller url:
$token = '?controller=AdminEvents&token='.Tools::getAdminTokenLite('AdminEvents');
The url to post to is the token plus the domain, admin directory and index.php.
With the tool getValue I get the POST data like in PHP with $_POST["name"].
Tools::getValue('event_name')
So its working but I guess it can be better with other Presta default tools.
I know that it's very late to answer you, but for sure it will help other mates with same problem.
Here is an example about how to implement ajax calls in Prestashop 1.6 on Admin panel using ANY Controller from BackOffice (if you want also, you can use ajax.php controller, but I'm using for this AdminImportController() )
tpl part:
$('#mybtn').click(function(e) {
var data = $('#datalist').val();
// Ajax call with secure token
$.post( "{$current|escape:'html':'UTF-8'}&token= {$token|escape:'html':'UTF-8'}",
{ ajax: true, action: "MyFunction", mydata: data } );
  });
And in admin controller side:
public function ajaxProcessMyFunction()
{
// Get param
$mydata = (int)Tools::getValue('mydata');
$answer = 0;
if( $mydata > 0 ) {
$this->importProfList = Db::getInstance()->executeS(
"SELECT * FROM .... LIMIT 1"
);
...
$answer = $someOperationResult;
}
// Response
die(Tools::jsonEncode(array(
'answer' => htmlspecialchars($answer)
)));
}
Tested and working like a charm.
Regards

What else can I pass to the `form` property of Ext.Ajax.request?

Normally one posts an ExtJS form to the backend using form.submit({...}). I want to make my form submission synchronous now, so I'm switching to using Ext.Ajax.request({async: false, ...}). The form property of Ext.Ajax.request() usually looks like so:
Ext.Ajax.request({
url: 'formsubmit',
form: 'formid',
method:'POST',
success: function(response, opts) {
alert("successfull");
},
failure:function(res,opt) {
alert("request failed");
}
});
I'm dealing with a bunch of anonymous forms right now. Is there any way around this?
Given a var form = {xtype: 'form', items: [...]}
I've tried replacing 'formid' with form.getEl(), form.getForm(), and form.getForm().getFieldValues() which all don't work.
There's no other way around this other than assigning a generated id to each of my anonymous forms, is there.
Thanks for any input
It looks like you could just do this as an alternative to the form attribute:
var form = this.down('form');
Ext.Ajax.request({
url: 'test.xyz',
params: form.getValues()
// etc...
});
getValues gives you the name/value pairs you need for your submission.
It looks like the ExtJS forms do not actually use form elements in the markup. When the submit function is called on an ExtJS form, an HTML form element is crafted as part of the process, and that's the form that is used for the submission.
http://docs.sencha.com/extjs/4.2.1/#!/api/Ext.form.action.Submit-method-buildForm
Ideally, you could modify the options that are used in the Ajax request called within the doSubmit function. Since you can't, you might want to consider overriding Ext.form.action.Submit such that you can, then calling the form.submit() function you mentioned in your question.
http://docs.sencha.com/extjs/4.2.1/#!/api/Ext.form.action.Submit-method-doSubmit

Send form to server in jquery

I am learning ASP.NET MVC. I have to submit a to controller side after validation in client-side(in jquery). How this can be done? Should i use <form action="#" method="post"> instead of <form action="Controller/Method" method="post"> and add an event handler in click event of submit button of , to send via ajax etc? What should i do? pls help
You are on the right track, and what you suggested will work.
A better method would be to leave the original action intact, providing backwards compatibility to older browsers. You would then create the event handler as normal, and include code to prevent the default submit behavior, and use ajax instead.
$('#submitbutton').live('click', function(e){ e.preventDefault(); });
The easiest way to do this is to use the jQuery forms plugin.
This is my go-to plugin for this type of thing. Basically it will take your existing form, action url etc and convert the submission to an ajax call automatically. From the website:
The jQuery Form Plugin allows you to easily and unobtrusively upgrade
HTML forms to use AJAX. The main methods, ajaxForm and ajaxSubmit,
gather information from the form element to determine how to manage
the submit process. Both of these methods support numerous options
which allows you to have full control over how the data is submitted.
It is extremely useful for sites hosted in low cost web hosting
providers with limited features and functionality. Submitting a form
with AJAX doesn't get any easier than this!
It will also degrade gracefully if, for some reason, javascript is disabled. Take a look at the website, there are a bunch of clear examples and demos.
This is how I do:
In jQuery:
$('document').ready(function() {
$('input[name=submit]').click(function(e) {
url = 'the link';
var dataToBeSent = $("form#myForm").serialize();
$.ajax({
url : url,
data : dataToBeSent,
success : function(response) {
alert('Success');
},
error : function(request, textStatus, errorThrown) {
alert('Something bad happened');
}
});
e.preventDefault();
});
In the other page I get the variables and process them. My form is
<form name = "myForm" method = "post">//AJAX does the calling part so action is not needed.
<input type = "text" name = "fname"/>
<input type= "submit" name = "submit"/>
<FORM>
In the action page have something like this
name = Request.QueryString("fname")
UPDATE: As one of your comment in David's post, you are not sure how to send values of the form. Try the below function you will get a clear idea how this code works. serialize() method does the trick.
$('input[name=submit]').click(function(e){
var dataToBeSent = $("form#myForm").serialize();
alert(dataToBeSent);
e.preventDefault();
})

Django API Requests

I'm trying to access another service's API, using my model's fields as the keywords in the API request. The URL would be like like so:
http://api.example.com/json/?first_name=FNAME&last_name=LNAME&key={key}
Here's my code from views.py:
class ExamplePersonView(ListView):
context_object_name = "example_person"
template_name = "templates/example_person.html"
def get_queryset(self):
lname = get_object_or_404(ExamplePeople, lname__iexact=self.args[0])
return ExamplePeople.objects.filter(lname=lname)
From what I understand, I'll need to use AJAX to communicate between my page template and my views.py to send the request and then present the information on the page.
I've found several Django apps that make it easy to turn your models into a public API, but none that help you access API's from another service. Does anyone know of an app like that?
If not, does anyone have a good understanding of using AJAX with Django to make the request and present it in the template?
There's several ways to communicate with a "foreign" API. There's no necessity for ajax. Ajax is just for making background calls in a template, triggering whatever event you have in mind.
But let's say you want to communicate with the facebook GraphAPI to retrieve a profile
http://graph.facebook.com/bill.clinton
The standard result is serialized as JSON, which implements easily into AJAX or any JavaScript library, hence the name JavaScript Object Notation.
So an example with AJAX might be:
function callFacebook() {
$.ajax({
type: "GET",
data: ({}),
dataType: 'json',
url: "http://graph.facebook.com/bill.clinton",
success: function(data){
alert("Hi I am former "+data.name);
}
});
}
callFacebook();
Include this in your javascript file or within your template between script tags and you should get a nice alert message:
Hi I am former President Bill Clinton
Now you could turn this alert into something more meaningful, and put it within a h1 tag (not sure why this is meaningful)
$("body").html("<h1>"+data.name+"</h1>");
But sometimes you would want to retrieve data and do something with it server side in your application.
So create a django urlpattern and view, e.g.:
from urllib2 import urlopen
from django.http import HttpResponse
from django.utils import simplejson
def call_bill(request):
url = "http://graph.facebook.com/bill.clinton"
json = urlopen(url).read()
# do whatever you want
return HttpResponse(simplejson.dumps(json), mimetype="application/json")
# add this to your url patterns
url("^call_bill_clinton/$", call_bill)
Now visit your url
As a logic result, it's also perfectly possible to trigger async events by some user action. Eg the URL parameter in the previously mentioned ajax example, could also be a django url like "/call_bill_clinton/".
<!-- add a button to call the function -->
<button onclick="callFacebook();">Call Bill</button>
function callFacebook() {
$.ajax({
type: "GET",
data: ({}),
dataType: 'json',
url: "/call_bill_clinton/",
success: function(data){
alert("Hi I am former "+data.name+" and I came from Django");
}
});
)
// remove the auto call
Furthermore ajax calls let you do the same trickery as http requests, you can use a variety of request methods combined with cool javascript events, like a beforeSend event
beforeSend: function() {
$('#loading').show();
},
Where the #loading could be something like:
<div id="loading" style="display:none;">
<img src="{% static "images/loading.gif" %}" />
</div>

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