Normally one posts an ExtJS form to the backend using form.submit({...}). I want to make my form submission synchronous now, so I'm switching to using Ext.Ajax.request({async: false, ...}). The form property of Ext.Ajax.request() usually looks like so:
Ext.Ajax.request({
url: 'formsubmit',
form: 'formid',
method:'POST',
success: function(response, opts) {
alert("successfull");
},
failure:function(res,opt) {
alert("request failed");
}
});
I'm dealing with a bunch of anonymous forms right now. Is there any way around this?
Given a var form = {xtype: 'form', items: [...]}
I've tried replacing 'formid' with form.getEl(), form.getForm(), and form.getForm().getFieldValues() which all don't work.
There's no other way around this other than assigning a generated id to each of my anonymous forms, is there.
Thanks for any input
It looks like you could just do this as an alternative to the form attribute:
var form = this.down('form');
Ext.Ajax.request({
url: 'test.xyz',
params: form.getValues()
// etc...
});
getValues gives you the name/value pairs you need for your submission.
It looks like the ExtJS forms do not actually use form elements in the markup. When the submit function is called on an ExtJS form, an HTML form element is crafted as part of the process, and that's the form that is used for the submission.
http://docs.sencha.com/extjs/4.2.1/#!/api/Ext.form.action.Submit-method-buildForm
Ideally, you could modify the options that are used in the Ajax request called within the doSubmit function. Since you can't, you might want to consider overriding Ext.form.action.Submit such that you can, then calling the form.submit() function you mentioned in your question.
http://docs.sencha.com/extjs/4.2.1/#!/api/Ext.form.action.Submit-method-doSubmit
Related
I am learning ASP.NET MVC. I have to submit a to controller side after validation in client-side(in jquery). How this can be done? Should i use <form action="#" method="post"> instead of <form action="Controller/Method" method="post"> and add an event handler in click event of submit button of , to send via ajax etc? What should i do? pls help
You are on the right track, and what you suggested will work.
A better method would be to leave the original action intact, providing backwards compatibility to older browsers. You would then create the event handler as normal, and include code to prevent the default submit behavior, and use ajax instead.
$('#submitbutton').live('click', function(e){ e.preventDefault(); });
The easiest way to do this is to use the jQuery forms plugin.
This is my go-to plugin for this type of thing. Basically it will take your existing form, action url etc and convert the submission to an ajax call automatically. From the website:
The jQuery Form Plugin allows you to easily and unobtrusively upgrade
HTML forms to use AJAX. The main methods, ajaxForm and ajaxSubmit,
gather information from the form element to determine how to manage
the submit process. Both of these methods support numerous options
which allows you to have full control over how the data is submitted.
It is extremely useful for sites hosted in low cost web hosting
providers with limited features and functionality. Submitting a form
with AJAX doesn't get any easier than this!
It will also degrade gracefully if, for some reason, javascript is disabled. Take a look at the website, there are a bunch of clear examples and demos.
This is how I do:
In jQuery:
$('document').ready(function() {
$('input[name=submit]').click(function(e) {
url = 'the link';
var dataToBeSent = $("form#myForm").serialize();
$.ajax({
url : url,
data : dataToBeSent,
success : function(response) {
alert('Success');
},
error : function(request, textStatus, errorThrown) {
alert('Something bad happened');
}
});
e.preventDefault();
});
In the other page I get the variables and process them. My form is
<form name = "myForm" method = "post">//AJAX does the calling part so action is not needed.
<input type = "text" name = "fname"/>
<input type= "submit" name = "submit"/>
<FORM>
In the action page have something like this
name = Request.QueryString("fname")
UPDATE: As one of your comment in David's post, you are not sure how to send values of the form. Try the below function you will get a clear idea how this code works. serialize() method does the trick.
$('input[name=submit]').click(function(e){
var dataToBeSent = $("form#myForm").serialize();
alert(dataToBeSent);
e.preventDefault();
})
I've built an app that works, and uses forms to submit data. Once submitted, the view then redirects back to display the change. Cool. Django 101. Now, instead of using forms, I'm using Ajax to submit the data via a POST call. This successfully saves the data to the database.
Now, the difficult (or maybe not, just hard to find) part is whether or not it's possible to tell Django to add the new item that has been submitted (via Ajax) to the current page, without a page refresh. At the moment, my app saves the data, and the item shows up on the page after a refresh, but this obviously isn't the required result.
If possible, I'd like to use exactly the same view and templates I'm using at the moment - essentially I'd like to know if there's a way to replace a normal HTTP request (which causes page refresh) with an Ajax call, and get the same result (using jQuery). I've hacked away at this for most of today, so any help would be appreciated, before I pull all of my hair out.
I had a very similar issue and this is how I got it working...
in views.py
from django.utils import simplejson
...
ctx = {some data to be returned to the page}
if ajax == True:
return HttpResponse(simplejson.dumps(ctx), mimetype='json')
then in the javascript
jQuery.ajax({
target: '#id_to_be_updated',
type: "POST",
url: "/",
dataType: 'json',
contentType: "text/javascript; charset=\"utf-8\"",
data: {
'foo':foo,
'bar':bar,
},
success: function(data){
$("#id_to_be_updated").append(data.foo);
}
});
Here's how I did it:
The page that has the form includes the form like so
contact.html
{% include "contact_form.html" %}
This way it's reusable.
Next I setup my view code (this view code assumes the contact form needs to be save to the db, hence the CreateView):
class ContactView(CreateView):
http_method_names = ['post']
template_name = "contact_form.html"
form_class = ContactForm
success_url = "contact_form_succes.html"
There are a few things to note here,
This view only accepts pots methods, because the form will be received through the contact.html page. For this view I've setup another template which is what we included in contact.html, the bare form.
contact_form.html
<form method="POST" action="/contact">{% crsf_token %}
{{ form.as_p }}
</form>
Now add the javascript to the contact.html page:
$("body").on("submit", 'form', function(event) {
event.preventDefault();
$("#contact").load($(this).attr("action"),
$(this).serializeArray(),
function(responseText, responseStatus) {
// response callback
});
});
This POSTS the form to the ContactView and replaces whatever is in between #contact, which is our form. You could not use jquery's .load function to achieve some what more fancy replacement of the html.
This code is based on an existing working project, but slightly modified to make explaining what happens easier.
I have a form in Magento that I build in code, and that works with ajax, which I need to validate.
I would like to be able to use Magento's built-in validation functionality, but I don't know how I would trigger it since the form is not submitted. The data is retrieved via ajax and outputted in a list below the form.
Is there someone who can point me in the right direction?
Thanks in advance.
Edit:
This is the javascript code used to hande the ajax request. Its called by the onclick event of the button.
function advancedtranslateSearch(url){
new Ajax.Request(url, {
method: 'get',
parameters: $('search_form').serialize(),
onSuccess: function(transport) {
json = transport.responseText.evalJSON();
$('result').update('<div class="hor-scroll">'+json.records+'</div>');
}
});
}
You should use form's onsubmit event.
To prevent page from reloading you must return false value from your function.
I have a form that looks like this:
<form name="formi" method="post" action="http://domain.name/folder/UserSignUp?f=111222&postMethod=HTML&m=0&j=MAS2" style="display:none">
...
<button type="submit" class="moreinfo-send moreinfo-button" tabindex="1006">Subscribe</button>
In the script file I have this code segment where I submit the datas, while in a modal box I say thank you for the subscribers after they passed the validation.
function () {
$.ajax({
url: 'data/moreinfo.php',
data: $('#moreinfo-container form').serialize() + '&action=send',
type: 'post',
cache: false,
dataType: 'html',
success: function (data) {
$('#moreinfo-container .moreinfo-loading').fadeOut(200, function () {
$('form[name=formi]').submit();
$('#moreinfo-container .moreinfo-title').html('Thank you!');
msg.html(data).fadeIn(200);
});
},
Unfortunately, after I submit the datas, I'm navigated to the domain given in the form's action. I tried to insert return false; in the code (first into the form tag, then into the js code) but then the datas were not inserted into the database. What do I need to do if I just want to post the data and stay on my site and give my own feedback.
I edited Eric Martin's SimpleModal Contact Form, so if more code would be necessary to solve my problem, you can check the original here: http://www.ericmmartin.com/projects/simplemodal-demos/ (Contact Form)
Usually returning false is enough to prevent form submission, so double check your code. It should be something like this
$('form[name="formi"]').submit(function() {
$.ajax(...); // do your ajax call here
return false; // this prevent form submission
});
Update
Here is the full answer to your comment
I tried this, but it didn't work. I need to submit the data in the succes part, no?
Maybe, it depends from your logic and your exact needs. Normally to do what you asking for I use the jQuery Form Plugin which handle this kind of behavior pretty well.
From your comment I see that you're not submitting the form itself with the $.ajax call, but you retrieve some kind of data from that call, isn't it? Then you have two choices here:
With plain jQuery (no form plugin)
$('form[name="formi"]').submit(function() {
$.ajax(...); // your existing ajax call
// this will post the form using ajax
$.post($(this).attr('action'), { /* pass here form data */ }, function(data) {
// here you have server response from form submission in data
})
// this prevent form submission
return false;
});
With form plugin it's the same, but you don't have to handle form data retrieval (the commented part above) and return false, because the plugin handle this for you. The code would be
$(document).ready(function() {
// bind 'myForm' and provide a simple callback function
$(form[name="formi"]).ajaxForm(function() {
// this call back is executed when the form is submitted with success
$.ajax(...); // your existing ajax call
});
});
That's it. Keep in mind that with the above code your existing ajax call will be executed after the form submission. So if this is a problem for your needs, you should change the code above and use the alternative ajaxForm call which accepts an options object. So the above code could be rewritten as
$(document).ready(function() {
// bind 'myForm' and provide a simple callback function
$(form[name="formi"]).ajaxForm({
beforeSubmit: function() { $.ajax(...); /* your existing ajax call */},
success: function(data) { /* handle form success here if you need that */ }
});
});
On a fansite im doing http://yamikowebs.com/ee/
I have a few forms (2 atm). I used $.post to find out what form is being submited. submit the form and display that pages results where the form was originally with .html().
My next step was to use the validator which is working fine but im not sure how to put the 2 together.
submitHandler: function(form){} seems to be the setting for how its submitted. However, I can't get this to work with my $.post function or find out what form is being processed.
If I leave the defaults for validation plug-in if there no errors it will send you to the page. the ajax plug-in that it works with doesn't do what I want. Below is my $.post function
form validation:
//ajax post
$("form").submit(function(event)
{
event.preventDefault();//stop from submiting
//set needed variables
var $form = $(this)
var $div = $form.parent("div")
$url = $form.attr("action");
//submit via post and put results in div
$.post( $url, $form.serialize() , function(data)
{ $div.html(data) })
})
http://docs.jquery.com/Plugins/validation#source is the validation plugin
You're correct in thinking that submitHandler is the right callback to use. However, I ran into some interesting issues while using it with multiple forms (like you're trying to do). For example, in this code:
$("#form1, #form2").validate({
submitHandler: function(form) {
alert(form.action);
alert(form.id);
}
});
The submitHandler callback does not get supplied the correct parameter (it always gets #form1). I believe this is actually a bug in jQuery-validate (so I've filed it here).
Anyway, a decent workaround would be to wrap the validate call in .each():
$("form").each(function() {
$(this).validate({
submitHandler: function(form) {
/* 'form' has the correct value */
var values = $(form).serialize(),
$div = $(form).parent("div");
alert(form.action);
alert(form.id);
/* Perform AJAX call here */
}
});
});
Example: http://jsfiddle.net/andrewwhitaker/MmCXN/