Im not sure if this is the right approach to do this. In my searchs only found multiple partial views and one submit button but not in a layout.
I have tree different views each with their own model with the same _ViewStart.cshtml -> _Layout.cshtml (MVC convention). This is the control for the first one:
[Authorize]
public ActionResult UpDateData1 ()
{
return View();
}
[HttpPost]
public ActionResult UpDateData1(Data1Model model)
{
if (ModelState.IsValid)
{
SOME CODE…
}
else
{
ModelState.AddModelError…
}
return View(model);
The 3 views are pretty generics, but I don't want a submit button in there.
Also in _Layout.cshtml I have a partial view with common validation code for the 3 views:
<section id="main">
#RenderBody()
<div>
#Html.Partial("_CommonValidation ", new store.Models.CommonValidation())
</div>
<div>
<input type="submit" value="Only one Button" />
</div>
<div>
#Html.ActionLink("BackTo…", "MyAccountConfig", "Account")
</div>
</section>
I don’t want a submit button in _CommonValidation view neither.
It is possible to use "ONLY ONE BUTTON” submit button in the Layout.cshtml to validate the models of the partial _CommonValidation and the RenderBody() views ? it is a good practice to include strongly typed partial views in the _Layout.cshtml view? I'm new to MVC 3 so I don’t have any idea what direction to take… JavaScripts, HTML Helpers maybe...
Thanks
Related
I have a main Index view from which I call view called Create, into which I pass type of the widget I want to create as a string.
Index view:
<i class="fa fa-image"></i> Create Image Widget -
<i class="fa fa-file-text"></i> Create Text Widget
Create Action:
public ActionResult Create(string wType)
{
ViewBag.wType = wType;
return View();
}
the type is then passed into view via ViewBag.wType and this is evaluated in the Create View
Create view:
#using (Html.BeginForm())
{
<section class="row">
#{
if (ViewBag.wType == "image")
{
Html.RenderPartial("~/Views/WidgetEditor/_CreateImageWidget.cshtml");
}
else if (ViewBag.wType == "text")
{
Html.RenderPartial("~/Views/WidgetEditor/_CreateTextWidget.cshtml");
}
}
</section>
}
and depending on this, appropriate partial view is loaded.
Partial views have different models so when the form is submitted, I do not know how which model is passed back. The one from _CreateImageWidget or _CreateTextWidget.
If the HttpPost controller look like this
[HttpPost]
public ActionResult Create(DisplayWidgetImageViewModel imageModel, DisplayWidgetTextViewModel textModel)
{
return new ViewResult();
}
I will get populated imageModel if _CreateImageWidget partial is chosen and textMode if _CreateTextWidget partial is chosen.
This is acceptable it the number of widgets types does not change, but this is not the case.
Is there a way to get somehow specific model from a partial view and know/find out which one it is or am I doing this completely wrong way?
You can create multiple forms in single page. You can also use different action methods per partial:
#using (Html.BeginForm("Action", "Controller")) {
Html.RenderPartial("~/Views/WidgetEditor/_CreateImageWidget.cshtml")
}
You all this without having to use Ajax.
I have used this answer to solve my problem: determine-the-model-of-a-partial-view-from-the-controller-within-mvc
there are also several other link with more resources.
i wish to change the inner html of a view on button click but maintain the view. I know how to change the html content of a div in javascript, but how can I have the action of the button not return a different view?
My buton looks like
<input type="submit" value="submit" onchange="myfunc()"/>
where myfunc() is the function in Javascript changing the div content.
Assuming you want a link to render content using ajax (and hopefully using razor) you can do something like the following:
First, setup the action to render the content partially. this can be done a few ways, but I'll keep with the logic in the action (and make it callable directly or by ajax):
[HttpPost]
public ActionResult Save(SomeModel model)
{
/* build view */
return Request.IsAjaxRequest() ? PartialView(model) : Wiew(model);
}
Next, setup a container in your page where the content will be populated along with the form you're looking to submit. If you want the form to disappear on a save, wrap it in the container. Otherwise, keep the container separated. In the below example, the from will submit and on success it'll come back, otherwise the new content will appear in its place:
<div id="ajaxContentPlaceholder">
#using (Ajax.BeginForm("Save", new AjaxOptions { UpdateTargetId = "ajaxContentPlaceholder" })) {
<!-- form elements -->
<input type="submit" value="save" />
}
</div>
In my page there is one textbox by default and one add button beside it. I need to add the another textbox when user click Add button. And there should be two buttons Add and Remove beside newly added text box. And same process goes on i.e., user can add Textbox using Add button and remove it using remove button.
I am new to mvc 3 so i am confused how to proceed. Is there any way like placeholder in asp.net so that we can add control at runtime.
Any suggestion and idea will be helpful to me
MVC is a very "hands-off" framework compared to Web Forms, so you're free to add the new textboxes how you like. Note that "controls" don't exist in MVC.
Here's how I'd do it:
Model:
class MyModel {
public Boolean AddNewTextBox { get; set; }
public List<String> MultipleTextBoxes { get; set; } // this stores the values of the textboxes.
}
View (I prefer the Web Forms view engine, I'm not a fan of Razor):
<% for(int i=0;i<Model.MultipleTextBoxes.Count;i++) { %>
<%= Html.TextBoxFor( m => m.MultipleTextBoxes[i] ) /* this might look like magic to you... */ %>
<% } %>
<button type="submit" name="AddNewTextbox" value="true">Add New Textbox</button>
<button type="submit">Submit form</button>
Controller:
[HttpPost]
public ActionResult MyAction(MyModel model) {
if( model.AddNewTextBox ) model.MultipleTextBoxes.Add("Yet another");
else if( ModelState.IsValid ) {
// your regular processing
}
}
You can also add more textboxes with Javascript and it work perfectly fine. All that matters is the HTML input elements. There's no cryptic viewstate. MVC is stateless.
Note that because I used <button type="submit"> my example will not work reliably in Internet Explorer 6-8 (sucks, I know), but you can replace them with <input type="submit"> with no ill-effects.
This requires some Javascript/JQuery... The following is a sketch only, but will hopefully be useful as a general approach.
The remove button
You want to render a button that can target its own container for removal. To do that, use some markup like this:
<div class="item-container">
<input type="button" onclick="removeItem(this)" />
</div>
And the Javascript for removeItem:
<script>
function removeItem(element) {
// get the parent element with class "item-container" and remove it from the DOM
$(element).find(".item-container").remove();
}
</script>
The add button
You could either use a partial view with Ajax, or use straight Javascript; which one is best likely depends on whether you need a round-trip to the server to create a new item. Let's say you need to go the the server to generate a new ID or something.
First, create a partial view and corresponding controller action; this should contain the remove button as above, as well as the text box and add button.
Now, create an Ajax form on your main page that gets invoked when you click Add:
<script src="#Url.Content("~/Scripts/jquery.unobtrusive-ajax.min.js")" type="text/javascript"></script>
#using (Ajax.BeginForm("New", new AjaxOptions() { UpdateTargetId="ajaxTarget", HttpMethod = "GET" })) {
<input type='submit' value='Add New' />
}
<div id="ajaxTarget"></div>
This code fetches your partial view (from the action New in the current controller) and adds the result to the ajaxTarget element.
Note The Ajax form requires Unobtrusive Ajax, which you can install via Nuget: Install-Package JQuery.Ajax.Unobtrusive.
I'm new to MVC (MVC3) so not sure about the best way to implement this.
I want to create a single "main" view (not strongly-typed). This "main" view will contain multiple strongly-typed partial views that each contain a form. Each partial view will therefore post back to their own POST action that does whatever. The problem I see is that when a partial view posts back, it needs to only update the partial view itself and not affect the other partial views on the page.
When I postback from a partial view now, it just returns the partial view alone back, rather than the entire "main" page.
How can this functionality be achieved in MVC3? (from a high-level perspective)
Thanks
You can post data by AJAX.
In my example I use jQuery:
<div id="first-form" class="form-container">
#Html.Partial("FirstPartial")
</div>
<div id="second-form" class="form-container">
#Html.Partial("SecondPartial")
</div>
// and here go rest forms
Your partial view may be following:
#model YourModelClass
#using (Html.BeginForm())
{
// some fields go there
}
<input type="button" value="Save Form Data" class="save-button"/>
Js would be following:
$("input.save-button").on("click", function () {
var button = $(this);
var container = button.closest("div.form-container");
var url = container.find("form").attr("action");
container.busy($.post(url, function (response) {
container.html(response);
}));
return false;
});
My site has a concept like Skype that allow users to go "Online" and "Offline". I created a partial view that allows the user to switch mode:
#if (Convert.ToBoolean(ViewData["IsLogged"].ToString()))
{
<div id="onlineStatus">
You are currently <strong>ONLINE</strong> >>
#Html.ActionLink("Go OFFLINE", "GoOffline", "Account")
</div>
}
else
{
<div id="offlineStatus">
Ready for business >>
#Html.ActionLink("Go ONLINE", "GoOnline", "Account")
</div>
}
This is how we load the Partial View:
public ActionResult OnlineStatusCtrl()
{
if (SiteUser.IsAuthenticated)
ViewData["IsLogged"] = SiteUser.IsOnline.ToString();
return PartialView("OnlineStatusCtrl");
}
When a user clicks on the link "Go ONLINE" or "Go OFFLINE", the Controller respond as:
public ActionResult GoOnline()
{
if (SiteUser.IsAuthenticated)
SiteUser.GoOnline();
ViewData["IsLogged"] = "True";
return RedirectToAction("Index", "Home");
//return PartialView("OnlineStatusCtrl");
//return EmptyResult();
}
public ActionResult GoOffline()
{
if (SiteUser.IsAuthenticated)
SiteUser.GoOffline(true);
ViewData["IsLogged"] = "False";
return RedirectToAction("Index", "Home");
}
This works well ...but the ONLY problem is that if I am on View XXXX, and I click on "Go Online", the controller redirects me to the Index View.
I tried "return EmptyResult()" or "return PartialView("OnlineStatusCtrl") but it does just not work.
From the code, you can see that the only thing the PartialView cares about is the "ViewData['IsLogged'] value"
QUESTION:
What is the way to REFRESH a partial view without having to refresh the entire page or redirect to the main page?
Is it maybe a matter of putting an Html.Beginform() ?
Is it maybe a matter of the Controller returning something that just refresh the content of the PartialView independently from what view is holding the PV itself?
Aiaiaiaia
I still can't figure out how MVC works with PartialViews/
UPDATE
I have updated the code as x suggested and the HTML output is as follow:
<div id="divStatus">
<form action="/" data-ajax="true" data-ajax-mode="replace" data-ajax-update="#divStatus" id="form0" method="post">
<div id="offlineStatus">
Ready for business >>
Go Online
</div>
</form>
</div>
When I click on the LINK, the Controller return PartialView("_OnlineStatusCtrl"); which is hte name of the calling PV ...and the ENTIRE PAGE gets replaced.
You're going to have to use an ajax call of some sort (Microsoft ajax helpers built into MVC, or jquery/javascript ajax call.
To use Microsoft's Ajax, you can use Ajax.BeginForm or Ajax.ActionLink. Both take an AjaxOptions parameter that will allow you to set javascript functions for OnSuccess, and an UpdateTargetId to display the returned data (usually a partial view). Using this will call your action which should return a partial view. Your partial view then replaces the html element (usually a div) identified by the UpdateTargetId parameter. If you decide to go this route, make sure you reference all the proper Microsoft ajax/mvc scripts. You'll pretty much need each script with any combinations of Microsoft, Ajax, Mvc, and even unobtrusive in the name.
Here's an example of one of my ajax forms (modified slightly for simplicity)
<% using(Ajax.BeginForm("addAttribute", new { id = Model.PersonId, attributeId = item.AttributeId }, new AjaxOptions { UpdateTargetId = "myTargetId", OnSuccess = "initForm" })) { %>
<input type="submit" value="Ok" class="editMode okButton" disabled="disabled" />
<input type="button" class="editMode cancelButton" value="Cancel" />
<br />
<input type="button" value="Add" class="addButton" />
<% } %>
I have a div with an id of "myTargetId" (for this example) that will be updated with the returned partial view.