I need to place two blockquotes in sequence, however markdown combines them into a single blockquote. The only way I can get them to separate is placing some junk text between them. As this textfield allows me to use Markdown I can demonstrate:
> First Quote
> Second Quote
Results in:
First Quote
Second Quote
While using junk text:
> First Quote
.
> Second Quote
Results in:
First Quote
.
Second Quote
I cannot use HTML tags or HTML entities. Only Markdown.
You can separate blockquotes without html elements by using comment markup <!-- --> with an extra whiteline between the blocks:
> Imagination is more important than knowledge.
<!-- -->
> Never think of the future. It comes soon enough.
<!-- -->
> Anyone who has never made a mistake has never tried anything new.
Of course you can use any HTML elements you like as well (as noted by #pepoloan):
> Imagination is more important than knowledge.
<div></div>
> Never think of the future. It comes soon enough.
<div></div>
> Anyone who has never made a mistake has never tried anything new.
An empty header, #, followed by a space also works.
> Hello World
#
> Goodbye world
Unfortunately it isn't much better than <!-- --> But I kind of like it more, and use it.
>If I try a non breaking space
>it line breaks; don't ask me how
Result:
If I try a non breaking space
it line breaks; don't ask me how
Try this:
Use a U+200B character in-between the quotes, which is defined as a zero-length space to break up the quotes.
> Quote
> Quote
It looks like this:
> Quote
> Quote
You could use pandoc, which parses your original input as two consecutive blockquotes.
From experimenting, I found these to work also. Note they are not legal HTML or Markdown, but they seem do to the job:
<!
<$
</
<a
One way to do so is by just adding </> after first blockquote followed by a newline. And by this way nothing gets printed as well.
First quote
Second Quote
You have something like your first block quote, then 2 enters and on the second enter give a # symbol for Heading but leave the heading blank and then you next quote in next line.
This is one quote
This is another quote
Related
My target asciidoc text is this:
[red]#Some prompt[x]# Make sure the option is [checked]
But it won't display in asciidoc
On further investigation, I found that any line beginning with a [colour] in square brackets, and ending in a right-bracket is similarly not displayed.
Now, in this case, I've got around the problem by putting the whole prompt section in bold, like this:
*[red]#Some prompt[x]#* Make sure the option is [checked]
but this is not ideal. Adding a period after the final close bracket \] also AVOIDS the problem - but in my use case I didn't like it.
I'd like to know if there is a better way. So far I've tried:
Escaping the leading open bracket \[
Escaping the final close bracket \]
Removing the [x] in the middle, thinging the additional brackets in the middle may influence the outcome
but none of these has worked.
So my question is:
Is there a way to get around the problem of lines beginning with [colour] attributes ending with ] not displaying in asciidoc?
It seems to me that a line which begins with an opening bracket and ends with a closing bracket is being interpreted as a block attribute line.
There are a number of ways you can mitigate this.
Use a character replacement attribute. There are many built-in attributes, or you can easily define your own.
For example:
[.red]#Some prompt[x]# Make sure the option is [checked{endsb}
Use one of the inline pass-through syntaxes, for example ++:
[.red]#Some prompt[x]# Make sure the option is [checked++]++
Prevent the first opening bracket from being the first character of the line. Also, uses a built-in attribute, and the markup needs to be changed to unconstrained.
For example:
{empty}[.red]##Some prompt[x]## Make sure the option is [checked]
Notepad++ obviously recognizes all comments as such. Is there a way to simply delete all?
Edit: Stat-R's bookmark method has helped greatly, not only for removing comments but for conditionally removing lines in general.
For a general file, first of all you need to know the comment operator of the language you are writing the file in. For example, in java script the comment operator is //.
For the following code...
In NP++, you need to
Mark the lines that contains '//'. Make sure the bookmark option is enabled.
Then, choose from NP++ menu Search>Bookmark>Remove Bookmarked lines
EDIT:
Another solution after #Chris Mirno 's suggestion is as follows:
Use regular expression. See the image below. It is self explanatory
To understand it better, refer to these
In the Find & Replace Dialog, put the following regex and adjust the search options as depicted.
/\*.*?\*/
Replace with: (empty)
Select Mode: Regular Expression AND .(dot) matches newline
This should remove all your C style comments spanned across lines.
Star-R and Chris Mirno Answer are also Correct and Good.
But For Line Comment:
//.*?(?=\r?$)
Explanation:
// will be the Starting Position
.*? Will be any character
(?=\r?$) will search to the end of the line (as it is required in line comment)
Note:
But Still check each of the line because for example if your code contains soap format like
//www.w3.org/2001/XMLSchema-instance\x2......");
it will capture this line because the starting is // and it goes to end of the line so watch out for this :)
Warning to all using Stat-R's solution:
This method will remove lines of code if formatted like this:
echo "hello"; //This comment will be detected
Following his method, the entire line will be removed.
Therefore make sure to go through and make these comments, their own line before doing this method.
I have had some luck running a macro for the above. Basically:
search for // (F3)
select to end of line (shift+end)
delete (delete)
Put // into the search dialog by just searching for it once. Then record the three steps in a macro, then play it back until EOF.
The first time I did it I had a problem, but then it worked, not sure what I did differently.
Anton Largiader's answer was the most reliable one, including complex inline comments.
However, it will leave many empty lines, including ones with empty characters (space, tabs...) so I would just add another step to make it almost perfect:
After running the macro, just do:
Edit > Line Operations > Remove Empty Lines
OR
Edit > Line Operations > Remove Empty Lines (Containing Blank Characters)
1st option is good if you wish to remove only really empty lines
2nd options will remove every empty line even containing space etc. so there will be no more actual spacing left between code blocks. 1st option might be the safest with some manual cleanup afterwards.
As someone suggested in another post, the simplest and most reliable is maybe to export the all text in .RTF format using Menu Plugin-->NppExport-->Export to RTF and then:
-Open the newly created file in Word
-Select any part of any comment
-On the top-right side of Word clic Select--> Select all texts with similar formatting
-Remove the selected comments all at once (del or cut if doesn't work)
To remove Powershell comments if someone find it handy:
Removing Comment in a Powershell using Notepad ++
To find just lines beginning with # (and not with # elsewhere in the line).
Notepad++ SEARCH Menu > Find
‘Mark‘ Tab – fill in as below.
Select ‘Mark All’ (clear all marks if used previously).
Regex ^[#}
enter image description here
SEARCH Menu > bookmark > Remove (or do anything on the list with
them)
Clear all marks to reset
You can select no comments just code by doing the following:
Regex ^[^#}
enter image description here
Enter ctrl+shift+K to remove comment
I'm having problems about a regexp.
I'm trying to implement a regex to select just the tab indent blocks, but i cant find a way of make it work:
Example:
INDENT(1)
INDENT(2)
CONTENT(a)
CONTENT(b)
INDENT(3)
CONTENT(c)
So I need blocks like:
INDENT(2)
CONTENT(a)
CONTENT(b)
AND
INDENT(3)
CONTENT(c)
How I can do this?
really tks, its almost that, here is my original need:
table
tr
td
"joao"
"joao"
td
"marcos"
I need separated "td" blocks, could i adapt your example to that?
It depends on exactly what you are trying to do, but maybe something like this:
^(\t+)(\S.*)\n(?:\1\t.*\n)*
Working example: http://www.rubular.com/r/qj3WSWK9JR
The pattern searches for:
^(\t+)(\S.*)\n - a line that begins with a tab (I've also captured the first line in a group, just to see the effect), followed by
(?:\1\t.*\n)* - lines with more tabs.
Similarly, you can use ^( +)(\S.*)\n(?:\1 .*\n)* for spaces (example). Mixing spaces and tabs may be a little problematic though.
For the updated question, consider using ^(\t{2,})(\S.*)\n(?:\1\t.*\n)*, for at least 2 tabs at the beginning of the line.
You could use the following regex to get the groups...
[^\s]*.*\r\n(?:\s+.*\r*\n*)*
this requires that your lines not begin with white space for the beginning of the blocks.
I have a string like this.
<p class='link'>try</p>bla bla</p>
I want to get only <p class='link'>try</p>
I have tried this.
/<p class='link'>[^<\/p>]+<\/p>/
But it doesn't work.
How can I can do this?
Thanks,
If that is your string, and you want the text between those p tags, then this should work...
/<p\sclass='link'>(.*?)<\/p>/
The reason yours is not working is because you are adding <\/p> to your not character range. It is not matching it literally, but checking for not each character individually.
Of course, it is mandatory I mention that there are better tools for parsing HTML fragments (such as a HTML parser.)
'/<p[^>]+>([^<]+)<\/p>/'
will get you "try"
It looks like you used this block: [^<\/p>]+ intending to match anything except for </p>. Unfortunately, that's not what it does. A [] block matches any of the characters inside. In your case, the /<p class='link'>[^<\/p>]+ part matched <p class='link'>try</, but it was not immediately followed by the expected </p>, so there was no match.
Alex's solution, to use a non-greedy qualifier is how I tend to approach this sort of problem.
I tried to make one less specific to any particular tag.
(<[^/]+?\s+[^>]*>[^>]*>)
this returns:
<p class='link'>try</p>
In my Ruby app, I've used the following method and regular expression to remove all HTML tags from a string:
str.gsub(/<\/?[^>]*>/,"")
This regular expression did just about all I was expecting it to, except it caused all quotation marks to be transformed into “
and all single quotes to be changed to ”
.
What's the obvious thing I'm missing to convert the messy codes back into their proper characters?
Edit: The problem occurs with or without the Regular Expression, so it's clear my problem has nothing to do with it. My question now is how to deal with this formatting error and correct it. Thanks!
Use CGI::unescapeHTML after you perform your regular expression substitution:
CGI::unescapeHTML(str.gsub(/<\/?[^>]*>/,""))
See http://www.ruby-doc.org/core/classes/CGI.html#M000547
In the above code snippet, gsub removes all HTML tags. Then, unescapeHTML() reverts all HTML entities (such as <, “) to their actual characters (<, quotes, etc.)
With respect to another post on this page, note that you will never ever be passed HTML such as
<tag attribute="<value>">2 + 3 < 6</tag>
(which is invalid HTML); what you may receive is, instead:
<tag attribute="<value>">2 + 3 < 6</tag>
The call to gsub will transform the above to:
2 + 3 < 6
And unescapeHTML will finish the job:
2 + 3 < 6
You're going to run into more trouble when you see something like:
<doohickey name="<foobar>">
You'll want to apply something like:
gsub(/<[^<>]*>/, "")
...for as long as the pattern matches.
This regular expression did just about
all I was expecting it to, except it
caused all quotation marks to be
transformed into “ and all
single quotes to be changed to ”
.
This doesn't sound as if the RegExp would be doing this. Are you sure it's different before?
See this question here for information about the problem, it has got an excellent answer:
Get non UTF-8 form fields as UTF-8 in php.
I've run into a similar problem with character changes, this happened when my code ran through another module that enforced UTF-8 encoding and then when it came back, I had a different file (slurped array of lines) on my hands.
You could use a multi-pass system to get the results you are looking for.
After running your regular expression, run an expression to convert &8220; to quotes and another to convert &8221; to single quotes.