I have installed xampp and by default my website files are stored in htdocs. How do I change the webdirectory path?
Edit the file /opt/lampp/etc/httpd.conf and change the lines containing current web directory path. It should start with DocumentRoot. Update all the places having the current path to the path you would like it to be.
It can be done by editing the "httpd.conf" file present in this path "\xampp\apache\conf\".
Change the line that starts with "Directory ...".
Note that all the lines that start with a hash (#) are just comments and are there just to describe the commands present there in the file.
search for the file "httpd.conf" and change the path in that file.
change localhost's name ? thus instead of having localhostdomain/webdirectory
you may have newdomain/webdirectory ?
Related
Oracle's sqlldr defaults to a .dat extension. That I want to override. I don't like to rename the file. When googled get to know few answers to use . like data='fileName.' which is not working. Share your ideas, please.
Error message is fileName.dat is not found.
Sqlloder has default extension for all input files data,log,control...
data= .dat
log= .log
control = .ctl
bad =.bad
PARFILE = .par
But you have to pass filename without apostrophe and dot
sqlloder pass/user#db control=control data=data
sqloader will add extension. control.ctl data.dat
Nevertheless i do not understand why you do not want to specify extension?
You can't, at least in Unix/Linux environments. In Windows you can use the trailing period trick, specifying either INFILE 'filename.' in the control file or DATA=filename. on the command line. WIndows file name handling allows that; you can for instance do DIR filename. at a command prompt and it will list the file with no extension (as will DIR filename). But you can't do that with *nix, from a shell prompt or anywhere else.
You said you don't want to copy or rename the file. Temporarily renaming it might be the simplest solution, but as you may have a reason not to do that even briefly you could instead create a hard or soft link to the file which does have an extension, and use that link as the target instead. You could wrap that in a shell script that takes the file name argument:
# set variable from correct positional parameter; if you pass in the control
# file name or other options, this might not be $1 so adjust as needed
# if the tmeproary file won't be int he same directory, need to be full path
filename=$1
# optionally check file exists, is readable, etc. but overkill for demo
# can also check temporary file does not already exist - stop or remove
# create soft link somewhere it won't impact any other processes
ln -s ${filename} /tmp/${filename##*/}.dat
# run SQL*Loader with soft link as target
sqlldr user/password#db control=file.ctl data=/tmp/${filename##*/}.dat
# clean up
rm -f /tmp/${filename##*/}.dat
You can then call that as:
./scriptfile.sh /path/to/filename
If you can create the link in the same directory then you only need to pass the file, but if it's somewhere else - which may be necessary depending on why renaming isn't an option, and desirable either way - then you need to pass the full path of the data file so the link works. (If the temporary file will be int he same filesystem you could use a hard link, and you wouldn't have to pass the full path then either, but it's still cleaner to do so).
As you haven't shown your current command line options you may have to adjust that to take into account anything else you currently specify there rather than in the control file, particularly which positional argument is actually the data file path.
I have the same issue. I get a monthly download of reference data used in medical application and the 485 downloaded files don't have file extensions (#2gb). Unless I can load without file extensions I have to copy the files with .dat and load from there.
How can I open a form stored in the current directory
do form ADDBS( JUSTPATH(SYS(16,0))) +"\form5.scx" WITH thisform.grid1.Column1.Text1.Value TO aa
I tried this but says that the file doesn't exist
do form form5 with ...
VFP uses relative pathing and also search paths. If it is in current directory then would be the first one to be picked by VFP.
ADDBS( JUSTPATH(SYS(16,0)))
this adds already a slash ("\") to the path and you add another slash with "\form5.scx"
can do
do form ADDBS( JUSTPATH(SYS(16,0)))+"form5.scx"
or use relative path or locfile() function
to test what i said copy this code and execute it: you can see there is 2 "\"
addbs() works only on what its applied not in the second independent term of the path.
local m.myvar
text to m.myvar noshow
messagebox(ADDBS( JUSTPATH(SYS(16,0))) +"\form5.scx")
_cliptext=ADDBS( JUSTPATH(SYS(16,0))) +"\form5.scx"
endtext
strtofile(m.myvar,"test.prg")
do test
http://blazemeter.com/blog/how-performance-test-upload-and-download-scenarios-apache-jmeter
I've used above link for reference.
I'm Using Save Responses to a file with Download call.
But fail to Download file.
Can anyone tell me What Exactly i need Specify in
FileName Prefix:
Variable name :
and where to Specify download location ?
Provide absolute file path with a file name.
FileName Prefix: c:\workspace\jmeter-download\myfile
For ex: If your test is downloading a pdf file, you would see a 'myfile.pdf' under 'c:\workspace\jmeter-download'
I've used path like D:/xyzFolder/filename as Filename Prifix
it's working fine for me
and if any one wants file to download in same Dir in which your jmx file is
then just need to use ~/pre as Filename Prifix
Here I am creating the logs folder under the current path of the directory using Dir::pwd. But I want to change this to pick the directory path from config files which will run in any other machines.
date_directory= "#{Dir::pwd}/logs/#{DateHelper.getDirectoryYearStamp}/#{DateHelper.getDirectoryMonthStamp}/#{DateHelper.getDirectoryDateStamp}/"
FileUtils.mkdir_p(date_directory) unless Dir.exists?(date_directory)
I tired with giving the absolute path and it works. But how do I make the directory by passing the relative path?
You are allready using a relative path, so is is generic solution, the subfolder of your current folder is a relative position. Is the code you published working ? But inside your question you mention config files, is it that what you want ? What kind of file ? a yaml, ini or of a simple text file ?
If a simple textfile you can do with
path = File.read("#{File.dirname(__FILE__)}/path.txt")
EDIT: based on your comment, the following snippets wil create a logfile a day in the /some/x/y/z
folder.
require 'logger'
$log = Logger.new("/some/x/y/z/logs.txt", 'daily' )
$log.info "teststring"
gives in the file "C:\some\x\y\z\logs.txt"
# Logfile created on 2013-04-05 13:17:27 +0200 by logger.rb/31641
I, [2013-04-05T13:20:19.811837 #3300] INFO -- : teststring
I am trying to copy the contents of a log file to another log file using this command:
type \\server\f$\Test path\Test.log >> \\server2\f$\Logs\Testpath\Test.log
This has always worked in the path, but recently I have changed the location (path) to Test.log. The path is slightly longer. I now get an error:
The system could not find the file specified
I have googled this statement and the common responses are: 1) check the filename exists, 2) check the filename is not corrupt 3) Check the server is online.
I have done all of this. Is there a restriction on the number of characters a path can have? If there is then is there a workaround?
UPDATE 12/07/2012 09:49 GMT
Adding quotes around the path seems to resolve the problem. Why does adding quotes resolve the problem?
The problem was that the source path had a space in it. Adding quotes around the path resolved the problem.
Type is to examine a file, not to copy.
Also, if server is an actual server and not a folder, then you should be using two slashes (\server\share)
Example:
copy \\server\f$\Sourcepath\Test.log \\server2\f$\Logs\Destpath\Test.log /y
http://www.microsoft.com/resources/documentation/windows/xp/all/proddocs/en-us/ntcmds.mspx?mfr=true