Here I am creating the logs folder under the current path of the directory using Dir::pwd. But I want to change this to pick the directory path from config files which will run in any other machines.
date_directory= "#{Dir::pwd}/logs/#{DateHelper.getDirectoryYearStamp}/#{DateHelper.getDirectoryMonthStamp}/#{DateHelper.getDirectoryDateStamp}/"
FileUtils.mkdir_p(date_directory) unless Dir.exists?(date_directory)
I tired with giving the absolute path and it works. But how do I make the directory by passing the relative path?
You are allready using a relative path, so is is generic solution, the subfolder of your current folder is a relative position. Is the code you published working ? But inside your question you mention config files, is it that what you want ? What kind of file ? a yaml, ini or of a simple text file ?
If a simple textfile you can do with
path = File.read("#{File.dirname(__FILE__)}/path.txt")
EDIT: based on your comment, the following snippets wil create a logfile a day in the /some/x/y/z
folder.
require 'logger'
$log = Logger.new("/some/x/y/z/logs.txt", 'daily' )
$log.info "teststring"
gives in the file "C:\some\x\y\z\logs.txt"
# Logfile created on 2013-04-05 13:17:27 +0200 by logger.rb/31641
I, [2013-04-05T13:20:19.811837 #3300] INFO -- : teststring
Related
I am trying to write some data in one Ruby file to a file in another folder but I am having trouble identifying the path to get to the file I want to write to.
My current code is:
File.write('../csv_fixtures/loans.csv', 'test worked!')
And my folder structure is as follows:
Where I am trying to run my code in 'run_spec.rb' and write to 'loans.csv'.
Additionally, this is the error I am getting:
Give the path relative to the working directory, not the file that you call File.write from. The working directory is the place you've navigated to through cd before calling the ruby code. If you ran rspec from the root of your project, then the working directory will also be the root. So, in this case, it looks like it would be ./spec/csv_fixtures/loans.csv. You can run puts Dir.pwd to see the working directory that all paths should be relative to.
If you wanted to something more like require_relative, you have to use some sort of workaround to turn it into an absolute path, such as File.dirname(__FILE__) which gives the absolute path of the folder containing the current file:
path = File.join(File.dirname(__FILE__, "../csv_fixtures/loans.csv"))
So, I have a function that creates an object specifying user data. Then, using the Ruby YAML gem and some code, I put the object to a YAML file and save it. This saves the YAML file to the location where the Ruby script was run from. How can I tell it to save to a certain file directory? (A simplified version of) my code is this
print "Please tell me your name: "
$name=gets.chomp
$name.capitalize!
print "Please type in a four-digit PIN number: "
$pin=gets.chomp
I also have a function that enforces that the pin be a four-digit integer, but that is not important.
Then, I add this to an object
new_user=Hash.new (false)
new_user["name"]=$name
new_user["pin"]=$pin
and then add it to a YAML file and save it. If the YAML file doesn't exist, one is created. It creates it in the same file directory as the script is run in. Is there a way to change the save location?
The script fo save the object to a YAML file is this.
def put_to_yaml (new_user)
File.write("#{new_user["name"]}.yaml", new_user.to_yaml)
end
put_to_yaml(new_user)
Ultimately, the question is this: How can I change the save location of the file? And when I load it again, how can i tell it where to get the file from?
Thanks for any help
Currently when you use File.write it takes your current working directory, and appends the file name to that location. Try:
puts Dir.pwd # Will print the location you ran ruby script from.
You can specify the absolute path if you want to write it in a specific location everytime:
File.write("/home/chameleon/different_location/#{new_user["name"]}.yaml")
Or you can specify a relative path to your current working directory:
# write one level above your current working directory
File.write("../#{new_user["name"]}.yaml", new_user.to_yaml)
You can also specify relative to your current executing ruby file:
file_path = File.expand_path(File.dirname(__FILE__))
absolute_path = File.join(file_path, file_name)
File.write(absolute_path, new_user.to_yaml)
You are supplying a partial pathname (a mere file name), so we read and write from the current directory. Thus you have two choices:
Supply a full absolute pathname (personally, I like to use the Pathname class for this); or
Change the current directory first (with Dir.chdir)
Ok so with siriproxy it my lib folder along with the rb file for the plugin I have created a myconfig.yml file so I can change certain settings by writing to that file.
I have been able to write to the file but only if I include the full path all the way from the home directory down.
But is there not a way to open the file from the same directory i am in? I have tried every path combination I can think of.
There has to be one i am missing
If you use the following in your ruby file, you should get the absolute path where it is
File.expand_path(__FILE__)
From doc __FILE__
The name of the file currently being executed, including path relative to the directory where the application was started up (or the current directory, if it has been changed)
From doc File.expand_path
Converts a pathname to an absolute pathname.
As you probably want the directory, you should use File.dirname(__FILE__), so the path of your file myconfig.yml should be obtained with
File.join(File.expand_path(File.dirname(__FILE__)), 'myconfig.yml')
In more recent Ruby (>=2.0.0), you can use __dir__ (from Archonic's comment):
Returns the canonicalized absolute path of the directory of the file from which this method is called. It means symlinks in the path is resolved. If FILE is nil, it returns nil. The return value equals to File.dirname(File.realpath(FILE)).
I am creating files from within Ruby scripts and adding stuff to them. But where are these files stored that I am creating?
I'm very new to this, sorry!
The files are created at whatever location you specified. For instance:
f = File.new("another_test.txt","w+")
that will create the file in the current working directory. You specify the path along with the file name. For example:
f = File.new("~/Desktop/another_test.txt","w+") # will create the file on the desktop.
For more details, check the File documentation.
Updated:
Included mu is too short correction.
I need to get the main project working directory, for example I have a project folder structure like,
Projectmainfolder->
SourceCodeFolder
AnotherFolder
I have my all code files in sourceCodeFolder, and now I want to get or print Projectmainfolder path, Kindly let me know if there is a way to get the location path of the root project folder.
This will give you the path to the current file.
__FILE__
In order to expand a relative path, do this:
File.expand_path("../../", __FILE__)
if you start your script from the Projectmainfolder directory, Dir.getwd should print you the path you want. Or did you mean something different?