optimizing simple select query in oracle - oracle

I am trying to optimize the following query:
SELECT tickstime AS time,
quantity1 AS turnover
FROM cockpit_test.ticks
WHERE date_id BETWEEN 20111104 AND 20111109
AND mdc_id IN (297613)
ORDER BY time;
It is pretty simple but it takes about 60-90 seconds to run. cockpit_test.TICKS table contains more than 100M of rows. It also has an index by MDC_ID and DATE_ID columns.
EXPLAIN PLAN gives the following output
"-------------------------------------------------------------------------------------------------------"
"| Id | Operation | Name | Rows | Bytes |TempSpc| Cost (%CPU)| Time |"
"-------------------------------------------------------------------------------------------------------"
"| 0 | SELECT STATEMENT | | 26905 | 604K| | 11783 (1)| 00:02:22 |"
"| 1 | SORT ORDER BY | | 26905 | 604K| 968K| 11783 (1)| 00:02:22 |"
"| 2 | TABLE ACCESS BY INDEX ROWID| TICKS | 26905 | 604K| | 11596 (1)| 00:02:20 |"
"|* 3 | INDEX RANGE SCAN | TICKS_MDC_DATE | 26905 | | | 89 (0)| 00:00:02 |"
"-------------------------------------------------------------------------------------------------------"
" "
"Predicate Information (identified by operation id):"
"---------------------------------------------------"
" "
" 3 - access(""MDC_ID""=297613 AND ""DATE_ID"">=20111104 AND ""DATE_ID""<=20111109)"
So I am not completely sure what all that means, but it seems that index is being hit and most time is being consumed by accessing rows by index rowid.
Are there any ways to make this query run faster?
UPD
Here is the table definition:
Name Null? Type
----------------------------------------- -------- ----------------------------
DATE_ID NOT NULL NUMBER(38)
MDC_ID NOT NULL NUMBER(38)
TICKSTIME NOT NULL DATE
STATE NOT NULL NUMBER(38)
VALUE1 NOT NULL FLOAT(126)
VALUE2 FLOAT(126)
VOLUME1 FLOAT(126)
VOLUME2 FLOAT(126)
QUANTITY1 NUMBER(38)
QUANTITY2 NUMBER(38)
There are 3 indexes on the table:
Index on MDC_ID
Compound index on DATE_ID, MDC_ID, TICKSTIME
Compound index on DATE_ID, MDC_ID

I would check that this explain plan has accurate estimations of the cardinalities. It's quite typical for the cardinality to poorly estimated when multiple predicates are supplied, and the execution time seems very high for such a small query and estimated sort size (unless you have grossly underpowered storage infrastructure, which again is pretty typical).
Given the duration of the query I'd make sure that the estimate is accurate by invoking dynamic sampling ...
SELECT
/*+ dynamic_sampling(4) */
tickstime AS time,
quantity1 AS turnover
FROM
cockpit_test.ticks
WHERE
date_id BETWEEN 20111104 AND 20111109 and
mdc_id IN (297613)
ORDER BY
tickstime;
If it turns out that the estimated temp space is smaller than realtiy (and you can check that by querying V$SQL_WORKAREA_ACTIVE) then you might have to tweak the memory settings for the session to switch to automatic memory management and increase the sort area size.

In general, Oracle can't combine two separate indexes (unless they're bitmap indexes and not "ordinary" btree indexes).
What is the mdc_id column? If there are many distinct values for it, you could create a compound index on mdc_id, date_id.
In theory, Oracle can use an index to return sorted data. In this case your index should be on mdc_id, date_id, time.
Why aren't you using date datatypes for your date columns? For this particular query it probably won't make much difference, but in general Oracle will much better be able to determine the distribution of data if you use correct datatypes.

Related

How should I index a FULLNAME field in Oracle when I need to query by first and last name?

I have a rather large table (34 GB, 77M rows) which contains payment information. The table is partitioned by payment date because users usually care about small ranges of dates so the partition pruning really helps queries to return quickly.
The problem is that I have a user who wants to find out all payments that have ever been made to certain people.
Names are stored in columns NAME1 and NAME2, which are both VARCHAR2(40 Byte) and hold free-form full name data. For example, John Q Public could appear in either column as:
John Q Public
John Public
Public, John Q
or even embedded in the middle of the field, like "Estate of John Public"
Right now, the way the query is set up is to look for
NAME1||NAME2 LIKE '%JOHN%PUBLIC%' OR NAME1||NAME2 LIKE '%PUBLIC%JOHN%' and as you can imagine, the performance sucks.
Is this a job for Oracle Text? How else could I better index the atomic bits of the columns so that the user can search by first/last name?
Database Version: Oracle 12c (12.1.0.2.0)
Create a multi-column index on both names and modify your query to use an INDEX FAST FULL SCAN operation.
Traversing a b-tree index is a great way to quickly find a small amount of data. Unfortunately the leading wildcards ruin that access path for your query. However, Oracle has multiple ways of reading data from an index. The INDEX FAST FULL SCAN operation simply reads all of the index blocks in no particular order, as if the index was a skinny table. Since the average row length of your table is 442 bytes, and the two columns use at most 80 bytes, reading all the names in the index may be much faster than scanning the entire table.
But the index alone probably isn't enough. You need to change the concatenation into multiple OR expressions.
Sample schema:
--Create payment table and index on name columns.
create table payment
(
id number,
paydate date,
other_data varchar2(400),
name1 varchar2(40),
name2 varchar2(40)
);
create index payment_idx on payment(name1, name2);
--Insert 100K sample rows.
insert into payment
select level, sysdate + level, lpad('A', 400, 'A'), level, level
from dual
connect by level <= 100000;
--Insert two rows with relevant values.
insert into payment values(0, sysdate, 'other data', 'B JOHN B PUBLIC B', 'asdf');
insert into payment values(0, sysdate, 'other data', 'asdf', 'C JOHN C PUBLIC C');
commit;
--Gather stats to help optimizer pick the right plan.
begin
dbms_stats.gather_table_stats(user, 'payment');
end;
/
Original expression uses a full table scan:
explain plan for
select name1, name2
from payment
where NAME1||NAME2 LIKE '%JOHN%PUBLIC%' OR NAME1||NAME2 LIKE '%PUBLIC%JOHN%';
select * from table(dbms_xplan.display);
Plan hash value: 684176532
-----------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
-----------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 9750 | 4056K| 1714 (1)| 00:00:01 |
|* 1 | TABLE ACCESS FULL| PAYMENT | 9750 | 4056K| 1714 (1)| 00:00:01 |
-----------------------------------------------------------------------------
Predicate Information (identified by operation id):
---------------------------------------------------
1 - filter("NAME1"||"NAME2" LIKE '%JOHN%PUBLIC%' OR "NAME1"||"NAME2"
LIKE '%PUBLIC%JOHN%')
New expression uses a faster INDEX FAST FULL SCAN operation:
explain plan for
select name1, name2
from payment
where
NAME1 LIKE '%JOHN%PUBLIC%' OR
NAME1 LIKE '%PUBLIC%JOHN%' OR
NAME2 LIKE '%JOHN%PUBLIC%' OR
NAME2 LIKE '%PUBLIC%JOHN%';
select * from table(dbms_xplan.display);
Plan hash value: 1655289165
------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
------------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 18550 | 217K| 152 (3)| 00:00:01 |
|* 1 | INDEX FAST FULL SCAN| PAYMENT_IDX | 18550 | 217K| 152 (3)| 00:00:01 |
------------------------------------------------------------------------------------
Predicate Information (identified by operation id):
---------------------------------------------------
1 - filter("NAME1" LIKE '%JOHN%PUBLIC%' AND "NAME1" IS NOT NULL AND
"NAME1" IS NOT NULL OR "NAME1" LIKE '%PUBLIC%JOHN%' AND "NAME1" IS NOT NULL
AND "NAME1" IS NOT NULL OR "NAME2" LIKE '%JOHN%PUBLIC%' AND "NAME2" IS NOT
NULL AND "NAME2" IS NOT NULL OR "NAME2" LIKE '%PUBLIC%JOHN%' AND "NAME2" IS
NOT NULL AND "NAME2" IS NOT NULL)
This solution should definitely be faster than a full table scan. How much faster depends on the average name size and the name being searched. And depending on the query you may want to add additional columns to keep all the relevant data in the index.
Oracle Text is also a good option, but that feature feels a little "weird" in my opinion. If you're not already using text indexes you might want to stick with normal indexes to simplify administrative tasks.

Oracle partitioned table query cost vs non-partitioned table query cost

I have a table PO_HEADER with ~20 million records. Considering our future load on the table we have decided to partitioned the table to increase the performance of the sql queries. Below are the queries used to create the new partitioned tables.
CREATE TABLE PO_HEADER_LP
PARTITION BY LIST (BUYER_IDENTIFIER)
(PARTITION GC66287246AA VALUES ('GC66287246AA') TABLESPACE MITRIX_TABLES,
PARTITION GC43837235JK VALUES ('GC43837235JK') TABLESPACE MITRIX_TABLES,
PARTITION GC84338293AA VALUES ('GC84338293AA') TABLESPACE MITRIX_TABLES,
PARTITION DEFAULTBUID VALUES (DEFAULT) TABLESPACE MITRIX_TABLES)
AS SELECT *
FROM PO_HEADER;
create index PO_HEADER_LP_SI_IDX on PO_HEADER_LP("SUPPLIER_IDENTIFIER") TABLESPACE MITRIX_INDEXES LOCAL;
Old Table PO_HEADER has two indexes on "BUYER_IDENTIFIER" and "SUPPLIER_IDENTIFIER" columns as follows:
create index PO_HEADER_BI_IDX on PO_HEADER("BUYER_IDENTIFIER") TABLESPACE MITRIX_INDEXES;
create index PO_HEADER_SI_IDX on PO_HEADER("SUPPLIER_IDENTIFIER") TABLESPACE MITRIX_INDEXES;
To test the performance of the query, I executed below query on both the tables. But, to my wonder I saw the cost of the 2nd query is almost double than the 1st one. Can any body know, why is the query cost is high of the partitioned table compared to normal table. Thanks in Advance.
select * from po_header where buyer_identifier='GC84338293AA' and supplier_identifier='GC75987723HT'; --cost: 56,941
select * from po_header_lp where buyer_identifier= 'GC84338293AA' and supplier_identifier='GC75987723HT'; --cost: 93,309
PO_HEADER with Global Index on buyer_identifier & supplier_identifier column
PO_HEADER_LP with Global Index on supplier_identifier column
PO_HEADER_LP with Local Index on supplier_identifier column
From your DDL I assume, you have three big buyers (say 5M records each) and a bunch of smaller ones. In other word this would be the correct setup for you list partitioning schema.
You may verify, whether it works testing access on buyer only:
EXPLAIN PLAN SET STATEMENT_ID = 'jara1' into plan_table FOR
select * from tab_lp where BUYER_ID = 1;
;
SELECT * FROM table(DBMS_XPLAN.DISPLAY('plan_table', 'jara1','ALL'));
------------------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | Pstart| Pstop |
------------------------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 6662K| 82M| 4445 (2)| 00:00:01 | | |
| 1 | PARTITION LIST SINGLE| | 6662K| 82M| 4445 (2)| 00:00:01 | KEY | KEY |
| 2 | TABLE ACCESS FULL | TAB_LP | 6662K| 82M| 4445 (2)| 00:00:01 | 2 | 2 |
------------------------------------------------------------------------------------------------
The same query for the non-partitioned table should produce much higher cost. Why?
In the partitioned table the selected buyer (in your case GC84338293AA, I'm using surrogate keys) has it own partition.
So full scan of this partition is the best access.
select * from tab where BUYER_ID = 1;
--------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
--------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 6596K| 81M| 14025 (1)| 00:00:01 |
|* 1 | TABLE ACCESS FULL| TAB | 6596K| 81M| 14025 (1)| 00:00:01 |
--------------------------------------------------------------------------
1 - filter("BUYER_ID"=1)
For the non-partitioned table (to get approximately one fourth of the data) the FULL TABLE SCAN is OK as well,
but of course has higher cost as all data must be scanned.
Note - if you see here lower cost, unrealistically low Rows count and/or INDEX ACCESS,
than this is the cause of the problem of the underestimating of the cost. So don't worry the old cost are too low, not the new one too high!
The next step is the access on both buyer and supplier. To get the answer you must provide
additional information.
How selective is the supplier filter?
I.e. if the predicate buyer_identifier='GC84338293AA' returns say 5M records, how may records return the predicate with both columns?
buyer_identifier='GC84338293AA' and supplier_identifier='GC75987723HT'
Is it 4M or 100 records?
If the complete predicate returns only few records than the local index on supplier is OK.
If it returns large number of rows (say the quarter of the partition) - you should stay on FULL PARTITION SCAN and not use it.
This is similar to my comment on the non partitioned table.
Estimation of the supplier cardinality
In case that the column SUPPLIER contains a skewed data (which may fool the CBO to calulate improper cost) you may define explicitely histogram in this column.
I used this statement statement, that calculates the histogram on full data (100% is important for highly skewed data) and for the table and partition.
exec dbms_stats.gather_table_stats(ownname=>user,tabname=>'TAB_LP',granularity=>'all',estimate_percent => 100,METHOD_OPT => 'for columns SUPPLIER_ID size 254');
This worked for my test data, i.e. for supplier with low cardinality an index access was opened (on local no-prefixed index) and for huge suppliers a full partition scan was used.
You can create a Local partitioned index using this script.
CREATE INDEX PO_HEADER_LOCAL_IDX ON PO_HEADER_LP
(BUYER_IDENTIFIER, SUPPLIER_IDENTIFIER)
LOCAL (
PARTITION GC66287246AA,
PARTITION GC43837235JK,
PARTITION GC84338293AA,
PARTITION DEFAULTBUID
);
Also it is recommended to gather statistics of the newly created partition table using this script:
EXEC DBMS_STATS.GATHER_TABLE_STATS('SCHEMA Name','PO_HEADER_LP');
Now you can generate the execution plan again of the following SQL:
select * from po_header_lp where buyer_identifier= 'GC84338293AA' and supplier_identifier='GC75987723HT';
Hope this will help you.

Oracle is not using the Indexes

I have a very large table in oracle 11g that has a very simple index in a char field (that is normally Y or N)
If I just execute the queue as bellow it takes around 10s to return
select QueueId, QueueSiteId, QueueData from queue where QueueProcessed = 'N'
However if I force it to use the index I create it takes 80ms
select /*+ INDEX(avaqueue QUEUEPROCESSED_IDX) */ QueueId, QueueSiteId, QueueData
from queue where QueueProcessed = 'N'
Also if I run under the explain plan for as bellow:
explain plan for select QueueId, QueueSiteId, QueueData
from queue where QueueProcessed = 'N'
and
explain plan for select /*+ INDEX(avaqueue QUEUEPROCESSED_IDX) */
QueueId, QueueSiteId, QueueData
from queue where QueueProcessed = 'N'
For the frist plan I got:
------------------------------------------------------------------------------
Plan hash value: 803924726
------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 691K| 128M| 12643 (1)| 00:02:32 |
|* 1 | TABLE ACCESS FULL| AVAQUEUE | 691K| 128M| 12643 (1)| 00:02:32 |
------------------------------------------------------------------------------
Predicate Information (identified by operation id):
---------------------------------------------------
1 - filter("QUEUEPROCESSED"='N')
For the second pla I got:
Plan hash value: 2012309891
--------------------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
--------------------------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 691K| 128M| 24386 (1)| 00:04:53 |
| 1 | TABLE ACCESS BY INDEX ROWID| AVAQUEUE | 691K| 128M| 24386 (1)| 00:04:53 |
|* 2 | INDEX RANGE SCAN | QUEUEPROCESSED_IDX | 691K| | 1297 (1)| 00:00:16 |
--------------------------------------------------------------------------------------------------
Predicate Information (identified by operation id):
---------------------------------------------------
2 - access("QUEUEPROCESSED"='N')
------------------------------------------------------------------------------
What proves that if I don't explicit tell oracle to use the index it does not use it, my question is why is oracle not using this index? Oracle is normally smart enough to make decisions 10 times better than me, that is the first time I actually have to force oracle to use a index and I am not very comfortable with it.
Does anyone have a good explanation for oracle decision to not use the index in this very explicit case?
The QueueProcessed column is probably missing a histogram so Oracle does not know the data is skewed.
If Oracle does not know the data is skewed it will assume the equality predicate, QueueProcessed = 'N', returns DBA_TABLES.NUM_ROWS /
DBA_TAB_COLUMNS.NUM_DISTINCT. The optimizer thinks the query returns half the rows in the table. Based on the 80ms return time the real number of rows returned is small.
Index range scans generally only work well when they select a small percentage of the rows. Index range scans read from a data structure one block at a time. And if the data is randomly distributed, it may need to read every block of data from the table anyway. For those reasons, if the query accesses a large portion of the table, it is more efficient to use a multi-block full table scan.
The bad cardinality estimate from the skewed data causes Oracle to think a full table scan is better. Creating a histogram will fix the issue.
Sample schema
Create a table, fill it with skewed data, and gather statistics the first time.
drop table queue;
create table queue(
queueid number,
queuesiteid number,
queuedata varchar2(4000),
queueprocessed varchar2(1)
);
create index QUEUEPROCESSED_IDX on queue(queueprocessed);
--Skewed data - only 100 of the 100000 rows are set to N.
insert into queue
select level, level, level, decode(mod(level, 1000), 0, 'N', 'Y')
from dual connect by level <= 100000;
begin
dbms_stats.gather_table_stats(user, 'QUEUE');
end;
/
The first execution will have the problem.
In this case the default statistics settings do not gather histograms the first time. The plan shows a full table scan and estimates Rows=50000, exactly half.
explain plan for
select QueueId, QueueSiteId, QueueData
from queue where QueueProcessed = 'N';
select * from table(dbms_xplan.display);
Plan hash value: 1157425618
---------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
---------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 50000 | 878K| 103 (1)| 00:00:01 |
|* 1 | TABLE ACCESS FULL| QUEUE | 50000 | 878K| 103 (1)| 00:00:01 |
---------------------------------------------------------------------------
Predicate Information (identified by operation id):
---------------------------------------------------
1 - filter("QUEUEPROCESSED"='N')
Create a histogram
The default statistics settings are usually sufficient. Histogram may not be collected for several reasons. They may be manually disabled - check for the tasks, jobs or preferences set by the DBA.
Also, histograms are only automatically collected on columns that are both skewed and used. Gathering histograms can take time, there's no need to create the histogram on a column that is never used in a relevant predicate. Oracle tracks when a column is used and could benefit from a histogram, although that data is lost if the table is dropped.
Running a sample query and re-gathering statistics will make the histogram appear:
select QueueId, QueueSiteId, QueueData
from queue where QueueProcessed = 'N';
begin
dbms_stats.gather_table_stats(user, 'QUEUE');
end;
/
Now the Rows=100 and the Index is used.
explain plan for
select QueueId, QueueSiteId, QueueData
from queue where QueueProcessed = 'N';
select * from table(dbms_xplan.display);
Plan hash value: 2630796144
----------------------------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
----------------------------------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 100 | 1800 | 2 (0)| 00:00:01 |
| 1 | TABLE ACCESS BY INDEX ROWID BATCHED| QUEUE | 100 | 1800 | 2 (0)| 00:00:01 |
|* 2 | INDEX RANGE SCAN | QUEUEPROCESSED_IDX | 100 | | 1 (0)| 00:00:01 |
----------------------------------------------------------------------------------------------------------
Predicate Information (identified by operation id):
---------------------------------------------------
2 - access("QUEUEPROCESSED"='N')
Here's the histogram:
select column_name, histogram
from dba_tab_columns
where table_name = 'QUEUE'
order by column_name;
COLUMN_NAME HISTOGRAM
----------- ---------
QUEUEDATA NONE
QUEUEID NONE
QUEUEPROCESSED FREQUENCY
QUEUESITEID NONE
Create the histogram
Try to determine why the histogram was missing. Check that statistics are gathered with the defaults, there are no weird column or table preferences, and that table is not constantly dropped and re-loaded.
If you cannot rely on the default statistics job for your process you can manually gather histograms with the method_opt parameter like this:
begin
dbms_stats.gather_table_stats(user, 'QUEUE', method_opt=>'for columns size 254 queueprocessed');
end;
/
The answer - at least the first one that will just lead to more questions - is right there in the plans. The first plan has an estimated cost and estimated execution time about half that of the second plan. In the absence of the hint, Oracle is choosing the plan that it thinks will run faster.
So of course the next question is why is its estimate so far off in this case. Not only are the estimated times wrong relative to each other, both are much greater than what you actually experience when running the query.
The first thing I would look at is the estimated number of rows returned. The optimizer is guessing, in both cases, that there are about 691,000 rows in table matching your predicate. Is this close to the truth, or very far off? If it's far off, then refreshing statistics may be the right solution. Although if the column only has two possible values, I'd be kind of surprised if the existing stats are so off base.

Oracle linguistic index not used when SQL contains parameter with LIKE

My schema (simplified):
CREATE TABLE LOC
(
LOC_ID NUMBER(15,0) NOT NULL,
LOC_REF_NO VARCHAR2(100 CHAR) NOT NULL
)
/
CREATE INDEX LOC_REF_NO_IDX ON LOC
(
NLSSORT("LOC_REF_NO",'nls_sort=''BINARY_AI''') ASC
)
/
My query (in SQL*Plus):
ALTER SESSION SET NLS_COMP=LINGUISTIC NLS_SORT=BINARY_AI
/
VAR LOC_REF_NO VARCHAR2(50)
BEGIN
:LOC_REF_NO := 'SPDJ1501270';
END;
/
-- Causes full table scan (i.e, does not use LOC_REF_NO_IDX)
SELECT * FROM LOC WHERE LOC_REF_NO LIKE :LOC_REF_NO||'%';
-- Causes index scan (i.e. uses LOC_REF_NO_IDX)
SELECT * FROM LOC WHERE LOC_REF_NO LIKE 'SPDJ1501270%';
That the index is not used has been confirmed by doing an AUTOTRACE (EXPLAIN PLAN) and the SQL just runs slower. Tried a number of thing without success. Anyone got any idea what is going on? I am using Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit.
Update 1:
Note that the index is used when I use an equals with a parameter:
SELECT * FROM LOC WHERE LOC_REF_NO = :LOC_REF_NO;
Explain Plan:
----------------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
----------------------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 1 | 93 | 5 (0)| 00:00:01 |
| 1 | TABLE ACCESS BY INDEX ROWID| LOC | 1 | 93 | 5 (0)| 00:00:01 |
|* 2 | INDEX RANGE SCAN | LOC_REF_NO_IDX | 1 | | 3 (0)| 00:00:01 |
----------------------------------------------------------------------------------------------
Predicate Information (identified by operation id):
---------------------------------------------------
2 - access(NLSSORT("LOC_REF_NO",'nls_sort=''BINARY_AI''')=NLSSORT(:LOC_REF_NO,'nls_
sort=''BINARY_AI'''))
Whereas
SELECT * FROM LOC WHERE LOC_REF_NO LIKE :LOC_REF_NO||'%';
Explain Plan:
--------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
--------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 50068 | 3471K| 5724 (1)| 00:01:09 |
|* 1 | TABLE ACCESS FULL| LOC | 50068 | 3471K| 5724 (1)| 00:01:09 |
--------------------------------------------------------------------------
Predicate Information (identified by operation id):
---------------------------------------------------
1 - filter("LOC_REF_NO" LIKE :LOC_REF_NO||'%')
Dumbfounded!
Update 2:
The reason we are using NLSSORT on an index is to make Oracle queries case insensitive and this was the general recommendation. Previously we use functional indexes with NLS_UPPER. The strange thing that is that the index is always used, parameter or not, as shown below.
So if table is as above, LOC_REF_NO_IDX index removed and this one added:
CREATE INDEX LOC_REF_NO_CI_IDX ON LOC
(
NLS_UPPER(LOC_REF_NO) ASC
)
/
The all of the following use the index:
ALTER SESSION SET NLS_COMP=BINARY NLS_SORT=BINARY;
SELECT * FROM LOC WHERE NLS_UPPER(LOC_REF_NO) LIKE :LOC_REF_NO||'%';
-------------------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
-------------------------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 50068 | 5329K| 5700 (1)| 00:01:09 |
| 1 | TABLE ACCESS BY INDEX ROWID| LOC | 50068 | 5329K| 5700 (1)| 00:01:09 |
|* 2 | INDEX RANGE SCAN | LOC_REF_NO_CI_IDX | 9012 | | 43 (0)| 00:00:01 |
-------------------------------------------------------------------------------------------------
Predicate Information (identified by operation id):
---------------------------------------------------
2 - access(NLS_UPPER("LOC_REF_NO") LIKE :LOC_REF_NO||'%')
filter(NLS_UPPER("LOC_REF_NO") LIKE :LOC_REF_NO||'%')
So for some reason when using LIKE with a parameter on a linguistic index, the Oracle optimizer is deciding not to use the index.
According to Oracle support note 1451804.1 this is a known limitation of using LIKE with NLSSORT-based indexes.
If you look at the execution plan for your fixed-value query you see something like:
Predicate Information (identified by operation id):
---------------------------------------------------
2 - access(NLSSORT("LOC_REF_NO",'nls_sort=''BINARY_AI''')>=HEXTORAW('7370646A313530
3132373000') AND NLSSORT("LOC_REF_NO",'nls_sort=''BINARY_AI''')<HEXTORAW('7370646A313
5303132373100') )
Those raw values evaluate to spdj1501270 and spdj1501271; those are derived from your constant string, and any values matching your like condition will be in that range. That parse-time transformation has to be based on a constant value, and doesn't work with a bind variable or an expression, presumably because it's evaluated too late.
See the note for more information, but there doesn't seem to be a workaround unfortunately. You might have to go back to your NLS_UPPER approach.
Previous explanation applies generally but not in this specific case, but kept for reference...
In general, with the fixed value the optimiser can estimate how selective your query is when it parses it, because it can know roughly what proportion of index values match that value. It may or may not use the index, depending on the actual value you use.
With the bind variable it comes up with a plan via bind variable peeking:
In bind variable peeking (also known as bind peeking), the optimizer looks at the value in a bind variable when the database performs a hard parse of a statement.
When a query uses literals, the optimizer can use the literal values to find the best plan. However, when a query uses bind variables, the optimizer must select the best plan without the presence of literals in the SQL text. This task can be extremely difficult. By peeking at bind values the optimizer can determine the selectivity of a WHERE clause condition as if literals had been used, thereby improving the plan.
It uses the statistics it has gathered to decide if any particular value is more likely than others. That probably isn't going to be the case here, especially with the like. It's falling back to a full table scan becuse it can't determine when it does the hard parse that the index will be more selective most of the time. Imagine, for example, that the parse decided to use the index, but then you supplied a bind value of just S, or even null - using the index would then do much more work than a full table scan.
Also worth noting:
When choosing a plan, the optimizer only peeks at the bind value during the hard parse. This plan may not be optimal for all possible values.
Adaptive cursor sharing can mitigate this, but this query may not qualify:
The criteria used by the optimizer to decide whether a cursor is bind-sensitive include the following:
The optimizer has peeked at the bind values to generate selectivity estimates.
A histogram exists on the column containing the bind value.
When I mocked this up with a small-ish amount of limited data, v$sql reported both is_bind_sensitive and is_bind_aware as 'N'.

Using function based index (oracle) to speed up count(X)

I've a table Film:
CREATE TABLE film (
film_id NUMBER(5) NOT NULL,
title varchar2(255));
And I wanted to make the query, which counts how many titles start with the same word and only displays ones with more than 20, faster using a function based index. The query:
SELECT FW_SEPARATOR.FIRST_WORD AS "First Word", COUNT(FW_SEPARATOR.FIRST_WORD) AS "Count"
FROM (SELECT regexp_replace(FILM.TITLE, '(\w+).*$','\1') AS FIRST_WORD FROM FILM) FW_SEPARATOR
GROUP BY FW_SEPARATOR.FIRST_WORD
HAVING COUNT(FW_SEPARATOR.FIRST_WORD) >= 20;
The thing is, I created this function based index:
CREATE INDEX FIRST_WORD_INDEX ON FILM(regexp_replace(TITLE, '(\w+).*$','\1'));
But it didn't speed anything up...
I was wondering if anyone could help me with this :)
Add a redundant predicate to the query to convince Oracle that the expression will not return null values and an index can be used:
select regexp_replace(film.title, '(\w+).*$','\1') first_word
from film
where regexp_replace(film.title, '(\w+).*$','\1') is not null;
Oracle can use an index like a skinny version of a table. Many queries only contain a small subset of the columns in a table. If all the columns in that set are part of the same index, Oracle can use that index instead of the table. This will be either an INDEX FAST FULL SCAN or an INDEX FULL SCAN. The data may be read similar to the way a regular table scan works. But since the index is much smaller than the table, that access method can be much faster.
But function-based indexes do not store NULLs. Oracle cannot use an index scan if it thinks there is a NULL that is not stored in the index. In this case, if the base column was defined as NOT NULL, the regular expression would always return a non-null value. But unsurprisingly, Oracle has not built code to determine whether or not a regular expression could return NULL. That sounds like an impossible task, similar to the halting problem.
There are several ways to convince Oracle that the expression is not null. The simplest may be to repeat the predicate and add an IS NOT NULL condition.
Sample Schema
create table film (
film_id number(5) not null,
title varchar2(255) not null);
insert into film select rownumber, column_value
from
(
select rownum rownumber, column_value from table(sys.odcivarchar2list(
q'<The Shawshank Redemption>',
q'<The Godfather>',
q'<The Godfather: Part II>',
q'<The Dark Knight>',
q'<Pulp Fiction>',
q'<The Good, the Bad and the Ugly>',
q'<Schindler's List>',
q'<12 Angry Men>',
q'<The Lord of the Rings: The Return of the King>',
q'<Fight Club>'))
);
create index film_idx1 on film(regexp_replace(title, '(\w+).*$','\1'));
begin
dbms_stats.gather_table_stats(user, 'FILM');
end;
/
Query that does not use index
Even with an index hint, the normal query will not use an index. Remember that hints are directives, and this query would use the index if it was possible.
explain plan for
select /*+ index_ffs(film) */ regexp_replace(title, '(\w+).*$','\1') first_word
from film;
select * from table(dbms_xplan.display);
Plan hash value: 1232367652
--------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
--------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 10 | 50 | 3 (0)| 00:00:01 |
| 1 | TABLE ACCESS FULL| FILM | 10 | 50 | 3 (0)| 00:00:01 |
--------------------------------------------------------------------------
Query that uses index
Now add the extra condition and the query will use the index. I'm not sure why it uses an INDEX FULL SCAN instead of an INDEX FAST FULL SCAN. With such small sample data it doesn't matter. The important point is that an index is used.
explain plan for
select regexp_replace(film.title, '(\w+).*$','\1') first_word
from film
where regexp_replace(film.title, '(\w+).*$','\1') is not null;
select * from table(dbms_xplan.display);
Plan hash value: 1151375616
------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 10 | 50 | 1 (0)| 00:00:01 |
|* 1 | INDEX FULL SCAN | FILM_IDX1 | 10 | 50 | 1 (0)| 00:00:01 |
------------------------------------------------------------------------------
Predicate Information (identified by operation id):
---------------------------------------------------
1 - filter( REGEXP_REPLACE ("TITLE",'(\w+).*$','\1') IS NOT NULL)

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