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I was attempting to do what I thought should be a very basic script as my first bit of ruby code. Perhaps someone can help me out with what's going on.
./delete_file.rb: line 3: puts: command not found
./delete_file.rb: line 4: auth_token: command not found
./delete_file.rb: line 6: puts: command not found
User1$ cat delete_file.rb
# /usr/bin/ruby
# Delete file script
puts "Enter current token"
auth_token = gets.chomp
puts "data goes here" + auth_token + "more data here"
first line of file should be:
#!/usr/bin/ruby
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i want to copy some files from ../soft to ../copu_new. The name of that tests are in ../sim/soft.txt.
I had en error : cp:cannot stat '../soft/file1.txt\file2.txt\file3.txt': File too long
Follow the code below:
input="../sim/soft.txt"
while read line
do
##to skip the first line of the file
a=$(tail -n +1)
##From string to table
for i in $a
do
table_soft[$i]="$i"
done
for i in "${tabke_soft[#]}"
do
cp ../soft/$i ../copy_new
done
done < $input
The file Soft.txt is :
###This all tests:
file1.txt
file2.txt
file3.txt
It's most likely the classic bash issue where trying to run an array through a for loop gives you all the content unless you wrap it in double quotes first. Try this..
a="$(tail -n +1)"
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I have a '.GS3' file with multiple lines like this one:
0123456789 aaa.aaa3456
I want to separate it like this:
01234;56789 ;aaa.aaa;3456
I know the start and end of each part of the line. Is it possible to do this considering multiple lines? For example:
0123456789 aaa.aaa3456
aaaaabbbbbbbxxxxxxxwwww
Into
01234;56789 ;aaa.aaa;3456
aaaaa;bbbbbbb;xxxxxxx;wwww
.. but if it does have fixed lengths you can do it this way:
$ sed -r 's/^(.{5})(.{7})(.{7})(.{4})$/\1;\2;\3;\4/' test.txt
01234;56789 ;aaa.aaa;3456
aaaaa;bbbbbbb;xxxxxxx;wwww
I think .{5} is self explanatory. Due to the -r option the first group (.{5}) can be referenced by \1. It's a group due to ( and ).
The characters ^ and $ represent the beginning and ending of every line in the file test.txt.
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This is my text file and I want to remove every first line:
aaaa
bbbb/bbbb
/cccc/cccc
/Dddd/zzzz/wwww
.gggg
.oooo/sssss
/.vvvvv
!#%#/$%
How can I remove all first "/" from my text file?
I want the result text file to be like:
aaaa
bbbb/bbbb
cccc/cccc
Dddd/zzzz/wwww
.gggg
.oooo/sssss
.vvvvv
!#%#/$%
if it's any help, I'm using sed command.
sed can be instructed to replace the first / of each line with nothing:
sed 's_^/__' 'my text file name'
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I have this ruby program to parse a CSV file. I am missing a endif somewhere and I cannot figure out.
require 'csv'
prevrow=nil
newarray=Array.new
CSV.foreach("\\\\192.168.0.1\\fe18cb0618cabd41\\ninjatrader\\uniqueside.csv", col_sep: ',') do |row|
if(prevrow==nil)
# do nothing
newarray<<row
prevrow=row
elsif (prevrow!=nil and row[0]!=prevrow[0] )
# do something
newarray<<row
prevrow=row
##count=1
elsif(prevrow!=nil and row[0]=prevrow[0] and ##count<4)
puts "new date"
newarray<<row
prevrow=row
##count++
end
end
removesamedirctiontop4.rb:23: syntax error, unexpected keyword_else
removesamedirctiontop4.rb:27: syntax error, unexpected end-of-input, expecting keyword_end
#count++ is not valid ruby. The final "plus" is expecting another parameter and thinks it's on the next line, so the line ends up being interpreted as...
`#count + +end`
So you have an invalid statement and you lose an end.
Change the offending line to
#count += 1
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I am writing a Ruby script to unzip a file where each pass through the %x{unzip } will have a different file name.
I have been successful getting
%x{unzip FILENAME.ZIP} to unzip the contents of FILENAME.ZIP
However, I want to be able to pass in the name of the file to unzip.
I've tried variations of
filename = "CONSTANT+variable+"NEXT_CONSTANT.ZIP"
%x{${filename}}
and I have been unable to get the %x to let me construct a filename that I want to unzip.
You can do it the same way you'd do it in a double-quoted string: #{filename}.
filename = "my_files.zip"
%x{unzip #{filename}}