I have getting data from a database and using
$query = $this->db->query("SELECT * FROM mytable");
echo $this->dbutil->csv_from_result($query);
however I want to change the name of my headers for the CSV for first_name is First Name...how would I go about doing that?
Thanks,
J
Try renaming the columns returned by the sql query:
$query = $this->db->query("
SELECT
first_name as 'First Name', last_name as 'Last Name'
FROM mytable
");
The downside is that you will have to list the columns instead of a simple *.
Related
SQL table:
SELECT id,
account_name,
parent_id
FROM
(SELECT id,
account_name,
parent_id,
CASE
WHEN id = 1 THEN #idlist := CONCAT(id)
WHEN FIND_IN_SET(parent_id, #idlist) THEN #idlist := CONCAT(#idlist, ',', id)
END AS checkId
FROM chart_of_account
ORDER BY id ASC) AS T
WHERE checkId IS NOT NULL
When I run this query in MySQL it works fine and the result is fetched perfectly, but when I run it in Laravel like this:
$accountId = DB::select('SELECT id,account_name,parent_id FROM
(SELECT id,account_name,parent_id,
CASE WHEN id = '.$account_id.' THEN #idlist := CONCAT(id)
WHEN FIND_IN_SET(parent_id,#idlist) THEN #idlist := CONCAT(#idlist,', ',id)
END as checkId
FROM chart_of_account
ORDER BY id ASC) as T
WHERE checkId IS NOT NULL');
it gives an error.
Argument 1 passed to Illuminate\\Database\\Connection::prepareBindings() must be of the type array, string given,
Try this:
$query = 'YOUR_QUERY_THE_BIG_ONE:)';
$result = DB::select($query,[]);
dd($result);
Optionally, you can use ? sign in your query wherever you are using user inputs to prevent mySQL injection issue and then provide their value in second parameter array of select function. One example would be:
$inputUserEmail = $request->input('email');
$query = 'SELECT * FROM users WHERE email=?';
$result = DB::select($query,[$inputUserEmail]);
dd($result);
I hope it gives you an idea
How to use like clause in code iginiter query() WITH BIND PARAMS?
Eg:
When I use
$query = 'SELECT mycol FROM mytable WHERE name LIKE %?';
$name = 'foo';
$db->this->query($query,array($name));
//the clause generated
//SELECT mycol FROM mytable WHERE id LIKE '%'foo'%'
//I expected this
//SELECT mycol FROM mytable WHERE id LIKE '%foo'
I don't to put param values inside query and use like below:
$query = 'SELECT mycol FROM mytable WHERE name LIKE '%foo';
Also I can not use $this->db->like() function as my query consists of:
INSERT IGNORE
and
INSERT INTO table SELECT col FROM table2;
Please suggests?
Thanks,
just use CodeIgniter Query Builder
$name = 'foo';
$query = $this
->db
->select('mycol')
->like('name', $name)
->get('mytable');
$query = 'SELECT mycol FROM mytable WHERE name LIKE ?';
$name = '%foo';
$this->db->query($query,array($name));
codeigniter will replace ? with 'params' value.
if you write this
$query = 'SELECT mycol FROM mytable WHERE name LIKE %?';
$name = 'foo';
//$db->this->query($query,array($name)); //you wrote this line wrong.
//it should be like this
$this->db->query($query,array($name));
it will produce
SELECT mycol FROM mytable WHERE name LIKE %'foo' //inverse comma after % ,actually before and after foo.
So your right way will be
$query = 'SELECT mycol FROM mytable WHERE name LIKE ?';
$name = '%foo';
$this->db->query($query,array($name));
It will produce
SELECT mycol FROM mytable WHERE name LIKE '%foo'
NOTE
You wrote this which is wrong
$db->this->query($query,array($name));
Right way
$this->db->query($query,array($name));
$code = Array(1,2,3,4)
$sql = "SELECT * FROM Table1 WHERE Field1 IN (?)";
$query = $this->db->query($sql, array($code));
$this->db->last_query() will show
"SELECT * FROM Table1 WHERE Field1 IN ('1,2,3,4')"
How can I remove the single quote in the IN condition?
Even if the $code is array of strings, example
$code = Array('This one', 'Next code', 'And this')
the statement will be:
"SELECT * FROM Table1 WHERE Field1 IN ('This one, Next Code, And This')"
Am I missing something ?
TIA.
You can use this simple and alternate way
$this->db->where_in('Field1',$code);
$this->db->get('Table1');
From codeigniter active record manual
$this->db->where() accepts an optional third parameter. If you set it
to FALSE, CodeIgniter will not try to protect your field or table
names with backticks.
$this->db->where('MATCH (field) AGAINST ("value")', NULL, FALSE);
So, put a 3rd parameter on a where clause with FALSE
Then your query should be
$this->db->select('*')
->where('Field1 IN('.$code.'),NULL,FALSE)
->get('Table1');
I have a following table and I want to know how to write the inset query using JDatabaseQuery in Joomla.
jos_esolutions_movies - table name
id, name, description, status - field names
1 , 'ABC' , 'ABC description', 0 - example values
$db = JFactory::getDbo();
$query = $db->getQuery(true);
$query->insert('#__tablename');
$query->set("field1='values1', field2='values2'");
$db->setQuery($query);
$db->query();
the following link will help you to create a joomla database query http://docs.joomla.org/How_to_use_the_database_classes_in_your_script
$db =& JFactory::getDBO();
$query = "insert into #__esolutions_movies (id, name, description, status) values(1 , 'ABC' , 'ABC description', 0)";
$db->setQuery($query);
$db->query();
I have a query similar to this:
SELECT username
FROM users
WHERE locationid IN
(SELECT locationid FROM locations WHERE countryid='$')
$ is a value I get from end user.
How could I run this query in CodeIgniter? I can't find a solution in CodeIgnite's user guide.
Thank you so much for your answers!
Regards!
Look here.
Basically you have to do bind params:
$sql = "SELECT username FROM users WHERE locationid IN (SELECT locationid FROM locations WHERE countryid=?)";
$this->db->query($sql, '__COUNTRY_NAME__');
But, like Mr.E said, use joins:
$sql = "select username from users inner join locations on users.locationid = locations.locationid where countryid = ?";
$this->db->query($sql, '__COUNTRY_NAME__');
Note that these solutions use the Code Igniter Active Records Class
This method uses sub queries like you wish but you should sanitize $countryId yourself!
$this->db->select('username')
->from('user')
->where('`locationId` in', '(select `locationId` from `locations` where `countryId` = '.$countryId.')', false)
->get();
Or this method would do it using joins and will sanitize the data for you (recommended)!
$this->db->select('username')
->from('users')
->join('locations', 'users.locationid = locations.locationid', 'inner')
->where('countryid', $countryId)
->get();
Also, to note - the Active Record Class also has a $this->db->where_in() method.
I think you can create a simple SQL query:
$sql="select username from user where id in (select id from idtables)";
$query=$this->db->query($sql);
and then you can use it normally.