$code = Array(1,2,3,4)
$sql = "SELECT * FROM Table1 WHERE Field1 IN (?)";
$query = $this->db->query($sql, array($code));
$this->db->last_query() will show
"SELECT * FROM Table1 WHERE Field1 IN ('1,2,3,4')"
How can I remove the single quote in the IN condition?
Even if the $code is array of strings, example
$code = Array('This one', 'Next code', 'And this')
the statement will be:
"SELECT * FROM Table1 WHERE Field1 IN ('This one, Next Code, And This')"
Am I missing something ?
TIA.
You can use this simple and alternate way
$this->db->where_in('Field1',$code);
$this->db->get('Table1');
From codeigniter active record manual
$this->db->where() accepts an optional third parameter. If you set it
to FALSE, CodeIgniter will not try to protect your field or table
names with backticks.
$this->db->where('MATCH (field) AGAINST ("value")', NULL, FALSE);
So, put a 3rd parameter on a where clause with FALSE
Then your query should be
$this->db->select('*')
->where('Field1 IN('.$code.'),NULL,FALSE)
->get('Table1');
Related
SQL table:
SELECT id,
account_name,
parent_id
FROM
(SELECT id,
account_name,
parent_id,
CASE
WHEN id = 1 THEN #idlist := CONCAT(id)
WHEN FIND_IN_SET(parent_id, #idlist) THEN #idlist := CONCAT(#idlist, ',', id)
END AS checkId
FROM chart_of_account
ORDER BY id ASC) AS T
WHERE checkId IS NOT NULL
When I run this query in MySQL it works fine and the result is fetched perfectly, but when I run it in Laravel like this:
$accountId = DB::select('SELECT id,account_name,parent_id FROM
(SELECT id,account_name,parent_id,
CASE WHEN id = '.$account_id.' THEN #idlist := CONCAT(id)
WHEN FIND_IN_SET(parent_id,#idlist) THEN #idlist := CONCAT(#idlist,', ',id)
END as checkId
FROM chart_of_account
ORDER BY id ASC) as T
WHERE checkId IS NOT NULL');
it gives an error.
Argument 1 passed to Illuminate\\Database\\Connection::prepareBindings() must be of the type array, string given,
Try this:
$query = 'YOUR_QUERY_THE_BIG_ONE:)';
$result = DB::select($query,[]);
dd($result);
Optionally, you can use ? sign in your query wherever you are using user inputs to prevent mySQL injection issue and then provide their value in second parameter array of select function. One example would be:
$inputUserEmail = $request->input('email');
$query = 'SELECT * FROM users WHERE email=?';
$result = DB::select($query,[$inputUserEmail]);
dd($result);
I hope it gives you an idea
I have a perl code which queries the Oracle 11G database to pull the count of the 'values' from a table.
$sqlStatement="SELECT count(values) FROM Table WHERE values IN ('value1','value2','value3',.... 'valuen')"
How can I pass the values in query through a subroutine's argument?
For example:
$sqlStatement="SELECT count(values) FROM Table WHERE values IN ($values)
subroutine($values)
Wouldn't it make more sense to pass in the values using an array rather than a scalar?
count_values(#values);
Then the subroutine could start like this:
sub count_values {
my #values = #_;
my $sql = 'select count(values) from table where values in (';
$sql .= join ',', ('?') x #values;
$sql .= ')';
my $sth = $dbh->prepare($sql);
$sth->execute(#values);
my $count = ($sth->fetchrow_array)[0];
}
How to use like clause in code iginiter query() WITH BIND PARAMS?
Eg:
When I use
$query = 'SELECT mycol FROM mytable WHERE name LIKE %?';
$name = 'foo';
$db->this->query($query,array($name));
//the clause generated
//SELECT mycol FROM mytable WHERE id LIKE '%'foo'%'
//I expected this
//SELECT mycol FROM mytable WHERE id LIKE '%foo'
I don't to put param values inside query and use like below:
$query = 'SELECT mycol FROM mytable WHERE name LIKE '%foo';
Also I can not use $this->db->like() function as my query consists of:
INSERT IGNORE
and
INSERT INTO table SELECT col FROM table2;
Please suggests?
Thanks,
just use CodeIgniter Query Builder
$name = 'foo';
$query = $this
->db
->select('mycol')
->like('name', $name)
->get('mytable');
$query = 'SELECT mycol FROM mytable WHERE name LIKE ?';
$name = '%foo';
$this->db->query($query,array($name));
codeigniter will replace ? with 'params' value.
if you write this
$query = 'SELECT mycol FROM mytable WHERE name LIKE %?';
$name = 'foo';
//$db->this->query($query,array($name)); //you wrote this line wrong.
//it should be like this
$this->db->query($query,array($name));
it will produce
SELECT mycol FROM mytable WHERE name LIKE %'foo' //inverse comma after % ,actually before and after foo.
So your right way will be
$query = 'SELECT mycol FROM mytable WHERE name LIKE ?';
$name = '%foo';
$this->db->query($query,array($name));
It will produce
SELECT mycol FROM mytable WHERE name LIKE '%foo'
NOTE
You wrote this which is wrong
$db->this->query($query,array($name));
Right way
$this->db->query($query,array($name));
I have getting data from a database and using
$query = $this->db->query("SELECT * FROM mytable");
echo $this->dbutil->csv_from_result($query);
however I want to change the name of my headers for the CSV for first_name is First Name...how would I go about doing that?
Thanks,
J
Try renaming the columns returned by the sql query:
$query = $this->db->query("
SELECT
first_name as 'First Name', last_name as 'Last Name'
FROM mytable
");
The downside is that you will have to list the columns instead of a simple *.
I have the following mysql query. Could you please tell me how to write the same query in Codeigniter's way ?
SELECT * FROM myTable
WHERE trans_id IN ( SELECT trans_id FROM myTable WHERE code='B')
AND code!='B'
You can use sub query way of codeigniter to do this for this purpose you will have to hack codeigniter. like this
Go to system/database/DB_active_rec.php
Remove public or protected keyword from these functions
public function _compile_select($select_override = FALSE)
public function _reset_select()
Now subquery writing in available
And now here is your query with active record
$this->db->select('trans_id');
$this->db->from('myTable');
$this->db->where('code','B');
$subQuery = $this->db->_compile_select();
$this->db->_reset_select();
// And now your main query
$this->db->select("*");
$this->db->where_in("$subQuery");
$this->db->where('code !=', 'B');
$this->db->get('myTable');
And the thing is done. Cheers!!!
Note : While using sub queries you must use
$this->db->from('myTable')
instead of
$this->db->get('myTable')
which runs the query.
Watch this too
How can I rewrite this SQL into CodeIgniter's Active Records?
Note : In Codeigntier 3 these functions are already public so you do not need to hack them.
$data = $this->db->get_where('columnname',array('code' => 'B'));
$this->db->where_in('columnname',$data);
$this->db->where('code !=','B');
$query = $this->db->get();
return $query->result_array();
Try this one:
$this->db->select("*");
$this->db->where_in("(SELECT trans_id FROM myTable WHERE code = 'B')");
$this->db->where('code !=', 'B');
$this->db->get('myTable');
Note: $this->db->select("*"); is optional when you are selecting all columns from table
try this:
return $this->db->query("
SELECT * FROM myTable
WHERE trans_id IN ( SELECT trans_id FROM myTable WHERE code='B')
AND code!='B'
")->result_array();
Is not active record but is codeigniter's way http://codeigniter.com/user_guide/database/examples.html
see Standard Query With Multiple Results (Array Version) section
you can use a simpler approach, while still using active record
$this->db->select("a.trans_id ,a.number, a.name, a.phone")
$this->db->from("Name_Of_Your_Table a");
$subQueryIn = "SELECT trans_id FROM Another_Table";
$this->db->where("a.trans_id in ($subQueryIn)",NULL);