There are records in table for particular date. But when I query with that value, I am unable to filter the records.
select * from TBL_IPCOLO_BILLING_MST
where LAST_UPDATED_DATE = '03-09-21';
The dates are in dd-mm-yy format.
To the answer by Valeriia Sharak, I would just add a few things since your question is tagged Oracle. I was going to add this as a comment to her answer, but it's too long.
First, it is bad practice to compare dates to strings. Your query, for example, would not even execute for me -- it would end with ORA-01843: not a valid month. That is because Oracle must do an implicit type conversion to convert your string "03-09-21" to a date and it uses the current NLS_DATE_FORMAT setting to do that (which in my system happens to be DD-MON-YYYY).
Second, as was pointed out, your comparison is probably not matching rows due LAST_UPDATED_DATE having hours, minutes, and seconds. But a more performant solution for that might be:
...
WHERE last_update_date >= TO_DATE('03-09-21','DD-MM-YY')
AND last_update_date < TO_DATE('04-09-21','DD-MM-YY')
This makes the comparison without wrapping last_update_date in a TRUNC() function. This could perform better in either of the following circumstances:
If there is an index on last_update_date that would be useful in your query
If the table with last_update_date is large and is being joined to other tables (because it makes it easier for Oracle to estimate the number of rows from your table that are inputs to the join).
Your column might contain hours and seconds, but they can be hidden.
So when you filter on the date, oracle implicitly adds time to the date. So basically you are filtering on '03-09-21 00:00:00'
Try to trunc your column:
select * from TBL_IPCOLO_BILLING_MST
where trunc(LAST_UPDATED_DATE) = '03-09-21';
Hope, I understood your question correctly.
Oracle docs
I have three timestamps in my SQL Table.
Column Name Data Type Nullable Data_Default
STATUS_TIMSTM TIMESTAMP(6) No (null)
CREATED_TIMSTM TIMESTAMP(6) No SYSTIMESTAMP
UPDATED_TIMSTM TIMESTAMP(6) No (null)
INSERT INTO "TABLE_NAME" ("STATUS_TIMSTM","CREATED_TIMSTM","UPDATED_TIMSTM")
VALUES(TIMESTAMP '2020-12-10 00:00:00', TIMESTAMP '2020-06-15 00:00:00',TIMESTAMP '2020-06-15 00:00:00');
The above works correctly.
How do I insert the current systimestamp?
I've tried several options: curdate(), now(), systimestamp().
I usually get errors such as Error report -
SQL Error: ORA-00904: "NOW": invalid identifier 00904. 00000 - "%s: invalid identifier"
You should be able to use current_timestamp:
create table t (x TIMESTAMP(6));
insert into t (x) values (current_timestamp);
Of course, systimestamp should also work.
Here is a db<>fiddle.
Since you already have a DATA DEFAULT, only inserting data in below format must populate the CREATED_TIMSTM column with current TIMESTAMP.
INSERT INTO "TABLE_NAME" ("STATUS_TIMSTM","UPDATED_TIMSTM")
VALUES(TIMESTAMP '2020-12-10 00:00:00', TIMESTAMP '2020-06-15 00:00:00');
Here is a simplified DB fiddle demonstrating the same.
In Oracle you would
insert into my_table(timestamp_column) values (systimestamp);
Notice that the function call does not include parentheses after the function name. Oracle is pretty odd in this regard; functions that don't take parameters, but that you define yourself, must use empty parentheses, but similar functions (no parameters) that are provided by Oracle must be used without parentheses. Only Oracle knows why it's inconsistent this way. This explains why your attempt was failing.
(Actually, some experimentation with systimestamp shows that it can take an argument - a positive integer which shows how many decimal places you want for seconds! In any case, you can't use it with empty parentheses.)
There are other "current" timestamp functions, but they do different things. systimestamp returns the timestamp of the computer system that hosts the database server. (Note that this may, and often is, different from the database timestamp.) In any case, systimestamp is by far the most commonly used of these; similar to sysdate for dates.
Beware of time zone though. systimestamp returns timestamp with time zone. By inserting it into a timestamp column, you are losing information. Is that OK for your business application?
We are using oracle 12c forms and reports. In one of the query the users will enter the date through forms and the below mentioned query will fetch the required data.
SELECT COUNT(*)
FROM T_APPLICATION_HDR,T_APPLN_PENSIONER
WHERE APPLN_PK=APEN_APPLN_PK
AND APPLN_DATE <=:APPLN_DATE
AND APPLN_SECN_ID ='PV1'
AND APPLN_STAT='04'
What i require is from the above query the data fetched will be prior to the date entered by the users. I want to add 10 days to the date entered by users and records populated based on that date.
i modified the above query like this
SELECT COUNT(*)
FROM T_APPLICATION_HDR,T_APPLN_PENSIONER
WHERE APPLN_PK=APEN_APPLN_PK
AND APPLN_DATE <=:APPLN_DATE+10
AND APPLN_SECN_ID ='PV1'
AND APPLN_STAT='04'
It gives this error
ORA-00932: inconsistent datatypes: expected DATE got NUMBER.
How do i modify this query
i modified the above query like this
SELECT COUNT(*)
FROM T_APPLICATION_HDR,T_APPLN_PENSIONER
WHERE APPLN_PK=APEN_APPLN_PK
AND APPLN_DATE <=:APPLN_DATE+10
AND APPLN_SECN_ID ='PV1'
AND APPLN_STAT='04'
For example if the appln_date entered is 10-may-2019, then the query should fetch records prior to 20-may-2019.
It gives this error
ORA-00932: inconsistent datatypes: expected DATE got NUMBER.
How do i modify this query
'10-may-2019' is not a date, it's text string. In the first case Oracle is smart enough to convert the text string to a date. In the first case Oracle is able to do the conversion but in the second case it gets confused.
I suggest changing your code to be
SELECT COUNT(*)
FROM T_APPLICATION_HDR,T_APPLN_PENSIONER
WHERE APPLN_PK=APEN_APPLN_PK
AND APPLN_DATE <= TO_DATE(:APPLN_DATE, 'DD-MON-YYYY') + INTERVAL '10' DAY
AND APPLN_SECN_ID ='PV1'
AND APPLN_STAT='04'
I have a table with one column data type as 'timestamp'. Whenever i try to do some queries on the table, even simple select statement i am getting errors.
example of a row in my column,
'2014-01-01 05:05:20.664592-08'
The statement i am trying,
'select * from mytable limit 10;'
the error i am getting is
'Failed with exception java.io.IOException:java.lang.NumberFormatException: For input string: "051-08000"'
Date functions in hive like TO_DATE are also not working.If i change the data type to string, i am able to extract the date part using substring. But i need to work with timestamp.
Has anyone faced this error before? Please let me know.
Hadoop is having trouble understanding '2014-01-01 05:05:20.664592-08' as a timestamp because of the "592-08" at the end. You should change the datatype to string, cut off the offending portion with a string function, then cast back to timestamp:
select cast(substring(time_stamp_field,1,23) as timestamp) from mytable
Get the above error when the execute immediate is called in a loop
Update CustomersPriceGroups set 1AO00=:disc Where cuno=:cuno
Parameters: disc=66 cuno=000974
Update CustomersPriceGroups set 1AP00=:disc Where cuno=:cuno
Parameters: disc=70.5 cuno=000974
Update CustomersPriceGroups set 1AQ00=:disc Where cuno=:cuno
Parameters: disc=66 cuno=000974
Update CustomersPriceGroups set 1ZA00=:disc Where cuno=:cuno
Parameters: disc=60 cuno=000974
What does this mean ?
Here is the code fragment
c:=PriceWorx.frcPriceListCustomers('020','221');
LOOP
fetch c into comno,cuno,nama,cpls;
exit when c%notfound;
dbms_output.put_Line(cuno);
g:=priceWorx.frcPriceListItemGroups('020','221');
d:=priceworx.frcCustomerDiscounts('020','221',cuno);
loop
fetch g into comno,cpgs,n;
fetch d into comno,cpls,cuno,cpgs,stdt,tdat,qanp,disc,src;
--dbms_output.put(chr(9)||cpgs);
sQ:='Update saap.CustomersPriceGroups set "'|| trim(cpgs)||'"=:disc '
|| ' Where cuno=:cuno';
execute immediate sQ using disc,cuno;
commit;
dbms_output.put_line( sQ );
dbms_output.put_line( chr(9)||'Parameters: disc='|| disc||' cuno='||cuno);
exit when g%notfound;
end loop;
close g;
close d;
end loop;
check your query for double comma.
insert into TABLE_NAME (COLUMN1, COLUMN2,,COLUMN3) values(1,2,3);
(there is extra comma after COLUMN2).
Update: recently (some people have special talents) i succeed to get same exception with new approach:
update TABLE_NAME set COLUMN1=7, set COLUMN2=8
(second SET is redundant)
Unquoted identifiers must begin with an alphabetic character (see rule 6 here). You're trying to assign a value to a column with a name starting with a number 1AO00, 1AP00 etc.
Without seeing the table definition for CustomersPriceGroups we don't know if it has columns with those names. If it does then they must have been created as quoted identifiers. If so you'll have to refer to them (everywhere) with quotes, which is not ideal - makes the code a bit harder to read, makes it easy to make a mistake like this, and can be hard to spot what's wrong. Even Oracle say, on the same page:
Note: Oracle does not recommend using quoted identifiers for database
object names. These quoted identifiers are accepted by SQL*Plus, but
they may not be valid when using other tools that manage database
objects.
In you code you appear to be using quotes when you assign sQ, but the output you show doesn't; but it doesn't have the saap. schema identifier either. That may be because you're not running the version of the code you think, but might just have been
lost if you retyped the data instead of pasting it - you're not showing the earlier output of c.cuno either. But it's also possible you have, say, the case of the column name wrong.
If the execute is throwing the error, you won't see the command being executed that time around the loop because the debug comes after it - you're seeing the successful values, not the one that's breaking. You need to check all the values being returned by the functions; I suspect that g is returning a value for cpgs that actually isn't a valid column name.
As #ninesided says, showing more information, particularly the full exception message, will help identify what's wrong.
It means that the Oracle parser thinks that one of your columns is not valid. This might be because you've incorrectly referenced a column, the column name is reserved word, or because you have a syntax error in the UPDATE statement that makes Oracle think that something which is not a column, is a column. It would really help to see the full statement that is being executed, the definition of the CustomersPriceGroups table and the full text of the exception being raised, as it will often tell which column is at fault.
if you add a extra "," at the end of the set statement instead of a syntax error, you will get ORA-01747, which is very very odd from Oracle
e.g
update table1
set col1 = 'Y', --this odd 1
where col2 = 123
and col3 = 456
In addition to reasons cited in other answers here, you may also need to check that none of your table column names have a name which is considered a special/reserved word in oracle database.
In my case I had a table column name uid. uid is a reserved word in oracle and therefore I was getting this error.
Luckly, my table was a new table and I had no data in it. I was a able to use oracle DROP table command to delete the table and create a new one with a modified name for the problem column.
I also had trouble with renaming the problem column as oracle wouldn't let me and kept throwing errors.
You used oracle keyword in your SQL statement
And I was writing query like. I had to remove [ and ]
UPDATE SN.TableName
SET [EXPIRY_DATE] = systimestamp + INTERVAL '12' HOUR,
WHERE [USER_ID] ='12345'
We recently moved from SQL Server to Oracle.
The cause may also be when you group by a different set of columns than in select for example:
select tab.a, tab.b, count(*)
from ...
where...
group by tab.a, tab.c;
ORA-01747: invalid user.table.column, table.column, or column
specification
You will get when you miss the column relation when you compare both column id your is will not be the same check both id in your database
Here is the sample Example which I was facing:
UPDATE TABLE_NAME SET APPROVED_BY='1000',CHECK_CONDITION=ID, WHERE CONSUMER_ID='200'
here Issue you will get when 'CHECK_CONDITION' and 'ID' both column id will no same
If both id will same this time your query will execute fine, Check id Id both Column you compare in your code.
For me, the issue was due to use to column name "CLUSTER" which is a reserved word in Oracle. I was trying to insert into the column. Renaming the column fixed my issue.
insert into table (JOB_NAME, VERSION, CLUSTER, REPO, CREATE_TS) VALUES ('abc', 169, 'abc.war', '1.3', 'test.com', 'test', '26-Aug-19 04.27.09.000000949 PM')
Error at Command Line : 1 Column : 83
Error report -
SQL Error: ORA-01747: invalid user.table.column, table.column, or column specification
In my case, I had some.* in count. like count(dr.*)