tmux OSX 10.8.3 show ipaddress - osx-mountain-lion

I am trying to display my ipaddress and the date on the right side of my tmux status line. I have the following command:
set -g status-right "#[fg-cyan]#(ifconfig | awk '$1 == "inet" { print $2 }') #[fg=cyan]%d %b %R"
It is displaying the date but not the ipaddress. I am not getting any error from Tmux so I am not sure what is going wrong.
Any help is apprecited!


Check the value that actually ends up being set:
tmux show-option -g | grep status-right
I expect that you will find that there are no double quotes around inet. The double quote parsing does not consider the #() syntax as special (unlike "$()" in shells, where you can simply use double quotes inside the command substitution). Thus, the parsing is done in three pieces:
"#[fg-cyan]#(ifconfig | awk '$1 == "
inet
" { print $2 }') #[fg=cyan]%d %b %R"
These are concatenated into this:
#[fg-cyan]#(ifconfig | awk '$1 == inet { print $2 }') #[fg=cyan]%d %b %R
As an awk program, this ends up checking $1 against an unset variable named inet instead of the literal string "inet"; awk will probably not complain, but no lines will ever match.
You can escape the double quotes to let them pass into the final string:
set -g status-right "#[fg-cyan]#(ifconfig | awk '$1 == \"inet\" { print $2 }') #[fg=cyan]%d %b %R"
When I set this, I just see 127.0.0.1 though; you might want to add a |tail -1 to use the last line instead of the first.
Two other items:
you have [fg- instead of [fg=, and
since you are specifying the same color in both place, you can probably just omit the second one.
Thus:
set -g status-right "#[fg=cyan]#(ifconfig | awk '$1 == \"inet\" { print $2 }'|tail -1) %d %b %R"

Related

awk match by variable with dot in it

I have a script that will iterate over a file containing domains (google.com, youtube.com, etc). The purpose of the script is to check how many times each domain is included in the 12th column of a tab seperated value file.
while read domain; do
awk -F '\t' '$12 == '$domain'' data.txt | wc -l
done < domains.txt
However awk seems to be interpretating the dots in the domains as a special character. The following error message is shown:
awk: syntax error at source line 1
context is
$12 ~ >>> google. <<< com
awk: bailing out at source line 1
I am a beginner in bash so any help would be greatly appreciated!

When you write:
domain='google.com'
awk -F '\t' '$12 == '$domain'' data.txt
the $domain is outside of any quotes:
awk -F '\t' '$12 == '$domain' ' data.txt
< > < >
start end start end
and so exposed to the shell for interpretation first and THEN it becomes part of the body of the awk script before awk sees it. So what awk sees is:
awk -F '\t' '$12 == google.com' data.txt
and google.com is not a valid symbol (e.g. variable or function) name nor string nor number. What you MEANT to do was:
awk -F '\t' '$12 == "'"$domain"'"' data.txt
so the shell would see "$domain" instead of just $domain (see https://mywiki.wooledge.org/Quotes for why that's important) and awk would finally see:
awk -F '\t' '$12 == "google.com"' data.txt
which is fine as now "google.com" is a string, not a symbol BUT you should never allow shell variables to expand to become part of an awk script as there are other caveats so what you should really have done is:
awk -F '\t' -v dom="$domain" '$12 == dom' data.txt
See How do I use shell variables in an awk script? for more information.
By the way, even after fixing the above problem do not do this:
while read domain; do
awk -F '\t' -v dom="$domain" '$12 == dom' data.txt | wc -l
done < domains.txt
as it'll be immensely slow and contains insidious bugs (see why-is-using-a-shell-loop-to-process-text-considered-bad-practice). Do something like this instead (untested):
awk -F'\t' '
NR==FNR {
cnt[$1] = 0
next
}
$12 in cnt {
cnt[$12]++
}
END {
for ( dom in cnt ) {
print dom, cnt[dom]
}
}
' domains.txt data.txt
That will be far more efficient, robust, and portable than calling awk inside a shell read loop.
See What are NR and FNR and what does "NR==FNR" imply? for how that awk script works. Get the book Effective AWK Programming, 5th Edition, by Arnold Robbins to learn awk.

awk -F '\t' '$12 == '$domain'' data.txt | wc -l
The single quotes are building an awk program. They are not something visible to awk. So awk sees this:
$12 == google.com
Since there aren't any quotes around google.com, that is a syntax error. You just need to add quotation marks.
awk -F '\t' '$12 == "'"$domain"'"' data.txt
The quotes jammed together like that are a little confusing, but it's just this:
'....' stuff to send to awk. Single quotes are for the shell.
'..."...' a double quote inside the awk program for awk to see
'...'"..." stuff in double quotes _outside_ the awk program for the shell
We can combine those like this:
'..."'"$var"'"...'
That's a bunch of literal awk code ending in a double-quote, followed by the expansion of the shell parameter var, which is double-quoted as usual in the shell for safety, followed by more literal awk code starting with a double quotes. So the end result is a string passed to awk that includes the value of the var inside double quotes.
But you don't have to be so fancy or confusing since awk provides the -v option to set variables from the shell:
awk -v domain="$domain" '$12 == domain' data.txt
Since the domain is not quoted inside the awk code, it is interpreted as the name of a variable. (Periods are not legal in variable names, which is why you got a syntax error with your domains; if you hadn't, though, awk would have treated them as empty and been looking for lines whose twelfth field was likewise blank.)

Use a combination of cut to print the 12th column of the TAB-delimited file, sort and uniq to count the items:
cut -f12 data.txt | sort | uniq -c

This should give the count of how many lines of the input has "google.com" in $12
{m,g}awk -v __="${domain}" '
BEGIN { _*=\
( _ ="\t[^\t]*")*gsub(".",(_)_,_)*sub(".","",_)*\
gsub("[.:&=/-]","[&]",__)*sub("[[][^[]+$",__"\t?",_)*(\
FS=_ } { _+=NF } END { print _-NR }'

How to make a '$N' within a string variable in a bash script be used as a operator in awk command when variable is expanded?

So due to the sugggestions Im gonna try be more conscise.
#!/bin/env bash
out1='$3 ~ "RB"'
out2='&& $3 ~ "F[0-9]"'
out3='&& $3 ~ /H*TF/'
printing=''"\t"'$3'
awk_output=$(awk -F, -v o1="$out1" -v o2="$out2" -v o3="$out3" -v p1="$printing" \
'o1 o2 o3 { print NR,p1}' test.csv)
dialog --title "title" \
--msgbox "$awk_output" 0 0
The above code is a example of a little program i am trying to write that takes a few user picked varibles, the outs and the printing variables at the top. And uses those to make a awk query of a database.
The problem is that the passed over variable strings contain a '$3' as an example. I want this to be read as a field operator in awk as it normally is but It is read as a literal string. Therefore when printing, awk prints the literal '$3' instead of the field it should represent in the csv file.
I have tried ENVIRON and SYMTAB with little success also. Has anyone come across this type of thing before as well?
Thank you, hope it was a bit more concise too.
jsut to clarify the output at the current moment is this:
1 $3
2 $3
3 $3
4 $3
5 $3
I would like the "$3" to actually represent a field of the csv file in the awk command. Something like this is what I am trying to get
1 "info from 3rd field in csv"
2 "info from 3rd field in csv"
3 "info from 3rd field in csv"
4 "info from 3rd field in csv"
5 "info from 3rd field in csv"

I want this to be read as a field operator in awk as it normally is but It is read as a literal string
So pass it as part of the command, not as a variable...
printing='$3'
awk -F, -v OFS='\t' "$out1 $out2 $out3 { print NR, $printing}" test.csv
Debug you shell scripts with set -x. Be sure to read about the difference between single and double quotes in shell and how the expansions happen.

A simpler approach is, rather than pass all the shell variables with special characters to awk, we can use printf to build the awk command and then use eval to execute and store the output.
Modified Script:
#!/bin/env bash
out1='$3 ~ "RB"'
out2='&& $3 ~ "F[0-9]"'
out3='&& $3 ~ /H*TF/'
printing='"\t"$3'
printf -v cmd $'awk -F, \'%s %s %s {print NR, %s}\'' "$out1" "$out2" "$out3" "$printing"
awk_output=$(eval "$cmd" test.csv)
dialog --title "title" \
--msgbox "$awk_output" 0 0
Explanation:
Changed printing='"\t"$3'. That is all is needed to print a tab in the output
Included the printf line. printf -v cmd $'awk -F, \'%s %s %s {print NR, %s}\'' "$out1" "$out2" "$out3" "$printing"
variables will be substituited in %s placeholders
Note $ in front of the awk -F, .... This is because the awk string contains '. To use literal ', we need to add $ before the string.
CSV used:
apple,orange,RBF1HTF
apple,orange,RBF2HTF
Output:

Awk add a variable to part of a column string

Objective
add "67" to column 1 of the output file with 67 being the variable ($iv) classified on the difference between 2 dates.
File1.csv
display,dc,client,20572431,5383594
display,dc,client,20589101,4932821
display,dc,client,23030494,4795549
display,dc,client,22973424,5844194
display,dc,client,21489000,4251031
display,dc,client,23150347,3123945
display,dc,client,23194965,2503875
display,dc,client,20578983,1522448
display,dc,client,22243554,920166
display,dc,client,20572149,118865
display,dc,client,23077785,28077
display,dc,client,21811100,5439
Current Output 3_file1.csv
BOB-UK-,display,dc,client,20572431,5383594,0.05,269.18
BOB-UK-,display,dc,client,20589101,4932821,0.05,246.641
BOB-UK-,display,dc,client,23030494,4795549,0.05,239.777
BOB-UK-,display,dc,client,22973424,5844194,0.05,292.21
BOB-UK-,display,dc,client,21489000,4251031,0.05,212.552
BOB-UK-,display,dc,client,23150347,3123945,0.05,156.197
BOB-UK-,display,dc,client,23194965,2503875,0.05,125.194
BOB-UK-,display,dc,client,20578983,1522448,0.05,76.1224
BOB-UK-,display,dc,client,22243554,920166,0.05,46.0083
BOB-UK-,display,dc,client,20572149,118865,0.05,5.94325
BOB-UK-,display,dc,client,23077785,28077,0.05,1.40385
BOB-UK-,display,dc,client,21811100,5439,0.05,0.27195
TOTAL,,,,,33430004,,1671.5
Desired Output 3_file1.csv
BOB-UK-67,display,dc,client,20572431,5383594,0.05,269.18
BOB-UK-67,display,dc,client,20589101,4932821,0.05,246.641
BOB-UK-67,display,dc,client,23030494,4795549,0.05,239.777
BOB-UK-67,display,dc,client,22973424,5844194,0.05,292.21
BOB-UK-67,display,dc,client,21489000,4251031,0.05,212.552
BOB-UK-67,display,dc,client,23150347,3123945,0.05,156.197
BOB-UK-67,display,dc,client,23194965,2503875,0.05,125.194
BOB-UK-67,display,dc,client,20578983,1522448,0.05,76.1224
BOB-UK-67,display,dc,client,22243554,920166,0.05,46.0083
BOB-UK-67,display,dc,client,20572149,118865,0.05,5.94325
BOB-UK-67,display,dc,client,23077785,28077,0.05,1.40385
BOB-UK-67,display,dc,client,21811100,5439,0.05,0.27195
TOTAL,,,,,33430004,,1671.5
Current Code
#! bin/sh
set -eu
de=$(date +"%d-%m-%Y" -d "1 month ago")
ds="15-04-2014"
iv=$(awk -vdate1=$de -vdate2=$ds 'BEGIN{split(date1, A,"-");split(date2, B,"-");year_diff=A[3]-B[3];if(year_diff){months_diff=A[2] + 12 * year_diff - B[2] + 1;} else {months_diff=A[2]>B[2]?A[2]-B[2]+1:B[2]-A[2]+1};print months_diff}')
for f in $(find *.csv); do
awk -F"," -v OFS=',' '{print "BOB-UK-"$iv,$0,0.05}' $f > "1_$f.csv" ##PROBLEM LINE##
awk -F"," -v OFS=',' '{print $0,$6*$7/1000}' "1_$f.csv" > "2_$f.csv" ##calculate price
awk -F"," -v OFS=',' '{print $0}; {sum+=$6}{sum2+=$8} END {print "TOTAL,,,,," (sum)",,"(sum2)}' "2_$f.csv" > "3_$f.csv" ##calculate total
done
Issue
When I run the first awk line (Marked as "## PROBLEM LINE##") the loop doesn't change column $1 to include the "67" after "BOB-UK-". This should be done with the print "BOB-UK-"$iv but instead it doesn't do anything. I suspect this is due to the way print works in awk but I haven't been able to work out a way to treat it within this row. Does anyone know if this is possible or do I need to create a new row to achieve this?

You have to pass the variable value to awk. awk does not inherit variables from the shell and does not expand $variable variables like shell. It is another tool with it's internal language.
awk -v iv="$iv" -F"," -v OFS=',' '{print "BOB-UK-"iv,$0,0.05}' "$f"
Tested in repl with the input provided.
for f in $(find *.csv)
Is useless use of find, makes no sense, just
for f in *.csv
Also note that you are creating 1_$f.csv, 2_$f.csv and 3_$f.csv files in the current directory in your loop, so the next time you run your script there will be 4 times more .csv files to iterate through. Dunno if that's relevant.
How $iv works in awk?
The $<number> is the field number <number> from the line in awk. So for example the $1 is the first field of the line in awk. The $2 is the second field. The $0 is special and it is the whole line.
The $iv expands to $ + the value of iv. So for example:
echo a b c | awk '{iv=2; print $iv}'
will output b, as the $iv expands to $2 then $2 expands to the second field from the input - ie. b.
Uninitialized variables in awk are initialized with 0. So $iv is substituted for $0 in your awk line, so it expands for the whole line.

How can I replace a / with a _ in a shell pipeline?

Running
ip -o -f inet addr show | grep $INTERNAL |awk '/scope global/ {print $4}'
Want to replace the / in my output to _ so rather than reading
10.168.122.59/16
it reads as
10.168.122.59_16
.
|sed s///_/
didnt help
Any suggestions?

All the postprocessing requested can be done internal to awk. Expanding a one-liner provided in a comment by #123 for better readability, this can look like the following:
ip -o -f inet addr show | \
awk -v i="$INTERNAL" '
$0 ~ i && /scope global/ {
sub(/\//, "_", $4);
print $4;
}'
Breaking down how this works:
awk -v i="$INTERNAL" defines an awk variable based on a shell variable. (As an aside, all-caps shell variable names are bad form; per POSIX convention, lowercase names are reserved for application use, whereas all-caps names can have meaning to the OS and surrounding tools).
$0 ~ i filters for the entire line ($0) matching the awk variable i.
/scope global/ by default is applied as a regex against $0 as well (it's equivalent to $0 ~ /scope global/).
sub(/\//, "_", $4) substitutes /s with _s in the fourth field.
print $4 prints that field.

You need to scape the / or use a different separator as below:
echo 10.168.122.59/16 | sed s:/:_:

echo 10.168.122.59/16| awk '{sub(/\//,"_")}1'
10.168.122.59_16

SSH call inside ruby, using %x

I am trying to make a single line ssh call from a ruby script. My script takes a hostname, and then sets out to return the hostname's machine info.
return_value = %x{ ssh #{hostname} "#{number_of_users}; #{number_of_processes};
#{number_of_processes_running}; #{number_of_processes_sleeping}; "}
Where the variables are formatted like this.
number_of_users = %Q(users | wc -w | cat | awk '{print "Number of Users: "\$1}')
number_of_processes = %Q(ps -el | awk '{print $2}' | wc -l | awk '{print "Number of Processes: "$1}')
I have tried both %q, %Q, and just plain "" and I cannot get the awk to print anything before the output. I either get this error (if I include the colon)
awk: line 1: syntax error at or near :
or if I don't include the slash in front of $1 I just get empty output for that line. Is there any solution for this? I thought it might be because I was using %q, but it even happens with just double quotes.

Use backticks to capture the output of the command and return the output as a string:
number_of_users = `users | wc -w | cat | awk '{print "Number of Users:", $1}'`
puts number_of_users
Results on my system:
48
But you can improve your pipeline:
users | awk '{ print "Number of Users:", NF }'
ps -e | awk 'END { print "Number of Processes:", NR }'

So the solution to this problem is:
%q(users | wc -w | awk '{print \"Number of Users: \"\$1}')
Where you have to use %q, not %, not %Q, and not ""
You must backslash double quotes and the dollar sign in front of any awk variables
If somebody could improve upon this answer by explaining why, that would be most appreciated
Though as Steve pointed out I could have improved my code using users | awk '{ print \"Number of Users:\", NF }'
In which case there is no need to backslash the NF.

Resources