Programming concept - data-structures

Question

I want to make a program that sort mail from junkmail using a point--system.
For some couple of words in the mail,
I want the program to give different points for each word that I have in my program categorized as "junkwords" where I also have assign different points for different words, so that each word is worth some amount of points.
My pseudocode:
Read text from file
Look for "junk words"
for each word that comes up give the point the word is worth.
If the total points for each junkword is 10 print "SPAM" followed by a list of words that were in the file and categorized as junkwords and their points.
Example (a textfile):
Hello!
Do you have trouble sleeping?
Do you need to rest?
Then dont hesitate call us for the absolute solution- without charge!
So when the programs run and analyzes the text above it should look like:
SPAM 14p
trouble 6p
charge 3p
solution 5p
So what I was planing to write was in this manners:
class junk(object):
fil = open("filnamne.txt","r")
junkwords = {"trouble":"6p","solution":"3p","virus":"4p"}
words = junkwords
if words in fil:
print("SPAM")
else:
print("The file doesn't contain any junk")
So my problem now is how do I give points for each word in my list that comes up in the file?
And how to I sum the total points so that if total_points are > 10 then the program should print "SPAM",
Followed by the list of the 'junkwords' that are found in the file and the total points of each word..

Answer 1

Here is a quick script that might get you close to there:
MAXPOINTS = 10
JUNKWORDS={"trouble":6,"solution":5,"charge":3,"virus":7}
fil = open("filnamne.txt", "r")
foundwords = {}
points = 0
for word in fil.read().split():
if word in JUNKWORDS:
if word not in foundwords:
foundwords[word] = 0
points += JUNKWORDS[word]
foundwords[word] += 1
if points > 10:
print "SPAM"
for word in foundwords:
print word, foundwords[word]*JUNKWORDS[word]
else:
print "The file doesn't contain any junk"
You may want to use .lower() on the words and make all your dictionary keys lowercase. Maybe also remove all non-alphanumeric characters.

Answer 2

Here's another approach:
from collections import Counter
word_points = {'trouble': 6, 'solution': 5, 'charge': 3, 'virus': 7}
words = []
with open('ham.txt') as f:
for line in f:
if line.strip(): # weed out empty lines
for word in line.split():
words.append(word)
count_of_words = Counter(words)
total_points = {}
for word in word_points:
if word in count_of_words:
total_points[word] = word_points[word] * count_of_words[word]
if sum(i[0] for i in total_points.iteritems()) > 10:
print 'SPAM {}'.format(sum(i[0] for i in total_points.iteritems()))
for i in total_points.iteritems():
print 'Word: {} Points: {}'.format(*i)
There are some optimizations you can do, but it should give you an idea of the general logic. Counter is available from Python 2.7 and above.

Answer 3

I have assumed that each word has different points, so I have used a dictionary.
You need to find the number of times a word in words has come in the file.
You should store the point for each word as an integer. not as '6p' or '4p'
So, try this:
def find_junk(filename):
word_points = {"trouble":6,"solution":3,"charge":2,"virus":4}
word_count = {word:0 for word in word_points}
count = 0
found = []
with open(filename) as f:
for line in f:
line = line.lower()
for word in word_points:
c = line.count(word)
if c > 0:
count += c * word_points[word]
found.append(word)
word_count[word] += c
if count >= 10:
print ' SPAM'*4
for word in found:
print '%10s%3s%3s' % (word, word_points[word], word_count[word])
else:
print "Not spam"
find_junk('spam.txt')