I try make PUT request but i can't. My form.
<form method="put" action="http://localhost/index.php/book">
<input type="text" name="bookName" />
<input type="submit" value="Send"/>
</form>
My controller
<?php
require(APPPATH.'libraries/REST_Controller.php');
class Book extends REST_Controller {
function index_put(){
echo $this->put('bookName');
}
}
?>
The problem is that do not show anything.
The HTML standard does not support put inside the <form method=""> attribute, if you put anything else other than post or get it should be sent as a GET request according to spec.
The canonical workaround implemented by many framewrok for this is to include a hidden _method field in your form and put the actual HTTP verb there. It seems like you are using this library, and it does this _method parameter workaround too.
Related
I am working on an Excel import module as part of a CRM for my company. I want to import an excel sheet. I use the Maatwebsite Excel package, version 3.1. I want to show the form and then upload a sheet. However I can't even get to that point. I have already determined the issue is within the form route, just not sure what it is exactly that I am missing.
Routes that I use to display the page (index works fine)
Form used to get the Excel sheet imported
Navigation bar link in the menu
DataController (from which I am trying to call the import method)
If you know what may be wrong please do tell, this is really frustrating!
Route code:
Route::get('importeren', 'Datacontroller#index');
Route::post('import', 'Datacontroller#import');
<div class="container-fluid">
<form action="import" method="POST" enctype="multipart/form-data">
#csrf
<input type="file" name="import_file">
<br>
<input type="submit" value="Import">
</form>
</div>
namespace App\Http\Controllers;
use Illuminate\Http\Request;
use App\Imports\DataImport;
use Maatwebsite\Excel\Facades\Excel;
use App\Http\Controllers\Controller;
class DataController extends Controller
{
public function index(){
return view('importeren');
}
public function import(Request $request){
Excel::import(new DataImport(), $request->file('import_file'));
return redirect()->route('/home');
}
}
Don't use route() method because you're not defining any routes name, use something like:
form action="/import" method="POST" enctype="multipart/formdata">
you should use route() only with route name, use this instead :
return redirect('/home');
You can give a name to your route:
Route::post('import', 'Datacontroller#import')->name('import');
and leave the form action as it is with the route() helper:
<div class="container-fluid">
<form action="{{ route('import') }}" method="POST" enctype="multipart/form-data">
#csrf
<input type="file" name="import_file">
<br>
<input type="submit" value="Import">
</form>
</div>
You could also use the url() helper and leave the route with no name, but I highly recommend the option of giving your route a name.
<form action="{{ url('import') }}" method="POST" enctype="multipart/form-data">
Note that in the controller return you are also using a redirect to a named route, so I suggest that you give that route a name and use that name in the redirect. For example:
Route::get('home', 'SomeController#someMethod')->name('home');
and
return redirect()->route('home');
I give up ! 2days i'm looking for solution for my problem.
All I need is pass FORM Data to Controller, then just show it on the same View.
Easy, right ? But i can not find any solution and Laravel's Manual does not explain that clearly...
So this is my View with the form :
form.blade.php
<form action="{{ action('FormController#ReceiveDataForm') }}" method="post">
<input type="text" name="name" placeholder="Enter your name">
<input type="text" name="surname" placeholder="Enter your surname">
<input type="submit" value="Send">
</form>
<div class="ShowDataHere">
{{-- Here i want to show this Data from FORM above, but with using Controller. --}}
</div >
My Controller receiving data:
FormController.php
namespace App\Http\Controllers;
use Input;
use Illuminate\Http\Request;
class FormController extends Controller
public function Form()
{
return view('test.form');
}
public function ReceiveDataForm()
{
Input::post('name');
Input::post('surname');
}
And my question is how to pass this Data to the same View and show it on
user's screen ?
Please note that Data must be basically pushed to the Controller, just then passing to the View via Routing.
All solution i found in Internet does not work for me, what guys am i doing wrong ?
If you do not know proper answer, please direct me where to find it or similar.
Thank You !
You can do
public function ReceiveDataForm(Request $request)
{
//Input::post('name');
//Input::post('surname');
return view('test.form');
}
Import the Request class by adding use Illuminate\Http\Request; in your controller.
In your view
<div class="ShowDataHere">
#if(!empty(request()->all()))
{{ request()->name }}
#endif
</div >
In your web.php file, make sure you have
Route::post('/test', 'FormController#ReceiveDataForm');
It is my first time to use laravel. I just want to ask a question regarding cross domain form submission best practice.
Let say I have simple HTML form in myfirstdomain.com/form
<form action="http://myseconddomain.com/insert/data/" method="POST">
<input name="fullname" type="text" placeholder="Enter your name" />
<input type="submit" value="submit">
</form>
And I have register "/insert/data" on my route file in other domain, let say myseconddomain.com :
Route::get('/insert/data', function()
{
$fullname = Input::get('fullname');
// Insert the name after this...
});
Is it safe to do that? I mean I'm using POST to submit form and using Route::get to fetch it?
Is there any other better option? I tried Route::post and get the MethodNotAllowed error instead.
Thank you
I'm creating a simple Joomla 2.5 module that will have an html form.
mod_mymodule/tmpl/default.php:
<form method="post" id="myemailform" action="">
<label for="ReferralName">Enter Name:</label><input type="text" name="name" value="<?php echo modCamcloudReferralHelper::getReferralName(); ?>">
<label for="ReferralEmail">Enter Email Address:</label><input type="text" name="email">
<label for="ReferralMessage">Enter Message (optional):</label><textarea class="message"></textarea>
<span class="countdown"></span>
<button type="submit" value="Send Email">Send Email</button>
<?php echo JHtml::_('form.token'); ?>
</form>
I have a helper class at:
mod_mymodule/helper.php - this just has some utility functions in it.
My question is what is the usual convention here to process my form on the server side. I tried to find examples of what people have done but I can't seem to find anything. Do I just put everything in the helper class:
<form method="post" id="myemailform" action="..\helper.php">
Or something like that? Thanks in advance.
Yes, you should do form processing in module helper class. Keep any logic out of the template file, and you can use mod_mymodule.php to call helper methods and assign variables before including the view file.
Do not set as form action helper file! I think in your case action should be the same page, so you can also ommit action url.
Edit: As requested in the comments, this would be the content of your mod_mymodule.php
// include helper file
require_once dirname(__FILE__).'/helper.php';
// call some method of the helper class
$items = modMymoduleHelper::getItems();
$moduleclass_sfx = htmlspecialchars($params->get('moduleclass_sfx'));
// render view file from mod_mymodule/tmpl/default.php, $items is available in the view file
require JModuleHelper::getLayoutPath('mod_mymodule', $params->get('layout', 'default'));
I am trying to implement something like this.
http://app.maqetta.org/mixloginstatic/LoginWindow.html
I want the login page to load but if you click the signup button then an ajax will replace the login form with the signup form.
I have got this to work using this code
dojo.xhrGet({
// The URL of the request
url: "'.$url.'",
// The success callback with result from server
load: function(newContent) {
dojo.byId("'.$contentNode.'").innerHTML = newContent;
},
// The error handler
error: function() {
// Do nothing -- keep old content there
}
});'
the only problem is the new form just loads up as a normal form, not a dojo form. I have tried to return some script with the phaser but it doesnt do anything.
<div id="loginBox"><div class="instructionBox">Please enter your details below and click <a><strong>signup</strong>
</a> to have an activation email sent to you.</div>
<form enctype="application/x-www-form-urlencoded" class="site-form login-form" action="/user/signup" method="post"><div>
<dt id="emailaddress-label"><label for="emailaddress" class="required">Email address</label></dt>
<dd>
<input 0="Errors" id="emailaddress" name="emailaddress" value="" type="text"></dd>
<dt id="password-label"><label for="password" class="required">Password</label></dt>
<dd>
<input 0="Errors" id="password" name="password" value="" type="password"></dd>
<dt id="captcha-input-label"><label for="captcha-input" class="required">Captcha Code</label></dt>
<dd id="captcha-element">
<img width="200" height="50" alt="" src="/captcha/d7849e6f0b95cad032db35e1a853c8f6.png">
<input type="hidden" name="captcha[id]" value="d7849e6f0b95cad032db35e1a853c8f6" id="captcha-id">
<input type="text" name="captcha[input]" id="captcha-input" value="">
<p class="description">Enter the characters shown into the field.</p></dd>
<dt id="submitButton-label"> </dt><dd id="submitButton-element">
<input id="submitButton" name="submitButton" value="Signup" type="submit"></dd>
<dt id="cancelButton-label"> </dt><dd id="cancelButton-element">
<button name="cancelButton" id="cancelButton" type="button">Cancel</button></dd>
</div></form>
<script type="text/javascript">
$(document).ready(function() {
var widget = dijit.byId("signup");
if (widget) {
widget.destroyRecursive(true);
}
dojo.parser.instantiate([dojo.byId("loginBox")]);
dojo.parser.parse(dojo.byId("loginBox"));
});
</script></div>
any advice on how i can get this to load as a dojo form. by the way i am using Zend_Dojo_Form, if i run the code directly then everything works find but through ajax it doesnt work. thanks.
update
I have discovered that if I load the form in my action and run the __toString() on it it works when i load the form from ajax. It must do preparation in __toString()
Firstly; You need to run the dojo parser on html, for it to accept the data-dojo-type (fka dojoType) attributes, like so:
dojo.parser.parse( dojo.byId("'.$contentNode.'") )
This will of course only instantiate dijits where the dojo type is set to something, for instance (for html5 1.7+ syntax) <form data-dojo-type="dijit.form.Form" action="index.php"> ... <button type="submit" data-dojo-type="dijit.form.Button">Send</button> ... </form>.
So you need to change the ajax contents which is set to innerHTML, so that the parser reckognizes the form of the type dijit.form.Form. That said, I urge people into using a complete set of dijit.form.* Elements as input fields.
In regards to:
$(document).ready(function() {});
This function will never get called. The document, youre adding innerHTML to, was ready perhaps a long time a go.
About Zend in this issue:
Youre most likely rendering the above output form from a Zend_ Dojo type form. If the renderer is set as programmatic, you will see above html a script containing a registry for ID=>dojoType mappings. The behavior when inserting <script> as an innerHTML attribute value, the script is not run under most circumstances (!).
You should try something similar to this pseudo for your form controller:
if request is ajax dojoHelper set layout declarative
else dojoHelper set layout programmatic