Check if SASS parent selector exists. Is it possible - sass

I have a question. So in a mixing I am making a reference to the parent selector "&". This works as long as the mixin is not nested. Is there a way to to detect if the mixing is being used in a non nested scenario, or to check if "&" is null?
This works when the mixin call is not nested
=myresponsiveMixin($media)
#if $media == small {
#media only screen and (max-width: $break-small)
#content
#else if $media == medium
#media only screen and (min-width: $break-small + 1) and (max-width: $break-large - 1)
#content
This works great when the mixin call is nested, but will not resolve '&' when not nested
=myresponsiveMixin($media)
#if $media == small {
#media only screen and (max-width: $break-small)
.classInHTMLToAllowMediaQueries &
#content
#else if $media == medium
#media only screen and (min-width: $break-small + 1) and (max-width: $break-large - 1)
.classInHTMLToAllowMediaQueries &
#content
So the question is, if there is a way to be able to check the value of parent selector "&", so I can cover all bases in a single mixin?

#mixin does-parent-exist {
#if & {
.exists & {
color: red;
}
} #else {
.doesnt-exist {
color: red;
}
}
}
http://sass-lang.com/documentation/file.SASS_REFERENCE.html#parent-script

You're trying a wrong solution to solve your issue.
Have a look at how this problem is addressed in powerful SASS frameworks. Let's take Susy by Eric Meyer as a great example.
Let's imagine you've got the following HTML:
<div class="container">
<div class="parent">
<div class="child">
Bla bla
</div>
</div>
</div>
When you call a mixin for the first time, you're doing it simply (the code is in the indented .sass syntax):
$total-columns: 8 // Declaring a varible that will be used by the mixin
.parent
+span-columns(4) // Span four of eight columns
But when you call that for a child element, the proportions would be crooked, because the parent is already proportioned:
.child
+span-columns(2) // This will fail. You want 2 of 8 columns,
// but due to nesting the math is crooked.
// It will be "2 of (4 of 8)".
To address the issue, you provide an optional argument: a context that is used to do the math:
.child
+span-columns(2, 4) // Now the mixin will take 2 parts of 4
// instead of 2 parts of four
The source code for this mixin is available on GitHub.
In short, it creates an optional argument like this (the code is in the CSS-like .scss syntax):
#mixin span-columns(
$columns,
$context: $total-columns
//...
) {
//...
width: columns($cols, $context /*...*/);
//...
}
See how $context has a default value? Thanks to the default value this argument can be omitted. In other words, $context is an optional argument.
When calling this mixin, if $context is not provided (e. g. span-columns(2)), then it is set equal to $total-columns. The $total-columns variable should be set prior to calling the mixin for the first time (see my example above).
Then the two arguments are used to calculate the width.
UPD 2013-03-30
I am not trying to figure out things in regards to columns... I have modifier my question to make it clearer.
First of all, my recommendation concerns not only grid columns. It's a universal technique you can adopt.
Secondly, now i see that you're trying to nest media queries.
Well, some media queries of different type can be combined in CSS3: e. g. print and width. But you can't put a min-width: 601px inside max-width: 600px, this just won't work!
There's an extensive answer here on StackOverflow describing why you should not nest media queries of the same type: https://stackoverflow.com/a/11747166/901944
Thirdly, you're trying to invent the wheel. There's already a fantastic mixin for crunching media queries: Respond To by Snugug. It's super easy to use and very effective.
Fourthly, the XY thing. Instead of asking about your crooked mixin, please describe the problem that you're trying to solve with it! Show us the actual HTML and explain what behavior you would like to achieve.
We will show you that it can be solved with a simple, elegant, semantic solution that does not require SASS hacking.

Related

Scss function returns no calculated value

I am working on a mixin for breakpoints and I have the following issue.
when a specific state (mode for max-width) is set then the breakpoint should be recalculated by extracting one em value (1px/16 (default font size)).
This is the important part of my code (I might get rid of the function, basically this can be done inline):
$mediaBreakpoint: map-get( $breakpoints, $breakpoint );
// if the mode is for max-width then subtract 1px.
#if map-get( $modes, $mode ) == 'max-width' {
$mediaBreakpoint: calculateMaxWidth(#{$mediaBreakpoint})
}
#debug $mediaBreakpoint;
/**
* calculate the max width based on input
*/
#function calculateMaxWidth($breakpoint){
$newBreakpoint: calc( #{$breakpoint} - 0.0625em ); // 1px in em sizing.
#return $newBreakpoint;
}
But whatever I try, the #debug value shows as:
48em-0.0625em // this is invalid, I need the actual outcome (in this case 47.9375) .
64em // valid min-width
This is the compiled css:
#media screen and (max-width: calc( 48em - 0.0625 )) {
}
What am I missing?
I found the answer myself after a lot of debugging. At first I misunderstood the interpolation. After reading the docs in depth I noticed that I should have wrapped the whole calculation instead of just the variable because I am working inside the map expression.
Quoted from the official Sass docs:
Interpolation can be used almost anywhere in a Sass stylesheet to embed the result of a SassScript expression into a chunk of CSS.
I changed my function to calculate like this and then the mixin started working. hooray!
$newBreakpoint: #{$breakpoint - 0.0625em};

SASS / SCSS merge multi-values within single item [duplicate]

This question already has answers here:
Sass - Manipulate inherited property?
(4 answers)
Closed 7 years ago.
I have the following mixin:
#mixin rhombus() {
#include transform(rotate(45deg));
}
and another one:
#mixin centerVertically() {
#include transform(transform(0, -50%));
position: absolute;
top: -50%
}
Now I would like to use them both on the same element and of course it will fail because the last called will be a winner.
There is a similar question for LESS but I could not find any solution for SASS.
Don't stick to the code above, this is just an example. I don't ask how to center the element or how to rotate it; I also know the order of transformation can matter, but still, is there any way to make the transform property be merged?
EDIT
the question is marked as a duplicate, but the question is totally different (and answer is not covering my question as well). I am asking about sharing the properties within a single block:
div {
#mixin rhombus;
#mixin centerVertically;
}
The attached question is asked about accessing inherited properties and same level properties. My case is different and I believe the answer can be different as well. I don't search for manipulating the inherited property. I search for the way to merge the property values into one. And I already found an answer although the 'duplicate' question does not have the one which solves the problem.
I've made some research and found the following feature request on a SASS'es repo which describes exactly this case.
Yes, there is no nice solution for that SASS-wise. But there is a workaround by mahdaen which might be really helpful. The code below is fully belonging to this good guy
$tmp-box-shadow-value: none;
#mixin box-shadow($value, $append: false) {
#if ($tmp-box-shadow-value == none) {
$tmp-box-shadow-value: $value !global;
}
#else {
$tmp-box-shadow-value: ($tmp-box-shadow-value, $value) !global;
}
#if ($append == false) {
#include prefixer(box-shadow, $tmp-box-shadow-value, true);
$tmp-box-shadow-value: none !global;
}
}
with usage like
.shadow-elem {
// Appending values.
#include box-shadow(0 0 1px #ccc, true);
#include box-shadow(0 0 1px #ddd, true);
// Append and write the style.
#include box-shadow(0 0 1px #eee);
}
Although it may seem dirty in somebody's eyes, I really like it as after small adaptions it fully solves my problem.

Breaking out of a Sass mixin

Is it possible to break out/return early of a Sass mixin? I'd like to do something like this:
#mixin foo($bar: false) {
#if $bar {
// return early without applying any of the styles below
}
color: red;
}
Edit: Please keep in mind that this example is the simplest thing I could come up with that illustrates my problem. In the real world, my code is much more complex and the use case for this is clear.
Sass doesn't really have the concept of "break", but an #if/#else will get you pretty close:
#mixin foo($bar: false) {
#if $bar {
color: green;
}
#else {
color: red;
}
}
From the Lead Sass developer at https://github.com/nex3/sass/issues/378:
The issue is that the more seldom-used control structures exist in
Sass, the harder it is for something with only passing familiarity
with the language to read stylesheets that use those control
structures. That's why it started out with the bare minimum set of
structures needed to do anything: because in many cases it makes sense
to skew towards a smaller surface area of the language rather than
optimal semantics for writing complex code.
I still thinking that #if/#else statements is the easiest and best solution to deal with your problem in Sass but I've created two different breakout mixins to help you and as a challenge:
Play with this mixin first
Breakout mixin without #includes (link)
#include breakout($styles)
$style should be a list of styles separated by spaces, here are the allowed values:
Styles
Common CSS styles separated by spaces and without colon or semicolons, lists of values should be wrapped by brackets:
#include breakout(
color blue // <property> <value>
width (100 * 20px) // <property> <operation with values>
border (1px solid #fff) // <property> <list of values>
box-shadow (0 0 10px 4px #0000FF , 0 0 20px 30px #008000) // <property> <nested list of values>
)
Breaks
Breaks are styles that are compiled if its condition is true, also when the condition is true the mixin ends without returns all styles after the break value
$foo: true;
#include breakout(
break (false color red) // break (<condition> <property> <value>
break ((3 < 2) border (1px solid #fff)) // breaks also support list and nested lists
break ($foo width 10px) // This breaks is compiled because condition is true
color blue // This style isn't compiled because the $foo break ends the mixin
)
Note that the order of the mixin argument list is important because it determines the compiled and not compiled styles if a break condition is true
Breakout mixin with #includes (link)
This mixin is similar to the above but it introduces mixin values for $styles, break-mixin mixin and #content into the breakout mixin to allow use of #includes.
Mixins
If you want to use other mixins into breakout mixin you need to add some code into $styles and add each mixin into a break-mixin mixin.
#include breakout(
mixin foo // mixin <name of the mixin declared into break-mixin arguments>
mixin bar // mixin name should match break-mixin argument
mixin foobar
) {
#include break-mixin(foo) { // Here your mixin or mixins for mixin foo }
#include break-mixin(bar) { #include mixin1; #include mixin2; #include mixin3}
#include break-mixin(foobar) { #include foobar}
}
Mixin breaks
Now you can also use mixin into breaks. Here the order is still important:
$foo: true
#include breakout(
mixin foobar
mixin bar
break ($foo mixin foo) // This breaks is compiled because condition is true
color blue // This style isn't compiled because the $foo break ends the mixin
) {
#include break-mixin(foo) { // Here your mixin or mixins for mixin foo }
#include break-mixin(bar) { #include mixin1; #include mixin2; #include mixin3}
#include break-mixin(foobar) { #include foobar}
}
So for your specific case copy the Breakout mixin without #includes (link) to your scss file or use it as a partial and then add this to your code;
#include breakout(
break ($bar property value) // The break out statement
color red // If $bar != false this will be compiled if not it won't
);
I'm surprised that the #error statement has not been mentioned yet. According to the documentation (emphasis mine):
When writing mixins and functions that take arguments, you usually want to ensure that those arguments have the types and formats your API expects. If they aren't, the user needs to be notified and your mixin/function needs to stop running.
That said, #error may not be suitable for every situation, because it will stop the Sass compilation completely. This makes it unfit for mixins where breaking out is an expected end intended scenario.
Example from the Sass documentation:
#mixin reflexive-position($property, $value) {
#if $property != left and $property != right {
#error "Property #{$property} must be either left or right.";
}
$left-value: if($property == right, initial, $value);
$right-value: if($property == right, $value, initial);
left: $left-value;
right: $right-value;
[dir=rtl] & {
left: $right-value;
right: $left-value;
}
}
.sidebar {
#include reflexive-position(top, 12px);
// ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
// Error: Property top must be either left or right.
}

Using variables for CSS properties in Sass

I am writing a #mixin with some math in it that calculates the percentage width of an element, but since it is very useful I would like to use the same function for other properties too, like margins and paddings.
Is there a way to pass the property name as an argument to a mixin?
#mixin w_fluid($property_name, $w_element,$w_parent:16) {
$property_name: percentage(($w_element/$w_parent));
}
You need to use interpolation (eg. #{$var}) on your variable in order for Sass to treat it as a CSS property. Without it, you're just performing variable assignment.
#mixin w_fluid($property_name, $w_element, $w_parent:16) {
#{$property_name}: percentage(($w_element / $w_parent));
}
In addition to the #rcorbellini response
You can use string and variable together
#mixin margin($direction) { // element spacing
margin-#{$direction}: 10px;
}

Using SASS Variables within nth-child?

I have a grid set up of thumbnail images, currently 4 thumbs per row. To make sure they line up i have this snippet of code:
li:nth-child(5) { margin-left: 0;}
What I have tried to do is this but I am getting a syntax error:
$galleryGrid: 5;
li:nth-child($galleryGrid) { margin-left: 0;}
If I wanted to alter the nth-child to use another value, such as 10 (so I can have 8 thumbs in a row), I assumed this would work.
Is this not possible or am I just doing incorrectly?!
Thanks in advance for you help.
You need to use variable interpolation to allow nth-child to be a variable.
$galleryGrid: 5;
li:nth-child(#{$galleryGrid}) { margin-left: 0;}
Generates
li:nth-child(5){margin-left:0}
This markup is fine if you have absolute control over the images and layout to ensure that your elements always wrap in such a way that every 5th one begins a new row. If you cannot make such guarantees, setting negative margins on the parent element is a better way to go.

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