Here's the link to the page: Chapter 3, Practical: A Simple Database.
Essentially I have a database of lists with four values that I want to display. This is done with
(defun dump-db ()
(dolist (cd *db*)
(format t "~{~a:~10t~a~%~}~%" cd)))
The only problem is that the output isn't quite right:
TITLE: Home
ARTIST: Dixie Chicks
RATING: 9
RIPPED: T
... (Shortened for brevity)
For some reason "Home" doesn't start in the 10th column, can someone tell me why? I'm using SBCL to run the code, most recent version.
Two things:
Remark:
0] says that you are in a debug loop. Get out of it. help shows the command.
Problem:
Maybe it is a bug with SBCL. You might want to discuss it on its mailing list. That would be useful.
My guess:
* (dump-db)
^^ <- 2 characters
TITLE: Home
^^^^^^^^ <- 8 characters, 2 less than specified
If you are back on the toplevel, you then see that the SBCL prompt is * - which is two characters long. Now you see that the first indentation of Home is two characters short. So the Lisp printer thinks that the two characters of the prompt are on the same line and then position ten is on the next eight characters - two less than needed. Maybe the Lisp printer is confused by some way the REPL is programmed. The next lines then are fine.
Btw., this does not happen with LispWorks or Clozure CL.
0] (dump-db)
TITLE: Home
ARTIST: Dixie Chicks
RATING: 9
RIPPED: T
TITLE: Fly
ARTIST: Dixie Chicks
RATING: 8
RIPPED: T
TITLE: Roses
ARTIST: Kethy Mattea
RATING: 7
RIPPED: T
NIL
0] (dump-db)
TITLE: Home
ARTIST: Dixie Chicks
RATING: 9
RIPPED: T
TITLE: Fly
ARTIST: Dixie Chicks
RATING: 8
RIPPED: T
TITLE: Roses
ARTIST: Kethy Mattea
RATING: 7
RIPPED: T
NIL
0]
It appears to have fixed itself... I'm not sure how or why (questions I would still love an answer to) though.
Related
I am using this code for the first page of my Rmarkdown. I want to add :
name of the course
name of the tutor
number of the words
number of graphs
number of tables
This is my code :
title: "Title of report "
author: "my name"
Email: "my email"
output:
pdf_document:
latex_engine: xelatex
fig_width: 4.5
fig_height: 3
html_document:
df_print: paged
header-includes:
- \usepackage{setspace}
- \onehalfspacing
date: '2022-07-06'
csl: chicago-author-date.csl
bibliography: bib1.bib
Thank you in advance for your help
I am new to ETL and I was assigned with a task on sanitizing some sensitive information before giving the data to a client.
I am using HUE web client with Impala.
What I want to do is:
For example, a column info like '京客隆（三里屯店）', then I need to transform it into something like '京XXX店）' .
My query is:
select '京客隆（三里屯店）', concat(substr('京客隆（三里屯店）', 1, 3), 'XXX', substr('京客隆（三里屯店）', char_length('京客隆（三里屯店）') -6, 6));
But I get gibberish in the output:
'京客隆（三里屯店）' | concat(substr('京客隆（三里屯店）', 1, 3), 'xxx', substr('京客隆（三里屯店）', char_length('京客隆（三里屯店）') - 6, 6))
京客隆（三里屯店） | 京XXX�店�
The problem is that :
select '京客隆（三里屯店）', substr('京客隆（三里屯店）', char_length('京客隆（三里屯店）') -3 , 3);
output: 京客隆（三里屯店） ��
doesn't get the correct characaters. Why is that? I pasted the string in python shell and I can get the correct characters if I only take the last 3 bytes.
It turns out that I misunderstood the function substr.
substr(STRING a, INT start [, INT len]) :
It takes characters starting from (including) INT start. So for example my string '京客隆（三里屯店）' is 27 bytes long in total, and each utf8 char takes 3 bytes here. I need to take the last 3 bytes, which is the ） , then I need to write:
substr('京客隆（三里屯店）, 27 - 2 ,3 ) .
It then gets the 25, 26, 27 3 bytes and display the char ） correctly.
Updated:
I was told to use :
SELECT regexp_replace('京客隆（三里屯店）', '(.)(.*)(.{2})', '\\1***\\3');
works like an charm :P.
I would like to match all lines (including the first line) between two lines that start with 'SLX-', convert them to a comma separated line and then append them to a text file.
A truncated version of the original text file looks like:
SLX-9397._TC038IV_L_FLD0214.Read1.fq.gz
Sequences: 1406295
With index: 1300537
Sufficient length: 1300501
Min index: 0
Max index: 115
0 1299240
1 71
2 1
4 1
Unique: 86490
# reads processed: 86490
# reads with at least one reported alignment: 27433 (31.72%)
# reads that failed to align: 58544 (67.69%)
# reads with alignments suppressed due to -m: 513 (0.59%)
Reported 27433 alignments to 1 output stream(s)
SLX-9397._TC044II_D_FLD0197.Read1.fq.gz
Sequences: 308905
With index: 284599
Sufficient length: 284589
Min index: 0
Max index: 114
0 284290
1 16
Unique: 32715
# reads processed: 32715
# reads with at least one reported alignment: 13114 (40.09%)
# reads that failed to align: 19327 (59.08%)
# reads with alignments suppressed due to -m: 274 (0.84%)
Reported 13114 alignments to 1 output stream(s)
SLX-9397._TC047II_D_FLD0220.Read1.fq.gz
I imagine the ruby would look like
Convert all /n between two lines with SLX- to commas
Save the original text file as a new text file (or even better a CSV file.
I think I specifically have a problem with how to find and replace between two specific lines.
I guess I could do this without using ruby, but seeing as I'm trying to get into Ruby...
Assuming, that you have your string in str:
require 'csv'
CSV.open("/tmp/file.csv", "wb") do |csv|
str.scan(/^(SLX-.*?)(?=\R+SLX-)/m).map do |s| # break by SLX-
s.first.split($/).map do |el| # split by CR
"'#{el}'" # quote values
end
end.each do |line| # iterate
csv << line # fulfil csv
end
end
I don't know much about Ruby but this should work. You should read the entire file into a Sting. Use this regex - (\RSLX-) - to match all SLX- (all but the first one) and replace it with ,SLX-. For the explanation of the regex, go to https://regex101.com/r/pP3pP3/1
This question - Ruby replace string with captured regex pattern - might help you to understand how to replace in ruby
I am working with an RDBMS that contains a list of hierarchical objects stored like this:
Id Name ParentId
====================================
1 Food NULL
2 Drink NULL
3 Vegetables 1
4 Fruit 1
5 Liquor 2
6 Carrots 3
7 Onions 3
8 Strawberries 4
...
999 Celery 3
I do not know the specific reason why this was chosen, but it is fixed in so far as the rest of the system relies on fetching the structure in this form.
I want to expose this data via JSON using a RESTful API, and I wish to output this in the following format (array of arrays):
item:
{
id: 1, Description: "Food",
items: [
{
id: 3, Description: "Vegetables",
items: [ ... ]
},
{
id: 4, Description: "Fruit",
items: [ ... ]
}
]
},
item:
{
id: 2, Description: "Drink",
items: [ ... ]
}
What would be a sensible way of looping through the data and producing the desired output? I'm developing in C# but if there are libraries or examples for other languages I would be happy to re-implement where possible.
Thanks :)
I've got an array of classes, and I want to find where there may be a schedule overlap.
My array is something like this
[
{
id:2,
start: "3:30",
length: 40,
break: 30,
num_attendees: 14
},
{
id: 3,
start: "3: 40",
length: 60,
break: 40,
num_attendees: 4
},
{
id: 4,
start: "4: 40",
length: 30,
break: 10,
num_attendees: 40
}
]
pretty simple.
Now, I want to get an array where I add the start and the length, and then get the classes that overlap to notify the user that they have a conflict.
I know I can do a large for loop and compare that way, but I'm thinking there must be a nicer way to do this in Ruby, something like (ignore that we're not working in absolute minutes here, I've got that, I just want to keep the example simple).
overlap = class_list.select{|a,b| if a.start+a.length>b.start return a,b end}
any suggestions?
You can use Array#combination like this:
class_list.combination(2).select{|c1, c2|
# here check if c1 and c2 overlap
}