I am fairly new to XPath.
The requirement is to create a XPath expression which returns a list of elements, rather than a single element. After that we apply custom logic to locate the required element in the list.
The individual element can be accessed using the below XPaths:
.//*[#id='reportListItemID0']/td[12]/a
.//*[#id='reportListItemID1']/td[12]/a
.//*[#id='reportListItemID2']/td[12]/a
.
.
.
.//*[#id='reportListItemID20']/td[12]/a
.//*[#id='reportListItemID21']/td[12]/a
Please let me know, how to write a XPath expression which would returns all the above elements.
I tried the below and they did not work:
.//*[#id='reportListItemID.']/td[12]/a
.//*[#id='reportListItemID..']/td[12]/a
.//*[#id='reportListItemID*']/td[12]/a
.//*[#id='reportListItemID**']/td[12]/a
Please let me know what I am missing.
You should use the starts-with() function:
.//*[starts-with(#id,'reportListItemID')]/td[12]/a
You can also use contains:
//*[contains(#id, 'reportListItemID')]/td[12]/a
Related
In my problem I search for elements that have an example structure like:
<ngc-product-card ng-reflect-signup-type="comprehensive">
Since the elements may have the comprehensive value stored in another attribute, say:
<new-ngc-product-card data-label="comprehensive signup">
hence I would like to use a wildcard-attribute-name search and also apply the contains() function like:
//*[contains(#*,"comprehensive")]
which doesn't work
What does work is
//*[#*="comprehensive"]
Is there any way to use both '#*' and 'contains()' ?
This should do.
//*[#*[contains(., "comprehensive")]]
Am automating things using Selenium. Need your help to handle Dynamic Xpath as below:
Driver.findElement(By.xpath("//[#id='INQ_2985']/div[2]/tr/td/div/div[3]/div")).click();
As above INQ_2985 changes to 2986,2987,2988 etc during each run
HTML CODE:
< div> class="context-menu-item-inner" style="background-image:url(../images/productSmall.png);">Tender Assignment < /div>
Tried different combinations as below but with no success:
// Driver.findElement(By.name("//input[#name='Tender Assignment']")).click();
// Driver.findElement(By.className("context-menu-item-inner")).click();`
Can you help me on this.
you can try using contains() or starts-with() in xpath,
above xpath can be rewritten as follows,
Driver.findElement(By.xpath("//*[starts-with(#id,'INQ')]/div[2]/tr/td/div/div[3]/div")).click();
if you can post more of your html, we can help improve your xpath..
moreover using such long xpath's is not recommended, this may cause your test to fail more often
for example,if a "new table data or div" is added to the UI, above xpath will no longer be valid
you should try and use id, class or other attributes to get closer to the element your trying to find
i personally recommend using cssSelectors over xpath
you can use many methods,
use implicity wait;
driver.findElement(By.xpath("//*[contains(#id,'select2-result-label-535')]").click();
driver.findElement(By.xpath("//*[contains(text(), 'select2-result-label-535')]").click();
Good to use Regular expression
driver.findElement(By.xpath("//*[contains(#id,'INQ_')]")
Note: If you have single ID with name starts from INQ_ then you can take action on the element . If a bunch of ID then you can extract as a List<WebElements> and then match with the specific text of the element ( element.getText().trim() =="Linked Text" and if it matched then take action. You can follow other logic to traverse and match.
you can use css -
div.context-menu-item-inner
Use this xpath:
driver.findElement(By.cssSelector("div.context-menu-item-inner").click();
The best choice is using full xpath instead of id which you can get easily via firebug.
e.g.
/html/body/div[3]/div[3]/div[2]/div/div[2]/div[1]/div/div[1]
if your xpath is varying
Ex: "//*[#id='msg500']" , "//*[#id='msg501']", "//*[#id='msg502']" and so on...
Then use this code in script:
for (int i=0;i<=9;i++) {
String mpath= "//*[#id='msg50"+i+"']";
driver.findElement(By.xpath(mpath)).click();
}
I am trying to quickly find a specific node using XPath but it seems my multiple predicates are not working. The div I need has a specific class, but there are 3 others that have it. I want to select the fourth one so I did the following:
//div[#class='myCLass' and 4]
However the "4" is being ignored. Any help? I am new to XPath.
Thanks.
If a xpath query returns a node set you can always use the [OFFSET] operator to access a certain element of it.
Use the following query to access the fourth element that matches the #class='myClass' predicate:
//div[#class='myCLass'][4]
#WilliamNarmontas answer might be an alternative to the syntax showed above.
Alternatively,
//div[#class='myCLass' and position()=4]
The accepted answer works correctly only if all of the div elements have the same parent. Otherwise use:
(//div[#class='myCLass'])[4]
I try to write xpath expressions so that my tests won't be broken by small design changes. So instead of the expressions that Selenium IDE generates, I write my own.
Here's an issue:
//input[#name='question'][7]
This expression doesn't work at all. Input nodes named 'question' are spread across the page. They're not siblings.
I've tried using intermediate expression, but it also fails.
(//input[#name='question'])[2]
error = Error: Element (//input[#name='question'])[2] not found
That's why I suppose Seleniun has a wrong implementation of XPath.
According to XPath docs, the position predicate must filter by the position in the nodeset, so it must find the seventh input with the name 'question'. In Selenium this doesn't work. CSS selectors (:nth-of-kind) neither.
I had to write an expression that filters their common parents:
//*[contains(#class, 'question_section')][7]//input[#name='question']
Is this a Selenium specific issue, or I'm reading the specs wrong way? What can I do to make a shorter expression?
Here's an issue:
//input[#name='question'][7]
This expression doesn't work at all.
This is a FAQ.
[] has a higher priority than //.
The above expression selects every input element with #name = 'question', which is the 7th child of its parent -- and aparently the parents of input elements in the document that is not shown don't have so many input children.
Use (note the brackets):
(//input[#name='question'])[7]
This selects the 7th element input in the document that satisfies the conditions in the predicate.
Edit:
People, who know Selenium (Dave Hunt) suggest that the above expression is written in Selenium as:
xpath=(//input[#name='question'])[7]
If you want the 7th input with name attribute with a value of question in the source then try the following:
/descendant::input[#name='question'][7]
I'm not very familiar with xpath. But I was working with xpath expressions and setting them in a database. Actually it's just the BAM tool for biztalk.
Anyway, I have an xml which could look like:
<File>
<Element1>element1<Element1>
<Element2>element2<Element2>
<Element3>
<SubElement>sub1</SubElement>
<SubElement>sub2</SubElement>
<SubElement>sub3</SubElement>
<Element3>
</File>
I was wondering if there is a way to use an xpath expression of getting all the SubElements concatted? At the moment, I am using:
/*[local-name()='File']/*[local-name()='Element3']/*[local-name()='SubElement']
This works if it only has one index. But apparently my xml sometimes has more nodes, so it gives NULL. I could just use
/*[local-name()='File']/*[local-name()='Element3']/*[local-name()='SubElement'][0]
but I need all the nodes. Is there a way to do this?
Thanks a lot!
Edit: I changed the XML, I was wrong, it's different, it should look like this:
<item>
<element1>el1</element1>
<element2>el2</element2>
<element3>el3</element3>
<element4>
<subEl1>subel1a</subEl1>
<subEl2>subel2a</subEl2>
</element4>
<element4>
<subEl1>subel1b</subEl1>
<subEl2>subel2b</subEl2>
</element4>
</item>
And I need to have a one line code to get a result like: "subel2a subel2b";
I need the one line because I set this xpath expression as an xml attribute (not my choice, it's specified). I tried string-join but it's not really working.
string-join(/file/Element3/SubElement, ',')
/File/Element3/SubElement will match all of the SubElement elements in your sample XML. What are you using to evaluate it?
If your evaluation method is subject to the "first node rule", then it will only match the first one. If you are using a method that returns a nodeset, then it will return all of them.
You can get all SubElements by using:
//SubElement
But this won't keep them grouped together how you want. You will want to do a query for all elements that contain a SubElement (basically do a search for the parent of any SubElements).
//parent::SubElement
Once you have that, you could (depending on your programming language) loop through the parents and concatenate the SubElements.