I try to learn Laravel 4 and I have found it - so far - pretty great. But Blade templaes seem dfficult to me, less intuitive than Smarty for instance.
I have a small problem. I try to push my data from Controller to a View. I do this:
public function getGame($id, $slug = null) {
$game['info'] = Game::find($id);
$game['genres'] = Game::find($id)->genres()->get();
$game['dev'] = Game::find($id)->developers()->get();
$this->layout = View::make('user')->with('game',$game);
}
Pretty straightforward, isn't it? For now, my View is just {{ $game['info']->title }}. But it seems that it doesn't see my variable (throwing "Undefined variable: game"). What can I do? Can I post the data in that array format (I assumed from the docs that I can).
I think the problem is in the last line of your code. You either return a view like
return View::make('user')->with('game', $game);
or do something like this:
Create protected $layout = 'my_layout.blade.php' in your controller and create the file my_layout.blade.php and put it into views folder. In it write something like
#yield('content')
Then, create your user.blade.php and create a section like this
#section('content')
....
#stop
Finaly, at the end of your getGame function
$this->layout->content = View::make('user')->with('game', $game);
Home this make sense to you.
Btw, why not define 'genres' and 'developers' relationships in your Game model and then use eager loading like
$game = Game::with('genres', 'developers')->find( $id );
and pass this to the view. Then access title like $game->title, genres like $game->genres->... etc.
Regards,
Vlad
Related
I want to know is there any way to access table data without passing it from controller to view in laravel 5 ?
I have an Options table in my database that stores all my project options. it has three column:
id
name
value
Now I want to access each option value in my master.blade.php file.
what is the best way to do it.
If you understand what MVC is all about then you should know that passing a variable from controller to your view is the best practice. View is simply used for presentation and should only be used for presentation purpose for the sake of separation of concern.
With that been said the best approach is:
Create a model for options then pass it through your controller to the view.
For example:
use App\Option;
PageController extends Controller{
public function __construct(Option $option){
$this->option = $option;
}
public function about(){
$options = $this->option->list('id','value');
return view('about', $options);
}
}
To make variable global in all view see my answer here:
Laravel 5 - global Blade view variable available in all templates
Well there can be multiple ways available, but passing your Table data directly into views is not a recommended way, It would be much better if you follow the proper way, means from Controller to Model. Well its upto you. here is my suggested possible ways.
Method 1 (about which you are asking)
in your master.blade.php file, you can also do this,
<?php
$v = new \App\Message(); // your model object
echo $v ->testmeee(); // its method
?>
Method 2
If you are trying to use your Table data globally(means you want options data should be available on all pages/views), then this one is highly suggested way.
Goto your App/Http/Providers/AppServiceProvider.php file
view()->composer('*', function ($view)
{
$user = new \App\User();
$view->with('friend_new_req_count', count($user->getLoggedinUserNewFriends()));
});
now this variablefriend_new_req_count with data would be available in all views (only in views) means you can access in view {{$friend_new_req_count}}
I want to grab some data from a database and display on a layout page, I've basically started building a small CMS to get into Laravel and all has gone fine so far but now i'm at a wall, and can't find a solution.
I have a layout blade file like so: http://paste.laravel.com/1fB1 nothing majot but you will see i have used $page->meta_title etc in there and in my controller i have:
public function home()
{
$pages = Pages::all();
return View::make('frontend/home')->with('pages',$pages);
}
Which I have a pages model doing nothing else really like so:
class Pages extends Eloquent {
protected $table = 'pages';
}
So why is it trying to get property of non-object and I don't really want to use a foreach because this is going to be the frontend of my 'test' website so a foreach wouldn't suite.
You'll need to access these items as a multi-dimensional array if you don't want to loop through them.
$pages[0]['field_name_here']
or
$pages[1]['field_name_here']
Its a bit of a tough one to answer without knowing how you want your CMS to work.
For example, you could have a route as {pagename} in your routes.php file, then have a page controller where you would get the requested route from the variable passed in. This would then load the page you wanted using the variable
public function page( $pagename ) {
$page = Page::where('page_title', '=', $pagename)->first();
View::make('frontend/page', array( 'page' => $page ));
}
Using a route like that, and the controller, in your view you could use {{ $page->content }} to get the content of the requested page from the database and display it.
Hope this helps.
Edit: Example Route:
Route::get('{pagename}', 'PageController#page');
I was wondering if someone could help me out.
Im building a forum into my codeigniter application and im having a little trouble figuring out how i build the segments.
As per the CI userguide the uri is built as follows
www.application.com/CLASS/METHOD/ARGUMENTS
This is fine except i need to structure that part a bit different.
In my forum i have categories and posts, so to view a category the following url is used
www.application.com/forums
This is fine as its the class name, but i want to have the next segment dynamic, for instance if i have a category called 'mycategory' and a post by the name of 'this-is-my-first-post', then the structure SHOULD be
www.application.com/forums/mycategory/this-is-my-first-post
I cant seem to achieve that because as per the documentation the 'mycategory' needs to be a method, even if i was to do something like /forums/category/mycategory/this-is-my-first-post it still gets confusing.
If anyone has ever done something like this before, could they shed a little light on it for me please, im quite stuck on this.
Cheers,
Nothing is confusing in the document but you are a little bit confused. Let me give you some suggestions.
You create a view where you create hyperlinks to be clicked and in the hyperlink you provide this instruction
First Post
In the controller you can easily get this
$category = $this->uri->segment(3);
$post = $this->uri->segment(4);
And now you can proceed.
If you think your requirements are something else you can use a hack i have created a method for this which dynamically assign segments.
Go to system/core/uri.php and add this method
function assing_segment($n,$num)
{
$this->segments[$n] = $num;
return $this->segments[$n];
}
How to use
$this->uri->assign_segment(3,'mycategory');
$this->uri->assign_segment(4,'this-is-my-first-post');
And if you have error 'The uri you submitted has disallowed characters' then go to application/config/config.php and add - to this
$config['permitted_uri_chars'] = 'a-z 0-9~%.:_\-';
You could make a route that forwards to a lookup function.
For example in your routes.php add a line something like;
$route['product/(:any)/(:any)'] = "forums/cat_lookup/$1/$2";
This function would then do a database lookup to find the category.
...
public function cat_lookup($cat, $post) {
$catid = $this->forum_model->get_by_name($cat);
if ($catid == FALSE) {
redirect('/home');
}
$post_id = $this->post_model->get_by_name($post);
/* whatever else you want */
// then call the function you want or load the view
$this->load->view('show_post');
}
...
This method will keep the url looking as you want and handle any problems if the category does not exist.Don't forget you can store the category/posts in your database using underscores and use the uri_title() function to make them pretty,
Set in within config/routes.php
$route['song-album/(:any)/:num'] = 'Home/song_album/$id';
fetch in function with help of uri segment.
$this->uri->segment(1);
I have a table of data from a database that I want to display on various pages of my website. Ideally, i would like to just have an include or something that will go off and get the data, and return the html table. The html and data will be identical everytime I need to use this.
I wanted to know the best way of doing this
Thanks
EDIT
If this helps, something similar to a Django "inclusion" custom tag...for any django developers reading
you need to pass the variable $data to the view method.
This is your code:
function load_my_view(){
$this->load->model('my_table');
$data['my_results'] = $this->my_table->my_data();
$this->load->view('my_view');
}
Please change it to this in order to load the $data into the view:
function load_my_view(){
$this->load->model('my_table');
$data['my_results'] = $this->my_table->my_data();
$this->load->view('my_view',$data);
}
You should use a function in a model to fetch the data you need. Your controller calls the model function and sends the returned information to a view. You don't need to use traditional php includes with Codeigniter. I recommend a review of the user guide. It's very good and will tell you all the basic stuff you need to know to develop with CI. But to get you started, you watn to use Models, Views, and Controllers. Your url will tell CI what controller and function inside that controller to run. If your url is
http://www.example.com/my_controller/load_my_view
Then CI will do what is inside the load_my_view function in the my_controller controller. function load_my_view in turn instantiates a model "my_table" and runs a database query, returns information that the controller sends to the view. A basic example follows:
Your model
class my_table extends CI_Model{
function my_data(){
$this->db->select('column_1,column_2,column_3');
$this->db->from('my_table');
$query = $this->db->get();
if($query->num_rows()>0){
$result = $query->result();
}
else{
$result = false;
}
return $result;
}
}
Your controller
class my_controller extends CI_Controller{
function load_my_view(){
$this->load->model('my_table');
$data['my_results'] = $this->my_table->my_data();
$this->load->view('my_view');
}
}
Your View
<ul id = "my_db_results">
<?php foreach($my_results as $result):?>
<li><?php echo $result->column_1." : ".$result->column_2." ( ".$result->column_3." )";?></li>
<?php endforeach;?>
</ul>
It looks like a good oportunity to use cache: http://codeigniter.com/user_guide/libraries/caching.html
Ok, so here is one thing that worked for me, but its definitely not perfect.
I created a view in which made a call to the model getting the data then put the data into a table. This way, I only have to include this view to put the table anywhere.
I understand this completely ruins the point of having a MVC framework, but hopefully it demonstrates what I want to do...and it works
I'm fairly new to Zend Framework and MVC in general so I'm looking for some advice. We have a base controller class in which we have some methods to obtain some user information, account configurations, etc.
So I'm using some of those methods to write out code in various controllers actions, but now I want to avoid duplicating this code and further more I would like to take this code outside of the controller and in a view helper as it is mainly to output some JavaScript. So the code in the controller would look like this:
$obj= new SomeModel ( $this->_getModelConfig () );
$states = $obj->fetchByUser ( $this->user->getId() );
//Fair amount of logic here using this result to prepare some javascript that should be sent to the view...
The $this->_getModelConfig and $this->user->getId() are things that I could do in the controller, now my question is what is the best way to pass that information to the view helper once i move this code out of the controller ?
Should I just call these methods in the controller and store the results into the view and have the helper pick it up from there ?
Another option I was thinking of was to add some parameters to the helper and if the parameters are passed then I store them in properties of the helper and return, and when called without passing the parameters it performs the work. So it would look like this:
From controller:
$this->view->myHelper($this->user->getId(), $this->_getModelConfig());
From view:
<?= $this->myHelper(); %>
Helper:
class Zend_View_Helper_MyHelper extends Zend_View_Helper_Abstract
{
public $userId = '';
public $config = null;
public function myHelper ($userId = null, $config = null)
{
if ($userId) {
$this->userId = $userId;
$this->config = $config;
} else {
//do the work
$obj = new SomeModel($this->config);
$states = $obj->fetchByUser($this->userId);
//do the work here
}
return $this;
}
}
Any advice is welcomed!
Firstly the ASP style ending tag here at "$this->myHelper(); %>" is bad practice, with that said it is more advisable to keep the logic in the model and the controller just being used to call the model, get the results and spit that to the view for viewing.
what I would do is, if i simply want to pass a bunch of values to the view, i stuff them in an associative array and send them over.
anyway you should not be doing your ...
"//Fair amount of logic here using this result to prepare some javascript that should be sent to the view..."
part in the controller, I would advice you to make a new model that does that logic stuff for you, and you just call your model in the controller pass it what ever arguments that are needed and then spit the result of that to the view.
The best way is to get the data from your model throught your controller, and then pass to the view. But if you really need a custom helper to echo the view parts, we only will know if you say exactly what you're trying to do.
If you already have this logic in a helper, try to just pass the parameters in your view myhelper($this->params); ?>
You may want take a look at this approach too:
// In your view to put javascript in the header
// You can loop trought your data and then use it to generate the javascript.
<?php $this->headScript()->captureStart(); ?>
$().ready(function(){
$('#slideshow').cycle({
fx: 'fade',
speed: 1000,
timeout: 6500,
pager: '#nav'
});
});
<?php $this->headScript()->captureEnd() ?>