Since Microsoft Web API isn't MVC, you cannot do something like this:
var a = Request.MapPath("~");
nor this
var b = Server.MapPath("~");
because these are under the System.Web namespace, not the System.Web.Http namespace.
So how do you figure out the relative server path in Web API ? I used to do something like this in MVC:
var myFile = Request.MapPath("~/Content/pics/" + filename);
Which would give me the absolute path on disk:
"C:\inetpub\wwwroot\myWebFolder\Content\pics\mypic.jpg"
You can use HostingEnvironment.MapPath in any context where System.Web objects like HttpContext.Current are not available (e.g also from a static method).
var mappedPath = System.Web.Hosting.HostingEnvironment.MapPath("~/SomePath");
See also What is the difference between Server.MapPath and HostingEnvironment.MapPath?
string root = HttpContext.Current.Server.MapPath("~/App_Data");
As an aside to those that stumble along across this, one nice way to run test level on using the HostingEnvironment call, is if accessing say a UNC share: \example\ that is mapped to ~/example/ you could execute this to get around IIS-Express issues:
#if DEBUG
var fs = new FileStream(#"\\example\file",FileMode.Open, FileAccess.Read);
#else
var fs = new FileStream(HostingEnvironment.MapPath("~/example/file"), FileMode.Open, FileAccess.Read);
#endif
I find that helpful in case you have rights to locally test on a file, but need the env mapping once in production.
I can't tell from the context you supply, but if it's something you just need to do at app startup, you can still use Server.MapPath in WebApiHttpApplication; e.g. in Application_Start().
I'm just answering your direct question; the already-mentioned HostingEnvironment.MapPath() is probably the preferred solution.
Since Server.MapPath() does not exist within a Web Api (Soap or REST), you'll need to denote the local- relative to the web server's context- home directory. The easiest way to do so is with:
string AppContext.BaseDirectory { get;}
You can then use this to concatenate a path string to map the relative path to any file.
NOTE: string paths are \ and not / like they are in mvc.
Ex:
System.IO.File.Exists($"{**AppContext.BaseDirectory**}\\\\Content\\\\pics\\\\{filename}");
returns true- positing that this is a sound path in your example
Little bit late answering that but there we go.
I could solve this using Environment.CurrentDirectory
The selected answer did not work in my Web API application. I had to use
System.Web.HttpRuntime.AppDomainAppPath
You can try like:
var path="~/Image/test.png";
System.Web.Hosting.HostingEnvironment.MapPath( # + path)
Related
I'm trying to read an excel file(xlsx), I defined the path using
$uri = "public/storage/resultsheet/Revival Royal Academy_Primary 5B_1572753672.xlsx";
but I keep getting the error
File "public/storage/resultsheet/Revival Royal Academy_Primary 5B_1572753672.xlsx"
does not exist. I'm new to this framework.
This is the controller code.
public function show($id)
{
$reader = new \PhpOffice\PhpSpreadsheet\Reader\Xls();
$reader->setReadDataOnly(TRUE);
$uri = "public/storage/resultsheet/Revival Royal Academy_Primary 5B_1572753672.xlsx";
$spreadsheet = $reader->load($uri);
$worksheet = $spreadsheet->getActiveSheet();
return view('student.result', compact('worksheet'));
}
The path you're using is relative to the current directory that PHP is running in. For Laravel, that likely means you'll be running this in app/Services/MyUploadService.php or something similar.
Given your path is relative, PhpOffice will probably be trying to load `app/Services/public/storage... etc.' which is incorrect.
Laravel has helper methods that can assist you in working with paths within your app.
You could look at using base_dir() (so: base_dir('public/storage/example.xlsx').) as it will give you an absolute path, and a similar usage of public_path() would be better than that.
However, best out of all the options would be using storage_path(). So your code would instead read:
$reader->setReadDataOnly(TRUE);
$uri = storage_path("resultsheet/my.xlsx");
$spreadsheet = $reader->load($uri);
There's helpful documentation on the Path helpers in the Laravel docs.
To debug this, storing realpath('subdir/example.txt') etc. in a variable and using a debugging tool will help you figure out the relative/absolute paths in your project and server.
I want to save my logs to a folder which I can access with windows explorer. For example I want to create my log in the following path
This PC\Galaxy A5 (2017)\Phone\Android\data\MyApp\files
So I tried to use Environment variables... I get such as
/data/user/...
But here i cannot see the file what I created (using code I can access the path but I want to see in the explorer).
how I can create a path like above with code?
When I tried this code
var finalPath2 = Android.OS.Environment.GetExternalStoragePublicDirectory
(Android.OS.Environment.DataDirectory.AbsolutePath);
I get the path "/storage/emulated/0/data"
and
If i use the code
var logDirectory =Path.Combine(System.Environment.GetFolderPath
(System.Environment.SpecialFolder.ApplicationData),"logs");
I get the following path like:
/data/user/0/MyApp/files/.config/logs
and
var logDirectory =Path.Combine(System.Environment.GetFolderPath
(System.Environment.SpecialFolder.MyDocuments),"logs");
"/data/user/0/IM.OneApp.Presentation.Android/files/logs"
but unfortunately I cannot access this folder by explorer....
This PC\Galaxy A5 (2017)\Phone\Android\data\MyApp\files
So how to find out this path in c# by using environments?
Update:
when I give the following path hardcoded, it creates the file where I want..
logDirectory = "/storage/emulated/0/Android/data/MyApp/files/logs";
is there any environment to create this path? I can combine 2 environments and do some string processing in order to create this path. But maybe there is an easier way?
You are looking for the root of GetExternalFilesDir, just pass a null:
Example:
var externalAppPathNoSec = GetExternalFilesDir(string.Empty).Path;
Note: This is a Context-based instance method, you can access it via the Android application context, an Activity, etc... (see the link below to the Android Context docs)
Shared storage may not always be available, since removable media can be ejected by the user. Media state can be checked using Environment.getExternalStorageState(File).
There is no security enforced with these files. For example, any application holding Manifest.permission.WRITE_EXTERNAL_STORAGE can write to these files.
re: https://developer.android.com/reference/android/content/Context#getExternalFilesDir(java.lang.String)
string docFolder = Path.Combine(System.Environment.GetFolderPath
(System.Environment.SpecialFolder.MyDocuments), "logs");
string libFolder = Path.Combine(docFolder, "/storage/emulated/0/Android/data/MyApp/files/logs");
if (!Directory.Exists(libFolder))
{
Directory.CreateDirectory(libFolder);
}
string destinationDatabasePath = Path.Combine(libFolder, "temp.db3");
db.Backup( destinationDatabasePath, "main");
I want to access the file generated by Xtext to compile it automatically. So I need its absolute path. It's enough to get the absolute path of the current project at run-time. Any idea how I can get it?
I am working inside the "MyDslGenerator" Class. I tried to get it from the "resource" in
override void doGenerate(Resource resource, IFileSystemAccess fsa)
but couldn't find it.
Help is highly appreciated.
I ended up using this code:
var uri = (fsa as IFileSystemAccessExtension2).getURI(fileName)
maybe you can use the Interface org.eclipse.xtext.generator.IFileSystemAccessExtension2. the passed IFileSystemAccess may implement this interface too.
I am developing image extraction application in .net using C# in VS2010.
i have created a path ,where the image will be extracted.But this path is specific to my system.
string image1 = "c:\\Users\\Raghu\\Desktop\\r.bmp";
I want a path which should be general i.e when the project will be deployed ,the output file should be extracted in Target Users desktop.
how create a folder on desktop and and all my extracted files goes in it.
Any ideas! please help me!!
Next code will return path to the desktop of current user:
Environment.GetFolderPath(Environment.SpecialFolder.DesktopDirectory);
So, in your case it would be
string desktop = Environment.GetFolderPath(Environment.SpecialFolder.DesktopDirectory);
string image1 = System.IO.Path.Combine(desktop, "r.bmp");
Environment.SpecialFolder (http://msdn.microsoft.com/en-us/library/system.environment.specialfolder.aspx) contains many definitions of system folder paths. Take a look which you need.
You would use the DesktopDirectory for Environment.SpecialFolder. Something like this:
public static string GetDesktopDirectory()
{
return Environment.GetFolderPath(Environment.SpecialFolder.DesktopDirectory);
}
Then using the result of that method, you can use Path.Combine to append a file name to it.
var myFilePath = Path.Combine(GetDesktopDirectory(), "r.bmp");
Path.Combine is the general solution for this, as directly concating strings may result in double slashes, etc. This takes care of that for you.
I am working on an application where I have an images folder relative to my application root. I want to be able to specify this relative path in the Properties -> Settings designer eg. "\Images\". The issue I am running into is in cases where the Environment.CurrentDirectory gets changed via an OpenFileDialog the relative path doesn't resolve to the right location. Is there a way to specifiy in the Settings file a path that will imply to always start from the application directory as opposed to the current directory? I know I can always dynamically concatenate the application path to the front of the relative path, but I would like my Settings property to be able to resolve itself.
As far as I know, there is no built-in functionality that will allow this type of path resolution. Your best option is to dynamically determine the applications executing directory and concatenate to it your images path. You don't want to use Environment.CurrentDirectory specifically for the reasons you mention - the current directory may not always be correct for this situation.
The safest code I've found to find the executing assembly location is this:
public string ExecutingAssemblyPath()
{
Assembly actualAssembly = Assembly.GetEntryAssembly();
if (this.actualAssembly == null)
{
actualAssembly = Assembly.GetCallingAssembly();
}
return actualAssembly.Location;
}
Are you looking for Application.ExecutablePath ? That should tell you where the application's executable is, remove the executable name, and then append your path to it.
2 options:
The code that uses the setting can resolve the setting against the directory of the current executing assembly.
You can create your own type that serializes as a string relative to the executing assembly, and has an accessor for the full path that will resolve against the directory of the current executing assembly.
Code sample:
string absolutePath = Settings.Default.ImagePath;
if(!Path.IsPathRooted(absolutePath))
{
string root = Assembly.GetEntryAssembly().Location;
root = Path.GetDirectoryName(root);
absolutePath = Path.Combine(root, absolutePath);
}
The nice thing about this code is that it allows a fully qualified path, or a relative path, in your settings. If you need the path to be relative to a different assembly, you can change which assembly's location you use - GetExecutingAssembly() will give you the location of the assembly with the code you're running, and GetCallingAssembly() would be good if you go with option 2.
This seem to work in both WinForms and ASP.NET (gives the path to the config file):
new System.IO.FileInfo(AppDomain.CurrentDomain.SetupInformation.ConfigurationFile).Directory;
For Windows and Console applications, the obvious way is by using:
Application.StartupPath
I suggest you to use Assembly.CodeBase, as shown below:
public static string RealAssemblyFilePath()
{
string dllPath=Assembly.GetExecutingAssembly().CodeBase.Substring(8);
return dllPath;
}
You can try Application.ExecutablePath. But you need to make reference to System.Windows.Forms. This may not be a good idea if you want your class library to steer clear of forms and UI stuff.
You can try the Assembly.GetExecutingAssembly().Location. But if, somehow, you do a "Shadow Copy" before you run your application (like the default NUnit behavior), then this property will return you the shadow copy location, not the real, physical location.
The best way is to implement a function that calls the CodeBase property of Assembly object and chop off the irrelevant portion of the string.
I use the following two methods to help with that:
public static IEnumerable<DirectoryInfo> ParentDirs(this DirectoryInfo dir) {
while (dir != null) {
yield return dir;
dir = dir.Parent;
}
}
public static DirectoryInfo FindDataDir(string relpath, Assembly assembly) {
return new FileInfo((assembly).Location)
.Directory.ParentDirs()
.Select(dir => Path.Combine(dir.FullName + #"\", relpath))
.Where(Directory.Exists)
.Select(path => new DirectoryInfo(path))
.FirstOrDefault();
}
The reason to look at parent dirs to to be easier in use during development when various build scripts end up sticking things in directories like bin\x64\Release\NonsensePath\.