I have a string in this format: "2013-06-05T19:41:12.739" and I need to convert it to a date field in this format: "2013-06-05 19:41:12"
How can I do this with Oracle?
You use to_date() or to_timestamp() to convert a string literal to a date/timestamp value:
If you need the milliseconds you have to convert it into a timestamp, otherwise (if you want to discard the milliseconds) you can convert it into a date:
select to_timestamp('2013-06-05T19:41:12.739', 'yyyy-mm-dd"T"hh24:mi:ss.ff3')
from dual;
To get rid of the milliseconds, simply cast the result from the above statement to a DATE
select cast(to_timestamp('2013-06-05T19:41:12.739', 'yyyy-mm-dd"T"hh24:mi:ss.ff3') as date)
from dual;
I need to convert it to a date field in this format:
A DATE column does NOT have a "format".
You apply a format to a DATE column when you display it. Either explicitely by using to_char() or implicitely by the NLS settings in effect (or by some code in your application).
Related
I get the error message: ORA-01843: not a valid month after executing a sql plus script.
I try using the "standard" date format yyyy-mm-dd.
Is SQL/PL not understanding the alter session statement?
set linesize 200
set pagesize 1000
alter session set NLS_NUMERIC_CHARACTERS = ',.';
alter session set NLS_DATE_FORMAT = 'yyyy-mm-dd';
select
*
from my_table
where
date >= '2019-08-31';
exit
What you do need - from my point of view - is not to compare date values to strings.
Presuming that date here actually represent a DATE datatype column (why didn't you post table description?) (as already commented, you can't name a column that way, not unless you enclosed its name into double quotes), then
where date >= '2019-08-31'
---- ------------
DATE this is a string
datatype
Use date literal, which always has a DATE keyword and date in format 'yyyy-mm-dd':
where date >= date '2019-08-31'
Or, use to_date function with appropriate format mask:
where date >= to_date('2019-08-31', 'yyyy-mm-dd')
If date column (wrong name, as we already know) actually contains strings and you hope all of them are following the 'yyyy-mm-dd' format, well, some values don't. Storing dates into varchar2 datatype column is almost always a bad idea. Nobody prevents you from storing e.g. '2019-ac-31' into it, and that isn't a valid date value.
I have a date string coming from user input in the format of DD/MM/YYYY and I need to match it against a date column in our database in the format of DD-MON-YY.
Example input is 01/01/2015 and example date column in our database:
SELECT MAX(creation_date) FROM orders;
MAX(creation_date)
------------------
06-AUG-15
I need to query in the format:
SELECT * FROM orders WHERE creation_date = 01/01/2015
and somehow have that converted to 01-JAN-15.
Is it possible with some built-in Oracle function?
Use to_date, if the column in the table is in date format
http://www.techonthenet.com/oracle/functions/to_date.php
to_char allows you to specify different formats in a SQL statement.
Example: to_char(sysdate,'DD-MON-YYYY') will display 06-AUG-2015 for today's date.
TO_CHAR
Use to_date to compare your date column to a date string, but be careful in doing so since your date column may include a time component that isn't showing when selecting from your table.
If there is no index on your date column, you can truncate it during the comparison:
SELECT * FROM orders WHERE TRUNC(creation_date) = TO_DATE('01/01/2015','mm/dd/yyyy');
If there is an index on your date column and you still want to use it then use a ranged comparison:
SELECT * FROM orders
WHERE creation_date >= TO_DATE('01/01/2015','mm/dd/yyyy')
and creation_date < TO_DATE('01/01/2015','mm/dd/yyyy')+1;
I have a date type column in a table, where I store date along with time.
I want to query it by WHERE clause
I did it this way:
select *
from conference_hall_book
where to_date(end_time,'dd/mon/yyyy hh24:mi:ss') <= to_date('26/oct/2013 15:00:00','dd/mon/yyyy hh24:mi:ss')
But the result has 27/10/2013 8:00:00 AM also in end_time column.
Can any one help me finding the mistake?
The problem occurs because of
to_date(end_time,'dd/mon/yyyy hh24:mi:ss')
This is a wrong usage of the to_date function. To_date converts a string to a date.
When Oracle sees this expression, it will automatically convert the end_time value to a string, using the configured date format of your database/session. This format typically doesn't include the time part, so a date with the value of "27/10/2013 8:00:00 AM" will be converted to the string "27/10/2013" (if your database date format is dd/mm/yyyy).
Your to_date expression will then convert the string value "27/10/2013" back to a date. The resulting date value will be "27/10/2013 00:00:00", so you will have lost the time portion of your original date.
The simple and correct solution is to drop the to_date(end_time) expression and just use end_time. This will also ensure that if you have index on end_time, the query will be able to use that index.
select *
from conference_hall_book
where end_time <= to_date('26/oct/2013 15:00:00','dd/mon/yyyy hh24:mi:ss')
Which type of data type are used to insert date and time in this format
(10-Oct-2013, 04:00 PM) for oracle database..
CREATE TABLE OPERATOR (
LASTPSWDCHANGE DATE,
LASTSIGNONDTTM DATE,
LASTUPDDTTM DATE
);
DATE is the correct type to store date/time values.The DATE data type does not in itself specify any particular format when converting to or from a string.
To convert from string (usually VARCHAR2) to DATE use
TO_DATE(<string with date>, <date format>)
To convert from DATE to VARCHAR2 use
TO_CHAR(<date>, <date format>)
There is a default date format which is determined by the locale of the client. In tools like Toad or SQL developer the default format often doesn't include the time part.
DATE has second precision. For higher precision (millisecond, nanosecond etc) use TIMESTAMP.
EDIT:
You can find documentation on the format specifiers on Oracles website.
In your case, use:
TO_DATE('10-Oct-2013, 04:00 PM', 'DD-MON-YYYY, HH:MI PM')
TIMESTAMP data type can be used here
a TIMESTAMP := TIMESTAMP '2013-10-10 16:00:00';
b TIMESTAMP WITH TIME ZONE := TIMESTAMP '2013-10-10 16:00:00.00 +02:00';
Hope this helps.
You can use DATE as datatype. But you can retrieve date in various format using TO_CHAR function.
An example:
SELECT TO_CHAR( LASTPSWDCHANGE ,'DD-Mon-YYYY, HH:MI AM' ),
TO_CHAR( LASTSIGNONDTTM ,'DD-Mon-YYYY, HH:MI AM' ),
TO_CHAR( LASTUPDDTTM , 'DD-Mon-YYYY, HH:MI AM' )
FROM OPERATOR
I have a field in my table with datatype as DATE in Oracle.
I want to insert the current date into that field, in format DD/MM/YYYY format.
I tried the below query:
select to_date(to_char(sysdate,'dd/mm/yyyy'),'dd/mm/yyyy') from dual
But it gives
1/8/2011 12:00:00 AM.
I want it to insert and show as
08/01/2011 12:00:00 AM.
Can anyone help me in this please ?
DATE is a built-in type in Oracle, which is represented in a fixed way and you have no control over it.
So:
I want it to insert [...] as 08/01/2011 12:00:00 AM
The above is nonsensical. You don't insert a string, you insert a date.
Format is useful only when you want:
to convert a string to an internal representation of date with TO_DATE (format mask: how to parse the string);
to convert an internal representation of date to a string with TO_CHAR (format mask: how to render the date).
So basically, in your example you take a DATE, you convert it to a STRING with some format, and convert it back to DATE with the same format. This is a no-op.
Now, what your client displays: this is because your Oracle Client won't display DATE fields directly and the NLS layer will convert any DATE field that is selected. So it depends on your locale by default.
What you want is SELECT TO_CHAR(SYSDATE,'DD/MM/YYYY') FROM dual; which will explicitly perform the conversion and return a string.
And when you want to insert a date in a database, you can use TO_DATE or date literals.
Alternatively, if you want to retrieve the date part of the DATE field, you may use truncate, i.e.
select to_char(trunc(sysdate),'dd/mm/yyyy') from dual;
When the column is of type DATE, you can use something like:
Insert into your_table(your_date_column) Select TRUNC(SYSDATE) from DUAL;
This removes the time part from SYSDATE.
Maybe this can help
insert into pasok values ('&kode_pasok','&kode_barang','&kode_suplier',
to_date('&tanggal_pasok','dd-mm-yyyy'),&jumlah_pasok);
note: '&' help we to insert data again, insert / end than enter to
insert again example: Enter value for kode_pembelian: BEL-E005 Enter
value for kode_barang: ELK-02 Enter value for kode_customer: B-0001
old 2: '&kode_pembelian','&kode_barang','&kode_customer', new 2:
'BEL-E005','ELK-02','B-0001', Enter value for tanggal_pembelian:
24-06-2002 Enter value for jumlah_pembelian: 2 old 3:
to_date('&tanggal_pembelian','dd-mm-yyyy'),&jumlah_pembelian) new 3:
to_date('24-06-2002','dd-mm-yyyy'),2)
1 row created.
SQL> / (enter)