like '%%' have more then result [closed] - oracle

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I have the following table:
number | desc
1 | name
2 | pake
3 | name
4 | fly
5 | high
I'm using the 'like' keyword, but I want it to have more than 1 comparison
If I write query below, I'll get number 1 and 3:
select number from mytable where desc like'%name%'
I want to use several conditions for my desc column, this is what I have so far:
select number from mytable where desc like'%name%' and like'%fly%'
This will cause an error. Is there a something similar to what I'm trying?
Will nesting select do the trick ?

repeat targetted field name
select number
from mytable
where desc like '%name%'
or desc like '%fly%'
maybe and, maybe or, maybe.

select number from mytable where desc like'%name%' or desc like'%fly%'

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Select data from 2 tables and match on 2 fields (oracle sql developer) [closed]

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I have two tables
TABLE1
-DATADATE
-ISIN
-INDEXNAME
TABLE2
-AS_OF_DATE
-ISSUER_ISIN
-GPSCORE
-SPSCORE
I would like to merge the two tables by matching on:
AS_OF_DATE = DATADATE
and
ISIN = ISSUER_ISIN
Try this one:
SELECT * FROM TABLE1 tb1
INNER JOIN TABLE2 tb2
ON tb1.DATADATE = tb2.AS_OF_DATE
AND tb1.ISIN = tb2.ISSUER_ISIN

How do you remove duplicate rows in Access? [closed]

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I want to remove duplicate rows within my database.
I only want them removed if each field within that row matches another within the same table.
I've researched how to use the Query wizard to find duplicate fields, but I haven't found a way to match the entire row.
Are you able to perform queries?
DELETE FROM table_name
LEFT OUTER JOIN (
SELECT
MIN(RowId) as RowId,
column_name1,
column_name2,
column_name3
FROM
table_name
GROUP BY
column_name1,
column_name2,
column_name3
) as nonDuplicates ON
table_name.RowId = nonDuplicates.RowId
WHERE
nonDuplicates.RowId IS NULL

Function to convert a string to character [closed]

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select 'open' as "documentno" from c_order
union all
select documentno as "documentno" from c_invoice
.This is not working in oracle.
i need a query that works in both oracle and postgres
You have not provided enough information to answer your question.
My guess is that you want to include columns in a union that do not have the same data type and are looking for a way to cast a number to a character value (again I'm guessing because you didn't tell us what data type documentno is).
The following works in Oracle and Postgres:
select 'open' as "documentno" from c_order
union all
select cast(documentno as varchar(20)) as "documentno" from c_invoice;
However: the first part of the union does not make sense. Why are your retrieving the same constant value for each and every row in c_order without any additional information from that table?

Convert Row into columns [closed]

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how can I convert rows of my table as column value
for eg I have a table a
emp id
1
2
3
4
and I want my output as
1 2 3 4
i am also using pivot in oracle and crosstab in postgres but not able to get desired solution as shown above.
Check the listagg function. Note you need at least Oracle 11 for this.
Use this script and change it to your values to get desired results
SELECT * FROM (SELECT emp_id, emp_points
FROM emp_data)
PIVOT (
SUM(emp_points) AS sum_emp_points
FOR (emp_id) IN (1 AS [1], 2 AS [2],3 AS [3],4 AS [4])
);
select * from (select empno from t7) pivot(min(empno) for empno in (1,2,3,4));

How can I take substring in Oracle [closed]

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I have a row string in oracle table.
Some text № 3694452 from 31.08.2013, stilltext 02.09.2013 18:16:27
How can I take "02.09.2013 18:16:27" (from the end of row and after stilltext)
for converting it to date.
Assuming that the date string always positioned at the end of text,
you can use regular expression like this:
select
to_date(
regexp_substr(your_column_name, '\d{2}.\d{2}.\d{4} \d{2}:\d{2}:\d{2}$'),
'dd.mm.yyyy hh24:mi:ss')
from you_table_name;
This assumes that the date is always at the end of the string and is fixed in format.
with dummy as
(select '3694452 from 31.08.2013, stilltext 02.09.2013 18:16:27' data
from dual)
select to_date(substr(data,length(data)-19), 'MM.DD.YYYY HH24:MI:SS')
from dummy
There are more elegant ways to do this with regular expressions, but I am assuming this will suffice.
SQL Fiddle demo here

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