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how can I convert rows of my table as column value
for eg I have a table a
emp id
1
2
3
4
and I want my output as
1 2 3 4
i am also using pivot in oracle and crosstab in postgres but not able to get desired solution as shown above.
Check the listagg function. Note you need at least Oracle 11 for this.
Use this script and change it to your values to get desired results
SELECT * FROM (SELECT emp_id, emp_points
FROM emp_data)
PIVOT (
SUM(emp_points) AS sum_emp_points
FOR (emp_id) IN (1 AS [1], 2 AS [2],3 AS [3],4 AS [4])
);
select * from (select empno from t7) pivot(min(empno) for empno in (1,2,3,4));
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I have two tables
TABLE1
-DATADATE
-ISIN
-INDEXNAME
TABLE2
-AS_OF_DATE
-ISSUER_ISIN
-GPSCORE
-SPSCORE
I would like to merge the two tables by matching on:
AS_OF_DATE = DATADATE
and
ISIN = ISSUER_ISIN
Try this one:
SELECT * FROM TABLE1 tb1
INNER JOIN TABLE2 tb2
ON tb1.DATADATE = tb2.AS_OF_DATE
AND tb1.ISIN = tb2.ISSUER_ISIN
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I want to remove duplicate rows within my database.
I only want them removed if each field within that row matches another within the same table.
I've researched how to use the Query wizard to find duplicate fields, but I haven't found a way to match the entire row.
Are you able to perform queries?
DELETE FROM table_name
LEFT OUTER JOIN (
SELECT
MIN(RowId) as RowId,
column_name1,
column_name2,
column_name3
FROM
table_name
GROUP BY
column_name1,
column_name2,
column_name3
) as nonDuplicates ON
table_name.RowId = nonDuplicates.RowId
WHERE
nonDuplicates.RowId IS NULL
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Closed 7 years ago.
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i am trying to validate data inside my database that is number.
Am i able to detect the retrieved data whether it starts with 8 or 9?
For example:
8999999 is valid
9999999 is valid
7000000 is invalid
Thanks
You can try checking the first character of the field using SUBSTR():
SELECT field_value
FROM your_table
WHERE SUBSTR(TO_CHAR(field_value), 1, 1) IN ('8','9')
The following query will return all records where column data begins with an 8 or 9:
SELECT data
FROM your_table
WHERE REGEXP_LIKE (CAST(data AS varchar2(30)), '^(8|9)(*)');
I assume here that data is a numeric type, and so I cast it to varchar before using REGEXP_LIKE.
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I have a row string in oracle table.
Some text № 3694452 from 31.08.2013, stilltext 02.09.2013 18:16:27
How can I take "02.09.2013 18:16:27" (from the end of row and after stilltext)
for converting it to date.
Assuming that the date string always positioned at the end of text,
you can use regular expression like this:
select
to_date(
regexp_substr(your_column_name, '\d{2}.\d{2}.\d{4} \d{2}:\d{2}:\d{2}$'),
'dd.mm.yyyy hh24:mi:ss')
from you_table_name;
This assumes that the date is always at the end of the string and is fixed in format.
with dummy as
(select '3694452 from 31.08.2013, stilltext 02.09.2013 18:16:27' data
from dual)
select to_date(substr(data,length(data)-19), 'MM.DD.YYYY HH24:MI:SS')
from dummy
There are more elegant ways to do this with regular expressions, but I am assuming this will suffice.
SQL Fiddle demo here
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I have the following table:
number | desc
1 | name
2 | pake
3 | name
4 | fly
5 | high
I'm using the 'like' keyword, but I want it to have more than 1 comparison
If I write query below, I'll get number 1 and 3:
select number from mytable where desc like'%name%'
I want to use several conditions for my desc column, this is what I have so far:
select number from mytable where desc like'%name%' and like'%fly%'
This will cause an error. Is there a something similar to what I'm trying?
Will nesting select do the trick ?
repeat targetted field name
select number
from mytable
where desc like '%name%'
or desc like '%fly%'
maybe and, maybe or, maybe.
select number from mytable where desc like'%name%' or desc like'%fly%'