I have 50 column in a table and it returns only one row and I want that one row with 50 column to be displayed in 50 rows and one column.
Can any one suggest me the Oracle query for it?
You can use UNPIVOT for one row like this to get only column with values
SELECT colvalue
FROM
(
SELECT *
FROM Table1
UNPIVOT INCLUDE NULLS
(
colvalue FOR cols IN (col1, col2, col3, col4, col5, col6, col7, col8, col9, col10, ... col50)
)
);
Sample output:
| COLVALUE |
------------
| 1 |
| 2 |
| (null) |
|..........|
If you need column with column names from your pivoted table just ditch the outer select
SELECT *
FROM Table1
UNPIVOT INCLUDE NULLS
(
colvalue FOR cols IN (col1, col2, col3, col4, col5, col6, col7, col8, col9, col10, ... col50)
);
Sample output:
| COLS | COLVALUE |
--------------------
| COL1 | 1 |
| COL2 | 2 |
| COL3 | (null) |
| ..... |......... |
Here is SQLFiddle demo
Be prepared for a lot of typing :) Oracle has UNPIVOT functionality but it wants at least two columns in the result, so it won't work for your situation.
First off, you'll need a counter from 1 to 50. You can query one like this:
SELECT LEVEL as Counter FROM DUAL CONNECT BY LEVEL <= 50
If you execute this query you'll get the numbers 1-50 as your result. With that as a basis, here's the full(ish) query:
WITH Cols AS (
SELECT LEVEL as Counter
FROM DUAL
CONNECT BY LEVEL <= 50
)
SELECT
CASE Cols.Counter
WHEN 1 THEN Col1
WHEN 2 THEN Col2
WHEN 3 THEN Col3
. . .
WHEN 50 THEN Col50
END AS myColumn
FROM myTable
CROSS JOIN Cols
ORDER BY Cols.Counter
Note that all of the columns must be the same data type, so if you have a mixture of character, number and date you'll need to convert them all to character.
Note that this query assumes one row in the table, as mentioned in the question. If there's more than one row you should end with ORDER BY a-column-that-identifies-the-row, Cols.Counter.
Related
I have a package in oracle. In the package i have a procedure which performs an (insert into ..select.. ) statement
which is like this:
insert into some_table(col1 , col2 , col3, col4)
select col1 , col2, my_func(col3) as new_col3 , col4
from some_other_table
my_func(col3) does some logic to return a value.
now i need to to return two values instead of one, using the same logic.
i can simply write another function to do the same logic and return the second value, but that would be expensive because the function selects from a large history table.
i can't do a join with the history table because the function doesn't perform a simple select.
is there a way to get two columns by calling this function only once?
Create an OBJECT type with two attributes and return that from your function. Something like:
SQL Fiddle
Oracle 11g R2 Schema Setup:
CREATE TYPE my_func_type IS OBJECT(
value1 NUMBER,
value2 VARCHAR2(4000)
);
/
CREATE FUNCTION my_func
RETURN my_func_type
IS
value my_func_type;
BEGIN
value := my_func_type( 42, 'The Meaning of Life, The Universe and Everything' );
RETURN value;
END;
/
CREATE TABLE table1 (col1, col2, col5 ) AS
SELECT 1, 2, 5 FROM DUAL
/
Query 1:
SELECT col1,
col2,
t.my_func_value.value1 AS col3,
t.my_func_value.value2 AS col4,
col5
FROM (
SELECT col1,
col2,
my_func() AS my_func_value,
col5
FROM table1
) t
Results:
| COL1 | COL2 | COL3 | COL4 | COL5 |
|------|------|------|--------------------------------------------------|------|
| 1 | 2 | 42 | The Meaning of Life, The Universe and Everything | 5 |
I have a table like this in Oracle 9i DB:
+------+------+
| Col1 | Col2 |
+------+------+
| 1 | a |
| 2 | a |
| 3 | a |
| 4 | b |
| 5 | b |
+------+------+
Col1 is the primary key, Col2 is indexed.
I input col1 as condition for my query and I want to get col1 where col2 is the same as my input.
For example I query for 1 and the result should be 1,2,3.
I know I can use self join for this, I would like to know if there is a better way to do this.
I'd call this a semi-join: does it satisfy your 'no self joins' requirement?:
SELECT *
FROM YourTable
WHERE Col2 IN ( SELECT t2.Col2
FROM YourTable t2
WHERE t2.Col1 = 1 );
I'd be inclined to avoid the t2 range variable like this:
WITH YourTableSearched
AS ( SELECT Col2
FROM YourTable
WHERE Col1 = 1 )
SELECT *
FROM YourTable
WHERE Col2 IN ( SELECT Col2
FROM YourTableSearched );
but TNH I would probably do this:
WITH YourTableSearched
AS ( SELECT Col2
FROM YourTable
WHERE Col1 = 1 )
SELECT *
FROM YourTable
NATURAL JOIN YourTableSearched;
It's possible. Whether it's better (i.e. more performant) than using a self-join, particularly if there is an index on col1, col2, is anyone's guess.
Assuming col1 is unique, you could do:
SELECT col1
FROM (SELECT col1,
col2,
MAX(CASE WHEN col1 = :p_col1_value THEN col2 END) OVER () col2_comparison
FROM your_table)
WHERE col2 = col2_comparison;
And with :p_col1_value = 1:
COL1
----------
1
2
3
And with :p_col1_value = 5:
COL1
----------
4
5
I have a requirement to display one column in a matrix table.
ex:
Select SlotNumber from Parking_lot_table;
out:
SL01
SL02
SL03
SL04
SL05
SL06
SL07
SL08
SL09
SL10
My Output must be like :
Col1 Col2 Col3 Col4 Col5
SL01 SL02 SL03 SL04 SL05
SL06 SL07 SL08 SL09 SL10
even Its fine to fix the number of columns ...
Kindly suggest ... How to do this in Oracle SQL
select * from
( select trunc((rownum -1) / 5 ) gr , mod(rownum, 5) rn, slot
from
( select * from
parking_lot_table order by to_number(REGEXP_REPLACE(slot, '[^0-9]+', ''))
)
)
pivot
( max(slot)
for rn in ( 1 as Col1, 2 as Col2, 3 as Col3, 4 as Col4, 0 as Col5) )
order by 1
I have 50 column in a table and it returns only one row and I want that one row with 50 column to be displayed in 50 rows and one column.
Can any one suggest me the Oracle query for it?
You can use UNPIVOT for one row like this to get only column with values
SELECT colvalue
FROM
(
SELECT *
FROM Table1
UNPIVOT INCLUDE NULLS
(
colvalue FOR cols IN (col1, col2, col3, col4, col5, col6, col7, col8, col9, col10, ... col50)
)
);
Sample output:
| COLVALUE |
------------
| 1 |
| 2 |
| (null) |
|..........|
If you need column with column names from your pivoted table just ditch the outer select
SELECT *
FROM Table1
UNPIVOT INCLUDE NULLS
(
colvalue FOR cols IN (col1, col2, col3, col4, col5, col6, col7, col8, col9, col10, ... col50)
);
Sample output:
| COLS | COLVALUE |
--------------------
| COL1 | 1 |
| COL2 | 2 |
| COL3 | (null) |
| ..... |......... |
Here is SQLFiddle demo
Be prepared for a lot of typing :) Oracle has UNPIVOT functionality but it wants at least two columns in the result, so it won't work for your situation.
First off, you'll need a counter from 1 to 50. You can query one like this:
SELECT LEVEL as Counter FROM DUAL CONNECT BY LEVEL <= 50
If you execute this query you'll get the numbers 1-50 as your result. With that as a basis, here's the full(ish) query:
WITH Cols AS (
SELECT LEVEL as Counter
FROM DUAL
CONNECT BY LEVEL <= 50
)
SELECT
CASE Cols.Counter
WHEN 1 THEN Col1
WHEN 2 THEN Col2
WHEN 3 THEN Col3
. . .
WHEN 50 THEN Col50
END AS myColumn
FROM myTable
CROSS JOIN Cols
ORDER BY Cols.Counter
Note that all of the columns must be the same data type, so if you have a mixture of character, number and date you'll need to convert them all to character.
Note that this query assumes one row in the table, as mentioned in the question. If there's more than one row you should end with ORDER BY a-column-that-identifies-the-row, Cols.Counter.
I am using posexplode to split single to multiple records in hive.
Along with multiple records as output i need to generate sequence number for each row.
col1, col2, col3 and col4 are defined as string because rarely we get alpha data as well.
col1 | col2| col3 | col4
---------------------------
7 | 9 | A | 3
5 | 6 | 9
Seq | Col
----------
1 | 7
2 | 9
3 | A
4 | 3
1 | 5
2 | 6
3 | 9
I am using below mentioned query but I am getting error
-bash: syntax error near unexpected token (
My query is :
SELECT
seq, col
FROM
(SELECT array( col1, col2 , col3,col4) as arr_r FROM srctable ) arrayrec
LATERAL VIEW posexplode(arrayrec) EXPLODED_rec as seq, col
How can this be resolved
I am able to run successfully this query :
SELECT col FROM
(SELECT array( col1, col2 , col3,col4)
as arr_r FROM srctable ) arrayrec
LATERAL VIEW explode(arrayrec) EXPLODED_rec as col
Which produces below output
Col
-----
7
9
A
3
5
6
9
I have checked the link : How to get first n elements in an array in Hive
Try
SELECT Seq, col FROM
(SELECT array( col1, col2 , col3,col4)
as arr_r FROM srctable ) arrayrec
LATERAL VIEW posexplode(arrayrec.arr_r) EXPLODED_rec as Seq, col;
Also check your hive version. posexplode() is available as of Hive 0.13.0.