I have a requirement to display one column in a matrix table.
ex:
Select SlotNumber from Parking_lot_table;
out:
SL01
SL02
SL03
SL04
SL05
SL06
SL07
SL08
SL09
SL10
My Output must be like :
Col1 Col2 Col3 Col4 Col5
SL01 SL02 SL03 SL04 SL05
SL06 SL07 SL08 SL09 SL10
even Its fine to fix the number of columns ...
Kindly suggest ... How to do this in Oracle SQL
select * from
( select trunc((rownum -1) / 5 ) gr , mod(rownum, 5) rn, slot
from
( select * from
parking_lot_table order by to_number(REGEXP_REPLACE(slot, '[^0-9]+', ''))
)
)
pivot
( max(slot)
for rn in ( 1 as Col1, 2 as Col2, 3 as Col3, 4 as Col4, 0 as Col5) )
order by 1
Related
I have two tables, customers and products.
products:
productid name
1 pro1
2 pro2
3 pro3
customers:
id name productid
1 cust1 1,2
2 cust2 1,3
3 cust3
i want following result in select statement,
id name productid
1 cust1 pro1,pro2
2 cust2 pro1,pro3
3 cust3
i have 300+ records in both tables, i am beginner to back end coding, any help?
Definitely a poor database design but the bad thing is that you have to live with that. Here is a solution which I created using recursive query. I don't see the use of product table though since your requirement has nothing to do with product table.
with
--Expanding each row seperated by comma
tab(col1,col2,col3) as (
Select distinct c.id,c.prdname,regexp_substr(c.productid,'[^,]',1,level)
from customers c
connect by regexp_substr(c.productid,'[^,]',1,level) is not null
order by 1),
--Appending `Pro` to each value
tab_final as ( Select col1,col2, case when col3 is not null
then 'pro'||col3
else col3
end col3
from tab )
--Displaying result as expected
SELECT
col1,
col2,
LISTAGG(col3,',') WITHIN GROUP( ORDER BY col1,col2 ) col3
FROM
tab_final
GROUP BY
col1,
col2
Demo:
--Preparing dataset
With
customers(id,prdname,productid) as ( Select 1, 'cust1', '1,2' from dual
UNION ALL
Select 2, 'cust2','1,3' from dual
UNION ALL
Select 3, 'cust3','' from dual),
--Expanding each row seperated by comma
tab(col1,col2,col3) as (
Select distinct c.id,c.prdname,regexp_substr(c.productid,'[^,]',1,level)
from customers c
connect by regexp_substr(c.productid,'[^,]',1,level) is not null
order by 1),
--Appending `Pro` to each value
tab_final as ( Select col1,col2, case when col3 is not null
then 'pro'||col3
else col3
end col3
from tab )
--Displaying result as expected
SELECT
col1,
col2,
LISTAGG(col3,',') WITHIN GROUP( ORDER BY col1,col2 ) col3
FROM
tab_final
GROUP BY
col1,
col2
PS: While using don't forget to put your actual table columns as in my example it may vary.
Have 2 tables with same columns and want to generate the difference between the tables and want to show the difference listing all columns from both tables
example:
select a.*,b.* from (
(
select a.col1,a.col2 from
(select col1, col2 from table1 minus select col1, col2 from table2) as a
)
union
(
select b.col1, b.col2 from
(select col1, col2 from table2 minus select col1, col2 from table2) as b
)
)
The result should be
a.col1 a.col2 b.col1 b.col2
a.FName a.ZipCode b.FName b.ZipCode
John <same value> Jane <same value as A>
Alpha 1234 Beta 2345
My query returns exception that it is missing R parenthesis after the 1st minus keyword
I think you are trying to find rows from table a which are missing in table b and rows in table b which are missing from table a. However, there is no point in joining these two sets. Try the following query and see if it works for you.
SELECT col1, col2, 'Missing from table 2' title
FROM
(
SELECT col1,
col2
FROM table1
MINUS
SELECT col1,
col2
FROM table2
)
UNION ALL
SELECT col1, col2, 'Missing from table 1' title
FROM
(
SELECT col1,
col2
FROM table2
MINUS
SELECT col1,
col2
FROM table1
)
Is it possible to "set" values inside case statement during update as below ?
UPDATE TABLE1
CASE WHEN COL1 = 'A' THEN SET COL2 = 10, COL3 = 20, COL4 = 30
WHEN COL1 IN ('B','N') THEN SET COL2 = 1, COL3 = 5, COL4 = 7
WHEN COL1 = 'D' THEN SET COL2 = 11, COL3 = 13, COL4 = 17
ELSE SET COL2 = 0, COL3 = 0, COL4 = 0
END;
The corresponding valid syntax would be like this.
UPDATE TABLE1 SET
COL2 = (CASE WHEN COL1 = 'A' THEN 10
WHEN COL1 IN ('B','N') THEN 1
WHEN COL1 = 'D' THEN 11
ELSE 0
END),
COL3 = (CASE WHEN COL1 = 'A' THEN 20
WHEN COL1 IN ('B','N') THEN 5
WHEN COL1 = 'D' THEN 13
ELSE 0
END),
COL4 = (CASE WHEN COL1 = 'A' THEN 30
WHEN COL1 IN ('B','N') THEN 7
WHEN COL1 = 'D' THEN 17
ELSE 0
END);
Looks like you're trying to do a MERGE, with one exception. You can update the table in a single merge statement as follows, except your logic to update all non-matching rows to 0's.
SQL> create table tab1
(
col1 varchar2(10),
col2 number,
col3 number,
col4 number,
merge_flag char(1)
)
Table created.
SQL> insert into tab1 values ('A', 10,11,12,null)
1 row created.
SQL> insert into tab1 values ('B', 20,21,22,null)
1 row created.
SQL> insert into tab1 values ('C', 30,31,32,null)
1 row created.
SQL> commit
Commit complete.
SQL> select * from tab1
COL1 COL2 COL3 COL4 MERGE_FLAG
---------- ---------- ---------- ---------- ----------
A 10 11 12
B 20 21 22
C 30 31 32
3 rows selected.
SQL> merge into tab1 t
using (
select 'A' as col1, 10 as col2, 20 as col3, 30 as col4 from dual
union
select 'B' as col1, 1 as col2, 5 as col3, 7 as col4 from dual
union
select 'N' as col1, 1 as col2, 5 as col3, 7 as col4 from dual
union
select 'D' as col1, 11 as col2, 13 as col3, 17 as col4 from dual
) x
on (t.col1 = x.col1)
when matched then
update set t.col2 = x.col2, t.col3 = x.col3, t.col4 = x.col4, t.merge_flag = 'X'
Merge successfully completed.
SQL> commit
Commit complete.
SQL> select * from tab1
COL1 COL2 COL3 COL4 MERGE_FLAG
---------- ---------- ---------- ---------- ----------
A 10 20 30 X
B 1 5 7 X
C 30 31 32
3 rows selected.
You could run a single update after the merge to change all non matching rows with 0.
In order to do this via case, you would have to repeat the case for each field (as demonstrated by #MaheswaranRavisankar). That's just the way case works. An alternative would be to fabricate a sub-query that provides the same results. While this is longer, it does group related values together, which may be more readable/easier to maintain.
Given the need to set all non-matching values to zero, I would solve that by setting all values to zero first, then updating the matches the appropriate value.
UPDATE table1
SET col2 = 0, col3 = 0, col4 = 0;
UPDATE table1
SET (col2, col3, col4) =
(SELECT a.col2, a.col3, a.col4
FROM (SELECT 'A' AS col1,
10 AS col2,
20 AS col3,
30 AS col4
FROM DUAL
UNION ALL
SELECT 'B' AS col1,
5 AS col2,
5 AS col3,
7 AS col4
FROM DUAL
UNION ALL
SELECT 'N' AS col1,
5 AS col2,
5 AS col3,
7 AS col4
FROM DUAL
UNION ALL
SELECT 'D' AS col1,
13 AS col2,
7 AS col3,
17 AS col4
FROM DUAL) a
WHERE a.col1 = table1.col1);
This also hints at another option: perhaps you should consider creating a table with these values, rather than embedding them in the SQL.
How to get the following result ?
Input : -
t1
--------------
col1 col2 col3
--------------
101, abc, 100
101, xyz, 200
101, rst, 300
-------------
Output : -
101 abc 100 xyz 200 rst 300
Please try:
SELECT col1, replace(wm_concat(col2||col3),',', '') FROM t1 GROUP BY col1;
or
SELECT col1, (SELECT XMLAGG(xmlelement(X, X1.col2||col3)order by X1.col2).extract('//text()')
FROM t1 X1 WHERE X1.col1=X.col1)
FROM t1 X
This works with 11g and maintains the order of items.
select LISTAGG (code, ' ') WITHIN GROUP (ORDER BY rn, coln)
from(
select code, min(rn) as rn, min(coln) as coln
from(
select col1 as code, rownum rn, 1 as coln from t order by col1, col3
union all
select col2 as code, rownum rn, 2 as coln from t order by col1, col3
union all
select col3 as code, rownum rn, 3 as coln from t order by col1, col3
)
group by code
)
Try with
select col1 || ' ' || listagg( col2 || ' ' || col3, ' ' ) within group ( order by COL3 )
from t1
group by col1;
I need to transform the rows into columns for the similar ID's in oracle
e.g.
The following is the result I will get if i query my database
Col1 Col2 Col3
---- ---- ----
1 ABC Yes
1 XYZ NO
2 ABC NO
I need to transform this into
Col1 Col2 Col3 Col4 Col5
---- ---- ---- ---- ----
1 ABC Yes XYZ No
2 ABC NO NULL NULL
Someone please help me in solving this issue
Thanks,
Siv
Based on AskTom:
select Col1,
max( decode( rn, 1, Col2 ) ) Col_1,
max( decode( rn, 1, Col3 ) ) Col_2,
max( decode( rn, 2, Col2 ) ) Col_3,
max( decode( rn, 2, Col3 ) ) Col_4
from (
select Col1,
Col2,
Col3,
row_number() over (partition by Col1 order by Col2 desc nulls last) rn
from MyTable
)
group by Col1;
I don't have access to an Oracle db to test it but I think that will work. If there could be more than two records per ID then you could just add more rows to the select cause with the corresponding row number.
One solution is to use the 10g MODEL clause:
SQL> select col1
2 , col2
3 , col3
4 , col4
5 , col5
6 from t23
7 model
8 return updated rows
9 partition by ( col1 )
10 dimension by ( row_number() over ( partition by col1
11 order by col2 desc nulls last) rnk
12 )
13 measures (col2, col3, lpad(' ',4) col4, lpad(' ',4) col5)
14 rules upsert
15 (
16 col2 [0] = col2 [1]
17 , col3 [0] = col3 [1]
18 , col4 [0] = col2 [2]
19 , col5 [0] = col3 [2]
20 )
21 /
COL1 COL2 COL3 COL4 COL5
---------- ---- ---- ---- ----
1 ABC Yes ABC NO
2 XYZ NO
SQL>
It is an unfortunate truth about such solutions that we need to specify the number of columns in the query. That is, in regular SQL there is no mechanism for determining that the table contains three rows where COL1 = 1 so we need seven columns, which is not unreasonable. For situations in which the number of pivot values is unknown at the time of coding there is always dynamic sql.