Get data from database pagination without refresh (symfony2) - ajax

I am new to symfony2 and this is my first question(please forgive me if something looks funny).
I've used some other 3rd party bundles before, but i need a way，which can implement pagination without refresh.
So, can anyone help me to solve this problem?


You can use Pagerfanta for pagination and use ajax call to update your view.

Related

Insert values from FORM to DB using AJAX on october cmd

I'm trying to get form data and put it into the database using ajax.
I'm missing the DB insert part.
Couldn't find appropriate documentation on this one.
Please advice.
(it is a very basic usage. basic form, ajax and db)
Thank

You can see here the tutorial http://www.tutorialspoint.com/ajax/ajax_database.htm

In Laravel project, Insert update delete data code on same page?

I am new for Laravel coding, Actually I want to data Insert, view, Update, Delete on same. Please give some project link or code.

use ajax call to achieve the the operations and the corresponding api should be present at back-end.. to achieve the same you can use RESTFul Controllers or define your own.

You want to learn RESTful controllers:
https://laravel.com/docs/5.2/controllers#restful-resource-controllers

Ajax implementation with Django

I am presently working on a Django project that requires the implementation of Ajax.
e.g adding model objects to the database, getting and updating model instances from the database etc without refreshing the page at all.
I have searched everywhere but am yet to come across any relevant material.
I would implore the gurus in the house to point me in the direction of materials you know could seriously be of help. Thanks

Django Ajax forms
Dajax project
Ajax and Django views

What you ask looks like implementing a RESTful API (create, update and get objects...)
You should have a look at Tastypie or Piston
For a comparison of those two look at this question

yii - form/modal based on mongodb

I am using mongo db in my yii project.
I am newbie in yii and mvc. I need to show some fields from database to user. And also allow them to edit those fields when they click edit. From what I know so far, I need a modal to create form. Modal should extend CActiveRecord (because I am allowing edit).
But I have no clue how this is going to work with mongodb ? Its very differnt from mysql (structure and fields are not definite in mongodb). Some users have field (column) abc while some do user do not have it.
I am looked into the mongodbsuite for yii. But its very hard for me to understand that at this level.
I am willing to write my own custom code, if someone can give me a direction. (or I'll have to write my own code destroying the feel of yii/mvc. Fetching everything and inserting into textboxes and then allow users to edit those)

I think this extension will help you. Pls check - YIIMongoDBSuite

What i suggest instead of writing your own code and doing testing to make it work, it is always better to shift to mysql,oracle or anything that Yii supports. it would save life
Yii Supports
SQLite
mysql
PostgreSQL
SQL Server
Oracle

It might be worth asking this question on the yiiframework forum
http://www.yiiframework.com/forum/
where there seem to be people actively using yii and mongodb.

Learning Yii: checking with ajax won't work

I have a small problem that seems to be big enough to hold me from my work.
As I said in the title, I am leaning Yii and after I developped my project, I realized that I don't have ajax check.
I tried to solve this by setting enableAjaxValidation to true and it didn't worked. I tried to make use of the method performAjaxValidation and, again, it didn't worked. The third way was to copy the content of performAjaxValidation and paste it inside my method (like in documentation and identical with the code generated by Yii.
I checked my js and they are loaded.
What could it be? How can I solve this? The problem is that I need my fields to modify while the user is completing the form.
Thank you!
PS: I checked some topics from stackoverflow but the only one who was related was Yii - Ajax Form with validations

Make sure the from that is being validated has the same ID that is being used in the performAjaxValidation function. For example if your form has the id product-form, the if statement should look like this:if(isset($_POST['ajax']) && $_POST['ajax']==='product-form')
If possible I recommend using Firefox with firebug extension so that you can debug whether the AJAX call is even being made, and what is being returned.

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