I have a bunch of files I'm trying to organize quickly, and I had two questions about how to do that. I really appreciate any help! I tried searching but couldn't find anything on these specific commands for OSX.
First, I have about 100 folders in a directory - I'd like to place an folder in each one of those folders.
For example, I have
Cars/Mercedes/<br>
Cars/BMW/<br>
Cars/Audi/<br>
Cars/Jeep/<br>
Cars/Tesla/
Is there a way I can create a folder inside each of those named "Pricing" in one command, i.e. ->
Cars/Mercedes/Pricing <br>
Cars/BMW/Pricing<br>
Cars/Audi/Pricing<br>
Cars/Jeep/Pricing<br>
Cars/Tesla/Pricing
My second question is a little tougher to explain. In each of these folders, I'd like move certain files into these newly created folders (above) in the subdirectory.
Each file has a slightly different filename but contains the same string of letters - for example, in each of the above folders, I might have
Cars/Mercedes/payment123.html
Cars/BMW/payment432.html
Cars/Audi/payment999.html
Cars/Jeep/payment283.html
Is there a way to search each subdirectory for a file containing the string "payment" and move that file into a subfolder in that subdirecotry - i.e. into the hypothetical "Pricing" folders we just created above with one command for all the subdirectories in Cars?
Thanks so much~! help with either of these would be invaluable.
I will assume you are using bash, since it is the default shell in OS X. One way to do this uses a for loop over each directory to create the subdirectory and move the file. Wildcards are used to find all of the directories and the file.
for DIR in Cars/*/ ; do
mkdir "${DIR}Pricing"
mv "${DIR}payment*.html" "${DIR}Pricing/"
done
The first line finds every directory in Cars, and then runs the loop once for each, replacing ${DIR} with the current directory. The second line creates the subdirectory using the substitution. Note the double quotes, which are necessary only if the path could contain spaces. The third line moves any file in the directory whose name starts with "payment" and ends with ".html" to the subdirectory. If you have multiple files which match this, they will all be moved. The fourth line simply marks the end of the loop.
If you are typing this directly into the command line, you can combine it into a single line:
for DIR in Cars/*/ ; do mkdir "${DIR}Pricing"; mv "${DIR}payment*.html" "${DIR}Pricing/"; done
Related
I have very little experience with the command line and I'm trying to do something very complicated (to me).
I have a directory with A LOT of subfolders and files in them. All file names contain the parent folder name, e.g.:
Folder1
data_Folder1.csv
other_file_Folder1.csv
Folder2
data_Folder2.csv
other_file_Folder2.csv
In another folder (all in one directory), I have a new version of all the data_FolderX.csv files and I need to replace them in the original folders. I cannot give them another name because of later analyses. Is there a way to replace the files in the original folders with the new version, in the command line?
I tried this Replacing a file into multiple folders/subdirectories but didn't work for me. Given that I have many .csv files in the derectories, I don't want to replace them all, so I don't think I should do it based on the file extension. I would also like to note that the name "FolderX" contains several other _, so in principal, I want to replace the .csv file starting with data in the FolderX.
Can anyone help?
Thanks in advance!
I have a script that takes as an argument a path to a file upon which it performs certain operations. These files are stored in directories with path storage///_id/files (so in 2016 July 22 it would be storage/2016/Jul/22_1/files for the first set of files, .../Jul/22_2/files for second one etc.). The problem is each directory stores files with two extensions (say file.doc, file.txt) and I want to perform operations only on .txt files. I've tested earlier something like
for file in "/home/gonczor/temp/"*/*".txt"; do
echo "$file"
done
And it worked perfectly given that names in directories don't change. When I move one step further and add this 22_1, 22_2, 23_1 directories something strange happens.
This is my script (simplified):
for file in "$FILE_PATH/""$YEAR/""$MONTH/""$DAY"*/*".txt"; do
my_program ${report}
done
And instead of finding .../2016/Jul/22_1/file.txt it finds /2016/Jul/22*/*.txt
How can I make it work? The solution I've tried to make up is from here
I have a huge list of files, they came through different processes, so for some reason the ones in the first folder are numbered like this
A9.txt A1.txt while the ones in the other have A00009.txt A.00001.txt
I have no more than 99837 files so only four "extra" 0 on one side.
I need to rename all the files inside one folder so the names matches. Is there any way to do this in a loop? Thanks for the help.
You should take a look at perl-rename (Sometimes called rename) Not to be confused with rename from util-linux.
perl-rename 's/\d+/sprintf("%05d", $&)/e' *.txt
The above script will rename all .txt files in a directory to the following:
A1.txt -> A00001.txt
A10.txt -> A00010.txt
Hello225.txt -> Hello00225.txt
Test it Online
Kind of easy question, but I can't find the answer. I want to extract the contents of multiple zipped folders into a single directory. I am using the bash console, which is the only tool available on the particular website I am using.
For example, I have two folders: a.zip (which contains a1.txt and a2.txt) and b.zip (which contains b1.txt and b2.txt). I want to get extract all four text files into a single directory.
I have tried
unzip \*.zip -d \newdirectory
But it creates two directories (a and b) with two text files in each.
I also tried concatenating the two zipped folders into one big folder and extracting it, but it still creates two directories, even when I specify a new directory.
I can't figure what I am doing wrong. Any help?
Thanks in advance!
Use the -j parameter to ignore any directory structure.
unzip -j -d /path/to/your/directory '*.zip*'
I have to use bash scripting to copy files from one folder to another. If the destination folder has a file with the same name but older timestamp, it should not copy. Only newer files should be copied. I could have used cp -u, but I was asked not to use it. Essentially I have to use the test command testing for "ot". Please let me know how could this be done. I believe two for loops one to read the files in the source and one for the destination directories can be used and the the time stamp compared. The problem is that both for loops produce the absolute path names along with the file name. So not sure how to compare them
Thanks
You can profit from the parameter substitution:
for file in "$folder1"/* ; do
filename=${file##*/} # Remove everything to the last slash.
Or, you can change the directory:
cd "$folder1"
for file in * ; do
## you have to use full or relative path to $folder2 here