How do I tell Spring that I am a certain user with certain authorities and then access an #Secured method with that user? - spring

Question

Given the following users :
<authentication-manager alias="authenticationManager">
<authentication-provider>
<user-service>
<user name="dev" password="devpass" authorities="DEV" />
<user name="user" password="userpass" authorities="USER" />
</user-service>
</authentication-provider>
</authentication-manager>
I want to be 'user' and then access a secured method
#Secured("DEV")
public void devOnly() {
// .. dev stuff
}
So far I've tried a lot of things and cannot get #Secured to throw an AccessDeniedException
EDIT: Added configuration files
web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app id="WebApp_ID" version="2.5"
xmlns="http://www.java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://www.java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<display-name>Spring MVC Application</display-name>
<!-- Spring MVC -->
<servlet>
<servlet-name>mvc-dispatcher</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>
classpath:/mvc-dispatcher-servlet.xml
</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>mvc-dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
classpath:/mvc-dispatcher-servlet.xml
classpath:/spring-security.xml
</param-value>
</context-param>
<!-- Spring Security -->
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>
org.springframework.web.filter.DelegatingFilterProxy
</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
spring-security.xml
<beans:beans xmlns="http://www.springframework.org/schema/security"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-3.1.xsd">
<global-method-security secured-annotations="enabled" />
<http auto-config="true">
<form-login/>
<http-basic/>
<!--<intercept-url pattern="/welcome*" access="ROLE_USER" />-->
</http>
<authentication-manager>
<authentication-provider>
<user-service>
<user name="admin" password="password" authorities="ROLE_ADMIN" />
</user-service>
</authentication-provider>
</authentication-manager>
mvc-dispatcher-servlet.xml
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<context:component-scan base-package="com.rodly.testapp" />
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix">
<value>/WEB-INF/frontend/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>