I have 3 tables.
Table1
|Obj_id|Obj_Name|
----------------
|A | AAA|
|B | BBB|
|C | CCC|
Table2
|Obj_id|Amount1|
----------------
|A | 1000|
|C | 20|
|A | 100|
|B | 50|
|C | 10|
Table3
|Obj_id|Amount2|
----------------
|B | 500|
|C | 10|
|C | 40|
Now I need to create a procedure "report" that returns a cursor like below
Report
|Obj_Name|Amount1|Amount2|Obj_id|
---------------------------------
|AAA | 1100| 0|A |
|BBB | 50| 500|B |
|CCC | 30| 50|C |
I googled everywhere but there is no matching answer.
Try this
SELECT
T1.Obj_Name
,NVL(T2.Amount1,0) AS Amount1
,NVL(T3.Amount2,0) AS Amount2
,NVL(T1.Obj_id ,0) AS Obj_id
FROM Table1 T1
LEFT JOIN Table2 T2 ON T1.Obj_id = T2.Obj_id
LEFT JOIN Table3 T3 ON T1.Obj_id = T3.Obj_id
ORDER BY T1.Obj_Name
SQL FIDDLE DEMO
OUTPUT
Obj_Name Amount1 Amount2 Obj_id
AAA 1000 0 A
BBB 0 500 B
CCC 20 10 C
EDIT
SELECT
T1.Obj_Name AS Obj_Name
,NVL(T2.Amount1,0) AS Amount1
,NVL(T3.Amount2,0) AS Amount2
,T1.Obj_id AS Obj_id
FROM Table1 T1
LEFT JOIN (SELECT Obj_id,SUM(Amount1) AS Amount1 FROM Table2 GROUP BY Obj_id) T2 ON T1.Obj_id = T2.Obj_id
LEFT JOIN (SELECT Obj_id,SUM(Amount2) AS Amount2 FROM Table3 GROUP BY Obj_id) T3 ON T1.Obj_id = T3.Obj_id
ORDER BY T1.Obj_Name;
SQL FIDDLE DEMO UPDATED
OUTPUT
OBJ_NAME AMOUNT1 AMOUNT2 OBJ_ID
AAA 1100 0 A
BBB 50 500 B
CCC 30 50 C
Related
I have 3 tables to join to get the output in the below format.
My table 1 is like:
--------------------------------------------------------
T1_ID1 | T1_ID2 | NAME
--------------------------------------------------------
123 | T11231 | TestName11
123 | T11232 | TestName12
234 | T1234 | TestName13
345 | T1345 | TestName14
--------------------------------------------------------
My table 2 is like:
--------------------------------------------------------
T2_ID1 | T2_ID2 | NAME
--------------------------------------------------------
T11231 | T21231 | TestName21
T11232 | T21232 | TestName21
T1234 | T2234 | TestName22
--------------------------------------------------------
My table 3 is like:
----------------------------------------------------------
T3_ID1 | TYPE | REF
----------------------------------------------------------
T21231 | 1 | 123456
T21232 | 2 | 1234#test.com
T2234 | 2 | 123#test.com
----------------------------------------------------------
My desired output is:
------------------------------------------------------
T1_ID1 | PHONE | EMAIL
------------------------------------------------------
123 | 123456 | 1234#test.com
234 | | 123#test.com
345 | |
------------------------------------------------------
Requirements:
T1_ID2 of table 1 left joins with T2_ID1 of table 2.
T2_ID2 of table 2 left joins with T3_ID1 of table 3.
TYPE of table 3 specifies 1 if the value is phone and specified 2 if value is email.
My output should contain T1_ID1 of table 1 and its corresponding value of REF in table 3, with the REF in the same row.
That is, in this case, T1_ID1 with value 123 has both phone and email. So, it is displayed in the same row in output.
If phone alone is available for corresponding value of T1_ID1, then phone should be populated in the result with email as null and vice versa.
If neither phone nor email is available, nothing should be populated.
I had tried the below SQLs but in vain. Where am I missing? Please extend your help.
Option 1:
SELECT DISTINCT
t1.t1_id1,
t3.ref
|| (
CASE
WHEN t3.type = 1 THEN
1
ELSE
0
END
) phone,
t3.ref
|| (
CASE
WHEN t3.type = 2 THEN
1
ELSE
0
END
) email
FROM
table1 t1
LEFT JOIN table2 t2 ON t1.t1_id2 = t2.t2_id1
LEFT JOIN table3 t3 ON t2.t2_id2 = t3.t3_id1;
Option 2:
SELECT DISTINCT
t1.t1_id1,
t3.ref,
(
CASE
WHEN t3.type = 1 THEN
1
ELSE
0
END
) phone,
t3.ref,
(
CASE
WHEN t3.type = 2 THEN
1
ELSE
0
END
) email
FROM
table1 t1
LEFT JOIN table2 t2 ON t1.t1_id2 = t2.t2_id1
LEFT JOIN table3 t3 ON t2.t2_id2 = t3.t3_id1;
Option 3:
SELECT DISTINCT
t1.t1_id1,
(
CASE
WHEN t3.type = 1 THEN
1
ELSE
0
END
) phone,
(
CASE
WHEN t3.type = 2 THEN
1
ELSE
0
END
) email
FROM
table1 t1
LEFT JOIN table2 t2 ON t1.t1_id2 = t2.t2_id1
LEFT JOIN table3 t3 ON t2.t2_id2 = t3.t3_id1;
select t1_id1, max(t3.ref )phone, max(t33.ref) email
from table1
left outer join
table2 on t1_id2=t2_id1
left outer join table3 t3 on t3.t3_id1=t2_id2 and t3.type=1
left outer join table3 t33 on t33.t3_id1=t2_id2 and t33.type=2
group by t1_id1
if you have maximum one phone and one email in table3 for each t2_id2 entry in table2.
I'm having a hard time trying to add a WHERE clause that filters null values from a column ONLY when there are other rows that return data for that same column.
If all rows have null values for that column, keep them all.
If any row has data for that column, remove the rows with null values and just keep the rows with data.
I'm working on an Oracle database.
In my SELECT statement, I'm currently using a LEFT JOIN to pull data from table B even if the values for column B.info are null.
The actual query goes as follows:
SELECT A.id as A_ID, A.name as A_NAME,
B.id as B_ID, B.name as B_NAME, B.info as B_INFO
FROM A
LEFT JOIN B ON B.id = A.id_B
WHERE A.filename = 'file1.txt'
I have 2 possible scenarios in the bussiness I'm working on:
For a given "filename", the query returns some rows with the B.info column with null values and some others with the B.info column filled with data. I want the query to return only the rows with B.info != null.
Scenario 1 - Actual output:
+-------+--------+------+--------+-----------+
| A_ID | A_NAME | B_ID | B_NAME | B_INFO |
+-------+--------+------+--------+-----------+
| 1 | John | null | null | null |
+-------+--------+------+--------+-----------+
| 2 | John | 3 | Julia | Age is 35 |
+-------+--------+------+--------+-----------+
| 3 | John | null | null | null |
+-------+--------+------+--------+-----------+
Scenario 1 - Desired output:
+-------+--------+------+--------+-----------+
| A_ID | A_NAME | B_ID | B_NAME | B_INFO |
+-------+--------+------+--------+-----------+
| 2 | John | 3 | Julia | Age is 35 |
+-------+--------+------+--------+-----------+
For a given "filename", the query returns all of the rows with the B.info column with null values.
I want the query to keep returning those rows.
Scenario 2 - Actual output = desired output:
+-------+--------+------+--------+--------+
| A_ID | A_NAME | B_ID | B_NAME | B_INFO |
+-------+--------+------+--------+--------+
| 1 | Mark | null | null | null |
+-------+--------+------+--------+--------+
| 2 | Mark | null | null | null |
+-------+--------+------+--------+--------+
| 3 | Mark | null | null | null |
+-------+--------+------+--------+--------+
I tried adding the condition B.info is not null in the where clause but, although it returns the desired output for the scenario 1, the output for the scenario 2 returns no rows:
SELECT A.id as A_ID, A.name as A_NAME,
B.id as B_ID, B.name as B_NAME, B.info as B_INFO
FROM A
LEFT JOIN B ON B.id = A.id_B
WHERE A.filename = 'file1.txt'
AND B.info is not null
Scenario 1 - Output
+-------+--------+------+--------+-----------+
| A_ID | A_NAME | B_ID | B_NAME | B_INFO |
+-------+--------+------+--------+-----------+
| 2 | John | 3 | Julia | Age is 35 |
+-------+--------+------+--------+-----------+
Scenario 2 - Output
+-------+--------+------+--------+--------+
| A_ID | A_NAME | B_ID | B_NAME | B_INFO |
+-------+--------+------+--------+--------+
+-------+--------+------+--------+--------+
I also tried adding a CASE in the WHERE clause but it throws an error (ORA-00934: group function is not allowed here)
SELECT A.id as A_ID, A.name as A_NAME,
B.id as B_ID, B.name as B_NAME, B.info as B_INFO
FROM A
LEFT JOIN B ON B.id = A.id_B
WHERE A.filename = 'file1.txt'
AND B.info = CASE WHEN count(B.info) > 0 THEN null
ELSE B.info
END
I'm sorry I can't use the real example for confidentiality issues. I hope my example is clear enough. I would appreciate any help!
Count all rows and nullable rows. Use analytic count, because you need details. Then show only rows containing data or null rows if both counts are equal:
select id, a_name, b_name, info
from (
select a.id, b.id b_id, a.name a_name, b.name b_name, b.info,
count(case when b.id is null then 1 end) over (partition by a.filename) c1,
count(1) over (partition by a.filename) c2
from a left join b on a.id = b.id )
where b_id is not null or c1 = c2
demo
You can consider this problem a ranking problem: You want to show the best rows only, with non-null rows being considered "better" than null rows.
Ranking can be achieved with an appropriate ORDER BY clause. As of Oracle 12c:
select
a.id as a_id, a.name as a_name,
b.id as b_id, b.name as b_name, b.info as b_info
from a
left join b on b.id = a.id_b
where a.filename = 'file1.txt'
order by case when b.id is null then 2 else 1 end
fetch first rows with ties;
In older versions:
select a_id, a_name, b_id, b_name, b_info
from
(
select
a.id as a_id, a.name as a_name,
b.id as b_id, b.name as b_name, b.info as b_info,
rank() over (order by case when b.id is null then 2 else 1 end) as rnk
from a
left join b on b.id = a.id_b
where a.filename = 'file1.txt'
)
where rnk = 1;
I have a table that has three columns ( primary key) and I need a delete sentece that allows me to remove the elements I don't need , using a join with the this table and other table, I've tried two delete sentences but they are not working as expected:
First One: This one gets the values I dont need and they are removed from table A, but the issue here is it deletes the values from Table B and C too and those rows can't be removed
DELETE
FROM
(SELECT A.*
FROM TABLE_A A
JOIN TABLE_B B
ON A.CODE =B.CODE
JOIN TABLE_C C
ON B.PRODUCT =C.PRODUCT
WHERE B.VALUE >10000
AND C.RANGE NOT IN (4006, 4005, 4004, 4003, 4002, 4001)
);
**Second One:**The problem with this one is that it removes all the rows from table A, but if I test the query ( select) it returns 5 rows, the ones that should be removed.
DELETE
FROM A WHERE EXIST
(SELECT A.*
FROM TABLE_A A
JOIN TABLE_B B
ON A.CODE =B.CODE
JOIN TABLE_C C
ON B.PRODUCT =C.PRODUCT
WHERE B.VALUE >10000
AND C.RANGE NOT IN (4006, 4005, 4004, 4003, 4002, 4001)
);
So has anyone any idea of what I could be doing wrong?
The first one will delete matched rows across the joins, the second one will delete all rows when there EXISTS any one matched row as you are not correlating the deleted rows to the sub-query.
You can perform this correlation using the ROWID pseudo-column:
SQL Fiddle
Oracle 11g R2 Schema Setup:
CREATE TABLE table_a ( id, code ) AS
SELECT 1, 1 FROM DUAL UNION ALL
SELECT 2, 2 FROM DUAL UNION ALL
SELECT 3, 3 FROM DUAL;
CREATE TABLE table_b ( id, code, product, value ) AS
SELECT 1, 1, 1, 10001 FROM DUAL UNION ALL
SELECT 2, 2, 2, 10001 FROM DUAL UNION ALL
SELECT 3, 3, 1, 9999 FROM DUAL;
CREATE TABLE table_c ( id, product, range ) AS
SELECT 1, 1, 1001 FROM DUAL UNION ALL
SELECT 2, 2, 4001 FROM DUAL;
DELETE
FROM table_A
WHERE ROWID IN (
SELECT A.ROWID
FROM TABLE_A A
JOIN TABLE_B B
ON A.CODE = B.CODE
JOIN TABLE_C C
ON B.PRODUCT = C.PRODUCT
WHERE B.VALUE >10000
AND C.RANGE NOT IN (4006, 4005, 4004, 4003, 4002, 4001)
);
Query 1:
SELECT * FROM table_a
Results:
| ID | CODE |
|----|------|
| 2 | 2 |
| 3 | 3 |
Query 2:
SELECT * FROM table_b
Results:
| ID | CODE | PRODUCT | VALUE |
|----|------|---------|-------|
| 1 | 1 | 1 | 10001 |
| 2 | 2 | 2 | 10001 |
| 3 | 3 | 1 | 9999 |
Query 3:
SELECT * FROM table_c
Results:
| ID | PRODUCT | RANGE |
|----|---------|-------|
| 1 | 1 | 1001 |
| 2 | 2 | 4001 |
I'm trying to join two tables with LEFT JOIN in Oracle. I need to include only the first record from the "right" joined table.
See the example below:
Table A
code | emp_no
101 | 11111
102 | 22222
103 | 33333
104 | 44444
105 | 55555
Table B
code | city | county
101 | City1 | Country1
101 | City2 | Country1
101 | City3 | Country1
102 | City4 | Country2
103 | City5 | Country3
Expected Output:
code | emp_no | city | county
101 | 11111 | City1 | Country1
102 | 22222 | City4 | Country2
103 | 33333 | City5 | Country3
104 | 44444 | NULL | NULL
105 | 55555 | NULL | NULL
I need to pick the first matched record from table B and ignore all other rows.
The query above suppose to works:
SELECT *
FROM TABLE_A a
LEFT JOIN TABLE_B b ON b.CODE = a.CODE
AND b.CODE =
(
SELECT CODE
FROM TABLE_B
WHERE ROWNUM = 1
)
But I'm getting the error:
ORA-01799: a column may not be outer-joined to a subquery
How can I do this?
Thanks
On Oracle 12c you can use OUTER APPLY and FETCH FIRST clauses:
SELECT *
FROM tableA a
OUTER APPLY (
SELECT * FROM tableB b
WHERE a.code = b.code
ORDER BY city, county
FETCH FIRST ROW ONLY
)
CODE EMP_NO CODE CITY COUNTY
---------- ---------- ---------- ----- --------
101 11111 101 City1 Country1
102 22222 102 City4 Country2
103 33333 103 City5 Country3
104 44444
105 55555
You can use the min() aggrenate function with the keep (dense_rank first ...) syntax to get the 'first' matching data from the outer-joined table:
select a.code, a.emp_no,
min(b.city) keep (dense_rank first order by city, county) as city,
min(b.county) keep (dense_rank first order by city, county) as county
from table_a a
left join table_b b on b.code = a.code
group by a.code, a.emp_no
order by a.code, a.emp_no;
CODE EMP_NO CITY COUNTY
---------- ---------- ----- --------
101 11111 City1 Country1
102 22222 City4 Country2
103 33333 City5 Country3
104 44444
105 55555
You have to define what 'first' means though - I've gone with order by city, county inside the keep clause, but you may have another column you haven't shown that should dictate the order.
(You can order by null to make it somewhat arbitrary, but that's not generally a good idea, not least as running the same query later could give different results for the same data.)
using row_number() function and get records where row_number() = 1
SELECT select a.code,
a.emp_no,
b.city,
b.county
FROM table_a a
left join (SELECT code,
city,
county,
row_number()
over (
PARTITION BY code
ORDER BY city, county ) rn
FROM table_b) b
ON b.code = a.code
WHERE rn = 1 OR rn IS NULL;
Note: It is still unclear from the question what actually this means.
first record from the "right" joined table
Problem:
Given two tables: TableA, TableB, where TableA has a one-to-many relationship with TableB, I want to retrieve all records in TableB for where the search criteria matches a certain column in TableB and return NULL for the unique TableA records for the same attribute.
Table Structures:
Table A
ID(Primary Key) | Name | City
1 | ABX | San Francisco
2 | ASDF | Oakland
3 | FDFD | New York
4 | GFGF | Austin
5 | GFFFF | San Francisco
Table B
ATTR_ID |Attr_Type | Attr_Name | Attr_Value
1 | TableA | Attr_1 | Attr_Value_1
2 | TableD | Attr_1 | Attr_Value_2
1 | TableA | Attr_2 | Attr_Value_3
3 | TableA | Attr_4 | Attr_Value_4
9 | TableC | Attr_2 | Attr_Value_5
Table B holds attribtue names and values and is a common table used across multiple tables. Each table is identified by Attr_Type and ATTR_ID (which maps to the IDs of different tables).
For instance, the record in Table A with ID 1 has two attributes in Table B with Attr_Names: Attr_1 and Attr_2 and so on.
Expected Output
ID | Name | City | TableB.Attr_Value
1 | ABX | San Francisco | Attr_Value_1
2 | ASDF | Oakland | Attr_Value_2
3 | FDFD | New York | NULL
4 | GFGF | Austin | NULL
5 | GFFFF | San Francisco | NULL
Search Criteria:
Get rows from Table B for each record in Table A with ATTR_NAME Attr_1. If a particular TableA record doesn't have Attr_1, return null.
My Query
select id, name, city,
b.attr_value from table_A
join table_B b on
table_A.id =b.attr_id and b.attr_name='Attr_1'
This is a strange data structure. You need a left outer join with the conditions in the on clause:
select a.id, a.name, a.city, b.attr_value
from table_A a left join
table_B b
on a.id = b.attr_id and b.attr_name = 'Attr_1' and b.attr_type = 'TableA';
I added the attr_type condition, because that seems logic with this data structure.
I dont have an sql server to test the command, but what you want is an inner/outer join query. You could do something like this
select id, name, city,
b.attr_value from table_A
join table_B b on
table_A.id *= b.attr_id and b.attr_name *= 'Attr_1'
Something like this should do the trick for you