I have a table that has three columns ( primary key) and I need a delete sentece that allows me to remove the elements I don't need , using a join with the this table and other table, I've tried two delete sentences but they are not working as expected:
First One: This one gets the values I dont need and they are removed from table A, but the issue here is it deletes the values from Table B and C too and those rows can't be removed
DELETE
FROM
(SELECT A.*
FROM TABLE_A A
JOIN TABLE_B B
ON A.CODE =B.CODE
JOIN TABLE_C C
ON B.PRODUCT =C.PRODUCT
WHERE B.VALUE >10000
AND C.RANGE NOT IN (4006, 4005, 4004, 4003, 4002, 4001)
);
**Second One:**The problem with this one is that it removes all the rows from table A, but if I test the query ( select) it returns 5 rows, the ones that should be removed.
DELETE
FROM A WHERE EXIST
(SELECT A.*
FROM TABLE_A A
JOIN TABLE_B B
ON A.CODE =B.CODE
JOIN TABLE_C C
ON B.PRODUCT =C.PRODUCT
WHERE B.VALUE >10000
AND C.RANGE NOT IN (4006, 4005, 4004, 4003, 4002, 4001)
);
So has anyone any idea of what I could be doing wrong?
The first one will delete matched rows across the joins, the second one will delete all rows when there EXISTS any one matched row as you are not correlating the deleted rows to the sub-query.
You can perform this correlation using the ROWID pseudo-column:
SQL Fiddle
Oracle 11g R2 Schema Setup:
CREATE TABLE table_a ( id, code ) AS
SELECT 1, 1 FROM DUAL UNION ALL
SELECT 2, 2 FROM DUAL UNION ALL
SELECT 3, 3 FROM DUAL;
CREATE TABLE table_b ( id, code, product, value ) AS
SELECT 1, 1, 1, 10001 FROM DUAL UNION ALL
SELECT 2, 2, 2, 10001 FROM DUAL UNION ALL
SELECT 3, 3, 1, 9999 FROM DUAL;
CREATE TABLE table_c ( id, product, range ) AS
SELECT 1, 1, 1001 FROM DUAL UNION ALL
SELECT 2, 2, 4001 FROM DUAL;
DELETE
FROM table_A
WHERE ROWID IN (
SELECT A.ROWID
FROM TABLE_A A
JOIN TABLE_B B
ON A.CODE = B.CODE
JOIN TABLE_C C
ON B.PRODUCT = C.PRODUCT
WHERE B.VALUE >10000
AND C.RANGE NOT IN (4006, 4005, 4004, 4003, 4002, 4001)
);
Query 1:
SELECT * FROM table_a
Results:
| ID | CODE |
|----|------|
| 2 | 2 |
| 3 | 3 |
Query 2:
SELECT * FROM table_b
Results:
| ID | CODE | PRODUCT | VALUE |
|----|------|---------|-------|
| 1 | 1 | 1 | 10001 |
| 2 | 2 | 2 | 10001 |
| 3 | 3 | 1 | 9999 |
Query 3:
SELECT * FROM table_c
Results:
| ID | PRODUCT | RANGE |
|----|---------|-------|
| 1 | 1 | 1001 |
| 2 | 2 | 4001 |
Related
I have a query in which I am producing results with rows that contain 0 values. I would like to exclude any rows in which columns B or C = 0. To exclude such rows, I have added the T2.A <> 0 and T2.A != 0. When I do this, the 0 values are replaced with NULLs. Thus I also added T2.A IS NOT NULL.
My results still produce the columns that I do not need which show (null) and would like to exclude these.
SELECT
(SELECT
SUM(T2.A) as prem
FROM Table_2 T2, Table_2 T1
WHERE T2.ENT_REF = T1.ENT_REF
AND UPPER(T2.PER) = 'HURR'
AND UPPER(T2.ENT_TYPE) = 'POL'
AND T2.Cov NOT IN ('OUTPROP','COV')
AND T2.A <> 0
AND T2.A IS NOT NULL
) as B,
(SELECT
SUM(T2.A) as prem
FROM Table_2 T2, Table_2 T1
WHERE T2.ENT_REFE = T1.ENT_REF
AND UPPER(T2.PER) IN ('I', 'II', 'II')
AND UPPER(T2.ENT_TYPE) = 'POL'
AND T2.Cov NOT IN ('OUTPROP','COV')
AND T2.A <> 0
AND T2.A IS NOT NULL
) as C
Ideally the result will go from:
+----+--------+--------+
| ID | B | C |
+----+--------+--------+
| 1 | 24 | 123 |
| 2 | 65 | 78 |
| 3 | 43 | 89 |
| 3 | 0 | 0 |
| 4 | 95 | 86 |
| 5 | 43 | 65 |
| 5 | (null) | (null) |
+----+--------+--------+
To something similar to the following:
+----+-----+-----+
| ID | B | C |
+----+-----+-----+
| 1 | 24 | 123 |
| 2 | 65 | 78 |
| 3 | 43 | 89 |
| 4 | 95 | 86 |
| 5 | 43 | 65 |
+----+-----+-----+
I have also attempted distinct values, but I have other columns such as dates which are different per row. Although I need to include dates, they are not as important to me as only getting B and C columns with only values > 0. I have also tried using a GROUP BY ID statement, but I get an error that states 'ORA-00979: not a GROUP BY expression'
You have written all the conditions in the SELECT clause.
You are facing the issue because the WHERE clause decides the number of rows to be fetched and SELECT clause decides values to be returned.
In your case, something like the following is happening:
Simple Example:
-- MANUAL DATA
WITH DATAA AS (
SELECT
1 KEY,
'VALS' VALUE,
1 SEQNUM
FROM
DUAL
UNION ALL
SELECT
2,
'IDEAL OPTION',
2
FROM
DUAL
UNION ALL
SELECT
10,
'EXCLUDE',
3
FROM
DUAL
)
-- QUERY OF YOUR TYPE
SELECT
(
SELECT
KEY
FROM
DATAA I
WHERE
I.KEY = 1
AND O.KEY = I.KEY
) AS KEY, -- DECIDE VALUES TO BE SHOWN
(
SELECT
KEY
FROM
DATAA I
WHERE
I.SEQNUM = 1
AND O.SEQNUM = I.SEQNUM
) AS SEQNUM -- DECIDE VALUES TO BE SHOWN
FROM
DATAA O
WHERE
O.KEY <= 2; -- DECIDES THE NUMBER OF RECORDS
OUTPUT:
If you don't want to change much logic in your query then just use additional WHERE clause outside your final query like:
SELECT <bla bla bla>
FROM <YOUR FINAL QUERY>
WHERE B IS NOT NULL AND C IS NOT NULL
Cheers!!
I guess you were on the right track, trying to group values.
In order to do that, columns (that are supposed to be distinct) will be left alone (such as ID in the following example), while the rest should be aggregated (using min, max or any other you find appropriate).
For example, as you said that there's some date column you don't care about - I mean, which one of them you'll select - then select the first one (i.e. min(date_column)). Similarly, you'd do with the rest. The group by clause should contain all non-aggregated columns (id in this example).
select id,
sum(a) a,
sum(b) b,
min(date_column) date_column
from your_current_query
group by id
If I understand your query right, it would be much easier and more performant, to avoid the lookups in the Select clause. Try to bring it all in one Query:
SELECT * FROM (
SELECT T2.ENT_REF AS ID,
SUM(CASE WHEN UPPER(T2.PER) = 'HURR' THEN T2.A END) AS B,
SUM(CASE WHEN UPPER(T2.PER) IN ('I', 'II', 'II') THEN T2.A END) as C
FROM Table_2 T2
WHERE UPPER(T2.ENT_TYPE) = 'POL'
AND T2.Cov NOT IN ('OUTPROP','COV')
GROUP BY T2.ENT_REF
)
WHERE B IS NOT NULL
OR C IS NOT NULL
I have an 'ITEMS' table like below:
ITEM_NO ITEM_NAME
1 Book
2 Pen
3 Sticky Notes
4 Ink
5 Corrector
6 Ruler
In another 'EMP_ITEMS' table I have the below:
EMPLOYEE ITEMS_LIST
John 1,2
Mikel 5
Sophia 2,3,6
William 3,4
Daniel null
Michael 6
The output has to be like this:
EMPLOYEE ITEMS_LIST ITEM_NAME
John 1,2 Book,Pen
Mikel 5 Corrector
Sophia 2,3,6 Pen,Sticky Notes,Ruler
William 3,4 Sticky Notes,Ink
Daniel null null
Michael 6 Ruler
I used the below query:
SELECT e.EMPLOYEE,e.ITEMS_LIST, LISTAGG(i.ITEM_NAME, ',') WITHIN GROUP (ORDER BY i.ITEM_NAME) ITEM_DESC
FROM EMP_ITEMS e
INNER JOIN ITEMS i ON i.ITEM_NO = e.ITEMS_LIST
GROUP BY e.EMPLOYEE,e.ITEMS_LIST;
But there is an error:
ORA-01722: invalid number
But there is an error: ORA-01722: invalid number
That is because your ITEMS_LIST is a string composed of numeric and comma characters and is not actually a list of numbers and you are trying to compare a single item number to a list of items.
Instead treat it as a string a look for sub-string matches. To do this you will need to surround the strings in the delimiter character and compare to see if one is the substring of the other:
SQL Fiddle
Oracle 11g R2 Schema Setup:
CREATE TABLE Items ( ITEM_NO, ITEM_NAME ) As
SELECT 1, 'Book' FROM DUAL UNION ALL
SELECT 2, 'Pen' FROM DUAL UNION ALL
SELECT 3, 'Sticky Notes' FROM DUAL UNION ALL
SELECT 4, 'Ink' FROM DUAL UNION ALL
SELECT 5, 'Corrector' FROM DUAL UNION ALL
SELECT 6, 'Ruler' FROM DUAL;
CREATE TABLE emp_items ( EMPLOYEE, ITEMS_LIST ) AS
SELECT 'John', '1,2' FROM DUAL UNION ALL
SELECT 'Mikel', '5' FROM DUAL UNION ALL
SELECT 'Sophia', '3,2,6' FROM DUAL UNION ALL
SELECT 'William', '3,4' FROM DUAL UNION ALL
SELECT 'Daniel', null FROM DUAL UNION ALL
SELECT 'Michael', '6' FROM DUAL;
Query 1:
SELECT e.employee,
e.items_list,
LISTAGG( i.item_name, ',' )
WITHIN GROUP (
ORDER BY INSTR( ','||e.items_list||',', ','||i.item_no||',' )
) AS item_names
FROM emp_items e
LEFT OUTER JOIN
items i
ON ( ','||e.items_list||',' LIKE '%,'||i.item_no||',%' )
GROUP BY e.employee, e.items_list
Results:
| EMPLOYEE | ITEMS_LIST | ITEM_NAMES |
|----------|------------|------------------------|
| John | 1,2 | Book,Pen |
| Mikel | 5 | Corrector |
| Daniel | (null) | (null) |
| Sophia | 3,2,6 | Sticky Notes,Pen,Ruler |
| Michael | 6 | Ruler |
| William | 3,4 | Sticky Notes,Ink |
I have two tables. TABLE_A and TABLE_B.
Both tables maintain columns to save CREATION_USER. But this column has different name in respective tables.
My motive is to get a count of records each user has created in both tables.
That is, combining result of these two queries with few conditions. The user name should not get repeated and for user names who have created records in both tables, the count should be their sum.
SELECT A.CREATION_USER_A AS "USER",
COUNT(*)
FROM TABLE_A A
GROUP BY A.CREATION_USER_A;
SELECT B.CREATION_USER_B AS "USER",
COUNT(*)
FROM TABLE_B B
GROUP BY B.CREATION_USER_B;
For e.g.,
USER_A has created 2 records in TABLE_A,
USER_B has created 3 records in TABLE_B and
USER_C has created 4 records in TABLE_A and 3 records in TABLE_B.
So the output should look like this:
| USER | COUNT |
| USER_A | 2 |
| USER_B | 3 |
| USER_C | 7 |
I have written a query which does this but it performs really bad.
SELECT A.CREATION_USER_A AS "USER",
(COUNT(A.CREATION_USER_A)+(SELECT COUNT(CREATION_USER_B) FROM TABLE_B WHERE CREATION_USER_B = A.CREATION_USER_A)) AS "COUNT"
FROM TABLE_A A
GROUP BY A.CREATION_USER_A
UNION
SELECT B.CREATION_USER_B,
COUNT(B.CREATION_USER_B)
FROM TABLE_B B
WHERE B.CREATION_USER_B NOT IN (SELECT CREATION_USER_A FROM TABLE_A)
GROUP BY B.CREATION_USER_B;
Please suggest a way to get this done.
You can simply build a set given by the union (keeping duplicates) of all the records in your tables, and then count the records grouping by creation user:
Bulding some sample data:
create table table_a(id, creation_user_a) as (
select 1, 'USER_A' from dual union all
select 1, 'USER_A' from dual union all
select 1, 'USER_C' from dual union all
select 1, 'USER_C' from dual union all
select 1, 'USER_C' from dual union all
select 1, 'USER_C' from dual
);
create table table_b(id, creation_user_b) as (
select 1, 'USER_B' from dual union all
select 1, 'USER_B' from dual union all
select 1, 'USER_B' from dual union all
select 1, 'USER_C' from dual union all
select 1, 'USER_C' from dual union all
select 1, 'USER_C' from dual
)
The query:
select count(1), creation_user
from ( /* the union of all the records from table_a and table_b */
select creation_user_a as creation_user from table_a
union all /* UNION ALL keeps duplicates */
select creation_user_B from table_b
)
group by creation_user
order by creation_user
The result:
2 USER_A
3 USER_B
7 USER_C
The explain plan:
---------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
---------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 12 | 96 | 8 (25)| 00:00:01 |
| 1 | SORT ORDER BY | | 12 | 96 | 8 (25)| 00:00:01 |
| 2 | HASH GROUP BY | | 12 | 96 | 8 (25)| 00:00:01 |
| 3 | VIEW | | 12 | 96 | 6 (0)| 00:00:01 |
| 4 | UNION-ALL | | | | | |
| 5 | TABLE ACCESS FULL| TABLE_A | 6 | 48 | 3 (0)| 00:00:01 |
| 6 | TABLE ACCESS FULL| TABLE_B | 6 | 48 | 3 (0)| 00:00:01 |
---------------------------------------------------------------------------------
An alternative (but more complicated, and possibly slower - you'd need to test both to check) solution to Aleksej's answer is to use a full outer join to join both grouped by queries, like so:
WITH table_a AS (SELECT 'USER_A' creation_user_a, 10 val FROM dual UNION ALL
SELECT 'USER_A' creation_user_a, 20 val FROM dual UNION ALL
SELECT 'USER_C' creation_user_a, 30 val FROM dual UNION ALL
SELECT 'USER_C' creation_user_a, 40 val FROM dual UNION ALL
SELECT 'USER_C' creation_user_a, 50 val FROM dual UNION ALL
SELECT 'USER_C' creation_user_a, 60 val FROM dual),
table_b AS (SELECT 'USER_B' creation_user_b, 10 val FROM dual UNION ALL
SELECT 'USER_B' creation_user_b, 20 val FROM dual UNION ALL
SELECT 'USER_B' creation_user_b, 30 val FROM dual UNION ALL
SELECT 'USER_C' creation_user_b, 40 val FROM dual UNION ALL
SELECT 'USER_C' creation_user_b, 50 val FROM dual UNION ALL
SELECT 'USER_C' creation_user_b, 60 val FROM dual)
-- end of mimicking your tables with data in them. See the SQL below:
SELECT COALESCE(a.creation_user_a, b.creation_user_b) "USER",
nvl(a.cnt_a, 0) + nvl(b.cnt_b, 0) total_records
FROM (SELECT creation_user_a,
COUNT(*) cnt_a
FROM table_a
GROUP BY creation_user_a) a
FULL OUTER JOIN (SELECT creation_user_b,
COUNT(*) cnt_b
FROM table_b
GROUP BY creation_user_b) b ON a.creation_user_a = b.creation_user_b
ORDER BY "USER";
USER TOTAL_RECORDS
------ -------------
USER_A 2
USER_B 3
USER_C 7
Thank you for helping me guys. I have found a simpler and more efficient solution. It works.
SELECT CREATION_USER, SUM(TOTAL_COUNT) TOTAL_COUNT FROM
(SELECT /*+ PARALLEL */ A.CREATION_USER_A CREATION_USER,
COUNT(A.CREATION_USER_A) TOTAL_COUNT
FROM TABLE_A A
GROUP BY A.CREATION_USER_A
UNION
SELECT /*+ PARALLEL */ B.CREATION_USER_B CREATION_USER,
COUNT(B.CREATION_USER_B) TOTAL_COUNT
FROM TABLE_B B
GROUP BY B.CREATION_USER_B)
GROUP BY CREATION_USER;
Hello I've got a problem with lead and retrieving the next value from the next group.
I've got this table:
TableA
-----------------
ID | value
-----------------
1 | 2.5
1 | 1
1 | 4.5
2 | 7
2 | 2
3 | 3
4 | 1
4 | 7
Expected result:
------------------------------
ID | value | lead_id
------------------------------
1 | 2.5 | 2
1 | 1 | 2
1 | 4.5 | 2
2 | 7 | 3
2 | 2 | 3
3 | 3 | 4
4 | 1 | NULL
4 | 7 | NULL
My SQL:
select ID, value, lead(id) OVER (order by id) lead_id from TableA
Is it possible to get that result ?
You can do this by adding in a windowing clause into the first_value analytic function:
with tablea as (select 1 id, 2.5 value from dual union all
select 1 id, 1 value from dual union all
select 1 id, 4.5 value from dual union all
select 2 id, 7 value from dual union all
select 2 id, 2 value from dual union all
select 3 id, 3 value from dual union all
select 4 id, 1 value from dual union all
select 4 id, 7 value from dual)
select id,
value,
first_value(id) over (order by id
range between 1 following and unbounded following) lead_id
from tablea;
ID VALUE LEAD_ID
---------- ---------- ----------
1 2.5 2
1 1 2
1 4.5 2
2 7 3
2 2 3
3 3 4
4 1
I think this gives the right output:
WITH g AS
(SELECT ID, lead(ID) OVER (ORDER BY ID) lead_id
FROM (SELECT DISTINCT ID FROM TableA) )
SELECT ID, VALUE, lead_id
FROM TableA
JOIN g USING (ID)
ORDER BY 1;
SELECT tablea.*, b.nextid FROM tablea
INNER JOIN (SELECT id, LEAD (id) OVER (ORDER BY id) nextid
FROM ( SELECT DISTINCT id
FROM tablea
ORDER BY id)) b
ON tablea.id = b.id
This should work.
Can I do like this in oracle,.? I have some data like this:
No | Data |
===========
1 | A |
1 | B |
1 | C |
1 | D |
Is there any query that can produce a result like this,.?
No | Data |
=================
1 | A, B, C, D |
Many thanks :D
Maybe this page shows what you are looking for.
SQL Fiddle
Oracle 11g R2 Schema Setup:
CREATE TABLE TEST ( ID, DATA ) AS
SELECT 1, 'A' FROM DUAL
UNION ALL SELECT 1, 'B' FROM DUAL
UNION ALL SELECT 1, 'C' FROM DUAL
UNION ALL SELECT 1, 'D' FROM DUAL
UNION ALL SELECT 2, 'E' FROM DUAL
UNION ALL SELECT 2, 'F' FROM DUAL;
Query 1:
SELECT ID,
LISTAGG( DATA, ',' ) WITHIN GROUP ( ORDER BY DATA ) AS AGGREGATED_DATA
FROM TEST
GROUP BY ID
Results:
| ID | AGGREGATED_DATA |
|----|-----------------|
| 1 | A,B,C,D |
| 2 | E,F |
In Oracle we can use wm_concat function. Here is the query for example above:
SELECT no, wm_concat(data) from table group by no
reference: wm_concat
select
no,
rtrim (xmlagg (xmlelement (d, data|| ',')).extract ('//text()'), ',') data
from
table_name
group by
no
;