Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 8 years ago.
Improve this question
I'm trying to make a gsub that when I make an input like this:
'09/02 10:00 hs any string'
Will give me back something like:
'09/02 10:00'
So my gsub should take out all the strings that are non-numbers but I need ':' and '/' to stay
Help please.
Takes out all the strings that are non-numbers but I need ':' and '/' to stay
"09/02 10:00 hs any string".gsub(/[^0-9\/:]/, '')
# "09/0210:00"
Try this:
result = '09/02 10:00 hs any string'.gsub(/(?<=^\d{2}\/\d{2} \d{2}:\d{2}).*/, '')
the idea is to not capture the date time putting it in a lookbehind.
Related
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 6 years ago.
Improve this question
a= <<EOF
Password
:
7UV1ceFQ (You will be asked to change this after logging in for the first time)
EOF
I need to extract the value "7UV1ceFQ" using regular expression, I have tried using '/Password : 7UV1ceFQ/ but it's not working, I think it's because next line character is included, Can anyone please suggest me to exact this value?
▶ a[/^\S+(?=\s\(You will be)/]
#⇒ "7UV1ceFQ"
The regular expression above reads as:
starting with a new line start ^
get all non-space symbols greedy \S+
until the positive lookahead (?=\s\(You will be)
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 6 years ago.
Improve this question
I want to extract alpha-beta from:
text = "alpha-beta-1.0.txt"
to get:
output = "alpha-beta"
Can somebody here help me with a regex?
If you have a computer programming problem, and you think, "I'll use a
regex!", now you have two problems.
Here it is without a regex:
strings = [
"alpha-beta-1.0.txt",
"alpha-beta-theta-2.0.txt",
"alpha-3.0.text",
]
strings.each do |string|
output = string.rpartition('-')[0]
puts output
end
--output:--
alpha-beta
alpha-beta-theta
alpha
If you want to extract just before last -, you can use this regex
(^.*)-(?:.*$)
Rubular Demo
For finding all non-overlapping matches, you can use scan as
str = "alpha-beta-1.0.txt"
print str.scan(/(^.*)-(?:.*$)/)[0][0]
Ideone Demo
You can also use lookahead as
.*(?=-)
With the information we have i'd propose:
output = "alpha-beta-1.0.txt".match(/(.*-.*)-.*/)[1]
.* matches a lot though. So perhaps you need a more restrictive match.
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 8 years ago.
Improve this question
Here is a string a content is "hi all I'm new here(seriously)"
How can I return a "hi+all+I'm+new+here" using ruby code?
Why not simply chain the .gsub() commands?
x.gsub(/\(.*?\)/, '').gsub(/\s+/,'+')
Also, you can update your first gsub to delete any whitespace preceding the brackets aswell.
x.gsub(/\s+\(.*?\)/, '')
If you really want to use a single gsub operation, you can pass a hash as the replacement parameter:
x.gsub(/( *\(.*?\)| )/, ' ' => '+', default: '')
# => "hi+all"
What this does is captures either something in brackets (including the leading spaces) or spaces. If the capture is a space - it is replaced by '+', otherwise, it replaces to empty string ''
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 8 years ago.
Improve this question
In Ruby, I would like to create a regular expression that matches the following:
building/liberty-green/6d
(the word building and some number somewhere after it)
Currently, I have /building/ and need to add \d (any digit) to it, but I don't know how.
You need /building\/[\w-]+\/\w+/. For example:
irb(main):001:0> /building\/[\w-]+\/\w+/.match("building/liberty-green/6d")
=> #<MatchData "building/liberty-green/6d">
That expression will match any string that:
Starts with /building/
Then follows with one or more word characters or dashes (eg. foo-bar, foo, bar-1)
Then follows with a /
Finally ends with one or more word characters (eg. foo, 6d, 12345)
Note that \w includes digits.
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 8 years ago.
Improve this question
How can I convert the string russ(ai)(edocn)cup to russiancodecup using Ruby?
By using gsub with a block, you can replace any match of a regular expression by the result of this block.
s = "russ(ai)(edocn)cup"
s.gsub(/\(([^)]*)\)/) {$1.reverse} # => "russiancodecup"
Here the regular expression will match any non-) character between brackets. Then it will send reverse to $1 which is gonna be the content between brackets.
$0 will be the complete match and $n, the nth "submatch". (anybody for the correct word ?)