Need to fetch the password using Regular expression [closed] - ruby

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a= <<EOF
Password
:
7UV1ceFQ (You will be asked to change this after logging in for the first time)
EOF
I need to extract the value "7UV1ceFQ" using regular expression, I have tried using '/Password : 7UV1ceFQ/ but it's not working, I think it's because next line character is included, Can anyone please suggest me to exact this value?

▶ a[/^\S+(?=\s\(You will be)/]
#⇒ "7UV1ceFQ"
The regular expression above reads as:
starting with a new line start ^
get all non-space symbols greedy \S+
until the positive lookahead (?=\s\(You will be)

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sed replace entire string after match [closed]

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Hi I'm trying to sed replace the entire string after a match.
my scenario will be inside my file I have the below values:
"XX|TESTFILE|MATCH" "CHANGEME"
"XX|TESTFILE|MATCH1" "CHANGEME1"
I need to replace the string after the text MATCH" " so my expected output will be
"XX|TESTFILE|MATCH" "THIS IS CHANGED"
"XX|TESTFILE|MATCH1" "CHANGEME1"
Hope it is clear and someone will help.
Thank you!
sed -ri '/MATCH\"/ {s/(^\"XX.* \")(.*)(\"$)/\1THIS IS THE CHANGE\3/}'
Using sed with -r flag for regular expressions, search for entries with MATCH followed by a double quote and then when encountered, split the line into three section. Print the first section followed by "THIS IS THE CHANGE" and then the third section.

Extract substring from string using key pattern and delimiter using Ruby [closed]

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How can I extract substring from a string using key pattern and delimiter. e.g.
mystring = 'toto=1,2,3 mynames=ralf,john,franky myhobbies=tennis,soccer,naps'
I want to extract: ralf,john,franky
The pattern here is: mynames
The delimiter is: =
You can use this regular expression:
mynames=([^\s]+)
And then, look for the first group: $1
Here is a live example in JavaScript (works also in other languages):
var regex = /mynames=([^\s]+)/;
var text = "toto=1,2,3 mynames=ralf,john,franky myhobbies=tennis,soccer,naps"
console.log(regex.exec(text)[1]);
If you are looking for a regex which does only match everything after mynames=, so that you don't need to look for the first group, you can also use a positive lookbehind:
(?<=mynames=)[^\s]+
Here is a live example: https://regex101.com/r/mem6mA/1

Regular expression in ruby 2.1.5 [closed]

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I want to extract alpha-beta from:
text = "alpha-beta-1.0.txt"
to get:
output = "alpha-beta"
Can somebody here help me with a regex?
If you have a computer programming problem, and you think, "I'll use a
regex!", now you have two problems.
Here it is without a regex:
strings = [
"alpha-beta-1.0.txt",
"alpha-beta-theta-2.0.txt",
"alpha-3.0.text",
]
strings.each do |string|
output = string.rpartition('-')[0]
puts output
end
--output:--
alpha-beta
alpha-beta-theta
alpha
If you want to extract just before last -, you can use this regex
(^.*)-(?:.*$)
Rubular Demo
For finding all non-overlapping matches, you can use scan as
str = "alpha-beta-1.0.txt"
print str.scan(/(^.*)-(?:.*$)/)[0][0]
Ideone Demo
You can also use lookahead as
.*(?=-)
With the information we have i'd propose:
output = "alpha-beta-1.0.txt".match(/(.*-.*)-.*/)[1]
.* matches a lot though. So perhaps you need a more restrictive match.

Regex issue with a string and all numbers [closed]

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In Ruby, I would like to create a regular expression that matches the following:
building/liberty-green/6d
(the word building and some number somewhere after it)
Currently, I have /building/ and need to add \d (any digit) to it, but I don't know how.
You need /building\/[\w-]+\/\w+/. For example:
irb(main):001:0> /building\/[\w-]+\/\w+/.match("building/liberty-green/6d")
=> #<MatchData "building/liberty-green/6d">
That expression will match any string that:
Starts with /building/
Then follows with one or more word characters or dashes (eg. foo-bar, foo, bar-1)
Then follows with a /
Finally ends with one or more word characters (eg. foo, 6d, 12345)
Note that \w includes digits.

Convert string using Ruby [closed]

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How can I convert the string russ(ai)(edocn)cup to russiancodecup using Ruby?
By using gsub with a block, you can replace any match of a regular expression by the result of this block.
s = "russ(ai)(edocn)cup"
s.gsub(/\(([^)]*)\)/) {$1.reverse} # => "russiancodecup"
Here the regular expression will match any non-) character between brackets. Then it will send reverse to $1 which is gonna be the content between brackets.
$0 will be the complete match and $n, the nth "submatch". (anybody for the correct word ?)

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