i have a table in which two fields are id, controlflag.It looks like
Id CntrlFlag
121 SSSSSRNNNSSRSSNNR
122 SSSNNRRSSNNRSSSSS
123 RRSSSNNSSSSSSSSSSSSSSS
I have to get output in the following form( the occurences of R)
Id Flag
121 6,12,17
122 6,7,12
123 1,2
I tried oracle query( as i obtained from this forum):
select mtr_id,listagg(str,',') within group (order by lvl) as flags from
( select mtr_id, instr(mtr_ctrl_flags,'R', 1, level) as str, level as lvl
from mer_trans_reject
connect by level <= regexp_count(mtr_ctrl_flags, 'R'))group by mtr_id;
it gives the result but 2nd and 3rd occurrences(not 1st one) are duplicated a no. of times.
it looks like
id Flag
123 6,12,12,12,12,17,17,17,17,17.
Can anybody know what's wrong here?
It could be avoided by select distinct keyword.Is there any other way?
Yes, there is, but this one is a little bit heavier(distinct will cost you less):
with t1(Id1, CntrlFlag) as(
select 121, 'SSSSSRNNNSSRSSNNR' from dual union all
select 122, 'SSSNNRRSSNNRSSSSS' from dual union all
select 123, 'RRSSSNNSSSSSSSSSSSSSSS' from dual
)
select w.id1
, listagg(w.r_pos, ',') within group(order by w.id1) as R_Positions
from (select q.id1
, regexp_instr(q.CntrlFlag,'R', 1, t.rn) as r_pos
from t1 q
cross join (select rownum rn
from(select max (regexp_count(CntrlFlag, 'R')) ml
from t1
)
connect by level <= ml
) t
) w
where w.r_pos > 0
group by w.id1
Result:
ID1 R_POSITIONS
---------- -----------
121 12,17,6
122 12,6,7
123 1,2
Related
Is it possible to keep order from a 'IN' conditional clause?
I found this question on SO but in his example the OP have already a sorted 'IN' clause.
My case is different, 'IN' clause is in random order
Something like this :
SELECT SomeField,OtherField
FROM TestResult
WHERE TestResult.SomeField IN (45,2,445,12,789)
I would like to retrieve results in (45,2,445,12,789) order. I'm using an Oracle database. Maybe there is an attribute in SQL I can use with the conditional clause to specify to keep order of the clause.
There will be no reliable ordering unless you use an ORDER BY clause ..
SELECT SomeField,OtherField
FROM TestResult
WHERE TestResult.SomeField IN (45,2,445,12,789)
order by case TestResult.SomeField
when 45 then 1
when 2 then 2
when 445 then 3
...
end
You could split the query into 5 queries union all'd together though ...
SELECT SomeField,OtherField
FROM TestResult
WHERE TestResult.SomeField = 4
union all
SELECT SomeField,OtherField
FROM TestResult
WHERE TestResult.SomeField = 2
union all
...
I'd trust the former method more, and it would probably perform much better.
Decode function comes handy in this case instead of case expressions:
SELECT SomeField,OtherField
FROM TestResult
WHERE TestResult.SomeField IN (45,2,445,12,789)
ORDER BY DECODE(SomeField, 45,1, 2,2, 445,3, 12,4, 789,5)
Note that value,position pairs (e.g. 445,3) are kept together for readability reasons.
Try this:
SELECT T.SomeField,T.OtherField
FROM TestResult T
JOIN
(
SELECT 1 as Id, 45 as Val FROM dual UNION ALL
SELECT 2, 2 FROM dual UNION ALL
SELECT 3, 445 FROM dual UNION ALL
SELECT 4, 12 FROM dual UNION ALL
SELECT 5, 789 FROM dual
) I
ON T.SomeField = I.Val
ORDER BY I.Id
There is an alternative that uses string functions:
with const as (select ',45,2,445,12,789,' as vals)
select tr.*
from TestResult tr cross join const
where instr(const.vals, ','||cast(tr.somefield as varchar(255))||',') > 0
order by instr(const.vals, ','||cast(tr.somefield as varchar(255))||',')
I offer this because you might find it easier to maintain a string of values rather than an intermediate table.
I was able to do this in my application using (using SQL Server 2016)
select ItemID, iName
from Items
where ItemID in (13,11,12,1)
order by CHARINDEX(' ' + Convert("varchar",ItemID) + ' ',' 13 , 11 , 12 , 1 ')
I used a code-side regex to replace \b (word boundary) with a space. Something like...
var mylist = "13,11,12,1";
var spacedlist = replace(mylist,/\b/," ");
Importantly, because I can in my scenario, I cache the result until the next time the related items are updated, so that the query is only run at item creation/modification, rather than with each item viewing, helping to minimize any performance hit.
Pass the values in via a collection (SYS.ODCINUMBERLIST is an example of a built-in collection) and then order the rows by the collection's order:
SELECT t.SomeField,
t.OtherField
FROM TestResult t
INNER JOIN (
SELECT ROWNUM AS rn,
COLUMN_VALUE AS value
FROM TABLE(SYS.ODCINUMBERLIST(45,2,445,12,789))
) i
ON t.somefield = i.value
ORDER BY rn
Then, for the sample data:
CREATE TABLE TestResult ( somefield, otherfield ) AS
SELECT 2, 'A' FROM DUAL UNION ALL
SELECT 5, 'B' FROM DUAL UNION ALL
SELECT 12, 'C' FROM DUAL UNION ALL
SELECT 37, 'D' FROM DUAL UNION ALL
SELECT 45, 'E' FROM DUAL UNION ALL
SELECT 100, 'F' FROM DUAL UNION ALL
SELECT 445, 'G' FROM DUAL UNION ALL
SELECT 789, 'H' FROM DUAL UNION ALL
SELECT 999, 'I' FROM DUAL;
The output is:
SOMEFIELD
OTHERFIELD
45
E
2
A
445
G
12
C
789
H
fiddle
I am using Oracle 11.
I have 2 tables
TblA with columns id, entity_id and effective_date.
TblADetail with columns id and value.
If Value = 0 for the effective date, I want to keep looking for the next effective date until I found value <> 0 anymore.
The below query only look for value on 3/10/21.
If value = 0, I want to look for value on 3/11/21. If that's not 0, I want to stop.
But, if that's 0, I want to look for value on 3/12/21. If that's not 0, I want to stop.
But, if that's 0, I want to keep looking until value is not 0.
How can I do that ?
SELECT SUM(pd.VALUE)
FROM TblA p,TblADetail pd
WHERE p.id = pd.id
AND p.effective_date = to_date('03/10/2021','MM/DD/YYYY')
AND TRIM (p.entity_id) = 123
Sample data:
TblA
id entity_id effective_date
1 123 3/10/21
2 123 3/11/21
3 123 3/12/21
TblADetail
id value
1 -136
1 136
2 2000
3 3000
In the above data, for entity_id 123, starting from effective_date 3/10/21, I would like to to return value 2000 (from TblADetail) effective_date 3/11/21.
So, starting from a certain date, I want the results from the minimum date that has non-zero values.
Thank you.
You can do what you need to do by grouping the sum on the effective date, and using the MIN analytic function to find the earliest date. Once you've done that, you simply need to select the date that matches the earliest date.
E.g.:
with tbla as (select 1 id, ' 123' entity_id, to_date('10/03/2021', 'dd/mm/yyyy') effective_date from dual union all
select 2 id, ' 123' entity_id, to_date('11/03/2021', 'dd/mm/yyyy') effective_date from dual union all
select 3 id, ' 123' entity_id, to_date('12/03/2021', 'dd/mm/yyyy') effective_date from dual),
tbla_detail as (select 1 id, -136 value from dual union all
select 1 id, 136 value from dual union all
select 2 id, 2000 value from dual union all
select 3 id, 3000 value from dual),
results as (select a.effective_date,
sum(ad.value) sum_value,
min(case when sum(ad.value) != 0 then a.effective_date end) over () min_effective_date
from tbla a
inner join tbla_detail ad on a.id = ad.id
where a.effective_date >= to_date('10/03/2021', 'dd/mm/yyyy')
and trim(a.entity_id) = '123'
group by a.effective_date)
select sum_value
from results
where effective_date = min_effective_date;
SUM_VALUE
----------
2000
Straightforward; read comments within code. Sample data in lines #1 - 13, query begins at line #14.
SQL> with
2 -- sample data
3 tbla (id, entity_id, effective_date) as
4 (select 1, 123, date '2021-03-10' from dual union all
5 select 2, 123, date '2021-03-11' from dual union all
6 select 3, 123, date '2021-03-12' from dual
7 ),
8 tblb (id, value) as
9 (select 1, -136 from dual union all
10 select 1, 136 from dual union all
11 select 2, 2000 from dual union all
12 select 3, 3000 from dual
13 ),
14 tblb_temp as
15 -- simple grouping per ID
16 (select id, sum(value) value
17 from tblb
18 group by id
19 )
20 -- return TBLA values whose ID equals TBLB_TEMP's minimum ID
21 -- whose value isn't zero
22 select a.id, a.entity_id, a.effective_date
23 from tbla a
24 where a.id = (select min(b.id)
25 from tblb_temp b
26 where b.value > 0
27 );
ID ENTITY_ID EFFECTIVE_
---------- ---------- ----------
2 123 03/11/2021
SQL>
I i want to combine multiple rows result into single row based on one column called type.
Ex say suppose i have below result from my query .
seqnum type name
456 SH Google2
456 CN transwork
123 SH partyshipper
123 CN consignee
Actual result i want is something like below table
seqnum consigneename shippername
456 transwork Google2
123 consignee partyshipper
Basically i want to get result like consignee name when type is CN and shipper name is when type is SH if its not both then i can add extra column with name just like otherparty.
I can get result and iterate result set and set value of object. but i think this will be better if we get formatted result in query only.can some one help in in getting this.
Thanks for the help.
Something like this usually helps; lines #1 - 7 represent your sample data. Code you need begins at line #8.
SQL> with test (seqnum, type, name) as
2 (select 456, 'SH', 'Google2' from dual union all
3 select 456, 'CN', 'transwork' from dual union all
4 select 123, 'SH', 'partyshipper' from dual union all
5 select 123, 'CN', 'consignee' from dual union all
6 select 999, 'XX', 'littlefoot' from dual
7 )
8 select seqnum,
9 max(case when type = 'CN' then name end) consigneename,
10 max(case when type = 'SH' then name end) shipppername,
11 max(case when type not in ('CN', 'SH') then name end) otherparty
12 from test
13 group by seqnum;
SEQNUM CONSIGNEENAM SHIPPPERNAME OTHERPARTY
---------- ------------ ------------ ------------
123 consignee partyshipper
999 littlefoot
456 transwork Google2
SQL>
Borrowing the query from #Littlefoot. You may also use PIVOT for this getting the expected result.
with test (seqnum, type, name) as
(select 456, 'SH', 'Google2' from dual union all
select 456, 'CN', 'transwork' from dual union all
select 123, 'SH', 'partyshipper' from dual union all
select 123, 'CN', 'consignee' from dual union all
select 999, 'OT', 'littlefoot' from dual
)
select * from test
pivot (
min(name) for type in
(
'SH' shippingname
, 'CN' consigneename
, 'OT' someother
)
)
;
SEQNUM SHIPPINGNAME CONSIGNEENAM SOMEOTHER
---------- ------------ ------------ ------------
999 littlefoot
456 Google2 transwork
123 partyshipper consignee
I'd self join the table and filter different types in each side of the join:
SELECT COALESCE(c.seqnum, s.seqnum) AS seqnum,
COALESCE(c.name, 'other') AS consigneename,
COALESCE(s.name, 'other') AS shippername
FROM (SELECT *
FROM mytable
WHERE type = 'CN') c
FULL OUTER JOIN (SELECT *
FROM mytable
WHERE type = 'SN') s ON c.seqnum = s.seqnum
I have some strings within a column of a table like asdfAB98:(hjkl,)AB188(uiop)uuuAB78:jknd. I am wondering how may I extract the largest number within such a string in each row. For example, here the largest number is 188 (out of 188, 98 and 78).
Since the numbers I'm interested in are always right after AB, I was thinking about using regexp_substr. Unfortunately, I'm not sure how to have it output multiple rows so that I can use max clause. PLSQL language would be great as well. Please show me a simple example if you have an idea. Thank you in advance!
You could tokenize the string into all its number components, and then find the maximum:
select max(to_number(
regexp_substr('sdfAB98:(hjkl,)AB188(uiop)uuuAB78:jknd', '(\d+)', 1, level))
) as max_value
from dual
connect by regexp_substr('sdfAB98:(hjkl,)AB188(uiop)uuuAB78:jknd', '(\d+)', 1, level)
is not null;
MAX_VALUE
----------
188
or
select max(to_number(
regexp_substr('sdfAB98:(hjkl,)AB188(uiop)uuuAB78:jknd', '(\d+)', 1, level, null, 1))
) as max_value
from dual
connect by level <= regexp_count('sdfAB98:(hjkl,)AB188(uiop)uuuAB78:jknd', '\d+');
MAX_VALUE
----------
188
If you need to get values from multiple rows you need the connect-by to match the IDs, and also need to include a reference to a non-deterministic function to prevent looping; with two values in a CTE:
with your_table (id, str) as (
select 1, 'sdfAB98:(hjkl,)AB188(uiop)uuuAB78:jknd' from dual
union all select 2, '123abc456abc78d9' from dual
)
select id, max(to_number(regexp_substr(str, '(\d+)', 1, level, null, 1))) as max_value
from your_table
connect by prior id = id
and prior dbms_random.value is not null
and level <= regexp_count(str, '\d+')
group by id;
ID MAX_VALUE
---------- ----------
1 188
2 456
Alternatively (to Alex' answer), if there are multiple rows:
SQL> with your_table (id, str) as (
2 select 1, 'sdfAB98:(hjkl,)AB188(uiop)uuuAB78:jknd' from dual
3 union all select 2, '123abc456abc78d9' from dual
4 )
5 select id, max(to_number(regexp_substr(str, '\d+', 1, column_value))) max_num
6 from your_table,
7 table(cast(multiset(select level from dual
8 connect by level <= regexp_count(str, '\d+')
9 ) as sys.odcinumberlist))
10 group by id;
ID MAX_NUM
---------- ----------
1 188
2 456
SQL>
I have a table that stored users play list, a video can be viewed by multiple users for multiple times.
A records goes like this:
videoid, userid, time
123, abc , 2013-09-11
It means user(abc) has watched video(123) on 2013-09-11
Now I want to find distinct users watched video list (no duplication), and only show the users that have watched more than two videos.
SELECT videoid, userid
FROM table_play_list
WHERE SOME CONDICTION
GROUP BY userid, videoid
The sql only select distinct users watchlist, I also want to filter users that have watched more than two different videos.
I know I have to google and read the documentation first, some said 'HAVING' could solve this, unfortunately, I could not make it.
If I understand correctly, you are looking for users who watched more than two different videos. You can do this by using count(distinct) with a partition by clause:
select userid, videoid
from (SELECT userid, videoid, count(distinct videoid) over (partition by userid) as cnt
FROM table_play_list
WHERE <ANY CONDITION>
) t
where cnt > 2;
Try like this,
SELECT userid, count(*)
FROM table_play_list
--WHERE SOME CONDITION
GROUP BY user_id
having count(*) >2;
Try this if you need to get the count based on userid and videoid(users who watch the same video more than two times).
SELECT userid, videoid, count(*)
FROM table_play_list
--WHERE SOME CONDITION
GROUP BY user_id, video_id
having count(*) >2;
This is probably best handled with analytics (window functions). Without analytics you will probably need a self-join.
SQL> WITH table_play_list AS (
2 SELECT 123 videoid, 'a' userid FROM dual UNION ALL
3 SELECT 125 videoid, 'a' userid FROM dual UNION ALL
4 SELECT 123 videoid, 'b' userid FROM dual UNION ALL
5 SELECT 123 videoid, 'b' userid FROM dual UNION ALL
6 SELECT 123 videoid, 'c' userid FROM dual
7 )
8 SELECT videoid, userid,
9 COUNT(*) over(PARTITION BY userid) nb_video
10 FROM table_play_list;
VIDEOID USERID NB_VIDEO
---------- ------ ----------
123 a 2
125 a 2
123 b 2
123 b 2
123 c 1
This lists all user/video and the total number of videos watched by each user. As you can see user b has watched the same video twice, I don't know if it's possible in your system.
You can filter with a subquery:
SQL> WITH table_play_list AS (
2 SELECT 123 videoid, 'a' userid FROM dual UNION ALL
3 SELECT 125 videoid, 'a' userid FROM dual UNION ALL
4 SELECT 123 videoid, 'b' userid FROM dual UNION ALL
5 SELECT 123 videoid, 'b' userid FROM dual UNION ALL
6 SELECT 123 videoid, 'c' userid FROM dual
7 )
8 SELECT *
9 FROM (SELECT videoid, userid,
10 COUNT(*) over(PARTITION BY userid) nb_video
11 FROM table_play_list)
12 WHERE nb_video > 1;
VIDEOID USERID NB_VIDEO
---------- ------ ----------
123 a 2
125 a 2
123 b 2
123 b 2
The below will give users who have watched more than two different videos.
SELECT userid, count(distinct video_id)
FROM table_play_list
WHERE SOME CONDICTION
GROUP BY user_id
having count(distinct video_id) >2;
If you use Oracle PL/SQL you can use like this:
SELECT column1, column2
FROM
(
SELECT column1, column2, COUNT(column1)
OVER (PARTITION BY column1) AS cnt
FROM test
GROUP BY column1, column2
ORDER BY column1
)
WHERE cnt > 2
If you use standard SQL you can use like this:
SELECT column1, column2
FROM test
WHERE column1 IN
(
SELECT column1
FROM
(
SELECT column1, column2
FROM test
GROUP BY column1, column2
ORDER BY column1
)
GROUP BY column1
HAVING COUNT(column1) > 2
)
GROUP BY column1, column2
ORDER BY column1