Right, so in a Bash script I have the following line:
sed -i 's/$/,"123456","789101112","0001",'"$THEDATE"',"DDX"/' /tmp/tmp02.csv
However, whenever I run it I always get the error
sed: -e expression #1, char 42: unknown option to `s'
I think it's the variable bit, but however I do it it won't seem to escape the double quotes.. Any help greatly appreciated!
I think you have slashes in THEDATE, which are being confused as regex delimiters by sed. Try changing the substitution delimiter, for example with !:
sed -i 's!$!,"123456","789101112","0001",'"$THEDATE"',"DDX"!' /tmp/tmp02.csv
Related
I want to replace with sed in some bash script something like:
s:44:\"STRING\"
To:
s:NEWSTRING:\"NEWSTRING2\"
I tried many ways with escaping special characters, but I got always error
sed: -e expression #1, char 32: unterminateds' command`
or someting like that.
Can you please tell me the correct sed -i (sed -i "s/xxx/xxx/g" file) command for that?
You have to escape the backslashes properly:
sed 's/s:44:\\"STRING\\"/s:NEWSTRING:\\"NEWSTRING2\\"/'
Example:
$ echo 's:44:\"STRING\"' | sed 's/s:44:\\"STRING\\"/s:NEWSTRING:\\"NEWSTRING2\\"/g'
s:NEWSTRING:\"NEWSTRING2\"
You are missing the final delimiter. In your case it seems to be : therefore, you need to add a final : after your substitution content. It does not matter if you are using modification instruction like g
I keep getting the following error:
sed: -e expression #1, char 29: invalid reference \1 on `s' command's RHS
grep -l 'someFiles' | xargs sed -r 's/<add fileName="\(.+?\)"/\1/g'
I am escaping the () as I have read to do in other files, I have also tried to work through it elsewhere:
https://regex101.com/r/tU9qV4/2
so I know my regex is working, I have also tested my grep, I am actually using a few exclusions and things in the statement, but it's outputting exactly what I need. Why am I still not able to use the \1?
I'm having a problem with using sed in a bash script.
Here is the line:
sed -i "s/"$name"/"$input"/g" ~/input.script
I'm getting this error:
sed: -e expression #1, char 24: unterminated `s' command
Weirdly enough it was working in an earlier version of my code. I've been trouble shooting but I cannot find a solution.
You don't need nested quotes. Also, try changing the delimeter:
sed -i "s#$name#$input#g" ~/input.script
I have to find a specific text in the file and then replace that text with some new text.
The contents of the file are:
host=100
servers=4
clients=70
I have tried this:
var=$(grep "servers=" /path/to/file)
sed -i "s/${var}/servers=5/g" /path/to/file
But it gives me the error:
sed: -e expression #1, char 2: unterminated `s' command
Note: All I want is to update the value of each of the variable i.e. servers=4 should be replaced by servers=5.
Please help me figure out the solution.
Thanks.
The output of grep ends with a newline character. sed expects the whole command on one line or escaping line breaks.
However, you can easily achieve the complete task with sed only:
sed -i 's/^servers=[0-9]*$/servers=5/' /path/to/file
sed -i.bak "s/servers=[0-9]*/servers=5/" /path/to/file
I am using shell script. My requirement is to find and replace the string. The string contains "/" char as well. I am getting error sed: -e expression #1, char 18: unterminated `s' command. Can someone tell how should i replace the string which has "/"?
#!/bin/bash
...
search_string="../conf/TestSystem/Inst1.xml"
rep="Inst1/Instrument.xml"
sed -i 's|${line}|${rep}/g' MasterConfiguration.xml
I tried using another sed command but that one also gave error sed: -e expression #1, char 13: unknown option to `s'
sed -e "s/${line}/${rep}/g" MasterConfiguration.xml > tempfile
Whenever you deal with shell-variables you have to get them out of the "sed-string":
For example:
sed -e "s/"${line}"/"${rep}"/g" MasterConfiguration.xml > tempfile
Otherwise sed will treat the chars as-is and search for ${line} literally:
As you see, nothing happens here.
Furthermore, if your variables contain / you need to use another delimiter for sed. I tend to use ~ in such a case, but you're free to use other chars - just be consequent and don't mix them like in your first example-sed-command:
sed 's~'${line}'~'${rep}'/g' //WRONG
sed 's~'${line}'~'${rep}'~g' //RIGHT
Combine both and it will work:
You can try this sed,
sed -i "s#${line}#${rep}#g" MasterConfiguration.xml
Problem:
Instead you have,
sed -i "s|${line}|${rep}/g" MasterConfiguration.xml
It should be,
sed -i "s|${line}|${rep}|g" MasterConfiguration.xml
Syntax:
sed "s|pattern|replacement|g"