Hi guys I'm working with Spring 3.2.3, hibernate 4.2.2 and org.springframework.security 3.0.5. Before I start working with security in spring, my context file was called servlet-context.xml and everything worked fine. Since I start using org.springframework.security 3.0.5 when I try to run my application I get the error:
java.io.FileNotFoundException: Could not open ServletContext resource [/WEB-INF/appServlet-servlet.xml]
My web.xml is:
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<!-- Spring MVC -->
<servlet>
<servlet-name>appServlet</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>appServlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/servlet-context.xml,
/WEB-INF/spring-security.xml
</param-value>
</context-param>
<!-- Spring Security -->
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>
org.springframework.web.filter.DelegatingFilterProxy
</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
Notice that I'm specifying my servlet-context.xml:
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/servlet-context.xml,
/WEB-INF/spring-security.xml
</param-value>
</context-param>
If I leave my web.xml just like this and copy/paste my servlet-context.xml content in a new file called appServlet-servlet.xml, everything works fine. This is confusing for me since I told web.xml that my context file name was servlet-context.xml. Am I forced to call my context file as appServlet-servlet.xml??. Of course, if I delete servlet-context.xml and leave appServlet-servlet.xml making the specficiation in web.xml, works fine.
I just wanna know if is obligatory to call my context file as appServlet-servlet.xml if I want to use spring security in my app.
This is not strange. Spring works this way. Since your DispatchServlet name is appServlet, Spring automatically tries to find the servlet context that has the same name, here "appServlet-servlet.xml".
Here is a page that may help : http://syntx.io/difference-between-loading-context-via-dispatcherservlet-and-contextloaderlistener/
Related
I am using Spring boot 2.6.3 and I have the following web.xml in my project. What would be the ideal way to move this to Java config?
<web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
<display-name>My Web Application</display-name>
<servlet>
<servlet-name>my</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<init-param>
<param-name>contextClass</param-name>
<param-value>org.springframework.web.context.support.AnnotationConfigWebApplicationContext</param-value>
</init-param>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>com.xyz.my.service.custom.config.CustomServiceConfig</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>my</servlet-name>
<url-pattern>/v1/</url-pattern>
</servlet-mapping>
</web-app>
You don't need all of that. Just ditch your web.xml. The AnnotationConfigWebApplicationContext (actually Spring Boot has a specialized sub-class for it) is the default and your configuration class just can be imported or automatically detected
If your #SpringBootApplication annotated class is in the com.xyz.my.service you don't need to do anything. Your CustomServiceConfig will be automatically detected. If it isn't you can add an #Import(CustomServiceConfig.class) to your #SpringBootApplication annotated class.
I am a Spring newbie and am putting together a Spring web-app (not Spring-boot - how much difference does this make?). Deployment is on a Tomcat 7 server.
The app is up and running. My problem is that is only accessible via the standard URL:
http://mycompany.com:8081/cwing-0.0.3-SNAPSHOT/index.html
The following do not work:
http://mycompany.com:8081/cwing-0.0.3-SNAPSHOT
http://mycompany.com:8081/cwing-0.0.3-SNAPSHOT/
even though my web.xml lists index.html as the welcome page.
An additional symptom of the problem is that all sorts of links within the application need to be specified as relative, rather than with a prepended '/'.
But even these urls are not what I really want.
I would rather specify
http://mycompany.com:8081/cwing
and have it bring up the index.html.
Following the lead of Add context path to Spring Boot application
I created an application.xml file in src/main/resources with the following content:
server.contextPath=/cwing
server.port=8081
This doesn't work. http://mycompany.com:8081/cwing brings up a blank page, with a 404 error on the server, as does http://mycompany.com:8081/cwing/index.html.
I must be missing something. What else is needed to get this to work as I want it to work?
UPDATE: as asked, here is the web.xml (irrelevant details removed).
<?xml version="1.0"?>
<web-app xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
version="3.0">
<display-name>cwing</display-name>
<!-- Creates the Spring Container shared by all Servlets and Filters -->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<!-- The definition of the Root Spring Container shared by all Servlets
and Filters -->
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/spring/context.xml
/WEB-INF/spring/datasource.xml
/WEB-INF/spring/security.xml
</param-value>
</context-param>
<servlet>
<servlet-name>d</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/spring/context.xml
/WEB-INF/spring/datasource.xml
/WEB-INF/spring/security.xml
</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
<async-supported>true</async-supported>
</servlet>
<servlet-mapping>
<servlet-name>d</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
<!-- Disables Servlet Container welcome file handling. Needed for compatibility
with Servlet 3.0 and Tomcat 7.0 -->
<welcome-file-list>
<welcome-file>index.html</welcome-file>
</welcome-file-list>
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
...
</web-app>
This is not related to Spring MVC but to specific server, by default Tomcat gets your WAR name as context root. If you want to change this, you can always rename your WAR file or I recommends to change your pom.xml to build your WAR file with final name, here is how to do this:
<build>
<finalName>finalName</finalName>
. . .
</build>
This the file web.xml in WEB-INF
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/applicationContext.xml</param-value>
</context-param>
<filter>
<filter-name>LoginFilter</filter-name>
<filter-class>glpi.filter.LoginFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>LoginFilter</filter-name>
<url-pattern>/index.jsp</url-pattern>
</filter-mapping>
<servlet>
<servlet-name>context</servlet-name>
<servlet-class>org.springframework.web.context.ContextLoaderServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet>
<servlet-name>action</servlet-name>
<servlet-class>org.apache.struts.action.ActionServlet</servlet-class>
<init-param>
<param-name>config</param-name>
<param-value>/WEB-INF/struts-config.xml</param-value>
</init-param>
<init-param>
<param-name>debug</param-name>
<param-value>2</param-value>
</init-param>
<init-param>
<param-name>detail</param-name>
<param-value>2</param-value>
</init-param>
<load-on-startup>2</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>*.htm</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>action</servlet-name>
<url-pattern>*.do</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>
30
</session-timeout>
</session-config>
<welcome-file-list>
<welcome-file>/login.jsp</welcome-file>
</welcome-file-list>
</web-app>
I think you are missing the context loader listener(to pick your spring context file(s)).
Add this to your web.xml
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
You could also check out the Initial web configuration section # http://static.springsource.org/spring/docs/2.0.x/reference/beans.html
You have both ContextLoaderServlet and DispatcherServlet set to load-on-startup = 1. That means either one of them could start first, and you need the ContextLoaderServlet to start first, since that's what creates the root WebApplicationContext that your error says is missing. So leave ContextLoaderServlet's load-on-startup at 1, and change the DispatcherServlet's to 2 or higher.
Actually, it's preferred to use ContextLoaderListener instead of the Servlet unless you're on a really old container where the Listener doesn't work properly.
Add following code in web.xml file, bcs it looks for contex to load so we have to declare it initially.
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/HelloWeb-servlet.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
I've recently stumbled upon the same issue, and I knew for sure it couldn't be caused by misconfiguration because I've copied the entire working Tomcat installation from another machine. Yet I kept getting the same exception:
java.lang.IllegalStateException: No WebApplicationContext found: not in a DispatcherServlet request and no ContextLoaderListener registered?
As I've eventually figured out, it was a wrong JVM version that broke the application: this one used Java 7, whereas the working instance (and the webapp) was on Java 8.
Hope it helps someone struggling with this counter-intuitive error message.
i'm facing an error while trying to run my application, here is the error:
OK - Undeployed application at context path /gest_project In-place
deployment at C:\Users......\target\gest_project Deployment is in
progress...
deploy?config=file%3A%2FC%3A%2FUsers%2Fnadya%2FAppData%2FLocal%2FTemp%2Fcontext1123098247565520222.xml&path=/gest_project
FAIL - Deployed application at context path /gest_project but context
failed to start The module has not been deployed. at
org.netbeans.modules.j2ee.deployment.devmodules.api.Deployment.deploy(Deployment.java:187)
at
org.netbeans.modules.maven.j2ee.ExecutionChecker.performDeploy(ExecutionChecker.java:167)
at
org.netbeans.modules.maven.j2ee.ExecutionChecker.executionResult(ExecutionChecker.java:123)
at
org.netbeans.modules.maven.execute.MavenCommandLineExecutor.run(MavenCommandLineExecutor.java:208)
at
org.netbeans.core.execution.RunClassThread.run(RunClassThread.java:154)
on tomcat log i have this:
GRAVE: Error listenerStart 11 sept. 2011 23:37:04
org.apache.catalina.core.StandardContext startInternal GRAVE:Error
Starting context [/ gest_project] following previous errors
here is my web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
<!--Upload Filters-->
<filter>
<filter-name>PrimeFaces FileUpload Filter</filter-name>
<filter-class>org.primefaces.webapp.filter.FileUploadFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>PrimeFaces FileUpload Filter</filter-name>
<servlet-name>Faces Servlet</servlet-name>
</filter-mapping>
<!--End Upload Filters-->
<context-param>
<param-name>javax.faces.PROJECT_STAGE</param-name>
<param-value>Development</param-value>
</context-param>
<!-- Theme Aristo -->
<context-param>
<param-name>primefaces.THEME</param-name>
<param-value>start</param-value>
</context-param>
<!-- FIN -->
<servlet>
<servlet-name>Faces Servlet</servlet-name>
<servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>/faces/*</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>
30
</session-timeout>
</session-config>
<welcome-file-list>
<welcome-file>faces/admin-direction.xhtml</welcome-file>
</welcome-file-list>
<!-- Add Support for Spring -->
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
<listener>
<listener-class>
org.springframework.web.context.request.RequestContextListener
</listener-class>
</listener>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:application-context.xml</param-value>
</context-param>
<!-- JSF mapping -->
<!-- Map these files with JSF -->
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>*.jsf</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>*.faces</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>*.xhtml</url-pattern>
</servlet-mapping>
</web-app>
thanks a lot
(Not an answer)
Your errors are pretty generic and could be caused by lots of different problems in many other places apart from your web.xml. (The application-context, missing libraries, etc...)
You'll have to dig deeper (other files or look below in the same files) to find an error with more relevant information.
Try to find whether your application is up and running without any errors when you start the server. With that you eliminate any server configuration and dependency issues.
To do that:
1) Stop your tomcat server. Clean/Backup all log files.
2) If 'manager' app is not enabled, then try to enable it.
3) Start the tomcat server. Observe the start up logs for any errors.
4) If every thing is fine in the logs, then go to app manager 'http://localhost:8080/manager/'
to check whether your app is up and running (started) mode.
5) Now try to access the page or URL.
with this you could pin point the possible areas of error.
Problem could be also caused by lack of permissions. In my case I gave permissions (to everyone full access, because I'm not sure to who exactly give them) to folder containing Tomcat. This solved my problem.
I am trying to deploy a Spring application on WAS 6.0 (JDK 1.4.2). Day back I was getting tons of (Unsupported major.minor version 49.0) errors. I replaced most of the jar files and now I am left with only one error on:
org/springframework/orm/jpa/support/OpenEntityManagerInViewFilter (Unsupported major.minor version 49.0)
what jar file do I need to replace for this? Also when I am running my URL in the browser I am getting the error:
Error 500: Filter [Spring OpenEntityManagerInViewFilter]: could not be loaded
Can you please guide me ,where exactly I am doing wrong. Attached is my Web.xml.
Your help is highly appreciated.
enter code here
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
analytics
Roo generated analytics application
<context-param>
<param-name>webAppRootKey</param-name>
<param-value>analytics.root</param-value>
</context-param>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:applicationContext.xml</param-value>
</context-param>
<context-param>
log4jConfigLocation
classpath:log4j.properties
org.springframework.web.util.Log4jConfigListener
org.springframework.web.context.ContextLoaderListener
<servlet>
<servlet-name>analytics</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>2</load-on-startup>
</servlet>
<!-- Serves static resource content from .jar files such as spring-js.jar -->
<servlet>
<servlet-name>Resource Servlet</servlet-name>
<servlet-class>org.springframework.js.resource.ResourceServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>analytics</servlet-name>
<url-pattern>/*.html</url-pattern>
</servlet-mapping>
<!-- Map all /resources requests to the Resource Servlet for handling -->
<servlet-mapping>
<servlet-name>Resource Servlet</servlet-name>
<url-pattern>/resources/*</url-pattern>
</servlet-mapping>
<filter>
<filter-name>httpMethodFilter</filter-name>
<filter-class>org.springframework.web.filter.HiddenHttpMethodFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>httpMethodFilter</filter-name>
<servlet-name>analytics</servlet-name>
</filter-mapping>
<filter>
<filter-name>Spring OpenEntityManagerInViewFilter</filter-name>
<filter-class>org.springframework.orm.jpa.support.OpenEntityManagerInViewFilter</filter-class>
</filter>
Spring OpenEntityManagerInViewFilter
/*
<session-config>
<session-timeout>10</session-timeout>
</session-config>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
<error-page>
<exception-type>java.lang.Exception</exception-type>
<location>/WEB-INF/jsp/uncaughtException.jsp</location>
</error-page>
The "Unsupported major.minor version" errors are caused by your using JAR files compiled for a higher version of java than you're running.
I think class file version 49.0 is Java 5, and you're running 1.4. That means you must be using a library that's Java 5 only, and the only version of Spring thats java 5 only is Spring 3.0. If that's the case, then downgrade your Spring to 2.5.6.