What is the difference between view & partial view in mvc - asp.net-mvc-partialview

i am learning mvc. so like to know what is the difference between view & partial view in mvc in terms of functionality.
normal view & partial view both render html in page....so what is the difference and limitation for two?
what are things are accomplish by partial view. please give me few scenario where people need to use partial view.
here is posting two code to load view based on dropdown value change.
$(function() {
$('#myddl').change(function() {
var url = $(this).data('url');
var value = $(this).val();
$('#result').load(url, { value: value })
});
});
public ActionResult Foo(string value)
{
SomeModel model = ...
return PartialView(model);
}
public ActionResult GetView(int id)
{
switch (id)
{
case 1:
return View("View1", model1);
break;
case 2:
return View("View2", model2);
break;
default:
return View("Default", modelDefault);
}
}
now see one action result return PartialView and another return just view to ajax method. which approach is right? when second approach need to use?
please guide me with knowledge. thanks

We use partial view to render a specific section of a page, like take an example of Customer. Your Index view of Customer controller will be a normal view while your grid of customers will be a partial view so that when you update or insert a new customer or delete a customer you will just render your partial view which contains grid of customers not the whole index view.

As far as i know, a partial is used as part of a view and can be shared across multiple views to provide extra functionality for those views. Also, views can be broken down to partials to make editing easier and eliminate redundancy. Hope it helps a little

Partial view kept to use as partial page of the main page(parent page).
What does mean of partial view? Actually in the main page we will have all the HTML page attributes as below:
html lang="en"
head
title
meta
body
But in partial view we will not have all above attributes.
Find the features of partial page:
1. Partial page will be light wait and get fitted into the any view.
2. This will use as the reusable component.
3. Partial view will be render inside of a View(parent view or page).
For all who coming from ASP.Net background they can understand partial view as user control.
Thanks
Afazal
mdafazal#gmail.com

Related

CakePHP 3 and partial View update via Ajax - How it should be done?

One more time I have bumped into the problem how partial view upadtes via ajax should be done in CakePHP3.
From my point of view, there are 3 ways of doing this:
Render required part of the view in dedicated controller action and simply inject the HTML.
Create dedicated template (*.ctp) file for every ajax action, render it like any other action but without the main layout and inject the HTML (kind of variant 1 but with separated VC logic).
Return only required data as an ajax response (eg. entity data) and build part of my view from javascript on client side.
I think that the most efficient solution will be variant 2 because of separation of controller and view logic.
Variant 1 would most probably cause view beeing built twice (on demand, and after request is processed) like in following snipped:
public function ajaxRenderAuditDetails($id = null)
{
if ($id == null) {
return null;
}
if ($this->request->is("ajax")) {
$this->set("result", $this->viewBuilder()->build()->cell("audits", [$id]));
}
}
Variant 3 on the other hand will double the view code in some cases - for example the same html will be genrated in ViewCell as well as on client side javascript
What are the best practices for handling such functionality?

Back button causes naked partial view

Here's the scenario: I invoke an action method which returns PartialViewresult via ajax. The result is loaded into another view. Then I Navigate to another page and after this if I press browser back button the previously loaded PartialViewResult appears naked. By naked I mean no container view and layout is loaded, just plain html elements are rendered. Like this:
Has anyone faced and tackled this problem?
EDIT: To provide a better understanding of the situation here's my action method:
public ActionResult Inbox(int pageNumber = 1, int pageSize = 10, string filter = null)
{
var inboxItems = GetInboxItems(filter);
PagedList<InboxItem> pagedList = inboxItems.ToPagedList(pageNumber, pageSize);
pagedList.DisplayPage(pageNumber);
InboxViewModel vm = new InboxViewModel(pagedList);
if (!Request.IsAjaxRequest())
return View(vm);
return PartialView(vm);
}
In the Inbox.cshtml file I load layout based on if the request is ajax request:
#model Dokcentra.Models.InboxViewModel
#if (!Request.IsAjaxRequest())
{
Layout = "~/Views/Shared/_Cabinet.cshtml";
}
I think the last piece of code is what causes this problem because the layout file _Cabinet.cshtml has all the html, css and js and when I press browser back button that layout file doesn't load.
After lots of digging and hair pulling I realized that this only happens in Chrome. I found out that I need to provide a different url from the full html document. So when sending a reuest through AJAX to this action method I just append any arbitrary query string value to "?Cabinet/Inbox", like this:
var url= "/Cabinet/Inbox?anythingYouWant"

How to use partial views

I'm coming to a part in my MVC 3 page where I need to do a JQuery $.Ajax callback, but unlike before where I have returned some simple values and handled updating the UI using JQuery I need to refresh the part of the page that displays the main ViewModel data. So in effect it's almost as if I need to do a callback but instead of returning the JSonResult I want to return the original View?? I'm pretty sure though that I need to be thinking about using partial views? Could anyone advise or perhaps point me towards a good tutorial?
Thanks in advance.
If I understand correctly. In this sort of scenario I usually re-use the same action but return either a full or partial view based on the IsAjaxRequest method.
public ActionResult MyAction(string someParam)
{
//...
if (Request.IsAjaxRequest())
{
return PartialView(model);
}
else
{
return View(model);
}
}
This can then be called in jQuery using something like:
$("a.myAction").click(function (event)
{
event.preventDefault();
var button = $(this);
// Get more results using ajax
$.get(button.attr("href"), function (data)
{
// Add the new content
$('div#myActionResult').empty().html(data);
}, "html");
}
You may need to POST instead or change the Url to include a query string if you want to send data to the action to change the view.

How to change WebGrid action for getting data (.NET MVC3)

I have a Partial View that renders WebGrid. My controller looks like
public ActionResult Index()
{
return View();
}
public ActionResult GetUserList(int? page, string sort, string sortdir)
{
var model = UserModel.getList(page,sort,sortdir);
return PartialView("_UserList",model);
}
Index.cshtml :
....
#Html.Action("GetUserList")
The problem is that every time I click on grid navigation or sort links it calls Index method. How can I make Webgrid to execute a different action (GetUserList in this case)? I'm sure I can prepend GetUserList to all links in grid using jquery, but I believe it should be a better way.
It's also possible that what I'm doing is completely wrong, so thanks for your suggestions.
After lot of monkeying around and digging (and even fiddling with Reflector with WebGrid's source code), I came to the conclusion that with WebGrid, you cannot control/change the Header link action.
To create the header link URL, the path is taken from HttpContext.Request.Path, so there is no way to customize it to point to a different route.
One very ugly hack would be to tap into to jQuery Ajax's events (since the header link uses jQuery.load to sort) and overwrite the URL:
Album Id
Better solution would be to use:
Telerik Grid which lets you specify custom routes and also offers much more flexibility in rendering your layout
or MvcContrib Grid (not sure if this lets you modify header links but definitely offers more flexibility than WebGrid)
#MrChief had the idea above about the ugly hack...I put that together. Here is the main code that I used to do this. It does, indeed, hijack the ajax call before it is put on the wire. The key is to modify the URL that is getting sent because the grid will grab that URL from HttpContext.Request.Path. and plug it into the onclick for the anchor element.
I put this into my main common.js and will simply attach a function to capture the ajaxSend event which happens just before the data is sent.
// Used to hijack the sending of all AJAX calls. Before it sends the call to the server, it checks to see if the
// active element (the element that prompted the call) is marked with a given class. If so, then it will perform
// the given operation.
$(document).ajaxSend(function (event, jqXHR, ajaxOptions) {
var activeElement = document.activeElement;
if ($(activeElement).attr('redosorturl') != null) {
// If this is a sort anchor link from a grid that needs to have the sort link redone, do it here.
// the code is in the eipGrip.js file.
if ($(activeElement).attr('redosorturl').toString() == 'redoSortURL') {
var newURL = RedoGridSortURL(activeElement, ajaxOptions.url.toString());
ajaxOptions.url = newURL.toString();
}
}
return false;
});
When rendering the page, I have marked the tag in column header that contains the incorrect URL with a class named "redosorturl', so I know when I hijack the ajax call, the operation has to be done on this element. I then call a custom function that gives me the correct URL, then the ajaxOptions.url is then rewritten with that new URL.
I have to pass the activeElement to that rewrite function so I can traverse up the DOM to get the grid information, where I have put data like the controller and action method that is used along with and IDs and other info that I use for the URL. Likewise, I pass in the current url string because the grid will inject a token at the end of the url that I parse off and put on the new url.
Your conclusion isn't right. You just need to wrap your webgrid in a Get form:
using (Html.BeginForm("GetUserList", "ThingaMaBob", System.Web.Mvc.FormMethod.Get))
{
var grid = new WebGrid(
...
));
Html.Hidden(grid.SortFieldName, grid.SortColumn);
Html.Hidden(grid.SortDirectionFieldName, grid.SortDirection == SortDirection.Ascending ? "ASC" : "DESC");
}
The hiddens are so that the sort dir and sort field end up in parseable form in the querystring. You end up with urls like localhost/ThingaMaBob/GetUserList?someotherfields=whatever=&sort=city&sortdir=ASC
If you remove [HttpPost] attribute and let the route come to the same function. you'll find the Request["page"] value in your method. this will allow you to put a check on Request["Page"] value.

How do you handle displaying navigation and sub navigation in an MVC app?

I'm having trouble determining where to place navigation for an MVC app. For example, say you have the following structure:
Conferences
South Eastern Conference
Florida Gators
Georgia Bulldogs
Arkansas Razorbacks
Pac-10
USC
Hawaii
Big East etc...
How would you best create a structure for implementing a 'main' navigation and subsequent 'sub' navigation? Using the hypothetical example, You'd have specific sub navigation for each conference, showing its respective colleges (and only that conferences colleges).
Is this something you'd handle in the main view and just hide the non-selected conference?
Or would you create a menu helper (or yet another partial) and call that from each individual college's view?
Best way is to use multiple, nested master pages. e.g. Site.master would contain your top-level nav (list of conferences?) then you'd have a different master page for each conference that would 'extend' site.master. You can, in theory, have as many nested master pages as you want. Finally, Florida Gators etc would be 'real' views (i.e. non-master pages).
The tricky part is telling any parent master page which navigation item is currently selected. Because you can't bind master pages to the ViewModel you'll have to use the View Dictionary e.g. View["SelectedMainNavItem"].
Why not use some global layout template that always displays the main navigation, and relies on some helper to render the subnav? (The helper may be superfluous -- you might just output the subnavigation inline in the layout template)
Your controller passes current category/sub-category, and some data structure describing the current subnavigation options, to the view.
After contemplating this issue for a while along with the suggestions, I came up with this solution. Since my subnavigation will always be below the main navigation, I decided to go with the Convention over Configuration method.
In my Site.Master, I have the following two render partials. One displays the main navigation and the other makes a call to BuildSubNavigation to display get the name of a partial to render:
<% Html.RenderPartial("_MainNavigation"); %>
<% var submenu = ViewContext.BuildSubNavigation();
if (submenu != null) {
Html.RenderPartial(submenu);
}%>
Granted, this could be thrown into a Helper, and I intend to do that, this is more explicit and aids in the understanding of the issue.
What this does is call the BuildSubNavigation method. It goes with the convention that if a controller is to have a specific sub navigation, there will be a partial in the form of "_Navigation" So in the spirit of the example, one partial would be "_SouthEasternConferenceNavigation" What I do is then check to see if the current view actually exists. If it does, I return the name, where it's then used to render the partial.
public static string BuildSubNavigation(this ViewContext vc) {
var controller = vc.RouteData.Values["controller"] ?? "";
var viewName = "_" + controller + "Navigation";
if (ViewExists(vc.Controller.ControllerContext, viewName, null)) {
return viewName;
} else {
return null;
}
}
And this is the method that checks whether the View actually exists against the current View Engine:
public static bool ViewExists(ControllerContext cc, string viewName, string masterName) {
if (ViewEngines.Engines.FindView(cc, viewName, masterName).View != null) {
return true;
} else { return false; }
}
I'm unsure if this is the best way to do this, but it's working rather well for a small project I'm currently working on.
Thanks for the answers!

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